Rotational Kinematics

Serway Chapters 10 -11

Table Of Contents

1. Rotational Motion and Angular Displacement

2. Angular Velocity and Angular Acceleration

3. The Equations of Rotational Kinematics

4. Angular Variables and Tangential Acceleration

5. Centripetal Acceleration and Tangential

Acceleration

6. Rolling Motion

7. The Vector Nature of Angular Variables

Five kinematic variablesMaking Sense of it All

displacement

initial velocity

final velocity

elapsed time

acceleration

d or

x = r

Vo (m/s)

V (m/s) = r

t (sec)

a (m/s2) = r

(radians)

o r(radians /sec)

(radians /s2)

VARIABLES:

t (sec)

(radians /sec)

to

to 21

222o

221 tto

The “Equations”

atvv o

tvvx o 21

xavv o 222

221 attvx o

Rotational kinematics with constant angular acceleration:

Linear Kinematics with constant Linear acceleration:

Formulas

Lesson 1:Rotational KinematicsSection 1:Rotational Motion and Angular Displacement

Homework:

Serway page: 296 Example 1Page 317 #’s 1,3,5,7,9Chapter 10 EXAMPLES

HANDOUT????

Do NowDo Now:

Serway Page: 296 Example 1

o

First there was displacement (d)

Need to develop new variables for polar system

The angle through which the object rotates is called the Angular displacement.

LESSON 1

DEFINITION OF ANGULAR DISPLACEMENT

When a rigid body rotates about a fixed axis, the angular displacement is the angle swept out by a line passing through any point on the body and intersecting the axis of rotation perpendicularly.

By convention, the angular displacement is positive if it is counterclockwise and negative if it is clockwise.

SI Unit of Angular Displacement: radian (rad)

LESSON 1

r

s

Radius

length Arcradians)(in

For a full revolution:

360rad 2 rad 22

r

r

LESSON 1

Example 1 Adjacent Synchronous Satellites

Synchronous satellites are put into an orbit whose radius is 4.23×107m.If the angular separation of the twosatellites is 2.00 degrees, find the arc length that separates them.

rad 0349.0deg360

rad 2deg00.2

rs

r

s

Radius

length Arcradians)(in

rad 0349.0m1023.4 7

miles) (920 m1048.1 6s

LESSON 1

1.1 Over the course of a day (twenty-four hours), what is the angular displacement of the second hand of a wrist watch in radians?

a) 1440 rad

b) 2880 rad

c) 4520 rad

d) 9050 rad

e) 543 000 rad

c)60 min/hr * 24 hr = 1440 revolutions * 2π= 9047 rad

LESSON 1

Lesson 2Rotational KinematicsSection 2:Angular Velocity and Angular Acceleration

Homework:

Serway page: 318 #’s 11 – 19 odd

Do NowDo Now:

Serway

o

How do we describe the rateat which the angular displacementis changing?

Next, there was “velocity”

Lesson 2

RadiansRadians

DEFINITION OF AVERAGE ANGULAR VELOCITY

timeElapsed

ntdisplacemeAngular locity angular ve Average

o

o

tt

SI Unit of Angular Velocity: radian per second (rad/s)

t

Lesson 2

Example 3 Gymnast on a High Bar

A gymnast on a high bar swings throughtwo revolutions in a time of 1.90 s.

Find the average angular velocityof the gymnast.

rev 1

rad 2rev 00.2

s 90.1

rad 6.12

rad 6.12

t

srad63.6

Lesson 2

INSTANTANEOUS ANGULAR VELOCITY

0

lim

t tt

0

lim

Instantaneous Angular speed The magnitude of the instantaneous angular

velocity

SI Unit of Instantaneous Angular velocity: radian per second (rad/s)

Lesson 2

Changing angular velocity means that an angular acceleration is occurring.

DEFINITION OF AVERAGE ANGULAR ACCELERATION

ttt o

o

timeElapsed

locityangular vein Change on acceleratiangular Average

SI Unit of Angular acceleration: radian per second per second (rad/s2)

Then, there was “acceleration”

Example 4 A Jet Revving Its Engines

As seen from the front of the engine, the fan blades are rotating with an angular speed of -110 rad/s. As theplane takes off, the angularvelocity of the blades reaches-330 rad/s in a time of 14 s.

Find the angular acceleration, assuming it tobe constant.

