ScreeningTest-JEEAdvanced(IIT)/AIIMS-2017-2019 · 8. No candidates is allowed to carry any textual...

32
SCSS–Screen–1 12-04-2017 Shiv Chhatrapati Shikshan Sanstha, Latur. Date : Apr. 12, 2017 Duration : 3-00 Hrs Question Booklet Sr. No. Screening Test Seat No. ST 17 Candidate's Signature Invigilator's Signature {É®úÒIÉä ºÉÉ`öÒ ¶ÉÖ ¦Éä SUôÉ............! ( P.T.O. ) Section–I Section–II Subject Eng.+M.A. Physics Chemistry Mathematics Biology Questions 30 25 25 25 25 Marks 30 100 100 100 100 Screening Test-JEE Advanced(IIT)/AIIMS-2017-2019 IMPORTANT INSTRUCTIONS 1. Immediately fill in the particulars on this page of the Test Booklet as well as answersheet with Black or Blue Ball Point Pen. Use of pencil is strictly prohibited. 2. Do not open this Test Booklet unitl you are asked to do so. 3. The Test Booklet contains of 130 questions. The maximum marks are 300. 4. There are two sections in the question paper. The subject and distribution of marks of each part is as under. SECTION I – ENGLISH + MENTAL ABILITY – Question No. 1 to 30. Each question carries One Mark. NO negative marking. To qualify for Admission, a candiate has to score minimum 16 marks. SECTION II – This section contains 4 Parts. Candidate has to solve only 3 parts. Candidates opted for PCM group has to solve part A, B, and C. Candidates opted for PCB group has to solve part A, B and D. Part A – PHYSICS (100 marks), Question No. 31 to 55 Part B – CHEMISTRY (100 marks), Question No. 56 to 80 Part C – MATHEMATICS (100 marks), Question No. 81 to 105 Part D – BIOLOGY (100 marks), Question No. 106 to 130 5. There are four choices for every question. Out of which only one choice is correct. 6. Each Correct answer carries FOUR (4) marks and for each incorrect answer, ONE (1) mark will be deducted. For unattempted question NO mark will be deducted. 7. Filling up more than one response in any question will be treated as wrong response and marks for this will be deducted accordingly as per instruction 6 above. 8. No candidates is allowed to carry any textual material, printed or written, bits of papers, pager, mobile phone and other electronic devices. 9. Rough work is to be done on the space provided in the Test Booklet only. 10. On completion of the test, the candidate must hand over the Answer Sheet to the Invigilator on duty. However, candidates are allowed to take away this Question Paper with them. 11. Do not fold or make any stray marks on the Answer Sheet.

Transcript of ScreeningTest-JEEAdvanced(IIT)/AIIMS-2017-2019 · 8. No candidates is allowed to carry any textual...

Page 1: ScreeningTest-JEEAdvanced(IIT)/AIIMS-2017-2019 · 8. No candidates is allowed to carry any textual material, printed or written, bits of papers, pager, mobile phone and other electronic

SCSS–Screen–112-04-2017

Shiv Chhatrapati Shikshan Sanstha, Latur.

Date : Apr. 12, 2017

Duration : 3-00 Hrs

Question Booklet Sr. No. Screening Test Seat No.

S T 1 7

Candidate's Signature Invigilator's Signature

{É®úÒIÉäºÉÉ`öÒ ¶ÉÖ¦ÉäSUôÉ............!( P.T.O. )

Section–I Section–II

Subject Eng.+M.A. Physics Chemistry Mathematics Biology

Questions 3 0 2 5 2 5 2 5 2 5

Marks 3 0 1 0 0 1 0 0 1 0 0 1 0 0

Screening Test-JEE Advanced(IIT)/AIIMS-2017-2019

IMPORTANT INSTRUCTIONS

1. Immediately fill in the particulars on this page of the Test Booklet as well as answersheet with Black or Blue

Ball Point Pen. Use of pencil is strictly prohibited.

2. Do not open this Test Booklet unitl you are asked to do so.

3. The Test Booklet contains of 130 questions. The maximum marks are 300.

4. There are two sections in the question paper. The subject and distribution of marks of each part is as under.

SECTION I –

ENGLISH + MENTAL ABILITY – Question No. 1 to 30.

Each question carries One Mark. NO negative marking.

To qualify for Admission, a candiate has to score minimum 16 marks.

SECTION II – This section contains 4 Parts. Candidate has to solve only 3 parts.

Candidates opted for PCM group has to solve part A, B, and C.

Candidates opted for PCB group has to solve part A, B and D.

Part A – PHYSICS (100 marks), Question No. 31 to 55

Part B – CHEMISTRY (100 marks), Question No. 56 to 80

Part C – MATHEMATICS (100 marks), Question No. 81 to 105

Part D – BIOLOGY (100 marks), Question No. 106 to 130

5. There are four choices for every question. Out of which only one choice is correct.

6. Each Correct answer carries FOUR (4) marks and for each incorrect answer, ONE (1) mark will be deducted.

For unattempted question NO mark will be deducted.

7. Filling up more than one response in any question will be treated as wrong response and marks for this will

be deducted accordingly as per instruction 6 above.

8. No candidates is allowed to carry any textual material, printed or written, bits of papers, pager, mobile

phone and other electronic devices.

9. Rough work is to be done on the space provided in the Test Booklet only.

10. On completion of the test, the candidate must hand over the Answer Sheet to the Invigilator on duty. However,

candidates are allowed to take away this Question Paper with them.

11. Do not fold or make any stray marks on the Answer Sheet.

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Paper–I : English + Mental Ability

Directions for Q. No. 1 to 4

Pick out the most appropriate word from the words given below to each sentence to

complete it meaningfully.

001. Would you like to ----------- off the debate?

(a) Begin (b) Start

(c) Begins (d) Starting

002. She always said that when she grew up she wanted to be -----------.

(a) Doctor (b) A doctor

(c) The doctor (d) An doctor

003. Did you meet the lady ----------- uncle works in the library?

(a) Who (b) Whose

(c) Who’s (d) Whom

004. Later tonight I ----------- my uncle, who is ill in hospital.

(a) Visit (b) Am visiting

(c) Visited (d) Was visited

Directions for Q. No. 5 to 6

In the following questions a set of four words are given marked (A) to (D). In each set a word

has been spelt in four different ways, one of which is correct. Choose the correctly spelt word

005. (a) Accomodate (b) Acomodate

(c) Accommodate (d) Accommodet

006. (a) Vegeterian (b) Vegetarian

(c) Vegetarean (d) Vegitarean

Directions for Q. No. 7 to 8

In the following questions four alternatives are given for the idiom/phrase italicised in the

sentence. Choose the one that best expresses the meaning of the given idiom/phrase:

007. The captain played with determination because the honour of the team was at stake

(a) At the top (b) In danger

(c) Very low (d) Appropriate

008. He was in high spirits when I met him in the restaurant.

(a) He was in a drunken state (b) He was very cheerful

(c) He talked incoherently (d) He was deeply engrossed in thoughts

Directions for Q. No. 9 to 10

In the following questions, out of the four alternatives choose the one that can be substituted

for the given words.

009. The people in a threatre or cinema

(a) Assembly (b) Crowd

(c) Audience (d) Spectators

010. Government by one person

(a) Dictatorship (b) Monarchy

(c) Democracy (d) Oligarchy

011. In the following questions, three out of the four alternatives are same in a certain way and soform a group. Find the odd that does not belong to the group?(a) Triangle (b) Tangent(c) Square (d) Rhombus

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012. Look at this series :

2, 1,1

2,

1

4, ............

What number should come next?

(a)1

3(b)

1

8

(c)2

8(d)

1

16

013. Three ladies X, Y, and Z marry three men A, B & C. ‘X’ is married to A, Y is not married to an

engineer, ‘Z’ is not married to a doctor, ‘C’ is not a doctor and ‘A’ is a Lawyer. Then which of the

following statement is correct?

(a) Y is married to C who is an engineer

(b) Z is married to C who is a doctor

(c) X is married to a doctor

(d) None of these

014. There is a certain relation between two given words on one side of : : and one word is given on

another side of : : while another word is to be found from the given alternatives having the

same relation with this word as, the given pair has. Select the best alternative.

Horse : Jockey : : car :?

(a) Mechanic (b) Chauffeur

(c) Stressing (d) Brake

015. Which two of the five items do not belong with the others?

A B C D E

(a) A and C (b) D and E

(c) B and D (d) B and C

016. Find the odd man out

8, 27, 64, 100, 125, 216, 343

(a) 27 (b) 100

(c) 125 (d) 343

017. Read the following information and answer the question that follows

* Six friends A, B, C, D, E and F are sitting in a closed circle facing the centre

* ‘E’ is to the immediate left to ‘D’

* ‘C’ is exactly between ‘A’ and ‘B’

* ‘F’ is between ‘E’ and ‘A’

Who is to the immediate left of ‘B’?

(a) A (b) C

(c) D (d) E

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018. A certain code, a number 13479 is written as AQFJL and 5268 is written ad DMPN. How is396824 written in that code?(a) QLPNKJ (b) QLPNMF(c) QLPMNF (d) QLPNDF

019 If × means , – means ×, means + and + means –, then[3 – 15 19] × 8 + 6 = ?(a) 8 (b) 4(c) 2 (d) – 1

020. Soni, who is Dubey’s daughter, says to Preeti, “Your mother Shayama is the youngest sister ofmy father, Dubey’s father’s third child is Prabhat.” How is Prabhat related to Preeti?(a) Uncle (b) Father(c) Grandmother (d) Father in law

021. If LINGER is 123497 and FORCE is 56789, then FIERCE is(a) 345667 (b) 529789(c) 345677 (d) 556789

022. Find the missing term in the given figures?

8

9

7

35 7

5

6

04 ?

10

3

57

(a) 12 (b) 9(c) 14 (d) 10

023. On the basis of the following figures you have to tell which will come in place of?

(a) 2 (b) 3(c) 6 (d) 4

024. Find a positive number which when increased by 17 is equal to 60 times the reciprocal of thenumber(a) 3 (b) 10(c) 17 (d) 20

025. The difference between a two-digit number and the number obtained by interchanging thepositions of it’s digits is 36. What is the difference between the two digits of that number?(a) 3 (b) 4(c) 9 (d) can not be determined

026. If one-third of one-fourth of a number is 15, then three-tenth of that number is(a) 35 (b) 36(c) 45 (d) 54

027. In the following questions, three out of the four alternatives are same in a certain way and soform a group. Find the odd that does not belong to the group?(a) April (b) May(c) July (d) Septemer

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028. Look at this series :36, 34, 30, 28, 24, ............What number should come next?(a) 20 (b) 22(c) 23 (d) 26

029. A man walks 9 km to East and then 12 km to south. How far is he from the starting point?(a) 15 km (b) 8 km(c) 7 km (d) None

030. Select the suitable figure from the four alternatives that complete the figure matrix.

(a) (b)

(c) (d)

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Paper–II : Physics

031. A constant force acts on the body of mass m at rest. The velocity aquired in covering specific

distance depends on m as

m ´ÉºiÉÚ ÉÉxÉ +ºÉ±É䱪ÉÉ lÉÉƤɱÉ䱪ÉÉ ´ÉºiÉÚ É®ú κlÉ®ú ¤É±É |ɪÉÖCiÉ ½þÉääiÉä. Ê´Éʶɹ]õ +ÆiÉ®ú EòÉ{ɱªÉÉxÉÆiÉ®ú |ÉÉ{iÉ ½þÉähÉÉ®ú ' v '

B´ÉføÉ ´ÉäMÉ ´ÉºiÉÚ ÉÉxÉ m ´É®ú +´É±ÉƤÉÚxÉ +ºÉä±É iÉ®ú....

