Section 6: Trigonometric Identities and Applications · 2018-02-01 · Section 6: Trigonometric...

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Section 6: Trigonometric Identities and Applications The following maps the videos in this section to the Texas Essential Knowledge and Skills for Mathematics TAC §111.42(c). 6.01 Trigonometric Identities Precalculus (5)(M) Precalculus (5)(N) 6.02 Solving Trigonometric Equations Precalculus (5)(M) Precalculus (5)(N) 6.03 Sum and Difference Formulas of Trigonometric Functions Precalculus (5)(M) Precalculus (5)(N) 6.04 Double Angle and Half Angle Formulas of Trigonometric Functions 6.05 Law of Sines and Cosines Precalculus (4)(G) Precalculus (4)(H) 6.06 Trigonometric Word Problems Precalculus (4)(E) Precalculus (4)(F) Precalculus (5)(M) Precalculus (5)(N) 6.07 Vectors Precalculus (4)(I) Precalculus (4)(J) Precalculus (4)(K) Copyright 2017 Licensed and Authorized for Use Only by Texas Education Agency 1

Transcript of Section 6: Trigonometric Identities and Applications · 2018-02-01 · Section 6: Trigonometric...

Section6:TrigonometricIdentitiesandApplicationsThefollowingmapsthevideosinthissectiontotheTexasEssentialKnowledgeandSkillsforMathematicsTAC§111.42(c).6.01TrigonometricIdentities

• Precalculus(5)(M)• Precalculus(5)(N)

6.02SolvingTrigonometricEquations

• Precalculus(5)(M)• Precalculus(5)(N)

6.03SumandDifferenceFormulasofTrigonometricFunctions

• Precalculus(5)(M)• Precalculus(5)(N)

6.04DoubleAngleandHalfAngleFormulasofTrigonometricFunctions6.05LawofSinesandCosines

• Precalculus(4)(G)• Precalculus(4)(H)

6.06TrigonometricWordProblems

• Precalculus(4)(E)• Precalculus(4)(F)• Precalculus(5)(M)• Precalculus(5)(N)

6.07Vectors

• Precalculus(4)(I)• Precalculus(4)(J)• Precalculus(4)(K)

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6.01TrigonometricIdentities

ReciprocalIdentities

sin𝜃 = '()( *

cos𝜃 = ')-(*

tan𝜃 = '(01 *

QuotientIdentities

tan𝜃 = )23*(0)*

cot𝜃 = (0)*)23 *

CofunctionIdentities

sin𝜃 = cos 90 − 𝜃 sec𝜃 = csc 90 − 𝜃 tan𝜃 = cot 90 − 𝜃

cos𝜃 = sin 90 − 𝜃 csc𝜃 = sec 90 − 𝜃 cot𝜃 = tan 90 − 𝜃

NegativeAngleIdentities(Even/OddFunctions)

sin −𝜃 = −sin𝜃

cos −𝜃 = cos𝜃

tan −𝜃 = −tan𝜃

PythagoreanIdentities

sin8𝜃 + cos8𝜃 = 1

1 + tan8𝜃 = sec8𝜃

1 + cot8𝜃 = csc8𝜃

1. Givensec ;8− 𝜃 = 3andcos 𝜃 > 0,findcot 𝜃.

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Belowaresomeguidelinesformatchingorverificationproblems:

Step1: Startwithanyidentities.

Step2:Usethemethodsoffactoring,commondenominators,separatingnumerators,andconjugates.

Step3: Ifnothingisworking,trychangingeverythingtosin𝜃andcos𝜃.

2. Verify'>(0) ?'@(0) ?

= 2csc8𝑥 − 2 csc 𝑥 cot 𝑥 − 1.

3. Verify()( ?@'()( ?>'

= '@)23 ?'>)23 ?

.

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6.02SolvingTrigonometricEquations

Fortheseequations,morethanonesolutionmayexist,ortheremaybenosolution.

1. Solveforallangles𝐴:2 cos 𝐴 − 1 = 0

Belowarestepstousewhenaskedtosolveforallangles:

Step1: Solveforangleswithinthespecifiedinterval.

Step2: Iftheanglesareseparatedby𝜋radians,takethesmallestofthetwoanglesandadd𝜋𝑛,where𝑛isaninteger.

Step3: Iftheanglesarenotseparatedby𝜋radians,takeeachangleandadd2𝜋𝑛,where𝑛isaninteger.

2. Solvecos 𝑥 cot 𝑥 = cos 𝑥forallangles.

3. Solvecos8 𝐴 − 4 cos𝐴 + 3 = 0intheinterval[0,2𝜋).

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6.03SumandDifferenceIdentities

sin 𝑢 + 𝑣 = sin𝑢cos𝑣 + cos𝑢sin𝑣 sin 𝑢 − 𝑣 = sin𝑢cos𝑣 − cos𝑢sin𝑣

cos 𝑢 + 𝑣 = cos𝑢cos𝑣 − sin𝑢sin𝑣 cos 𝑢 − 𝑣 = cos𝑢cos𝑣 + sin𝑢sin𝑣

tan 𝑢 + 𝑣 = 1L3M@1L3N'>1L3M1L3N

tan 𝑢 − 𝑣 = 1L3M>1L3N'@1L3M1L3N

1. Findcos 75°usingsumanddifferenceidentities.

2. Findtan 𝐴 + 𝐵 ifsin𝐴 = ST,𝐴isinQuadrantII,sin𝐵 = − '8

'U,and𝐵isinQuadrantIV.