2srad16s 14

srad110srad330

Lesson 2

2.1 Example: The planet Mercury takes only 88 Earth days to orbit the Sun. The orbit is nearly circular, so for this exercise, assume that it is. What is the angular velocity, in radians per second, of Mercury in its orbit around the Sun?

a) 8.3 × 107 rad/s

b) 2.0 × 10 5 rad/s

c) 7.3 × 10 4 rad/s

d) 7.1 × 10 2 rad/s

e) This cannot be determined without knowing the radius of the orbit.

Lesson 2

88 days * 24 hr/day* 3600 sec/ day = 7.6032 X 10 6 sec/revolution

2π rad / revolution

= 8.2639 × 107 rad/s

2.2 Complete the following statement: For a wheel that turns with constant angular velocity,For a wheel that turns with constant angular velocity,

a) each point on its rim moves with constant acceleration.

b) the wheel turns through “equal angles in equal times.”

c) each point on the rim moves at a constant linear speed.

d) the angular displacement of a point on the rim is constant.

e) all points on the wheel are moving at a constant angular velocity.

Lesson 2

t

All True!All True!

Lesson 3:Rotational KinematicsSection 3:The Equations of Rotational Kinematics

Homework:

Glencoe page: 223Glencoe page: 223#’s 72 – 78 even plus 79#’s 72 – 78 even plus 79

Glencoe page: 227Glencoe page: 227#’s 1 - 7#’s 1 - 7

Five kinematic variablesMaking Sense of it All

displacement

initial velocity

final velocity

elapsed time

acceleration

d or x

Vo (m/s)

V (m/s)

t (sec)

a (m/s2)

(radians)

o r(radians /sec)

(radians /s2)

Lesson 3:

t (sec)

(radians /sec)

to to 2

1

222o

221 tto

The “Equations”

atvv o tvvx o 2

1

xavv o 222

221 attvx o

Lesson 3:

Rotational kinematics with constant angular acceleration:

Linear Kinematics with constant Linear acceleration:

More Coming!!!!

Reasoning Reasoning StrategyStrategy1. Make a drawing.2. Decide which directions are to be called positive (+)

and negative (-). (Counterclockwise default +)3. Write down the values that are given for any of the

five kinematic variables.4. Verify that the information contains values for at

least three of the five kinematic variables. Select the appropriate equation.

5. When the motion is divided into segments, remember that the final angular velocity of one segment is the initial velocity for the next.

6. Keep in mind that there may be two possible answers to a kinematics problem.

Lesson 3:

Example 5 Blending with a Blender

The blades are whirling with an angular velocity of +375 rad/s whenthe “puree” button is pushed in.

When the “blend” button is pushed,the blades accelerate and reach agreater angular velocity after the blades have rotated through anangular displacement of +44.0 rad.

The angular acceleration has a constant value of +1740 rad/s2.

Find the final angular velocity of the blades.

Lesson 3:

θ α ω ωo t+44.0 rad +1740 rad/s2 ? +375 rad/s

222o

22o

rad0.44srad17402srad375 22

srad542

Lesson 3:

3.1 The propeller of an airplane is at rest when the pilot starts the engine; and its angular acceleration is a constant value. Two seconds later, the propeller is rotating at 10 rad/s. Through how many revolutions has the propeller rotated through during the first two seconds?

a) 300

b) 50

c) 20

d) 10

e) 5

Lesson 3:

srevolution

tt

t

o

o

52/10

10250

52010

221

221

srevolution

to

52/10

102)100(21

21

3.2 A ball is spinning about an axis that passes through its center with a constant angular acceleration of rad/s2. During a time interval from t1 to t2, the angular displacement of the ball is radians. At time t2, the angular velocity of the ball is 2 rad/s. What is the ball’s angular velocity at time t1?