(a) m (b)1

m

(c) m (d)1

m

032. A man tries to remain in steady state by pushing his feet and hands against two parallel walls.

Then for equilibrium

BEò ´ªÉCiÉÒ ÎºlÉ®ú +´ÉºlÉä ÉvªÉä ®úɽþhªÉɺÉÉ`öÒ nùÉäx½þÒ {ÉÉªÉ +ÉÊhÉ nùÉäx½þÒ ½þÉiÉ nùÉäxÉ ºÉ¨ÉÉÆiÉ®ú ˦ÉiÉÒSªÉÉ Ê´É¯ûvnù Ênù¶ÉäxÉä

føEò±ÉiÉÉä iÉ®ú ºÉ¨ÉiÉÉä±É ®úÉJÉhªÉɺÉÉ`öÒ

(a) Force of friction should be equal on the two walls

nùÉäx½þÒ Ë¦ÉiÉÒ´É®ú PɹÉÇhÉ ¤É±É ºÉ¨ÉÉxÉ(b) Force exerted by him on both walls should be equal and the walls should not be

frictionless

nùÉäx½þÒ Ë¦ÉiÉÒ´É®ú ºÉ¨ÉÉxÉ ¤É±É |ɪÉÖCiÉ Eò¯ûxÉ +ÉÊhÉ Ë¦ÉiÉÒ PɹÉÇhÉ®úʽþiÉ xÉ äö´ÉiÉÉ(c) He should press his feet with greater force

òiªÉÉxÉä º´ÉiÉ:SªÉÉ {ÉɪÉÉ´É® +ÊiÉ¤É±É |ɪÉÖCiÉ Eäò±Éä {ÉÉʽþVÉä

(d) Coefficient of friction should be equal for both walls

nùÉäx½þÒ Ë¦ÉiÉÒ´É®úÒ±É PɹÉÇhÉÉSÉÉ ºÉ½þMÉÖhÉEò ºÉÉ®úJÉÉ {ÉÉʽþVÉä033. Which of the following is called Newton’s law of equilibrium ?

JÉɱÉÒ±É {ÉèEòÒ EòÉähÉiÉÉ ÊxÉªÉ¨É xªÉÚ]õxÉSÉÉ ºÉÆiÉÖ±ÉxÉ ÊxÉªÉ¨É ¨½þhÉÚxÉ +Éä³ýJɱÉÉ VÉÉiÉÉä ?

(a) 1st law of motion MÉÊiÉʴɹɪÉEò {Éʽþ±ÉÉ ÊxɪɨÉ

(b) 2nd law of motion MÉÊiÉʴɹɪÉEò nÖùºÉ®úÉ ÊxɪɨÉ

(c) 3rd law of motion MÉÊiÉʴɹɪÉEò ÊiɺɮúÉ ÊxɪɨÉ

(d) Law of gravitation MÉÖ ûi´ÉÉEò¹ÉÇhÉÉSÉÉ ÊxɪɨÉ

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034. Two equal masses each m have force F between them when they are at a distance r from each

other. Ifm

2mass is removed from one and added to other by keeping the distance constant the

new force will be

m ´ÉºiÉÚ ÉÉxÉÉSªÉÉ nùÉäxÉ ºÉ¨ÉÉxÉ ´ÉºiÉÚ ' r ' B´Éfø¬É +ÆiÉ®úÉ´É®ú +ºÉiÉÉxÉÉ iªÉÉÆSªÉɨÉvÉÒ±É ¤É±É F B´Éfäø +ºÉiÉä. +ÆiÉ®ú

ºÉ¨ÉÉxÉ äö´ÉÚxÉ VÉ®úm

2B´Éfäø ´ÉºiÉÚ ÉÉxÉ BEòÉ ´ÉºiÉÖiÉÚxÉ Eò¨ÉÒ Eò¯ûxÉ nÖùºÉ­ªÉÉ ´ÉºiÉÚ ÉvªÉä ʨɺɳý±Éä iÉ®ú |ɪÉÖCiÉ ½þÉähÉÉ®äú xÉ´ÉÒxÉ

¤É±É ...........

(a)3

F2

(b)3

F4

(c)3

F8

(d) 3F

035. A rain drop falls at constant speed. The mass of drop is 10 gm and it fall through a distance

100 m vertically then find the work due to gravity (g = 10 m/s2)

{ÉɴɺÉÉSÉÉ lÉå¤É BEòºÉ¨ÉÉxÉ ´ÉäMÉÉxÉä JÉɱÉÒ ªÉäiÉÉä. VÉ®ú lÉå¤ÉÉSÉä ´ÉºiÉÖ ÉÉxÉ 10gm +ºÉä±É 100m +ÆiÉ®úɴɯûxÉ JÉɱÉÒ ªÉäiÉ

+ºÉä±É iÉ®ú MÉÖ ûi´É ¤É±ÉɨÉÖ³äý ÊxɨÉÉÇhÉ ZÉɱÉä±Éä EòɪÉÇ EòÉføÉ.(a) 10 J (b) 100 J

(c) 1 J (d) 0.1 J

036. Average density of the earth

{ÉÞl´ÉÒSÉÒ ºÉ®úɺɮúÒ PÉxÉiÉÉ...

(a) does not depend on g (g SªÉÉ ÊEò¨ÉiÉÒ´É®ú +´É±ÉƤÉÚxÉ xÉɽþÒ)

(b) is a complex function of g (g SÉä Ê¨É¸É EòɪÉÇ +ºÉä±É)

(c) is directly proportional to g (g ¶ÉÒ ºÉ¨ÉÉxÉÖ{ɨÉÒ )

(d) is inversely proportional to g (g ¶ÉÒ ´ªÉºiÉiÉÖ{ÉÉiÉÒ)037. Two balls are dropped from the same point after an interval of 1 sec. If acceleration due to

gravity is 10 m/s2, the separation between the balls, 3 seconds after the release of first ball is

nùÉäxÉ SÉåbÚ÷ BEòÉSÉ Ê`öEòÉhÉɴɯûxÉ 1 ºÉäEÆònùÉSªÉÉ +ÆiÉ®úÉxÉä JÉɱÉÒ ]õÉEò±Éä. VÉ®ú MÉÖ ûi´É i´É®úhÉ 210m / s +ºÉä±É iÉ®ú {Éʽþ±ÉÉ

SÉåbÚ÷ ºÉÉäb÷±ªÉÉSªÉÉ 3 ºÉäEÆònùÉxÉÆiÉ®ú nùÉäxÉ SÉåbÚ÷ ¨ÉvÉÒ±É BEò¨ÉäEòÉÆ{ÉɺÉÚxÉSÉä +ÆiÉ®ú ÊEòiÉÒ +ºÉä±É ?(a) 5 m (b) 10 m

(c) 25 m (d) 30 m

038. At surface of earth where air friction is negligible, object fall with the

{ÉÞl´ÉÒSªÉÉ {ÉÞ¹`ö¦ÉÉMÉÉ´É®ú VªÉÉ Ê`öEòÉhÉÒ ½þ´ÉäSÉä PɹÉÇhÉ ¤É±É xÉMÉhªÉ +ɽäþ, ´ÉºiÉÚ {Éb÷iÉÉÆxÉÉ ÊiÉSÉä............

(a) Different acceleration ´ÉäMɳäý i´É®úhÉ (b) Same velocity BEòºÉÉ®úJÉÉ ´ÉäMÉ

(c) Same acceleration BEòºÉÉ®úJÉä i´É®úhÉ (d) Same speed BEòºÉÉ®úJÉÒ SÉɱÉ

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039 A person travels along a straight road for the first half time with a velocity 1

and the second

half time with a velocity 2. Then the mean velocity is given by

BEò ´ªÉCiÉÒ ºÉ®ú³ý ¨ÉÉMÉÉÇxÉä ºÉÖ û´ÉÉiÉÒSÉÉ +vÉÉÇ ´Éä³ý 1V ªÉÉ ´ÉäMÉÉxÉä +ÉÊhÉ ®úÉʽþ±Éä±ÉÉ +vÉÉÇ ´Éä³ý 2V ªÉÉ ´ÉäMÉÉxÉä |É´ÉÉºÉ Eò®úiÉä

iÉ®ú ºÉ®úɺɮúÒ ´ÉäMÉ V ?

(a)1 2

2

(b)

1 2

2 1 1

(c) 1 2 (d)2

1

040. Displacement-time graph of a body is shown below. Velocity-time graph of the motion of the

body is

BEòÉ ´ÉºiÉÚSÉÉ Ê´ÉºlÉÉ{ÉxÉ-´Éä³ý +ɱÉäJÉ Ênù±ÉÉ +ɽäþ iÉ®ú MÉÊiÉʴɹɪÉEò ´ÉäMÉ-EòÉ±É +ɱÉäJÉ EòÉªÉ +ºÉä±É ?

(a) (b)

(c) (d)

041. A ball is thrown upward from the ground. It is at a height 100 m at two times t1

and t2

respectively. If g = 10 m/s2, then t1t

2is equal to

BEò SÉåbÚ÷ ¨ÉènùÉxÉɴɯûxÉ ´É®ú ¡äòEò±ÉÉ. iÉÉä +xÉÖGò¨Éä 1t +ÉÊhÉ 2t ªÉÉ nùÉäxÉ ´Éä³äýºÉ 100m =ÆSÉÒ´É®ú ½þÉäiÉÉ VÉ®úg 10m / s 2g 10m/s

iÉ®ú 1 2t , t ?1 2t , t ?

(a) 10 (b) 20

(c) 40 (d) 50

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042. A car accelerates uniformly from 54 km/hr to 72 km/hr in 2.5 second. The acceleration of the

car is

BEò EòÉ®ú 54km / hr ´ÉäMÉÉ{ÉɺÉÚxÉ 72km / hr ´ÉäMÉÉ{ɪÉÈiÉ 2.5 ºÉäEÆònùÉiÉ i´É®úhÉÒiÉ ½þÉäiÉä. iÉ®ú ÊxɨÉÉÇhÉ ZÉɱÉä±Éä i´É®úhÉ

ÊEòiÉÒ ?(a) 7.2 m/s2 (b) 2 m/s2

(c) 1 m/s2 (d) 3.6 m/s2

043. A body is projected up with an initial velocity ‘u’ m/s. It goes up to a height ‘h’ meters in ‘t’

seconds time. Then it comes back at the point of projection. Considering negligible air

resistance. Which of the following statement is true?

BEò ´ÉºiÉÚ ‘u’ ¨ÉÒ]õ®ú/ºÉäEÆònù B´Éfø¬É ºÉÖ û´ÉÉiÉÒSªÉÉ ´ÉäMÉÉxÉä ´É®ú {ÉÉ`öʴɱÉÒ. iÉÒ t ºÉäEÆònùÉiÉ ' h ' B´Éfø¬É =ÆSÉÒ´É®ú {ÉÉä½þSÉiÉä.

xÉÆiÉ®ú iÉÒ +É®Æú¦É ˤÉnÚù{ÉɶÉÒ {É®úiÉ ªÉäiÉä. ½þ´ÉäSÉÉ ®úÉävÉ xÉMÉhªÉ ºÉ¨ÉVÉÚxÉ JÉɱÉÒ±É {ÉèEòÒ ¤É®úÉä¤É®ú Ê´ÉvÉÉxÉ EòÉähÉiÉä?

(a) The acceleration is zero i´É®úhÉ ¶ÉÚxªÉ +ɽäþ

(b) The displacement is zero ʴɺlÉÉ{ÉxÉ ¶ÉÚxªÉ +ɽäþ

(c) The average velocity is2h

tºÉ®úɺɮúÒ ´ÉäMÉ

2h

t+ɽä

(d) The final velocity is 2u when body reaches projection point

´ÉºiÉÚ +É®Æú¦É ˤÉnÚù±ÉÉ +ɱªÉÉxÉÆiÉ®ú +ÆÊiÉ¨É ´ÉäMÉ 2u +ºÉä±É044. Three conductors draw current 1A, 2A and 4A when connected in turn across a battery. If they

are connected in series across the same battery, the current drawn will be

iÉÒxÉ ´ÉɽþEò BEòÉ ¤Éì]õ®úÒ±ÉÉ +xÉÖGò¨Éä ´ÉäMÉ´ÉäMɲªÉÉ º´É¯û{ÉɨÉvªÉä VÉÉäb÷±Éä +ºÉiÉÉ, +xÉÖGò¨Éä 1A,2A ´É 4A Ê´ÉtÖiÉvÉÉ®úÉ

´ÉɽÚþxÉ xÉäiÉÉiÉ. VÉ®ú iÉä ºÉ´ÉÇ ´ÉɽþEò BEòºÉ®ú VÉÉäb÷hÉÒ¨ÉvªÉä VÉÉäb÷±Éä iÉ®ú ÊxɨÉÉÇhÉ ½þÉähÉÉ®úÒ Ê´ÉtÖiÉvÉÉ®úÉ..........

(a)2

A7

(b)3

A7

(c)4

A7

(d)5

A7

045. According to Joule’s law, if the potential difference across a conductor of resistivity‘’

remains constant, then the heat produced in the conductor is proportional to

VªÉÖ±ÉSªÉÉ ÊxɪɨÉÉxÉÖºÉÉ®ú, ®úÉävÉEòiÉÉ +ºÉ±É䱪ÉÉ ´ÉɽþEòɨÉvÉÒ±É Ê´É¦É´ÉÉÆiÉ®ú κlÉ®ú +ºÉä±É iÉ®ú ´ÉɽþEòɨÉvªÉä ÊxɨÉÉÇhÉ ½þÉähÉÉ®úÉ

=¹¨ÉÉ ½þÉ ......... ºÉ¨ÉÉxÉÖ{ÉÉiÉÒ +ºÉiÉÉä.

