SECTION 8.5-8.6 Solving Rational Equations and their Applications Solving equations containing...
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Transcript of SECTION 8.5-8.6 Solving Rational Equations and their Applications Solving equations containing...
SECTION 8.5-8.6 Solving Rational Equations and their Applications
Solving equations containing fractions:Key: GET RID OF THE FRACTIONS!Solve:
1486
)7(2)2(4)2(3
6
712
3
212
4
212
6
7
3
2
4
2
)1(6
7
)1(3
2
)1(4
1)1(3
equation. original in thesolution your Check :4 Step
1
99
1459
14839
2)7()2(4)13(3
for x. solve to termslike combine andproperty vedistributi Use:3 Step
126
7
3
212
4
1312
LCM. by theequation theof SIDES BOTH ON EVERYTHINGMultiply :2 Step
12x is6x and 3x, 4x, of CML The
).numerators about thet worry (don' RSDENOMINATO theall of LCM theFind :1 Step6
7
3
2
4
13
x
x
x
x
x
xxx
xx
xx
xxx
x
3 42
When solving proportions (1 rational expression set equal to another),then just cross-multiply.
YES
Check
x
x
xx
xx
multiplyCrossx
Yes
Check
x
x
x
?)3(6)3(83
4
6
83
4
33
8:
3
124
1248
)3(48
:
4
3x
8
Example
?)3(4)2(63
2
6
4:
6
122
)3(423
2
x
4
:Solve
Applications of proportions:Rates: A ratio of two numbers (usually in different units), where one number depends on the other in some manner.When setting up a proportion (one ratio = another ratio), make sure the units of the numerators match and the ratios of the denominators match.
The monthly loan payment for car is $29.50 for each $1000 borrowed. At this rate, find the monthly payment for a $9000 loan.
The phrase “for each” is like “per” in a rate. Since it is $29.50“for each” $1000 borrowed, the rate is written:
$265.50 ispayment Monthly
50.265$
)9000($9000$1000$
50.29$)9000($
$9000 by sidesboth gmultiplyinby itselfby Pget just
g,multiplyin-cross of instead case, In this
9000$1000$
50.29$
9000$1000$
50.29$
P
P
P
P
dAmtBorrowe
Payment
Example:An investment of $1200 earns $96 each year At the same rate,How much additional money must be invested to earn $128each year?
What are we asked to find? How much ADDITONAL money must be invested in order to earn $128 each year.Let x = additional money to be invested.Given info: Rate of investment = Investment/Amount Earned =
Also, amount earned from new investment is $128.
$400. additionalan invest shouldinvestor The:CONCLUSION
invest. amount to additional theyeah,Oh anyway?for stand x didWhat
400
3840096
11520015360096x
15360096115200
1281200120096
:multiply-Cross128$
1200$
96$
1200$128$
1200$
EarnedAmt New
Investment New
96$
1200$
EarnedAmt
Investment
x
x
x
)(x)(
x
x
96$
1200$
Work Problems
Savannah can paint a room in seven hours. Jordan can paint the same room in nine hours. How long does it take for both Savannah and Jordan to paint the room if they are working together?
Rate of Work * Time Worked = Part of Job CompletedRate of Work is the portion of a job that can get done in 1 unit of time (usually hours).If Savannah can paint a room in seven hours, then her rate of work is 1/7 = 1 job/7 hours = 1/7 of a job in 1 hour.Jordan’s rate of work = 1 room/9 hours = 1/9
Savannah’s Part + Jordan’s Part = Whole Job = 1
What are we being asked to find? How long it takes for both Savannah and Jordan to paint the room working together. That is, TIME. Let t = time to work together.
hours 16153
16
63
6316
6379
)63(19
637
63
63
197
19
1
7
1
t
t
tt
tt
LCD
tt
tt
Megan and Julia can finish a piece of work in 15 days. Megan can do the job herself in twenty days. If Julia wanted to do the job alone, how long would it take her?
In this case, let t = time for Julia to do the job alone.Julia’s rate of work =
Given information. The whole job can get done in 15 days. Megan’s rate of work is ____
Megan’s Part + Julia’s Part job = 1
t
1
dayst
t
tt
tt
tt
tLCDt
t
t
60
160
4603
)4(115
)4(4
3)4(
4
115
4
3
115
20
15
1)15(1
)15(20
1
Megan’s Rate of
Work
x Time Worked Together
+ Julia’s Rate of
Work
x Time Worked Together
= 1