θ= α= rad/s2 ω2 = 2 rad/s ω1= ?? t=

a) 6.28 rad/sb) 3.14 rad/sc) 2.22 rad/sd) 1.00 rad/se) zero rad/s

Lesson 3:

122

21

2

21

22

22

022

))((22

2

2

o

e) Zero rad/sec

Example 6 A Helicopter Blade

A helicopter blade has an angular speed of 6.50 rev/s and anangular acceleration of 1.30 rev/s2.For point 1 on the blade, findthe magnitude of (a) thetangential speed and (b) thetangential acceleration.

rev 1

rad 2

s

rev 50.6

rvT

raT

rev 1

rad 2

s

rev 30.1

2

srad 8.40

srad8.40m 3.00 sm122

2srad 17.8

2srad17.8m 3.00 2sm5.24

Lesson 3:

3.3 The Earth, which has an equatorial radius of 6380 km, makes one revolution on its axis every 23.93 hours. What is the tangential speed of Nairobi, Kenya, a city near the equator?

a) 37.0 m/s

b) 74.0 m/s

c) 148 m/s

d) 232 m/s

e) 465 m/s

Lesson 3:

3.4 The original Ferris (an RPI Graduate) wheel had a radius of 38 m and completed a full revolution (2 radians) every two minutes when operating at its maximum speed. If the wheel were uniformly slowed from its maximum speed to a stop in 35 seconds, what would be the magnitude of the instantaneous tangential speed at the outer rim of the wheel 15 seconds after it begins its deceleration?

a) 0.295 m/s

b) 1.12 m/s

c) 1.50 m/s

d) 1.77 m/s

e) 2.03 m/s

Lesson 3:

3.5 A long, thin rod of length 4L rotates counterclockwise with constant angular acceleration around an axis that is perpendicular to the rod and passes through a pivot point that is a length L from one end as shown. What is the ratio of the tangential acceleration at a point on the end closest to the pivot point to that at a point on the end farthest from the pivot point?

a) 4b) 3c) 1/2d) 1/3e) 1/4

Lesson 3:

3.6 A long, thin rod of length 4L rotates counterclockwise with constant angular acceleration around an axis that is perpendicular to the rod and passes through a pivot point that is a length L from one end as shown. What is the ratio of the tangential speed (at any instant) at a point on the end closest to the pivot point to that at a point on the end farthest from the pivot point?

a) 1/4

b) 1/3

c) 1/2

d) 3

e) 4

Lesson 3:

Tangential Acceleration? We define the axes as polar co-ordinates not

Cartesian.

(r,) not (x,y) Since they are perpendicular, we can treat each

axis independently Therefore, total acceleration would be vector sum

of ac plus aT

22Tc aaa

c

T

a

atan

Lesson 3

to to 2

1

222o

221 tto

The “Equations”

atvv o tvvx o 2

1

xavv o 222

221 attvx o

MORE EQUATIONS:

Rotational kinematics with constant angular acceleration:

Linear Kinematics with constant Linear acceleration:

r

vac

2

rv

r

rac

2

2rac 22Tc aaa

c

T

aa

tanφ

rsd ra

Example 7 A Discus Thrower

Starting from rest, the throweraccelerates the discus to a finalangular speed of +15.0 rad/s ina time of 0.270 s before releasing it. During the acceleration, the discusmoves in a circular arc of radius0.810 m.

Find the total acceleration.

Lesson 3

2rac

t

ω-ωrra o

T

22cT aaa

c

T

a

a1tan

2

2

182

0.45

sm

sm o9.13

22 sm0.45sm182 2sm187

s 0.270

srad0.15m 810.0

2sm0.45

2srad0.15m 810.02sm182

Lesson 3

3.7 An airplane starts from rest at the end of a runway and begins accelerating. The tires of the plane are rotating with an angular velocity that is uniformly increasing with time. On one of the tires, Point A is located on the part of the tire in contact with the runway surface and point B is located halfway between Point A and the axis of rotation. Which one of the following statements is true concerning this situation?

a) Both points have the same tangential acceleration.

b) Both points have the same centripetal acceleration.

c) Both points have the same instantaneous angular velocity.

d) The angular velocity at point A is greater than that of point B.

e) Each second, point A turns through a greater angle than point B.

Lesson 3

3.8 A wheel starts from rest and rotates with a constant angular acceleration. What is the ratio of the instantaneous tangential acceleration at point A located a distance 2r to that at point B located at r, where the radius of the wheel is R = 2r?

a) 0.25b) 0.50c) 1.0d) 2.0e) 4.0

Lesson 3

Lesson 4:Rotational KinematicsSection 6:Rolling Motion

Homework:

Serway / Glencoe Page #’s

Rolling Motion

A rolling object is a common example of

when you would need to be able to

transform from one coordinate system

to the other.

Usually a “rolling” object will not be

slipping on the surface.