(a)1

(b)

1

(c) 2 (d)

046. If the length of a wire is doubled and its cross-section is also doubled, then its resistance will

VÉ®ú iÉÉ®äúSÉÒ ±ÉÉƤÉÒ nÖù{{É]õ Eäò±ÉÒ +ÉÊhÉ EòÉ]õUäônù ºÉÖvnùÉ nÖù{{É]õ Eäò±ÉÉ iÉ®ú iÉÉ®äúSÉÉ ®úÉävÉ ...........

(a) becomes four times SÉÉè{É]õ ½þÉä<Ç±É (b) become one-fourth BEò SÉiÉÖlÉÉȶÉ

(c) become two times nÖù{{É]õõ ½þÉä<Ç±É (d) remain unchanged ¤Énù±ÉhÉÉ®ú xÉɽþÒ

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047. In the given network the equivalent resistance between A and B is

JÉɱÉÒ Ênù±É䱪ÉÉ +ÉEÞòiÉÒiÉ A +ÉÊhÉ B ¨ÉvÉÒ±É {ÉÊ®úhÉɨÉÒ ®úÉävÉ EòÉªÉ +ºÉä±É?

A BR R R

(a) 3R (b) R

(c)R

3(d)

2R

3

048. An electric current passes through a straight wire in the direction of south to north. Magnetic

compasses are placed at point A and B as shown in the figure.

BEòÉ ºÉ®ú³ý iÉÉ®äú¨ÉvÉÚxÉ nùÊIÉhÉäEòbÚ÷xÉ =kÉ®äúEòbä÷ Ê´ÉtÖiÉ |É´Éɽþ |É´ÉÉʽþiÉ Eäò±ÉÉ. +ÉEÞòiÉÒiÉ nùÉJÉʴɱªÉÉ|ɨÉÉhÉä ºÉÖSÉÒ SÉÖƤÉEò

ˤÉnÚù A +ÉÊhÉ B Ê`öEòÉhÉÒ äö´É±Éä iÉ®ú

A

B

(a) The needle will not deflect

ºÉÖSÉÒSÉÖƤÉEòÉSÉä Ê´ÉSɱÉxÉ ½þÉähÉÉ®ú xÉɽþÒ

(b) Only one of the needles will deflect

nùÉäx½þÒ{ÉèEòÒ BEòÉSÉ ºÉÖSÉÒ Ê´ÉSɱÉxÉ ½þÉä<DZÉ

(c) Both the needles will deflect in the same direction

nùÉäx½þÒ ºÉÖSÉÒSÉä BEòÉSÉ Ênù¶ÉäxÉä Ê ÉSɱÉxÉ ½þÉä<DZÉ

(d) The needles will deflect in the opposite direction

ºÉÖSÉÒ Ê´É¯ûvnù Ênù¶ÉäxÉä Ê´ÉSÉʱÉiÉ ½þÉäiÉÒ±É049. The direction of the force on a current-carrying wire placed in a magnetic field depends on

SÉÖƤÉEòÒªÉ IÉäjÉɨÉvªÉä äö´É±É䱪ÉÉ Ê´ÉtÖiÉvÉÉ®úÉ ´ÉɽÚþxÉ xÉähÉÉ­ªÉÉ ´ÉɽþEòÉ´É®úÒ±É ¤É±ÉÉSÉÒ Ênù¶ÉÉ .... ´É®ú +´É±ÉƤÉÚxÉ +ºÉiÉä.

(a) The direction of current Ê´ÉtÖiÉvÉÉ®äúSªÉÉ Ênù¶Éä É®ú

(b) The direction of the field SÉÖƤÉEòÒªÉ IÉäjÉÉSªÉÉ Ênù¶Éä É®ú

(c) The direction of current as well as field Ê´ÉtÖiÉvÉÉ®äúSªÉÉ ´É SÉÖƤÉEòÒªÉ IÉäjÉÉSªÉÉ Ênù¶Éä É®ú

(d) Neither the direction of current nor the direction of field

Ê´ÉtÖiÉvÉÉ®äúSªÉÉ ËEò´ÉÉ IÉäjÉÉSªÉÉ nùÉäx½þÒSªÉɽþÒ Ênù¶Éä É®ú xÉɽþÒ050. A magnetic field can exert force on

SÉÖƤÉEòÒªÉ IÉäjÉ ....... ´É®ú ¤É±É |ɪÉÖCiÉ Eò¯û ¶ÉEòiÉä.

(a) A moving magnet Ê¡ò®úiªÉÉ SÉÖƤÉEòÉ´É®ú (b) Stationary charge κlÉ®ú |ɦÉÉ®ú

(c) Moving charge SÉ±É |ɦÉÉ®ú (d) All of these ´É®úÒ±É ºÉ´ÉÇ

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051. An electric current can be produced in a closed loop

¤ÉÆÊnùºiÉ ´Éä]õÉ䲪ÉɨÉvªÉä ..... ¨ÉÖ³äý Ê´ÉtÖiÉvÉÉ®úÉ ÊxɨÉÉÇhÉ ½þÉä>ð ¶ÉEòiÉä(a) By connecting it to a battery, but not by moving a magnet near it

´Éä]õÉ䲪ÉɱÉÉ ¤Éì]õ®úÒ VÉÉäbÚ÷xÉ, {ÉhÉ SÉÖƤÉEò Vɴɳý xÉ PÉä ÉÚxÉ VÉÉiÉÉ(b) By moving a magnet near it, but not by connecting it to a battery

´Éä]õÉ䲪ÉÉSªÉÉ Vɴɳý SÉÖƤÉEò xÉä>ðxÉ {ÉhÉ ¤Éì]õ®úÒ±ÉÉ xÉ VÉÉäb÷iÉÉ(c) By connecting it to a battery, as well as by moving a magnet near it

¤Éì]õ®úÒ±ÉÉ VÉÉäbÚ÷xÉ iɺÉäSÉ SÉÖƤÉEò Vɴɳý xÉä>ðxÉ(d) Neither by connecting it to battery nor by moving a magnet near it

¤Éì]õ®úÒ±ÉɽþÒ xÉ VÉÉäb÷iÉÉ +ÉÊhÉ SÉÖƤÉEò½þÒ Vɴɳý xÉ xÉäiÉÉ052. Light ray of frequency n, wavelength , travelling with velocity in air, enters a glass slab of

refractive index . The frequency, wavelength and velocity of the light ray in the glass slab willbe respectively

´ÉÉ®Æú´ÉÉ®úiÉÉ n +ÉÊhÉ iÉ®ÆúMÉ ±ÉÉƤÉÒ +ºÉ±Éä±ÉÉ |ÉEòɶÉÊEò®úhÉ v B´Éfø¬É ´ÉäMÉÉxÉä ½þ´ÉäiÉÚxÉ +{É´ÉiÉÇxÉÉÆEò +ºÉ±É䱪ÉÉEòÉSÉäSªÉÉ ÊSÉ{Éä ÉvªÉä VÉÉiÉÉä iÉÒ EòÉSÉäSªÉÉ ÊSÉ{Éä ÉvÉÒ±É |ÉEòɶÉÊEò®úhÉÉSÉÒ ´ÉÉ®Æú´ÉÉ®úiÉÉ, iÉ®ÆúMÉ ±ÉÉƤÉÒ, +ÉÊhÉ ´ÉäMÉ +xÉÖGò¨Éä....

(a)n

, ,

(b) n, ,

(c) n, ,

(d) 2n, ,

053. A ray of light is incident on the surface separating two media A and B. The figure shows thevariation of sin r with sin i, where ‘i’ is the angle of incidence in medium A and ‘r’ is the angleof refraction in medium B. If C

Aand C

Bare the speeds of light in media A and B, respectivley,

thenA

B

C

C is

BEò |ÉEòÉ¶É ÊEò®úhÉ A +ÉÊhÉ B ªÉÉ nùÉäxÉ ¨ÉÉvªÉ¨ÉÉÆxÉÉ ´ÉäMɳäý Eò®úhÉÉ­ªÉÉ {ÉÞ¹`ö¦ÉÉMÉÉ´É®ú {Éb÷iÉÉä. JÉɱÉÒ±É +ÉEÞòiÉÒ¨ÉvªÉäsin r ´É sin i SÉÉ +ɱÉäJÉ nù¶ÉÇʴɱÉÉ +ɽäþ. +ÉEÞòiÉÒiÉ ‘i’ ½þÉ ¨ÉÉvªÉ¨É A ¨ÉvÉÒ±É +{ÉÉiÉÒ EòÉäxÉ +ÉÊhÉ ‘r’ ½þÉ ¨ÉÉvªÉ¨É

B ¨ÉvÉÒ±É +{É´ÉiÉÇxÉ EòÉäxÉ. VÉ®ú AC +ÉÊhÉ BC ½äþ +xÉÖGò¨Éä ¨ÉÉvªÉ¨É A +ÉÊhÉ ¨ÉÉvªÉ¨É B ¨ÉvÉÒ±É |ÉEòɶÉÉSÉä ´ÉäMÉ

+ºÉiÉÒ±É iÉ®ú A

B

C

C = ?

300

sin i

sin r

(a) 3 (b)1

3

(c)1

2(d) 2

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054. A object is placed at a distance of 60 cm from a convex mirror the magnification is1

2. Where

should the object be placed to get a magnification of1

3?

BEò ´ÉºiÉÚ ¤É̽þ´ÉGò +É®ú¶ÉÉ{ÉɺÉÚxÉ 60 cm +ÆiÉ®úÉ´É®ú äö´É±ÉÒ. ÊiÉSÉä ʴɶÉɱÉxÉ1

2+ɽäþ. iÉ®ú

1

3B´Éfäø ʴɶÉɱÉxÉ

ʨɳýÊ´ÉhªÉɺÉÉ`öÒ ´ÉºiÉÚ EòÉä äö äö´ÉÉ´ÉÒ ±ÉÉMÉä±É. ?(a) – 60 cm (b) – 180 cm

(c) – 120 cm (d) – 80 cm

055. If the linear magnification is + 1 it means the image is formed by

VÉ®ú BEò®äú¹ÉÒªÉ Ê´É¶ÉɱÉxÉ 1 +ºÉä±É iÉ®ú |ÉÊiɨÉÉ ½þÒ .......... ºÉ½þɪªÉÉxÉä iɪÉÉ®ú ZÉɱÉÒ +ºÉä±É.

(a) Concave mirror +ÆiÉÇ ÉGò +É®úºÉÉ (b) Convex mirror ¤É̽þ´ÉGò +É®úºÉÉ

(c) Convex lens ¤É̽þ´ÉGò ˦ÉMÉ (d) Plane mirror ºÉ{ÉÉ]õ +É®úºÉÉ

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Chemistry

056. Sodium or potassium salt of higher carboxylic acids are termed as

EòɤÉÉæCZÉÒʱÉEò +ɨ±ÉÉSªÉÉ ºÉÉäÊb÷ªÉ¨É ËEò´ÉÉ {ÉÉä]ìõζÉ+¨É IÉÉ®úɱÉÉ ..... ¨½þhÉiÉÉiÉ.(a) Oil iÉä±É (b) Fat ¨Éänù(c) Soap ºÉɤÉhÉ (d) Resin ®äúÊZÉxÉ

057. The process of alkaline hydrolysis of oils or fats is called

iÉä±É ËEò´ÉÉ ¨ÉänùÉSªÉÉ +±Eò±ÉÉ<ÇxÉ ½þɪÉbÅ÷ÉäʱÉÊºÉºÉ |ÉÊGòªÉä±ÉÉ ...... ¨½þhÉiÉÉiÉ.(a) Solvolysis ºÉÉì±´½þÉä±ÉɪÉÊºÉºÉ (b) Saponification ºÉɤÉhÉÒEò®úhÉ(c) Decomposition +{ÉPÉ]õxÉ (d) Hydration ½þɪÉbÅä÷¶ÉxÉ

058. In pure iron product from blast furnace is called

º¡òÉä]õ ¦É^õÒiÉÒ±É +¶ÉÖvnù ±ÉÉäJÉÆb÷ =i{ÉÉnùxÉÉºÉ ........ ¨½þhÉiÉÉiÉ.(a) Cast iron (b) Wrought iron

