Review Game. (2 pts.) (5 pts.) A. School B. Sleeping C. Fighting D. Money (2 pts.)
Section 5-1 - WSDblog.wsd.net/rejohnson/files/2014/01/5-1-lesson.pdfBell Quiz 5-1 Section 5-1 1 10...
Transcript of Section 5-1 - WSDblog.wsd.net/rejohnson/files/2014/01/5-1-lesson.pdfBell Quiz 5-1 Section 5-1 1 10...
Bell Quiz 5-1
1Section 5-1
10 pts
possible
4 pts
Simplify.
2 pts 1. (–2)3
2. 52 – 34
3. Evaluate –5xy when x = 4 and y = –34 pts
5-1 Chapter 5:
2Section 5-1
Chapter 5: Polynomials and Polynomial Functions
Key Concept
Properties of ExponentsProperties of ExponentsProperties of ExponentsProperties of Exponents
3Section 5-1
Property Name Property Example
Product of Powers
(Same base → Add Powers)
Power of a Power
(Power to a Power)
Power of a Product
Negative Exponent
Zero Exponent
Quotient of Powers
Power of a Quotient
nmnmaaa
+=⋅
( ) mnnmaa =
( ) mmmbaab =
0 ,1
≠=−
aa
am
m
0 , ≠=−
aaa
a nm
n
m
0 , ≠=
b
b
a
b
am
mm
0 ,10≠= aa
255555 2)1(313===⋅
−+−
( ) ( ) 729333 62323===
⋅
( ) 129681163232 444=⋅=⋅=⋅
49
1
7
17
2
2==
−
( ) 216666
6 363
6
3
===−−−
−
−
49
16
7
4
7
42
22
==
( ) 1890
=−
EXAMPLE 1 Evaluate numerical expressions
a. (–4 25)2 b.115
118
–1
4Section 5-1
EXAMPLE 1 Evaluate numerical expressions
a. (–4 25)2
= 16 25 2
Power of a product property
Power of a power property
Simplify and evaluate power.
= 118 – 5
Negative exponent property
Quotient of powers property
Simplify and evaluate power.= 113 = 1331
= 16 210 = 16,384
b.115
118
–1
= (– 4)2 (25)2
118
115=
GUIDED PRACTICE for Example 1
Evaluate the expression.
1. (42 )3 2. (–8)(–8)3 3. 2 3
9
6Section 5-1
4096 4096 8
729
EXAMPLE 2 Use scientific notation in real life
7Section 5-1
SKIPSKIPSKIPSKIP
EXAMPLE 3 Simplify expressions
a. b–4b6b7 b.r–2 –3
s3c. 16m4n –5
2n–5
8Section 5-1
EXAMPLE 3 Simplify expressions
a. b–4b6b7 Product of powers property
b.r–2 –3
s3
( r –2 )–3
( s3 )–3= Power of a quotient property
= r 6
s–9Power of a power property
= r6s9 Negative exponent property
c. 16m4n –5
2n–5= 8m4n –5 – (–5) Quotient of powers property
= 8m4n0= 8m4 Zero exponent property
= b–4 + 6 + 7 = b9
EXAMPLE 4 Standardized Test Practice
10Section 5-1
EXAMPLE 4 Standardized Test Practice
SOLUTION
(x–3y3)2
x5y6=
(x–3)2(y3)2
x5y6
x –6y6
x5y6=
Power of a product property
Power of a power property
EXAMPLE 4
= x –6 – 5y6 – 6 Quotient of powers property
= x–11y0 Simplify exponents.
Zero exponent property
= 1x11
Negative exponent property
= x–11 1
The correct answer is B. ANSWER
Standardized Test Practice
GUIDED PRACTICE for Examples 3 and 4
Simplify the expression.
4. x–6x5 x35. (7y2z5)(y–4z–1)
13Section 5-1
6. s 3 2
t–4 7. x4y–2 3
x3y6
x27z4
y2
s6t8 x3
y24
HOMEWORK
Sec 5-1 (pg 333)
3-12 every 3rd, 24-36 every 3rd
14Section 5-1