HOW MANY MINUTES DO YOU WORKOUT / EXERCISE A DAY?

Ricardo GarciaBertin PabloEric Gomez

Period: 22012

CA Standard 8.0 Student organized and describe distribution

of data by using of different methods, including frequency table, histogram, standard line and bar graphs, stem-and-leaf displays, scatter plots, and box of whisker plots.

17.0 Students determine confidence interval for a simple random sample from a normal distribution of data and determine the sample size required for a desired margin of error.

18.0 Student determine the P-value for a statistic for a simple random sample from a normal distribution

Hypothesis We believe our estimate for

a daily workout/ exercise is 60 minutes.

Data Collection Method For our sampling technique we used a

cluster method. We’re a group of 3 and we asked 42

seniors therefore each person got to 14 seniors to ask

We will collect data by using cluster sampling method. We asked 42 seniors at Century how many minutes do they workout / exercise a day.

Data Length 150,150,150,120,60,30,120,60,15,120,60

,150,30,0, 15,0,0,0,150,30,30,150,120,90,150,90,15,150,60,0,60,30,0,90,90,120,120,120,90,0,120,90

Histogram

13.335 40 66.665 93.335 120 146.665 173.8350

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Workout / Exercise a day

Minutes

Seni

ors

Statistics From our survey, senior sample commute

mean time is 73.2 minutes with sample standard deviation 54.7 minutes.

Confidence Interval 95% Confidence Interval (57.042-90.101) We are 95% confident mean commute

time for all the seniors are between 57 to 90.1 minutes

Hypothesis Testing

Test statistic p=000000000.3 000000.3<0.05 At 5% level of significance, we failed to

reject the claim. There is not enough evidence to support our claim

)(120:0 claimH 120: aH

Conclusion We hypothesized that Century seniors

commute time average 60 minutes. In our survey of 42 seniors, we found the sample mean of 71.2 with the standard deviation of 54.7 minutes. We conclude that the population mean for all seniors is between 57 to 90.1 minutes with 95% confident. We test our initial hypothesis with 5% level of significance, and confirm our hypothesis as incorrect.