(c) Pig iron (d) Steel

059. Compounds of Homologous series do not have similar......

ºÉ¨ÉVÉÉiÉ ¸ÉähÉÒ¶ÉÒ ºÉƤÉÆÊvÉiÉ ¨ÉÖ±Épù´ªÉÉÆSªÉÉ JÉɱÉÒ±É ¤ÉɤÉÒ ºÉ¨ÉÉxÉ xɺÉiÉÉiÉ.(a) General molecular formula (ºÉɨÉÉxªÉ ºÉÖjÉ)(b) Chemical properties (®úɺÉɪÉÊxÉEò MÉÖhÉvɨÉÇ)(c) Functional group (ÊGòªÉÉi¨ÉEò MÉ]õ)(d) Physical properties (¦ÉÉèÊiÉEò MÉÖhÉvɨÉÇ)

060. If K, L, M, N shells of an atom are full, the total number of electrons in the atom are

VÉ®ú BEò +hÉÚSªÉÉ K, L, M, N EòIÉÉ {ÉÚhÉÇ ¦É®ú±É䱪ÉÉ +ºÉiÉÒ±É iÉ®ú iªÉÉ +hÉÚiÉÒ±É BEÚòhÉ <±ÉäC]ÅõÉìxÉSÉÒ ºÉÆJªÉÉ ÊEòiÉÒ+ºÉä±É?(a) 60 (b) 26

(c) 42 (d) 36

061. The electronic configuration of Sc+3 ion is

Sc+3 +ɪÉxÉSÉä <±ÉäC]ÅõÉìxÉ ºÉÆ û{ÉhÉ-(a) 2, 8, 8, 0 (b) 2, 8, 10, 1

(c) 2, 8, 9, 1 (d) 2, 8, 9, 2

062. The element with electronic configuration [Ne] 3s2 3p6, 3d1, 4s2 belongs to

<±ÉäC]ÅõÉìxÉ ºÉÆ û{ÉhÉ [Ne] 3s2 3p6, 3d1, 4s2 +ºÉ±Éä±Éä ¨ÉÚ±Épù´ªÉ .......... ¶ÉÒ ºÉƤÉÆÊvÉiÉ +ɽäþ.(a) 11th group 4th period (b) 2nd group 3rd period

(c) 3rd group 4th period (d) 4th group 3r period

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063. Identify the type of reaction in each case

JÉɱÉÒ Ênù±É䱪ÉÉ +ʦÉÊGòªÉÉÆSÉä |ÉEòÉ®ú +Éä³ýJÉÉ : ZnCO3(s) ZnO

(s)+ CO

2(g)

H2(g)

+ Cl2(g) 2HCl

(g)

(a) Combination, Decomposition (ºÉƪÉÉäMÉ, +{ÉPÉ]õxÉ)(b) Double displacement (nÖù½äþ®úÒ Ê´ÉºlÉÉ{ÉxÉ)(c) Decomposition, Combination (+{ÉPÉ]õxÉ, ºÉƪÉÉäMÉ)(d) Displacement, Decomposition (ʴɺlÉÉ{ÉxÉ, +{ÉPÉ]õxÉ)

064. Which of the following electronic configuration corresponds to the most electropositive nature?

JÉɱÉÒ±É {ÉèEòÒ EòÉähÉiÉä <±ÉäC]ÅõÉìxÉ ºÉÆ û{ÉhÉ +ÊiÉvÉxÉ |ɦÉÉÊ®úiÉ MÉÖhÉ nù¶ÉÇ ÉiÉÉä ?(a) [He]2S1 (b) [He]2S2

(c) [Xe]6S1 (d) [Xe]6S2

065. Which of the following elements has the largest atomic radius ?

JÉɱÉÒ±É {ÉèEòÒ EòÉähÉiªÉÉ ¨ÉÖ±Épù´ªÉÉSÉÒ +Îh´ÉªÉ ÊjÉVªÉÉ ºÉ´ÉÉÇiÉ VÉɺiÉ +ɽäþ ?(a) Na+ (b) Mg+2

(c) O–2 (d) Al+3

066. Which of the following arrangements does not give the correct trends indicated against it ?

JÉɱÉÒ±É {ÉèEòÒ EòÉähÉiÉÒ ®úSÉxÉÉ iªÉɺɨÉÉä®ú Ênù±É䱪ÉÉ MÉÖhÉvɨÉÉDZÉÉ +xÉֺɯûxÉ xÉɽþÒ ?(a) F

2> Cl

2> Br

2> I

2electronegativity (@ñhÉ|ɦÉÉÊ®úiÉÉ)

(b) F2

> Cl2

> Br2

> I2oxidising power (+ÉìCºÉÒb÷ɪÉËZÉMÉ IɨÉiÉÉ)

(c) Cl2

> F2

> Br2

> I2electron gain enthalpy (<±ÉäC]ÅõÉìxÉ MÉäxÉ <xlÉɱ{ÉÒ)

(d) F2

> Cl2

> Br2

> I2bond dissociation energy (¤ÉÆvÉ iÉÉäb÷hÉÉ®úÒ (Breaking)>ðVÉÉÇ)

067. The molecular formula of sodium phosphate is

ºÉÉäÊb÷+¨É ¡òÉ캡äò]õSÉää ®äúhÉÖºÉÚjÉ .......... +ɽäþ.(a) NaPO

3(b) NaPO

4

(c) Na3PO

4(d) Na

4PO

3

068. If one mole of carbon contains X atoms then number of atoms in 12 g of Mg is

(C = 12, Mg = 24)

VÉ®ú EòɤÉÇxÉSªÉÉ BEòÉ ¨ÉÉä±É¨ÉvªÉä X +hÉÚ +ºÉiÉÒ±É iÉ®ú Mg SªÉÉ 12 g ¨ÉvÉÒ±É +hÉÚSÉÒ ºÉÆJªÉÉ ÊEòiÉÒ ?

(a) X (b)X

2

(c) 2X (d)3

X2

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069. If 1 ml of water has 20 drops and A is Avogadro’s number then number of molecules in the drop

of water are.....

VÉ®ú 1 ml {ÉÉhªÉɨÉvªÉä 20 lÉå¤É +ºÉiÉÒ±É +ÉÊhÉ A ½þÉ +ì ½þÉMÉìbÅ÷÷Éä xÉƤɮú +ºÉä±É iÉ®ú {ÉÉhªÉÉSªÉÉ BEòÉ lÉå¤ÉɨÉvªÉä +ºÉhÉÉ­ªÉÉ®äúhÉÚÆSÉÒ ºÉÆJªÉÉ ÊEòiÉÒ ?

(a) 0.5 A/18 (b) 0.05 A

(c) 0.5 A (d) 0.05 A/18

070. A Hydrate of Na2SO

3having 50 % water by mass is (Na = 23 S = 32 O = 16 H = 1)

{ÉÉhªÉÉSÉä ´ÉVÉxÉÒ |ɨÉÉhÉ 50 % +ºÉhÉÉ®äú Na2SO

3SÉÉ º¡òÊ]õEò VÉ±É (½þɪÉbÅä÷]õõ÷) EòÉähÉiÉä ?

(Na = 23 S = 32 O = 16 H = 1)

(a) Na2SO

3. 5H

2O (b) Na

2SO

3. 6H

2O

(c) Na2SO

3. 7H

2O (d) Na

2SO

3. 2H

2O

071. 23 g of sodium will react with methanol to give

23 g ºÉÉäÊb÷+¨ÉSÉÒ Ê¨ÉlÉìxÉÉì±É ºÉÉä¤ÉiÉ +ʦÉÊGòªÉÉ ZÉɱÉÒ +ºÉiÉÉ .... ʨɳýiÉä.

(a) 1 mole of O2

(b)1

2mole of H

2

(c) 1 mole of H2

(d)1

4mole of O

2

072. Co-efficients of reactants and products after balancing following reaction is

JÉɱÉÒ±É ®úɺÉɪÉÊxÉEò +ʦÉÊGòªÉÉ ºÉÆiÉÖ±ÉÒiÉ Eò¯ûxÉ +ʦÉÊGòªÉÉ EòÉ®úEäò +ÉÊhÉ =i{ÉÉÊnùiÉä ªÉÉÆSÉä ºÉ½þMÉÖhÉEò +Éä³ýJÉÉ.

4 2 6PtCl XeF PtF ClF Xe

(a) 16 (b) 13

(c) 18 (d) 12

073. Phenolphthalein is not a suitable indicator for the titration between

Ê¡òxÉÉ챡òlÉì±ÉÒxÉ ½äþ nù¶ÉÇEò JÉɱÉÒ±É{ÉèEòÒ EòÉähÉiªÉÉ ]õɪÉ]Åäõ¶ÉxÉ ºÉÉ`öÒ ªÉÉäMªÉ xÉɽþÒ ?(a) KOH and H

2SO

4(b) NaOH and HCl

(c) Ba(OH)2

and HCl (d) H2C

2O

4and KMnO

4

074. CaCO (s)3 Residue + Gas.

Residue when dissolves in water, produces

CaCO (s)3 MÉɳý + ´ÉɪÉÚ .

MÉɳý {ÉÉhªÉɨÉvªÉä Ê´É®úPɳý±ªÉÉ xÉÆiÉ®ú ......... iɪÉÉ®ú ½þÉäiÉÉä.(a) CO

2(g) (b) H

2(g)

(c) O2(g) (d) H

2O vapours

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075. Pencillin is an antibiotic with a formula C9H

11N

2O

4SR (R = alkyl group). Pencillin reacts with

CH3OH to give a compound methyl pencilloate having following structure

S

H N

CH3

CH3

H

COOH

HHH

CC N

O

R

H COOC3

The correct set of functional groups in the above compound is....

{ÉäÊxÉʺɱÉÒxÉ ªÉÉ |ÉÊiÉVÉèÊ´ÉEòÉSÉä ®äúhÉÖºÉÚjÉ C9H

11N

2O

4SR (R = +αEò±É MÉ]õ) {ÉäÊxÉʺɱÉÒxÉ SÉä ʨÉÊlÉ±É +±EòÉä½þÉä±É

+ʦÉÊGòªÉÉ ZÉɱªÉÉxÉÆiÉ®ú ʨÉÊlÉ±É {ÉäÎxºÉ±ÉÉäB]õ iɪÉÉ®ú ½þÉäiÉä VªÉÉSÉä ®úSÉxÉɺÉÚjÉ ´É®úÒ±É |ɨÉÉhÉä +ɽäþ iÉ®ú ªÉÉ ºÉƪÉÖMÉɨÉvªÉä +ºÉhÉÉ®äúªÉÉäMªÉ ÊGòªÉÉi¨ÉEò MÉ]õ EòÉähÉiÉä ?(a) acid, amide, aldehyde and primary amine

(b) acid, ester, amide, secondary amine

(c) secondary amine, ketone, amide, acid

(d) tertiary amine, ester, amide, ketone

076. CARNALLITE (K(x)

MgCl3

. 6H2O) and LANGBEINITE (K

(y)Mg

2(SO

4)

3) are mixed ore of K and

Mg. What is the sum of x and y ?

EòÉxÉDZÉÉ<] (K(x)

MgCl3

. 6H2O)õ ´É ±ÉÄMɤÉäxÉÉ<] (K

(y)Mg

2(SO

4)

3)õ ½äþ K +ÉÊhÉ Mg SÉä BEòÊjÉiÉ vÉÉiÉÖEò +ɽäþiÉ.

iªÉÉiÉÒ±É xú +ÉÊhÉ y SÉÒ ¤ÉäÊ®úVÉ ÊEòiÉÒ?(a) 4 (b) 3

(c) 2 (d) 5

077. The metal and non-metal present in fool’s gold are also present in

¡Öò±ºÉ MÉÉä±b÷ ¨ÉvªÉä +ºÉhÉÉ®äú vÉÉiÉÚ +ÉÊhÉ +vÉÉiÉÚ .... ¨ÉvªÉä½þÒ +ºÉiÉÉiÉ.

(a) Chalcopyrites SÉɱEòÉä{ÉɪɮúÉ<Ç]ÂõºÉ

(b) Galena MÉä±ÉäxÉÉ

(c) Cinnabar ʺÉxxÉɤÉÉ®ú

(d) Haematite ½äþ¨Éì]õÉ<Ç]õ

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078. The following molecules/compounds are square planar

Pt

NH3

H3N Cl

Cl

Figure - I

Pt

NH3

NH3

Cl

Cl

Figure - II

In the above molecules Pt–Cl distance is 2.32 A°. Then Cl–Cl distance in I and II

respectively are...