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6.04Double-AngleandHalf-AngleIdentities

Double-AngleFormulas

sin 2𝑢 = 2sin𝑢cos𝑢cos 2𝑢 = cos8𝑢 − sin8𝑢 = 2cos8𝑢 − 1 = 1 − 2sin8𝑢

tan 2𝑢 =2tan𝑢

1 − tan8𝑢

1. Ifsin𝐵 = − 'Uandtan𝐵 < 0,findsin 2𝐵.

2. Solvesin 2𝐴 = cos𝐴ontheinterval[0,2𝜋).

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Half-AngleFormulas

sin

𝑢2 = ±

1 − cos 𝑢2

cos𝑢2 = ±

1 + cos 𝑢2

tan𝑢2 = ±

1 − cos 𝑢1 + 𝑐𝑜𝑠𝑢 =

1 − cos 𝑢sin 𝑢 =

sin 𝑢1 + cos 𝑢

3. Findtheexactvalueofsin 105°usinghalf-angleformulas.

4. Findtheexactvalueofcos ?8ifcos 𝑥 = '

Tand𝑥isinthefourthquadrant.

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6.05LawofSinesandCosines

Thelawofsinesandcosinesisusedforobliquetriangles,whicharetrianglesthatdonothaverightangles.

Givenangles𝐴,𝐵,and𝐶ofanobliquetrianglewithoppositesides𝑎,𝑏,and𝑐,wehave

Lawofsines–)23^_= )23`

a= )23 b

c

Lawofcosines–𝑎8 = 𝑏8 + 𝑐8 −2𝑏𝑐 cos 𝐴 𝑏8 = 𝑎8 + 𝑐8 −2𝑎𝑐 cos𝐵

𝑐8 = 𝑎8 + 𝑏8 −2𝑎𝑏 cos 𝐶

Herearesomestrategiestoconsiderwhendecidingtousethelawofsinesorthelawofcosines:

• Lawofsines:Usewhenyouaregiventwoanglesandoneside.• Lawofcosines:Usewhenyouaregivenallthreesidesortwo

sidesandoneangle.

1. Givenanobliquetrianglewhere𝑎 = 4,𝑏 = 7,and𝑐 = 6,findangle𝐶.

2. Givenanobliquetrianglewhere𝑏 = 4,𝑐 = 7,andangle𝐶 = 50,findsin𝐵.

3. Findside𝑐ofanobliquetrianglewithside𝑎 = 4,angle𝐴 = 50°,andangle𝐵 = 60°.

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Wehavetwoequationsfortheareaofanobliquetriangle:

Heron’sformulaforarea–Givensides𝑎,𝑏,𝑐andthesemi-perimeter𝑠,wehave

( )12

s a b c= + + andthearea ( )( )( )A s s a s b s c= - - -

Areaofanobliquetriangle–Giventwosidesandtheanglebetweenthem,wehave

𝐴 = '8𝑎𝑏 sin 𝛾 𝐴 = '

8𝑎𝑐 sin 𝛽 𝐴 = '

8𝑏𝑐 sin 𝛼

4. Findtheareaofanobliquetrianglewiththeproperties𝑎 = 4,𝑏 = 7,and𝐶 = 75°.

5. Findtheareaofatrianglewhosesideshavelengthsof3ft,5ft,and6ft.

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6.06TrigonometricWordProblems

Herearetwotipswhensettingupwordproblemsinvolvingtrigonometry:

• Angleofelevationandangleofdepressionarewithrespecttothe𝑥-axis.

• Drawapicture!

1. Supposeyouleanan8-footladderagainstawallata60-degreeangleofelevation.Howhighisthetopoftheladderfromthebaseofthewall?

2. Imaginethatamanisfloatingintheocean,waitingtoberescued.Hespotstwohelicoptersonexactlyoppositesidesofhim,oneata30-degreeangleofelevationandtheotherata60-degreeangleofelevation.Ifthehelicoptersarebothflyingatanaltitudeof100meters,whatisthedistancebetweenthehelicopters?

3. Aplaneliftsoffatanangleofelevationof20degreesatarateof300feetpersecond.Howmanyminutespassbeforeitreachesanaltitudeof6,000feet?

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6.07Vectors

Avectorisadirectedlinesegmentinaplane.

• Avectorisadirectedlinesegmentandhasaninitialpointandaterminalpoint.

• Vectorshaveamagnitude(length)andadirection.

o Magnitudecanbecalculatedusingthedistanceformula.

o Directioncanbecalculatedusingtrigonometry.

• Vectorscanbewrittenas𝑣 =𝑃𝑄where𝑃and𝑄aretwopointsonaplane.

• Vectorscanalsobewrittenincomponentformas𝑣 =𝑣', 𝑣8 .

1. Findthecomponentformandmagnitudeofavectorwithinitialpoint(2,−5)andterminalpoint(−1,−9).

2. Ashipsailsfromportandtravelsonabearingof30degreesnorthofeastataspeedof20nauticalmilesperhour.Afterthreehours,howfareasthastheshipsailed?

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Vectoraddition–Giventwovectors𝑢 = 𝑢', 𝑢8 and𝑣 = 𝑣', 𝑣8 ,then𝑢 + 𝑣 = 𝑢' + 𝑣', 𝑢8 + 𝑣8 .

Scalarmultiplication–Givenavector𝑣 = 𝑣', 𝑣8 andaconstant𝑐,then𝑐𝑣 = 𝑐𝑣', 𝑐𝑣8 .

3. Given𝑢 = 5,8 and𝑣 = −3,7 ,find𝑢 + 𝑣,3𝑢,and3𝑢 − 4𝑣incomponentform.

4. Acycliststartedfromherhomeandtraveledfourmileswest,thenthreemilesnortheast,andfinallytwomilessouth.Howfaristhecyclistfromherhome?

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