Phys 102 – Lecture 6 Circuit elements: resistors, capacitors, and batteries 1.
Simple electric circuits that contain batteries, resistors...
Transcript of Simple electric circuits that contain batteries, resistors...
❑ Simple electric circuits that contain
batteries, resistors, and capacitors
in various combinations
28.1 Electromotive Force
• When the potential difference at the batteryterminals is constant in a particular circuit, thecurrent in the circuit is constant in magnitudeand direction and is called direct current.
• A battery is called either a source ofelectromotive force or, more commonly, asource of emf.
• The emf e of a battery is the maximumpossible voltage the battery can providebetween its terminals.
Terminal Voltage
Load Resistance
Internal Resistance
28.2 Resistors in Series and Parallel
Potential Divider
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𝑽𝒙 =𝑹𝒙
𝑹𝒆𝒒. 𝑽𝒎𝒂𝒊𝒏
Potential Divider
This technique is not restricted to only two resistors in series, but may be applied to any number. For
example, if there were three resistors in series, then the p.d. across each may be found from
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The Slidewire Potentiometer
• This instrument is used for the accurate measurement of small voltages.
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Potentiometer, Pot• A potentiometer, informally a pot, is a three-
terminal resistor with a sliding or rotatingcontact that forms an adjustable voltagedivider. If only two terminals are used, one endand the wiper, it acts as a variable resistor orrheostat.
• Potentiometers are commonly used to controlelectrical devices such as volume controls onaudio equipment
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Current Divider When the I is known
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Current Divider
The current divider theory is not limited to only two resistors in parallel. Any number can be
accommodated. However, with three or more parallel resistors the current division method can be
cumbersome to use, and it is much easier for mistakes to be made.
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Current Divider
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𝑰𝒙 =𝑹𝒆𝒒
𝑹𝒙. 𝑰𝒎𝒂𝒊𝒏
❑Use nodes for naming the
equivalent resistance of the
segments of the circuit.
✓ Rab, Rbc, Rac
Problems
I=600 m
A
𝑅𝑙𝑎𝑚𝑝
0.5 A
𝐼
𝐼𝑎𝑏 =2.94
25. 1.93 = 0.227 𝐴
𝑉𝑎𝑏 = 25𝑥0.227 = 5.68 𝑉
𝐼𝑎𝑏
𝐼
𝑉𝑎𝑏 = 1.93𝑥2.94 = 5.68 𝑉
𝐼𝑎𝑏
𝐼𝑎𝑏 =5.68
25= 0.227 𝐴
S is open
S is in position a
S is in position b
𝐼
𝐼
∆𝑉0.750= 0.750𝑥2,67 = 2.0 𝑉
𝑃3 =2.0 2
3=1.33 W 𝑃1 =
2.0 2
1=4.00 W