Section 6.2 Trigonometric Functions: Unit Circle Approach.

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Section 6.2 Trigonometric Functions: Unit Circle Approach

Transcript of Section 6.2 Trigonometric Functions: Unit Circle Approach.

Page 1: Section 6.2 Trigonometric Functions: Unit Circle Approach.

Section 6.2

Trigonometric Functions:

Unit Circle Approach

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2 2,

2 2

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Make a second congruent triangle.

Use Pythagorean Theorem to find b.

This triangle is equilateral so all sides are 1. 2a = 1 so a = .

1

2

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Find the exact value of each expression.

3 5 9(a) cos135 (b) tan (c) sin 225 (d) cos (e) sin

4 4 4

2 2 2(a) The point , corresponds to 35 so cos 135

2 2 2

2 2 3(b) The point , corresponds to

2 2 4

23 2so tan 14 2

2

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Find the exact value of each expression.

3 5 9(a) cos135 (b) tan (c) sin 225 (d) cos (e) sin

4 4 4

2 2 2(c) The point , corresponds to 225 so sin 225

2 2 2

2 2 5 5 2(d) The point , corresponds to so cos

2 2 4 4 2

2 2 9(e) The point , corresponds to

2 2 4

9 2so sin

4 2

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4 7Find: (a) cos 150 (b) sin ( 30 ) (c) tan (d) sin

3 6

5 3(a) cos 150 cos

6 2

1(b) sin ( 30 ) sin

6 2

34 2(c) tan 3

132

7 1(d) sin

6 2

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Your calculator has buttons for sin, cos, and tan so to find values of the remaining 3 trigonometric functions we use:

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CHANGE MODE TO RADIANS

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2 24 and 3 so 16 9 5a b r a b