Rube Goldberg Device An entirely complicated and complex system created by ridiculously good looking...

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  • Rube Goldberg Device An entirely complicated and complex system created by ridiculously good looking men, to achieve one mind boggling simple task.
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  • Design and build a Rube Goldberg device that will activate an electronic device Design and build a Rube Goldberg device that will activate an electronic device Make it annoyingly inefficient and complicated Make it annoyingly inefficient and complicated Set off another groups device Set off another groups device Use at least five steps and at least four physics concepts Use at least five steps and at least four physics concepts
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  • Physics Concept 1: Center of Mass Bottle filled with bee bees has weight in different parts of the bottle. The bottle has to be balanced perfectly at the center of mass before the chain reaction occurs. mass(bottle)*(1/2)length(bottle)+mass(neck)*((1/2)length(neck)+length(bottle)) Mass(bottle)+mass(neck) CM =
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  • Physics Concept 2: Torque As the chain reaction occurs, the center of mass is offset and moved from the back to the front and in effect, the torque of the bottle triggers another chain reaction by triggering beads and gravitational force. T = I(bottle+I(neck) * alpha I(bottle)=(1/2)mass((radius1)^2+(radius2)^2) I(neck)=(1/2)mass((radius1)^2+(radius2)^2) Alpha= Omega/radius^2
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  • Physics Concept 3: Conservation of Translational Energy As the beads travel in linear motion, they experience the conservation of translational energy, thus creating linear kinetic energy. For the translational kinetic energy, that is the kinetic energy associated with rectilinear motion, of a body with constant mass, whose center of mass is moving in a straight line with speed, as seen above is equal tomass, whose center of mass is moving in a straight line with speed, as seen above is equal to
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  • Physics Concept 4: Conservation of Angular Momentum Through the system of the angular ramps, the bee bees experience conservation of momentum and end with the same velocity they start with. M1v1 = m1v1 P1 = p2
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  • Picture of group Picture of group By: Devon Hardy, Scott McCoullugh, Matt Moore, and Scott Williams