Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

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Slide 3- 1 Quick Quiz Sections 3.4 – 3.6 4 3 3 3 3 Y ou should solve the follow ing problem sw ithoutusing agraphing calculator. 1. W hich ofthefollow ing gives for sin 3 ? A 4sin 3 cos 3 B 12sin 3 cos 3 C 12sin 3 cos 3 D 12sin 3 E 12sin 3 cos 3 dy y x dx x x x x x x x x x

Transcript of Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Page 1: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 1

Quick Quiz Sections 3.4 – 3.6

4

3

3

3

3

You should solve the following problems without using a graphing calculator.

1. Which of the following gives for sin 3 ?

A 4sin 3 cos 3

B 12sin 3 cos 3

C 12sin 3 cos 3

D 12sin 3

E 12sin 3 cos 3

dyy x

dx

x x

x x

x x

x

x x

Page 2: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

3.7

Implicit Differentiation

Page 3: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 3

What you’ll learn about

• Implicitly Defined Functions• Lenses, Tangents, and Normal Lines• Derivatives of Higher Order• Rational Powers of Differentiable Functions

… and why

Implicit differentiation allows us to find derivatives of functions that are not defined or written explicitly as a function of a single variable.

Page 4: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 4

Implicitly Defined Functions

An important problem in Calculus is how to find the slope when the

function can't conveniently be solved for . Instead, is treated as

a differentiable function of and both sides of the equation

y y

x are

differentiated with respect to , using the appropriate rules for sums,

products, quotients and the Chain rule. Then solve for in terms of

and together to obtain a formula that calculates

x

dyx

dxy

3 3

1 2

the slope at any

point , on the graph.

The process by which we find is called .

The phrase derives from the fact that the equation

9 0

defines the functions , a

x y

dy

dx

x y xy

f f

implicit differentiation

3nd implicitly (i.e., hidden inside the

equation), without giving us formulas to work with.

f

explicit

Page 5: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 5

Implicitly Defined Functions

Page 6: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

This is not a function, but it would still be nice to be able to find the slope.

Do the same thing to both sides.

Note use of chain rule.

Page 7: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 7

Example Implicitly Defined Functions

2Find if 3 2 5dy

y y xdx

2

2 2

To find differentiate both sides of the equation with respect

to , treating as a differentiable function of and applying the

Chain Rule.

3 2 5

3 3

6 2 5

2 2

dy

dxx y x

y y x

d d dyy y

dx dy dxdy dyy

d d dydx dxy y

dx dy

6 2 5

5

6 2

dx

dyy

dxdy

dx y

Page 8: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 8

Implicit Differentiation Process

1. Differentiate both sides of the equation with respect to .

2. Collect the terms with on one side of the equation.

3. Factor out .

4. Solve for .

x

dy

dxdy

dxdy

dx

Page 9: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

This can’t be solved for y.

This technique is called implicit differentiation.

1 Differentiate both sides w.r.t. x.

2 Solve for .

Page 10: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

We need the slope. Since we can’t solve for y, we use

implicit differentiation to solve for .

Find the equations of the lines tangent and normal to the

curve at .

Note product rule.

Page 11: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Find the equations of the lines tangent and normal to the

curve at .

tangent: normal:

Page 12: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 12

Rule 9 Power Rule For Rational

Powers of x

1

If is any rational number, then

.

If 1, then the derivative does not exist at 0.

n n

n

dx nx

dxn x

Page 13: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Slide 3- 13

Example Derivatives of a Higher Order

22 2

2Find if 25

d xx y

dy

2

Quotient Rule2 2

Substitute for 2

Differentiating each term with respect to gives

2 2 0

2 2

Differentiating again with respect to gives

1

x dy

y dx

x

dyx y

dxdyy xdx

dy x

dx y

x

dyy x

d x dx

dy y

xy x

y

y

2 2

Simplify3

2 2Substitute 25 for

3

25x y

y x

y

y

Page 14: Slide 3- 1 Quick Quiz Sections 3.4 – 3.6. 3.7 Implicit Differentiation.

Higher Order Derivatives

Find if .

Substitute back into the equation.