Lesson 4

rv

The tangential speed of apoint on the outer edge ofthe tire is equal to the speedof the car over the ground.

ra

rsd

Lesson 4

Example 4.1 An Accelerating Car

Starting from rest, the car acceleratesfor 20.0 s with a constant linear acceleration of 0.800 m/s2. The radius of the tires is 0.330 m.

What is the angle through which each wheel has rotated?

Lesson 4

221 tto

θ α ω ωo t? -2.42 rad/s2 0 rad/s 20.0 s

22

srad42.2m 0.330

sm800.0

r

a

22221 s 0.20srad42.2 rad 484

Lesson 4

4.1 The wheels of a bicycle have a radius of r meters. The bicycle is traveling along a level road at a constant speed v m/s. Which one of the following expressions may be used to determine the angular speed, in rev/min, of the wheels?

a)

b)

c)

d)

e)

r

v

r

v

30

r

v

30

r

v

2

30

r

v

60

Lesson 4

4.2. Josh is painting yellow stripes on a road using a paint roller. To roll the paint roller along the road, Josh applies a force of 15 N at an angle of 45 with respect to the road. The mass of the roller is 2.5 kg; and its radius is 4.0 cm. Ignoring the mass of the handle of the roller, what is the magnitude of the tangential acceleration of the roller?

a) 4.2 m/s2

b) 6.0 m/s2

c) 15 m/s2

d) 110 m/s2

e) 150 m/s2

Lesson 6

4.3. Which one of the following statements concerning a wheel undergoing rolling motion is true?

a) The angular acceleration of the wheel must be zero m/s2.

b) The tangential velocity is the same for all points on the wheel.

c) The linear velocity for all points on the rim of the wheel is non-zero.

d) The tangential velocity is the same for all points on the rim of the wheel.

e) There is no slipping at the point where the wheel touches the surface on which it is rolling.

Lesson 4

4.4. A circular hoop rolls without slipping on a flat horizontal surface. Which one of the following is necessarily true?

a) All points on the rim of the hoop have the same speed.

b) All points on the rim of the hoop have the same velocity.

c) Every point on the rim of the wheel has a different velocity.

d) All points on the rim of the hoop have acceleration vectors that are tangent to the hoop.

e) All points on the rim of the hoop have acceleration vectors that point toward the center of the hoop.

Lesson 4

4.5. A bicycle wheel of radius 0.70 m is turning at an angular speed of 6.3 rad/s as it rolls on a horizontal surface without slipping. What is the linear speed of the wheel?

a) 1.4 m/s

b) 28 m/s

c) 0.11 m/s

d) 4.4 m/s

e) 9.1 m/s

Lesson 4

Lesson 5:Rotational KinematicsSection 7:The Vector Nature of Angular Variables

Real World Real World Meets the Right Meets the Right HandHand The direction of the angular

velocity vector point along the axis of rotation.

Right-Hand Rule: Grasp the axis of rotation with your right hand, so that your fingers circle wrap the axis in the same direction as the rotation.

Your extended thumb points along the axis in the direction of the angular velocity.

Lesson 5Lesson 5

5.1. A packaged roll of paper towels falls from a shelf in a grocery store and rolls due south without slipping. What is the direction of the paper towels’ angular velocity?

a) north

b) east

c) south

d) west

e) down

Lesson 7Lesson 7

5.2. A packaged roll of paper towels falls from a shelf in a grocery store and rolls due south without slipping. As its linear speed slows, what are the directions of the paper towels’ angular velocity and angular acceleration?

a) east, east

b) west, east

c) south, north

d) east, west

e) west, west

Lesson 7Lesson 7

5.3. A top is spinning counterclockwise and moving toward the right with a linear velocity as shown in the drawing. If the angular speed is decreasing as time passes, what is the direction of the angular velocity of the top?

a) upward

b) downward

c) left

d) right

Lesson 5Lesson 5

5.4. A truck and trailer have 18 wheels. If the direction of the angular velocity vectors of the 18 wheels point 30 north of east, in what direction is the truck traveling?

a) 30° east of south

b) 30° west of north

c) 30° north of east

d) 30° south of west

e) 30° south of east

Lesson 5Lesson 5

5.5. A girl is sitting on the edge of a merry-go-round at a playground as shown. Looking down from above, the merry-go-round is rotating clockwise.

What is the direction of the girl’s angular velocity?

a) upward

b) downward

c) left

d) right

e) There is no direction since it is the merry go round that has the angular velocity.

Lesson 5Lesson 5