´É®ú Ênù±Éä±Éä ®äúhÉÚ ËEò´ÉÉ ºÉƪÉÖMÉä ½äþ SÉÉè®úºÉ ÊxɪÉÉäVÉEò +ɽäþiÉ. iªÉÉiÉ Pt–Cl +ÆiÉ®ú ½äþ 2.32 A° +ɽäþ iÉ®ú I ´É II ¨ÉvÉÒ±ÉCl-Cl SÉä +xÉÖGò¨Éä +ÆiÉ®ú ÊEòiÉÒ ?(a) 4.64 A°, 3.28 A° (b) 5.64 A°, 4.64 A°

(c) 3.28 A°, 4.64 A° (d) 3.28 A°, 3.28 A°

079. Formula of mercurous chloride is

¨ÉCªÉÖÇ®úºÉ C±ÉÉä®úÉ<b÷SÉä ®äúhÉÚºÉÚjÉ .......... +ɽäþ.(a) HgCl

2(b) HgCl

(c) Hg2Cl

2(d) Hg

2Cl

080. Identify the correct order of acidic strengths in CO2,CuO, CaO, H

2O

ªÉÉiÉÒ±É +ɨ±ÉÉSªÉÉ ÊiɵÉiÉäSÉÉ ªÉÉäMªÉ Gò¨É +Éä³JÉÉ.(a) CaO < CuO < H

2O < CO

2(b) H

2O < CuO < CaO < CO

2

(c) CaO < H2O < CuO < CO

2(d) H

2O < CO

2< CaO < CuO

Pt Pt

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Mathematics

081. There are 100 pages in a book. If a page of book is opened at random, then the probability thatthe number on the page is two digit number made up with the same digit is

BEòÉ {ÉÖºiÉEòɱÉÉ 100 {ÉÉxÉä +ɽäþiÉ. VÉ®ú {ÉÖºiÉEòÉÆSÉÒ {ÉÉxÉä ªÉÉoùÎSUôEò {ÉvnùiÉÒxÉä =PÉb÷±ÉÒ iÉ®ú {ÉÖºiÉEòÉÆSÉä {ÉÞ¹`öGò¨ÉÉÆEò({ÉäVÉ Gò¨ÉÉÆEò) nùÉäxÉ ºÉ¨ÉÉxÉ +ÆEòÉiÉ +ºÉhÉÉ­ªÉÉ ºÉÆJªÉäSÉÒ ºÉƦÉÉ´ªÉiÉÉ EòÉªÉ ?

(a)8

100(b)

1

10

(c)9

100(d)

8

10082. When a fair coin is tossed thrice. The probability of obtaining head at most twice is

VÉä ½þÉ BEò xÉÉhÉä iÉÒxÉnùÉ ¡äòEò±Éä +ºÉiÉÉ, VÉɺiÉÒiÉ VÉɺiÉ nùÉäxÉnùÉ UôÉ{ÉÉ Ê¨É³ýhªÉÉSÉÒ ¶ÉCªÉiÉÉ EòÉføÉ.

(a)1

2(b)

5

8

(c)7

8(d)

3

4083. As shown in the diagram, region R in the plane has vertices at (0, 0), (0, 5), (4, 5), (4, 1),

(9, 1) and (9, 0). There is straight line y = mx that partitions R into two subregions of equalarea, then value of m is

JÉɱÉÒ Ênù±É䱪ÉÉ +ÉEÞòiÉÒiÉ, ®äúJÉÉÆÊEòiÉ ¦ÉÉMÉÉSªÉÉ +ÉEÞòiÉÒSªÉÉ Ê¶É®úÉäˤÉnÖùSÉä ÊxÉnæù¶ÉEò (0, 0), (0, 5), (4, 5), (4, 1),

(9, 1) +ÉÊhÉ (9, 0) +ɽäþiÉ. ®äú¹ÉÉ y mx ½þÒ ®äú¹ÉÉËEòiÉ ¦ÉÉMÉÉSÉä nùÉäxÉ IÉäjÉ ºÉ¨É¦ÉÉMÉÉiÉ Ê´É¦ÉÉVÉxÉ Eò®úiÉä iÉ®ú m SÉÒËEò¨ÉiÉ ÊEòiÉÒ ?

O

1

1 2 3 4 5 6 7 8 9

2

3

4

5

(a) 1 (b)15

16

(c)5

4(d)

4

3

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084. In the fig. equal perpendiculars CE and BF intersect in O. If A( EOB) 4 , A( COF) 8 ,

A( BOC) 16 , A( AOE) y , A( AOF) x then x and y are

+ÉEÞòiÉÒiÉ, ºÉ¨ÉÉxÉ Ê¶É®úÉä±ÉÆ¤É CE ´É BF BEò¨ÉäEòÉÆºÉ Ë¤ÉnÚù O ¨ÉvªÉä UäônùiÉÉiÉ. iÉ®ú A( EOB) 4 , A( COF) 8 ,A( BOC) 16 , A( AOE) y , A( AOF) x iÉ®ú x ´É y SªÉÉ ËEò¨ÉiÉÒ EòÉføÉ.

B C

F

A

E

O

(a)20 24

x ,y7 7

(b)24 20

x ,y7 7

(c)12 10

x ,y7 7

(d)24 26

x ,y7 7

085. If AB, AC, PQ are tangents in the fig. and AB = 5 cm. Find the perimeter of APQ

VÉ®ú AB, AC, PQ ½äþ ´ÉiÉÖdzýÉSªÉÉ º{É̶ÉEòÉ +ɽäþiÉ +ÉÊhÉ AB = 5 cm iÉ® APQ SÉÒ {ÉÊ®úʨÉiÉÒ EòÉføÉ.

B P

A

Q

C

(a) 10 (b) 9

(c) 8 (d) 4

086. It is given that in a group of 3 students the probability of 2 students not have the same birthday

is 0.992. What is the probability that the two students have the same birthday.

3 Ê´ÉtÉlªÉÉÈSÉÉ BEòÉ MÉ]ÉiÉõ nùÉäxÉ Ê´ÉtÉlªÉÉÈSÉÉ ´ÉÉføÊnù´ÉºÉ BEòÉSÉ Ênù´É¶ÉÒ xɺÉhªÉÉSÉÒ ¶ÉCªÉiÉÉ 0.992 +ɽäþ. iÉ®ú nùÉäxÉ

Ê´ÉtÉlªÉÉÈSÉÉ ´ÉÉføÊnù´ÉºÉ BEòÉSÉ Ênù´É¶ÉÒ +ºÉhªÉÉSÉÒ ºÉƦÉÉ´ªÉiÉÉ EòÉªÉ ?(a) 0.662 (b) 0.653

(c) 0.080 (d) 0.008

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087. A missing helicopter is reported to have crashed somewhere in the rectangular region. shownin fig. what is the probability that it crashed inside the circle with diameter 7 km

BEòÉ +ɪÉiÉÉEÞòiÉÒ ¦ÉÉMÉÉiÉ, BEò SÉÖEò±Éä±Éä ½äþʱÉEòÉì{]õ®ú EòÉä äöiÉ®úÒ Gìò¶É ZÉɱÉä +ɽäþ iÉä +ÉEÞòiÉÒiÉ nùÉJɴɱÉä +ɽäþ iÉ®ú iÉä½äþʱÉEòÉì{]õ®ú +ÉEÞòiÉÒ¨ÉvÉÒ±É 7km ´ªÉÉºÉ +ºÉ±É䱪ÉÉ ´ÉiÉÖdzýÉEòÉ®ú ºÉ®úÉä É®ú ¨ÉvªÉä Gìò¶É ½þÉähªÉÉSÉÒ ºÉƦÉÉ ªÉiÉÉ EòÉªÉ ?

7 km4.5 km

9 km

(a)77

81(b)

81

77

(c)81

22(d)

22

81088. Find the ratio between area of a square inscribed in a circle and equilateral triangle

circumcribed about the same circle

BEòÉSÉ ´ÉiÉÖdzýÉiÉÒ±É +ÉÆiÉ®úʱÉÊJÉiÉ SÉÉè®úºÉ ´É ºÉ¨É¦ÉÖVÉ ÊjÉEòÉähÉÉSªÉÉ +ÆiÉÇ ÉiÉÖdzýÉSªÉÉ IÉäjÉ¡ò³ýÉSÉä MÉÖhÉÉäkÉ®ú ÊEòiÉÒ ?

(a) 2 (b)2

3

(c)1

3 3(d)

2

3 3

089 If the linear equations 2x + 3y = 7 and (a – b)x + (a + b)y = 3a + b – 2 have an infinite number ofsolutions. Then values of a and b

VÉ®ú 2x 3y 7 +ÉÊhÉ (a b)x (a b)y 3a b 2 ªÉÉ BEòºÉɨÉÉʪÉEò ºÉ¨ÉÒEò®úhÉÉÆxÉÉ +ÆxÉiÉ =Eò±ÉÒ +ºÉiÉÒ±É,iÉ®ú a +ÉÊhÉ b SªÉÉ ËEò¨ÉiÉÒ EòÉføÉ.(a) a = 1, b = 5 (b) a = 5, b = 1(c) a = 3, b = 2 (d) a = 5, b = 2

090. Find the value of 47

34

47

34 SÉÒ ËEò¨ÉiÉ EòÉføÉ.

(a) 3 1 (b) 3 1

(c)2

3 1(d)

2

3 1

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091. Four congruent triangle corners are cut off an 11 × 13 rectangle. The resulting octagon hasedges of equal length, then what is its length?

11 13 ʨÉiÉÒ +ºÉ±É䱪ÉÉ +ɪÉiÉɨÉvªÉä SÉÉ®ú EòÉä{É­ªÉÉiÉ SÉÉ®ú BEò¯û{É ÊjÉEòÉähÉ EòÉ{ɱªÉÉºÉ BEò ºÉÖºÉ¨É +¹]õEòÉäxÉ iɪÉÉ®ú½þÉäiÉÉä. iÉ®ú ºÉÖºÉ¨É +¹]õEòÉäxÉÉSÉÒ ¤ÉÉVÉÚ ÊEòiÉÒ ?(a) 21 (b) 4(c) 3 (d) 5

092. I f , , are roots of the equation 3x3 – 5x2 – 11x – 3 = 0 then the value of 3 3 3 3 is

VÉ®ú , , ½þÒ 3 23x 5x 11x 3 0 ªÉÉ ºÉ ÉÒEò®úhÉÉSÉÒ ÉÚ³äý +ºÉiÉÒ±É iÉ®ú 3 3 3 3 SÉÒ ËEò ÉiÉ EòÉªÉ ?

(a) less than zero (¶ÉÚxªÉÉ{ÉäIÉÉ ±É½þÉxÉ) (b) greater than zero (¶ÉÚxªÉÉ{ÉäIÉÉ ¨ÉÉä äö)(c) equal to zero (¶ÉÚxªÉ) (d) doesnt exist (ªÉÉ{ÉèEòÒ xÉɽþÒ)

093. Two tangents TP and TQ are drawn to a circle with centre O from an external point T, and

0m PTQ 30 then m OQP

+ÉEÞòiÉÒiÉ O Eåòpù +ºÉ±É䱪ÉÉ ´ÉiÉÖdzýɱÉÉ ®äú¹ÉÉ TP +ÉÊhÉ ®äú¹ÉÉ TQ ªÉÉ ´ÉiÉÖdzýɤÉɽäþ®úÒ±É T ªÉÉ Ë¤ÉnÚùiÉÚxÉ EòÉfø±É䱪ÉÉ

º{É̶ÉEòÉ +ɽäþiÉ. VÉ®ú 0m PTQ 30 iÉ®ú m OQP

O

P

Q

T

(a) 300 (b) 600

(c) 900 (d) 150

094. In fig. ABCD is rectangle, DEC is right angle triangle in which E is right angle and0ECD 30 and CFB is isoscles right angled triangle such that CF = BC then the value of

AC2 + BD2 is (given l(DE) = a and l(BF) = b)

ºÉÉä¤ÉiÉSªÉÉ +ÉEÞòiÉÒiÉ, ABCD ½þÉ +ɪÉiÉ +ɽäþ. DEC ½þÉ EòÉ]õEòÉäxÉ ÊjÉEòÉähÉ +ɽäþ. VªÉɨÉvªÉä E ½þÉ EòÉ]õEòÉäxÉ+ɽäþ +ÉÊhÉ 0ECD 30 +ÉÊhÉ CFB ½þÉ ºÉ¨ÉÊuù¦ÉÖVÉ EòÉ]õEòÉäxÉ ÊjÉEòÉähÉ +ºÉÉ +ɽäþ EòÒ, CF BC iÉ®ú

2 2AC BD .......

l(DE) = a +ÉÊhÉ l(BF) = b

A

D

a

E

300 C

F

B

b

(a) a2 + b2 (b) 2a2 + b2

(c) 8a2 + b2 (d) a2 + 4b2

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095. The number of integral points lies inside the triangle formed by the lines x = 0, y = 0 and

x + y = 5 is (integral points means the points whose x & y coordinates are integers)

