Sec. 3.4 Satellites and Circular Orbits...orbits. SPH4U1 Sec3.4 Satellites.notebook 3 November 26,...
Transcript of Sec. 3.4 Satellites and Circular Orbits...orbits. SPH4U1 Sec3.4 Satellites.notebook 3 November 26,...
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 191:47 PM
Sec. 3.4 Satellites and Circular Orbits
Learning Goal: By the end of today, I will understand the relationship between orbital velocity and distance from Earth.
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 2710:13 PM
For a communication satellite to be effective it needs to stay in one spot in the sky to receive and send signals.
The satellite wouldn't be effective if it was on the other side of the planet when we beamed our signal up into the sky.
Therefore it needs to maintain a constant velocity to maintain its position in the sky called Geosynchronous orbits.
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 192:22 PM
From our previous proof
The object in circular motion moves
IF the radius is changing, then why doesn't the object end up in the center of the circle?
The change in radius, matches the curvature of the circle, so the object is not only accelerating toward the center of the circle, it is also "falling" toward it.
Since the object is in motion, it essentially moves forward and away, then falls back toward the center.
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 192:23 PM
Satellites in circular orbits
For satellites to stay in orbit, they must match the distance from Earth and the desired velocity together to create the ideal situation for a fixed orbit.
If the velocity is too low or the distance from Earth too small, the satellite will get dragged toward Earth.
If the velocity is too high or the distance from Earth too great, the satellite can escape the gravitational pull of Earth and leave its orbital path
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 191:59 PM
Developing the Relationship for a Fixed OrbitWe are going to combine two ideas together to make a new idea.
Force from Centripetal Acceleration Gravitational Force
Since Fc and Fg need to be the same, we can equate the two together.
Isolate "v"
Notice the mass of the object (satellite) is not a factor.
Since G and me are constant, we now have a relationship between velocity and distance from the center of the Earth.
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 2710:38 PM
Important Known Information
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 2710:36 PM
page 146
radius of Earth PLUS altitude
v(a)
(b)
T = 1.61 hr
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 2710:58 PM
Artificial Gravity
spin the bucket please
Read Sample problem 2 (149)
SPH4U1Sec3.4Satellites.notebook
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November 26, 2020
Feb 199:12 PM
Homework
Read 145 151
page 147 #1, 3
page 150 #7, 8
page 151 # 4, 5