VÉ®ú ÊjÉEòÉähÉÉSªÉÉ iÉÒxÉ ¤ÉÉVÉÚÆSÉÒ ºÉ¨ÉÒEò®úhÉ x 0, y 0 +ÉÊhÉ x y 5 +ɽäþiÉ iÉ®ú ÊjÉEòÉähÉÉSªÉÉ +ÆiÉǦÉÉMÉÉiÉÒ±É

ˤÉnÚùSÉä ÊxÉnæù¶ÉEò {ÉÚhÉÉÈEò ºÉÆJªÉÉ +ºÉ±É䱪ÉÉ Ë¤ÉnÚùSÉÒ ºÉÆJªÉÉ ÊEòiÉÒ ?(a) 6 (b) 5

(c) 10 (d) 8

096. A circle is incribed in a equilateral triangle ABC of side 7 3 units. The area and circumference

of the circle are the roots of the equation

7 3 BEòEò ¤ÉÉVÉÚ +ºÉ±É䱪ÉÉ ºÉ¨É¦ÉÚVÉ ABC ¨ÉvªÉä ´ÉiÉÖdzý +ÉÆiÉ®úʱÉÊJÉiÉ +ɽäþ. iÉ®ú JÉɱÉÒ±É{ÉèEòÒ EòÉähÉiªÉÉ

ºÉ¨ÉÒEò®úhÉÉSÉÒ ¨ÉÚ³äý ½þÒ ´ÉiÉÖdzýÉSÉä IÉäjÉ¡ò³ý ´É {É®úÒPÉ +ɽäþ.(a) 2x 121x 1694 0 (b) 22x 121x 847 0

(c) 2x 242x 1694 0 (d) 22x 121x 1694 0

097. Twenty seven solid iron spheres each of radius ‘r’ and surface area ‘s’ are melted to form a

sphere with surface area ‘S´ ’ then the ratio of s and ‘S´ ’ is

VÉ®ú ÊjÉVªÉÉ ‘r’ +ÉÊhÉ {ÉÞ¹`ö¡ò³ý ‘s’ +ºÉ±É䱪ÉÉ 27 ¦É®úÒ´É vÉÉiÉÚSÉä MÉÉä±É Ê´Éiɳý´ÉÚxÉ {ÉÞ¹`ö¡ò³ý ‘S´ ’ +ºÉ±Éä±ÉÉ BEò ¦É®úÒ´É

MÉÉä±É iɪÉÉ®ú Eäò±ÉÉ iÉ®ú s +ÉÊhÉ s' SÉä MÉÖhÉÉäkÉ®ú ÊEòiÉÒ ?(a) 1 : 3 (b) 1 : 9

(c) 1 : 27 (d) 1 : 81

098. sin250 + sin2100 + sin2150 + ........... + sin2450 + sin2500 + .......... + .......... + sin2850 + sin2900 =

(a) 9 (b)17

2

(c)19

2(d) 10

099. If 2 2tan 1 p then 3sec tan cosec

VÉ® 2 2tan 1 p iÉ®ú 3sec tan cosec

(a) 2 3 / 2(2 P ) (b) 2 3 / 2(1 P )

(c) 2 3 / 2(2 P ) (d) 2 3 / 2(1 P )

100. If 1/ 3 3x (a) sin and 2/3 3y (b) cos . Then

VÉ® 1/ 3 3x (a) sin +ÉÊhÉ 2/3 3y (b) cos iÉ®ú

(a)

2 /3 4 / 3x y

1a b

(b)

2/ 3 2 /3

1/ 3

x y1

a b

(c)

1/ 3 2 /3

1/ 3 2 / 3

x y1

a b

(d)

2/ 3 2 / 3

1 /3 2 / 3

x y1

a b

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101. If2 23 2x 3x 2(20) (40 5) . Then x =

VÉ® 2 23 2x 3x 2(20) (40 5) . iÉ®ú x =

(a)13

12 (b)

12

13

(c)4

5 (d)

5

4

102. A man saves Rs. 200 in each of the first three months of his service. In each of the subsequentmonth his saving increases by 40 more than the saving of immediately previous month. Histotal saving from the start of service will be Rs. 11040 after

BEò ´ªÉCiÉÒ +É{ɱªÉÉ xÉÉèEò®úÒiÉ ºÉÖ û´ÉÉiÉÒSÉÒ iÉÒxÉ ¨ÉʽþxÉä |ÉiªÉäEòÒ 200 ¯û. ¤ÉSÉiÉ Eò®úiÉÉä. iªÉÉxÉÆiÉ®ú |ÉiªÉäEò ¨ÉʽþxªÉÉiɨÉÉMÉÒ±É ¨ÉʽþxªÉÉ{ÉäIÉÉ 40 ¯û. xÉä +ÊvÉEò ¤ÉSÉiÉ Eò®úiÉÉä. iÉ®ú xÉÉèEò®úÒSªÉÉ ºÉÖ û´ÉÉiÉÒ{ÉɺÉÚxÉ iªÉÉSÉÒ BEÚòhÉ ¤ÉSÉiÉ ¯û. 11040

½þÉähªÉÉEò®úÒiÉÉ ÊEòiÉÒ ¨ÉʽþxÉä ±ÉÉMÉiÉÒ±É ?(a) 20 months (20 ¨ÉʽþxÉä) (b) 21 months (21 ¨ÉʽþxÉä)(c) 18 months (18 ¨ÉʽþxÉä) (d) 19 months (19 ¨ÉʽþxÉä)

103. The nature of roots of the equation (x2 + x) (x2 + x – 2) = 24 is

JÉɱÉÒ±É ºÉ¨ÉÒEò®úhÉÉSªÉÉ ¨ÉÚ³ýÉSÉä º´É¯û{É `ö®ú´ÉÉ. 2 2(x x)(x x 2) 24

(a) All 4 roots are non-real

SÉÉ®ú½þÒ ¨ÉÚ³ä ´ÉɺiÉ´É xÉɽþÒiÉ(b) 1 root is real and 3 roots are non real

BEò ¨ÉÚ³ý ´ÉɺiÉ´É +ɽäþ +ÉÊhÉ iÉÒxÉ ¨ÉÚ³äý ´ÉɺiÉ´É xÉɽþÒiÉ(c) 2 roots real and 2 roots non real

nùÉäxÉ ¨ÉÖ³äý ´ÉɺiÉ´É +ɽäþiÉ ´É nùÉäxÉ ¨ÉÖ³äý ´ÉɺiÉ´É xÉɽþÒiÉ(d) all 4 roots are real

SÉÉ®ú½þÒ ¨ÉÚ³äý ´ÉɺiÉ´É +ɽäþiÉ104. A man is standing on the bank of a river and observers a bird on the tree 20m high other side

of the bank with the angle of elevation 600. If the bird flies away in a straight path, after twoseconds the angle of elevation is 300. Find the speed of the bird?

xÉnùÒSªÉÉ BEòÉ iÉÒ®úÉ´É®ú =¦ªÉÉ +ºÉ±É䱪ÉÉ BEòÉ ÊxÉ®úÒIÉEòÉºÉ {ɱÉÒEòb÷SªÉÉ iÉÒ®úÉÆ É®úÒ±É 20 ¨ÉÒ. =ÆSÉÒSªÉÉ ZÉÉb÷ÉSªÉɶÉåb÷¬É´É®ú ¤ÉºÉ±É䱪ÉÉ {ÉIªÉÉEòbä÷ {ÉɽþiÉÉxÉÉ 60 ¨ÉÉ{ÉÉSÉÉ =zÉiÉ EòÉäxÉ ½þÉäiÉÉä. VÉ®ú {ÉIÉÒ ºÉ®ú³ý ®äú¹ÉäiÉ =b÷iÉÉxÉÉ nùÉäxɺÉäEÆònùÉxÉÆiÉ®ú 300 ¨ÉÉ{ÉÉSÉÉ =zÉiÉ EòÉäxÉ ½þÉäiÉÉä. iÉ®ú =b÷hÉÉ­ªÉÉ {ÉIÉÉSÉÉ ´ÉäMÉ EòÉføÉ.

(a)40

3(b)

60

3

(c)20

3(d)

10

3

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105. If A = (2, 3), B = (– 2, – 5), C = (– 4, 6) and if22 9

P ,7 7

is point on BC such that

VÉ® A = (2, 3), B = (– 2, – 5), C = (– 4, 6) +ÉÊhÉ22 9

P ,7 7

½þÉ Ë¤ÉnÚù BC ´É®ú +ºÉÉ +ɽäþ EòÒ

(a) AP BC ( AP BC )

(b) AP bisector of segment BC (AP ½þÉ ®äúJÉ BC SÉÉ ±ÉƤÉn Öù¦ÉÉVÉEò +ɽäþ)(c) AP angle bisector of BAC (AP ½þÉ BAC SÉÉ EòÉäxÉnÖù¦ÉÉVÉEò +ɽäþ)(d) none of these (ªÉÉ{ÉèEòÒ xÉɽþÒ)

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Biology

106. Which of the following hormone inhibit the growth of plant?

JÉɱÉÒ±É{ÉèEòÒ EòÉähÉiÉä ºÉÆ|Éä®úEò ´Éxɺ{ÉiÉÒSÉÒ ´ÉÉfø JÉÖÆ]õ´ÉiÉä ?(a) Auxin (+ÉìÎCZÉxÉ) (b) Cytokinins (ºÉɪÉ]õÉäEòɪÉxÉÒxÉ)(c) Gibberllins ÊVÉ¥ÉÒʱÉxºÉ) (d) Abscisic acid (+ì¤ÉºÉɪÉʺÉEò +ìʺÉb÷)

107. Which of the following reaction is correct balanced photosynthetic reaction.

JÉɱÉÒ±É{ÉèEòÒ EòÉähÉiÉÒ ®úɺÉɪÉÊxÉEò +ʦÉÊGòªÉÉ ½þÒ ºÉÆiÉÖ±ÉÒiÉ |ÉEòÉ¶É ºÉƶ±Éä¹ÉxÉÉSÉÒ +ʦÉÊGòªÉÉ +ɽäþ.

1.chlorophyll

2 2 6 12 6 2 2sunlight6CO 12H O C H O 6H O 6O

2.chlorophyll

2 2 6 12 6 2sunlight12CO 6H O C H O 12H O 6O

3.chlorophyll

2 2 12 22 12 2sunlight12CO 6H O C H O 6O

4.chlorophyll

2 2 6 12 6 2sunlight6CO 6H O C H O 6O

(a) 1 (b) 2(c) 3 (d) 4

108. Double fertilization is the characteristic of

Êuù¡ò±ÉxÉ ½äþ JÉɱÉÒ±É{ÉèEòÒ Eò¶ÉÉSÉä ±ÉIÉhÉ +ɽäþ.(a) China rose (VÉɺ´ÉÆnùù) (b) Cycas (ºÉɪÉEòºÉ)(c) Bryophytes (¥ÉɪÉÉä¡òÉ<Ç]ºÉõ) (d) Pteridophytes (]äõ®úÒb÷Éä¡òÉ<Ç]ÂõºÉ)

109. Identify the type of pollination in the given figures (Ênù±É䱪ÉÉ +ÉEÞòiÉÒiÉ {É®úÉMÉҦɴÉxÉÉSÉÉ |ÉEòÉ®ú +Éä³ýJÉÉ.)

a b c(a) Self pollination Self pollination Cross pollination

º´ÉªÉÆ {É®úÉMÉҦɴÉxÉ º´ÉªÉÆ {É®úÉMÉҦɴÉxÉ {É®ú {É®úÉMÉҦɴÉxÉ(b) Self pollination Cross pollination Cross pollination

º´ÉªÉÆ {É®úÉMÉҦɴÉxÉ {É®ú {É®úÉMÉҦɴÉxÉ {É®ú {É®úÉMÉҦɴÉxÉ(c) Cross pollination Cross pollination Self pollination

{É®ú {É®úÉMÉҦɴÉxÉ {É®ú {É®úÉMÉҦɴÉxÉ º´ÉªÉÆú {É®úÉMÉҦɴÉxÉ(d) Cross pollination Self pollination Self pollination

{É®ú {É®úÉMÉҦɴÉxÉ º´ÉªÉÆ {É®úÉMÉҦɴÉxÉ º´ÉªÉÆú {É®úÉMÉҦɴÉxÉ

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( P.T.O. )

110. Identify the correct option for labelles A, B, C and D in the given diagram

Ênù±É䱪ÉÉ +ÉEÞòiÉÒiÉ A, B, C +ÉÊhÉ D ªÉÉÆSªÉɶÉÒ ºÉƤÉÆÊvÉiÉ ªÉÉäMªÉ xÉÉ´Éä +Éä³ýJÉÉ.

A

B

CD

A B C D

(a) Anther Style Petal Ovary

{É®úÉMÉEòÉä¹É EÖòIÉÒ´ÉÞÆiÉ nù±É +Æb÷ɶɪÉ(b) Style Anther Calyx Ovule

EÖòIÉÒ´ÉÞÆiÉ {É®úÉMÉEòÉä¹É ÊxÉnù±É ʤÉVÉEòÉä¶É(c) Stigma Filament Petal Ovary

EÖòIÉÒ ´ÉÞÆiÉ nù±É +Æb÷ɶɪÉ(d) Stigma Filament Sepal Ovary

EÖòIÉÒ ´ÉÞÆiÉ ÊxÉnù±É +Æb÷ɶɪÉ111. Mendel observed seven pair of contrasting characters in Pisum sativum. Which one of the

following pair of trait is not selected by Mendel for his experiment?

¨Éåb÷±ÉxÉä ´É]õÉhªÉɨÉvªÉä ({ÉÉªÉºÉ¨É ºÉ]õɪɴɨÉ) ºÉÉiÉ º´ÉªÉÆ Ê´É®úÉävÉɦÉɺÉÒ ±ÉIÉhÉä {ÉÉʽþ±ÉÒ. JÉɱÉÒ±É{ÉèEòÒ EòÉähÉiÉÒ BEò VÉÉäb÷Ò

¨Éåb÷±ÉxÉä iªÉÉÆSªÉÉ |ɪÉÉäMÉÉiÉ ÊxÉ´Éb÷±Éä±ÉÒ xÉ´½þiÉÒ.

(a) Tall and dwarf (=ÆSÉ ´É ¤ÉÖ]õEòÉ)

(b) Yellow and green seed colour (Ê{ɴɳýÉ ´É ʽþ®ú´ÉÉ ¤ÉÒVÉÉÆSÉÉ ®ÆúMÉ)

(c) Terminal and axial flower (+OÉ ´É úEòIÉÒªÉ |ÉEòÉ®úÉSÉÒ ¡Úò±ÉÉSÉÒ ®úSÉxÉÉ)

(d) Smooth and rough stem (¨É>ð ´É JÉb÷¤Éb÷ÒiÉ JÉÉäb÷)112. What will be the total percentage of homozygous recessive plant in F2 generation. If cross is

made in between pure tall and dwarf pea plant ?

VÉ®ú =ÆSÉ +ÉÊhÉ ¤ÉÖ]õCªÉÉ ´ÉÉ]õÉhªÉÉSªÉÉ ZÉÉb÷ɨÉvªÉä ºÉÆEò®ú PÉb÷´ÉÚxÉ +ÉhɱÉÉ iÉ®ú F2 ¨ÉvªÉä ºÉ¨ÉªÉÖM¨ÉxÉVÉÒ +|ɦÉÉ´ÉÒ ZÉÉb÷ÉÆSÉÒ

]õCEäò´ÉÉ®úÒ ÊEòiÉÒ +ºÉä±É ?(a) 0% (b) 50%

(c) 75% (d) 25%

113. Haploid structure present within the pollen sac of anther is

{É®úÉMÉEòÉä¶ÉÉSªÉÉ {É®úÉMÉEòhÉÉiÉ +ºÉ±Éä±Éä +vÉÇMÉÖhÉÒ ªÉÖM¨ÉEò

(a) Megaspores MÉÖ û¤ÉÒVÉÖEò (b) Microspores ±ÉPÉÖ¤ÉÒVÉÖEò

(c) Microsporophyll ±ÉPÉÖ¤ÉÒVÉ{ÉjÉ (d) Megasporophyll MÉÖ¯û¤ÉÒVÉ{ÉjÉ

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114 Observe the following diagrammatic representation and find out A, B and C.

JÉɱÉÒ±É +ÉEÞòiÉÒSÉä ÊxÉÊ®úIÉhÉ Eò¯ûxÉ A, B +ÉÊhÉ C +Éä³ýJÉÉ.

A B C

(a) Lactic acid CO2 Ethanol

±ÉìC]õÒEò +ɨ±É EòɤÉÇxÉb÷ÉªÉ +ÉìCºÉÉ<Çb÷ <lÉäxÉÉì±É(b) Ethanol Lactic acid CO2

<lÉäxÉÉì±É ±ÉìC]õÒEò +ɨ±É EòɤÉÇxÉb÷ÉªÉ +ÉìCºÉÉ<Çb÷(c) Ethanol CO2 Lactic acid

<lÉäxÉÉì±É EòɤÉÇxÉb÷ÉªÉ +ÉìCºÉÉ<Çb÷ ±ÉìC]õÒEò +ɨ±É(d) Ethanol Pyruvate Lactic acid

<lÉäxÉÉì±É {Éɪɯû´½äþ]õ ±ÉìC]õÒEò +ɨ±É115. How many mitotic division are needed form a single cell to forms 128 daughter cells in plants?

´ÉxɺiÉÒ¨ÉvªÉä BEòÉ {Éä¶ÉÒ{ÉɺÉÖxÉ 128 xÉ´ÉVÉÉiÉ {Éä¶ÉÒ iɪÉÉ®ú ½þÉähªÉɺÉÉ`öÒ ÊEòiÉÒ MÉÖhɺÉÖjÉÒ ºÉ¨ÉʴɦÉÉVÉxÉ ´½þÉ´Éä ±ÉÉMÉiÉÒ±É?(a) 7 (b) 14

(c) 28 (d) 32

116. If a round, green seed pea plant (RRyy) is crossed with wrinkled, yellow seed pea plant (rrYY).

What will be the phenotype and genotype of F1 hybrid?

VÉ®ú MÉÉä±É, ʽþ®ú´ÉÒ ¤ÉÒVÉä ªÉähÉÉ®úÒ ZÉÉbä÷ ´É ºÉÖ ûEÖòiɱÉä±ÉÒ Ê{ɴɳýÒ ¤ÉÒVÉä ªÉähÉÉ®úÒ ZÉÉbä÷ ªÉÉÆSÉÉ ºÉÆEò®ú Eäò±ÉÉ iÉ® F1ú Ê{ÉføÒSÉä

º´É¯û{ÉÊ´ÉvÉÉ ´É VÉxÉÖEòÊ´ÉvÉÉ EòÉªÉ +ºÉä±É.

(a) Round yellow and RrYy (MÉÉä±É Ê{ɴɳýÒ +ÉÊhÉ RrYy)

(b) Round green and Rryy) (MÉÉä±É ʽþ®ú´ÉÒ +ÉÊhÉ Rryy)

(c) Wrinkled green and rryy (ºÉÖ®úEÖòiɱÉä±ÉÒ Ê½þ®ú´ÉÒ +ÉÊhÉ rryy)

(d) Wrinkled yellow and rrYy (ºÉÖ®úEÖòiɱÉä±ÉÒ Ê{ɴɳýÒ +ÉÊhÉ rrYy)

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117. Match the column I which having phenotype obtained in F2 generation to the column II

which having total number of offsprings obtained in F2 generation of dihybrid cross.

ºiÉÆ¦É I ¨ÉvªÉä F2 Ê{ÉføÒ ¨ÉvÉÒ±É º´É¯û{ÉÊ´ÉvÉÉ ´É ºiÉÆ¦É II ¨ÉvÉÒ±É F2 Ê{ÉføÒiÉÒ±É BEÚòhÉ ºÉÆiÉiÉÒ ªÉÉÆSªÉÉ VÉÉäb÷¬É VÉÖ³ý´ÉÉ.Column - I (Phenophyte of F2) Column-II (No. of Phenotype in F2)

A) Round yellow (MÉÉä±É Ê{ɴɳýÒ) 1) Three (iÉÒxÉ)

B) Wrinkled Yellow (ºÉÖ®úEÖòiɱÉä±ÉÒ Ê{ɴɳýÒ) 2) Nine (xÉ>ð)

C) Round green (MÉÉä±É ʽþ®ú´ÉÒ) 3) Three (iÉÒxÉ)

D) Wrinkled Green (ºÉÖ®úEÖòiɱÉä±ÉÒ Ê½þ®ú´ÉÒ) 4) One (BEò)(a) A–2, B–1, C–4, D–3 (b) A–3, B–3, C–1, D–2

(c) A–4, B–3, C–2, D–1 (d) A–2, B–1, C–3, D–4

118. Read the following statement carefully, find out how many correct /incorrect statements?

JÉɱÉÒ±É ´ÉÉCªÉ EòɳýVÉÒ{ÉÚ ÉÇEò ´ÉÉSÉÉ ´É ªÉÉäMªÉ/+ªÉÉäMªÉ Ê´ÉvÉÉxÉä +Éä³ýJÉÉ.I) Multicrore project Ganga Action Plan was started in the year 1984

<.ºÉ. 1984 ºÉɱÉÒ MÉÆMÉÉ +ìC¶ÉxÉ {±ÉìxÉ ½þÉ ¨É½þi´ÉEòÉÆIÉÒ |ÉEò±{É ºÉÖ°ü ZÉɱÉÉ.II) The Ganga runs its course of over 4500 km from Gangothri in the Himalayas to Ganga

sagar in the way of Bangal

MÉÆMÉÉ xÉnùÒ ÊiÉSªÉÉ 4500 ÊEò.¨ÉÒ. SªÉÉ |É´ÉɺÉɨÉvªÉä ʽþ¨ÉɱɪÉÉiÉÒ±É MÉÆMÉÉäjÉÒ {ÉɺÉÚxÉ iÉä ¤ÉÆMÉɱÉSªÉÉ ={ɺÉÉMÉ®úÉiÉÒ±É

MÉÆMÉɺÉÉMÉ®ú {ɪÉÈiÉ ´ÉɽþiÉä.III) Ganga pollution caused by human activities like bathing, washing of clothes and

immersion of ashes or unbrunt corpses and then industries does not contribute

chemical effluents to the Ganga’s pollution.

MÉÆMÉÉ xÉnùÒSÉä |ÉnÚù¹ÉhÉ ½äþ ¨ÉÉxÉ´ÉÒ ½þºiÉIÉä{ÉɨÉÖ³äý VɺÉä +ÆPÉÉä³ý Eò®úhÉä, Eò{Ébä÷ vÉÖhÉä, EòSÉ®úÉ ]õÉEòhÉä ªÉɨÉÖ³äý ½þÉäiÉä

iÉ®ú EòÉ®úJÉÉxªÉÉÒ±É EòSÉ­ªÉɨÉÖ³äý MÉÆMÉÉ xÉnùÒSÉä |ÉnÚù¹ÉhÉ ½ÉäiÉ xÉɽþÒ.IV) Flow of energy in trophic level is generally unidirectional and sometimes bidirectional.

{ÉÉä¹ÉhÉ {ÉÉiɳýÒ¨ÉvªÉä =VÉæSÉÉ |É´Éɽþ ½þÉ ºÉÉvÉÉ®úhÉiÉ& BEäò®úÒ iÉ®ú EòvÉÒ EòvÉÒ nÖù½äþ®úÒ +ºÉiÉÉä.

(a) I, II, III are correct and IV incorrect (I,II,III ¤É®úÉä¤É®ú +ÉÊhÉ IV SÉÖEò)

(b) I and II are correct and III and IV are incorrect Ã(I,II ¤É®úÉä¤É®ú +ÉÊhÉ III,IV SÉÖEò)

(c) All are correct (ºÉ´ÉÇ ¤É®úÉä¤É®)

(d) All are incorrect (ºÉ´ÉÇ SÉÚEò)119. The world environmental day is celebrated annually on

VÉÉMÉÊiÉEò {ɪÉÉÇ É®úhÉ ÊnùxÉ........... ªÉÉ Ênù´É¶ÉÒ ºÉÉVÉ®úÉ Eäò±ÉÉ VÉÉiÉÉä.(a) 5th May (b) 9th June

(c) 5th June (d) 29th Decemner

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120. Read the following statements carefully. Pick up not correct statements.

JÉɱÉÒ±É Ê´ÉvÉÉxÉä EòɳýVÉÒ{ÉÚ ÉÇEò ´ÉÉSÉÚxÉ ªÉÉäMªÉ Ê´ÉvÉÉxÉ +Éä³ýJÉÉ.1. Simple squamous epithelial cells are extremely thick

ºÉ®ú³ý {É]õÂ]õEòÒ +ʦɺiÉ®úÒªÉ {Éä¶ÉÒ +ÊiÉ¶ÉªÉ VÉÉb÷ +ºÉiÉÉiÉ2. Stratified squamous epithelium prevents wear and tear

ºiÉÊ®úiÉ {É]Âõ]õEòÒ +ʦɺiÉ®ú ºÉÆ®úIÉhÉ +ÉÊhÉ ZÉÒVÉ ®úÉäJÉiÉÉiÉ.3. Epithelium of trachea has cilia which push mucous

¶´ÉºÉxÉ ¨ÉÉMÉÉÇiÉÒ±É ®úÉä ÉEò ºiÉƦÉÒªÉ +ʦɺÉiÉ®ú ¶±Éä¹¨É±É pù´ªÉ {ÉÖfäø føEò±ÉiÉÉiÉ.4. Epithelium of kidney tubule and ducts of salivary glands has pillar like cells

´ÉÞCEò xÉʱÉEòÉÆSªÉÉ +ÉiÉÒ±É ºiÉ®ú ´É ±Éɳý OÉÆlÉÒSªÉÉ xÉʱÉEòÉÆxÉÉ ºiÉƦÉɺÉÉ®úJªÉÉ {Éä¶ÉÒ +ºÉiÉÉiÉ.(a) 1 and 3 (b) 2 and 3

(c) 3 and 4 (d) 1 and 4

121. Which disease is caused by organism in the given figure where organism is lying next to RBC?

JÉɱÉÒ±É +ÉEÞòiÉÒiÉ ±ÉÉ±É ®úCiÉ{Éä¶ÉÒSªÉÉ ¤ÉÉVÉÚ±ÉÉ nùÉJɴɱÉä±ÉÉ VÉÒ´É EòÉähÉiÉÉ ®úÉäMÉ {ɺɮú´ÉiÉÉiÉ.

(a) Kala-azar (EòɱÉÉ-+ÉVÉÉ®ú) (b) Trypano somiasis (]ÅõɪÉ{ÉìxÉÉä ºÉÉäʨÉ+ìºÉÒºÉ)

(c) Acene ({ÉÖ®ú³ý ªÉähÉä) (d) Common cold (ºÉnùÔ)122. “Vaccinations prevent disease”. This concept is based on

“±ÉºÉÒEò®úhÉ ®úÉäMÉÉºÉ |ÉÊiɤÉÆvÉ Eò®úiÉä” ½þÒ ¤ÉÉ¤É Eò¶ÉɶÉÒ ºÉƤÉÆÊvÉiÉ +ɽäþ.

(a) Memory of immune system |ÉÊiÉEòÉ®ú ºÉƺlÉÉSÉÒ º¨ÉÞiÉÒ

(b) Memory of diseased person ®úÉäMÉÒ ´ªÉCiÉÒSÉÒ º¨ÉÞiÉÒ

(c) Memory of bacteria VÉÒ´ÉÉhÉÚÆSÉÒ º¨ÉÞiÉÒ

(d) Micro organism remember host ºÉÖI¨ÉVÉÒ´É ªÉVɨÉÉxÉɱÉÉ º¨É®úhÉä123. In pulmonary circulation oxygenated blood pumped to heart by

¡Öò¡ÖòÊºÉªÉ +ʦɺɮúhÉɨÉvÉÚxÉ ¶ÉÖvnù ®úCiÉ ------------ EòbÚ÷xÉ ¾þnùªÉÉEòbä÷ +ÉhɱÉä VÉÉiÉä.

(a) Lungs (¡Öò}¡ÖòºÉ) (b) Pulmonary vein (¡Öò}¡ÖòºÉ¶ÉÒ®ú)

(c) Pulmonary artery (¡Öò}¡ÖòºÉ vɨÉxÉÒ) (d) Aorta (¨É½þÉvɨÉxÉÒ)

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124. Read the following statements carefully . Choose correct statements

JÉɱÉÒ±É Ê´ÉvÉÉxÉä EòɳýVÉÒ{ÉÚ ÉÇEò ´ÉÉSÉÉ +ÉÊhÉ ªÉÉäMªÉ Ê´ÉvÉÉxÉ ÊxÉ´Éb÷É.1. External respiration – taking air into lungs

¤ÉÉÁ ¶´ÉºÉxÉ - ¡Öò¡ÖòºÉÉiÉ ½þ´ÉÉ PÉähÉä2. Internal respiration – occurs in mitochondria

+ÉÆiÉ: ¶´ÉºÉxÉ - iÉÆiÉÖEòÊhÉEòÉiÉ PÉb÷iÉä3. Sphygmomanometer – instrument to measure air pressure

κ¡òM¨ÉÉä ÉìxÉÉäʨÉ]õ®ú - ½þ´ÉäSÉÉ nùÉ¤É ¨ÉÉäVÉhªÉÉSÉä ={ÉEò®úhÉ4. Capillaries – one cell in thickness

EäòʶÉEòÉ - BEòÉ {Éä¶ÉÒ B´ÉføÒ VÉÉb÷Ò(a) All are correct (ºÉ´ÉÇ ¤É®úÉä¤É®)(b) All correct except 2 (Ê´ÉvÉÉxÉ 2 ºÉÉäbÚ÷xÉ ºÉ´ÉÇ ¤É®úÉä¤É®)(c) All correct except 3 (Ê´ÉvÉÉxÉ 3 ºÉÉäbÚ÷xÉ ºÉ´ÉÇ ¤É®úÉä¤É®)(d) All correct except 1 (Ê´ÉvÉÉxÉ 1 ºÉÉäbÚ÷xÉ ºÉ´ÉÇ ¤É®úÉä¤É®)

125. In dialysis, following are removed from blood ___1___ and machine works similar to ___2___

b÷ɪɱÉäÊºÉºÉ (´ªÉɹ±Éä¹ÉhÉ |ÉÊGòªÉäiÉ) 1------ ®úCiÉÉiÉÚxÉ MÉɳý±Éä VÉÉiÉä +ÉÊhÉ ¨ÉʶÉxÉSÉä EòɪÉÇ 2------ +ºÉiÉä.(a) 1–Red blood cells, 2–blood (1-±ÉÉ±É ®úCiÉ {Éä¶ÉÒ, 2-®úCiÉ)(b) 1–White blood cells, 2–spleen (1-{ÉÉÆfø­ªÉÉ {Éä¶ÉÒ, 2-{±ÉÒ½þÉ)(c) 1–Waste products, 2–kidney (1-]õÉEò>ð {ÉnùÉlÉÇ, 2-´ÉÞCEò)(d) 1–Oxygen, 2–tissue (1-+ÉìÎCºÉVÉxÉ, 2->ðiÉÒ)

126. Select the correct sequence with respect to urine formation.

¨ÉÖjÉ ÊxĘ́ÉiÉÒxÉÖºÉÉ®ú ªÉÉäMªÉ Gò¨É ±ÉÉ´ÉÉ.1. I–blood to nephron, II–initial filtrate, III–water absorption, IV–excretion

I xÉä£òÉìxÉEòbä÷ ®úCiÉ II |ÉÉlÉʨÉEò MÉɳýhÉ III {ÉÉhÉÒ ¶ÉÉä¹ÉhÉ IV =iºÉVÉÇxÉ2. I–initial filtrate, II–blood to nephron, III–water absorption, IV–excretion

I |ÉÉlÉʨÉEò MÉɳýhÉ II xÉä£òÉìxÉEòbä÷ ®úCiÉ III {ÉÉhÉÒ ¶ÉÉä¹ÉhÉ IV =iºÉVÉÇxÉ3. I–water absorption, II–initial filtrate, III–excretion, IV–blood to nephron

I {ÉÉhÉÒ ¶ÉÉä¹ÉhÉ II |ÉÉlÉʨÉEò MÉɳýhÉ III =iºÉVÉÇxÉ IV xÉä£òÉìxÉEòbä÷ ®úCiÉ4. I–blood to nephron, II–excretion, III–initial filtrate, IV–water absorption

I xÉä£òÉìxÉEòbä÷ ®úCiÉ II =iºÉVÉÇxÉ III |ÉÉlÉʨÉEò MÉɳýhÉ IV {ÉÉhÉÒ ¶ÉÉä¹ÉhÉ(a) 1 (b) 2(c) 3 (d) 4

127. Find odd one with respect to reproductive system in human.

¨ÉÉxÉ´ÉÒ |ÉVÉxÉxÉ ºÉƺlÉäxÉÖºÉÉ®ú ´ÉäMɳýÉ PÉ]õEò +Éä³ýJÉÉ.I. Prostrate gland |ÉÉäº]Åäõ]õ OÉÆlÉÒ II. Seminal vescicle ¶ÉÖGòɶɪÉIII. Cervix MɦÉÉÇ¶ÉªÉ ¨ÉÖJÉ IV. Vas deferens ¶ÉÖGòÉhÉÖ ´ÉÉʽþxÉÒ(a) I (b) III(c) II (d) IV

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128. Dramatic physical changes during puberty observed in Rahul’s body due to the secretion of

iÉɯûhªÉɴɺlÉäiÉ ®úɽÖþ±ÉSªÉÉ ¶É®úÒ®úɨÉvªÉä ZÉɱÉä±ÉÉ +¨ÉÖ±ÉÉOÉ ¶ÉÉÊ®ú®úÒEò ¤Énù±É ½þÉ....ªÉÉ ºÉÆ|Éä®úEò ºjÉɴɱªÉɨÉÖ³äý ½þÉäiÉ +ɽäþ.(a) Neurotransmittors xªÉÖ®úÉä]ÅõÉxºÉʨÉ]õ®ú (b) Testosteron ]äõº]õÉäº]äõ®úÉìxÉ(c) Oestrogen <º]ÅõÉäVÉäxÉ (d) Growth hormone ´ÉÞrùÒ ºÉÆ|Éä®úEò

129 Assertion : Pulling back hand from flameReason : Due to motor neuron passes stimulus from spinal cord to the hand

Ê´ÉvÉÉxÉ : =¹hÉiÉä{ÉɺÉÚxÉ ½þÉiÉ ¨ÉÉMÉä PÉähÉäEòÉ®úhÉ : |Éä®úEòSÉäiÉÉ ºÉÆ ÉänùxÉÉ ¨Éä û®úVVÉÚ {ÉɺÉÚxÉ ½þÉiÉÉEòbä÷ {ÉÉ`ö´ÉiÉÉiÉ(a) Assertion and Reason are correct but reason not correct explaination of assertion

Ê´ÉvÉÉxÉ +ÉÊhÉ EòÉ®úhÉ nùÉäx½þÒ ¤É®úÉä¤É®ú +ɽäþiÉ {ÉhÉ EòÉ®úhÉ ½äþ Ê´ÉvÉÉxÉÉSÉä ªÉÉäMªÉ º{ɹ]õÒEò®úhÉ xÉɽþÒ(b) Assertion and Reason are correct and Reason is correct explaination of Assertion

Ê´ÉvÉÉxÉ +ÉÊhÉ EòÉ®úhÉ nùÉäx½þÒ ¤É®úÉä¤É®ú +ɽäþiÉ ´É EòÉ®úhÉ ½äþ Ê´ÉvÉÉxÉÉSÉä ªÉÉäMªÉ º{ɹ]õÒEò®úhÉ +ɽäþ.(c) Assertion wrong, Reason correct

Ê´ÉvÉÉxÉ SÉÖEòÒSÉä, EòÉ®úhÉ ¤É®úÉä¤É®ú(d) Reason wrong, Assertion correct

EòÉ®úhÉ SÉÖEòÒSÉä, Ê´ÉvÉÉxÉ ¤É®úÉä¤É®ú130. Identify the likely organism I, II and III in the food web shown in figure.

JÉɱÉÒ±É Ênù±É䱪ÉÉ +xxÉ VÉɲªÉÉSªÉÉ +ÉEÞòiÉÒiÉ I, II +ÉÊhÉ III ¨ÉvªÉä ªÉähÉÉ­ªÉÉ ºÉVÉÒ´ÉÉÆSÉÒ xÉÉ´Éä +Éä³ýJÉÉ.

Mouse

Grass

Kookaburra

Eagle

IIIII

I

I II III(a) Snake Rabbit Grasshopper

ºÉÉ{É ºÉºÉÉ xÉÉEòiÉÉäb÷É(b) Grasshopper Rabbit Snake

xÉÉEòiÉÉäb÷É ºÉºÉÉ ºÉÉ{É(c) Rabbit Snake Grasshopper

ºÉºÉÉ ºÉÉ{É xÉÉEòiÉÉäb÷É(d) Grasshopper Snake Rabbit

xÉÉEòiÉÉäb÷É ºÉÉ{É ºÉºÉÉ

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Space for Rough Work

EòSSÉä EòɨÉ

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