Revised GCE Assessment Objectives Chemistry...15 25 33 47. GCE Chemistry . Contents . Introduction....
Transcript of Revised GCE Assessment Objectives Chemistry...15 25 33 47. GCE Chemistry . Contents . Introduction....
Revised GCEAssessment Objectives
GCE
ChemistryThis document contains the assessment objectives for the Specimen Assessment Materials
CCEA Exemplar Scheme of Work: GCE Chemistry
Page
5
15
25
33
47
GCE Chemistry
Contents
Introduction
Unit AS 1: Assessment Objectives
Unit AS 2: Assessment Objectives
Unit AS 3: Assessment Objectives
Unit A2 1: Assessment Objectives
Unit A2 2: Assessment Objectives
Unit A2 3: Assessment Objectives 57
1
CCEA Exemplar Scheme of Work: GCE Chemistry
CCEA Exemplar Scheme of Work: GCE Chemistry
Introduction
CCEA has developed a new GCE Chemistry specification for first teaching in September 2016. This Assessment Grid was developed together with the Specimen Assessment Materials (SAMs) and has been designed to support you in understanding the assessment objectives.
Please remember that assessment objectives are based on the specification and the context in which the knowledge and understanding is assessed. The scheme of work should therefore be used in conjunction with the specification and the SAMs.
A Microsoft Word version of this scheme of work is available on the subject microsite on the CCEA website (www.ccea.org.uk/microsites). You will be able to use it as a foundation for training within your department to develop understanding of assessment objectives and their balance within the examination papers.
I hope you find this support useful in your teaching.
Best wishes
Elaine Lennox Subject Officer Chemistry
E-mail [email protected] Telephone 028 9026 1200 (2320)
1
CCEA Exemplar Scheme of Work: GCE Chemistry
2
CCEA Exemplar Scheme of Work: GCE Chemistry
CCEA Assessment Grid: GCE Chemistry
3
CCEA Exemplar Scheme of Work: GCE Chemistry
4
CCEA Exemplar Scheme of Work: GCE Chemistry
GCE Chemistry Assessment Grid: Assessment Objectives (AO)
Unit AS 1
5
CCEA Exemplar Scheme of Work: GCE Chemistry
6
CCEA Exemplar Scheme of Work: GCE Chemistry
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) AS
Uni
t 1Q
uest
ion
Spec
Ref
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
CSe
ctio
n A
11.
2.2
B1
12
1.9.
2C
11
31.
2.8
D1
14
1.8.
5A
11
51.
3.7
B1
16
1.4.
1A
11
71.
6.4
D1
18
1.2.
10A
11
91.
2.3
A1
110
1.8.
6C
11
Sect
ion
A To
tal
Tota
l for
Sec
tion
A –
10 m
arks
64
10
Sect
ion
B11
(a)
(i)1.
2.9
a re
gion
with
in a
n at
om th
at c
an h
old
up to
two
elec
trons
with
opp
osite
spi
n [1
]1
1
(ii)
1.2.
9
[1]
11
1
(iii)
1.2.
81s
2 2s2 2
p6 3s2 3
p6 3d10
4s1
[1]
11
(b)
(i)1.
2.12
all 8
ioni
satio
n en
ergi
es s
how
ing
an in
crea
se [1
]bi
gges
t inc
reas
e is
bet
wee
n 6t
h an
d 7t
h io
nisa
tion
ener
gy [1
]
22
2
7
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(ii)
1.2.
11O
+ (g
) → O
2+ (g
) + e
− [1]
11
(iii)
1.2.
13O
has
sm
alle
r nuc
lear
cha
rge/
one
less
pro
ton
[1]
oute
r ele
ctro
n is
in th
e sa
me
shel
l so
the
shie
ldin
g is
si
mila
r [1]
less
nuc
lear
attr
actio
n on
out
erm
ost e
lect
ron
in O
[1]
33
(c)
1.2.
13go
ing
dow
n th
e gr
oup
the
ioni
satio
n en
ergy
de
crea
ses
[1]
the
oute
rmos
t ele
ctro
n is
furth
er fr
om th
e nu
cleu
s [1
]th
e ou
term
ost e
lect
ron
expe
rienc
es le
ss s
hiel
ding
[1]
oute
r ele
ctro
n is
attr
acte
d m
ore
stro
ngly
to th
e nu
cleu
s [1
]
31
4
Tota
lQ
uest
ion
11 T
otal
91
313
312
(a)
1.5.
1la
yers
of p
ositi
ve io
ns [1
]se
a of
del
ocal
ised
ele
ctro
ns [1
]2
2
(b)
(i)1.
2.4
atom
s of
the
sam
e el
emen
t [1]
U23
5 has
143
neu
trons
U23
8 has
146
[1]
22
(ii)
1.2.
623
7.97
9 =
235
x +
238
(100
-x) /
100
2379
7.9
= 23
5x +
238
00 –
238
xx=
abun
danc
e of
U23
5 = 0
.7%
; U23
8 = 9
9.3%
[3]
33
3
(c)
(i)1.
1.2
UF 4 +
2M
g →
U +
2M
gF2 [
2]2
22
(ii)
1.1.
2U
O2 +
4H
F →
UF 4 +
2H
2O [2
]2
22
(iii)
1.7.
1+6
[1]
+6 [1
]+4
[1]
33
(d)
(i)1.
7.6
nitro
gen(
IV) o
xide
[1]
11
(ii)
1.10
.1re
light
s gl
owin
g sp
lint [
1]1
1To
tal
Que
stio
n 12
Tot
al3
1316
7
8
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
13(a
)1.
5.2
wea
k fo
rces
/van
der
Waa
ls’ f
orce
s be
twee
n la
yers
[1]
laye
rs c
an s
lide/
slip
off
[1]
22
(b)
1.5.
2st
rong
cov
alen
t bon
ds [1
]3d
/gia
nt te
trahe
dron
[1]
22
(c)
1.5.
2no
free
cha
rge
carr
iers
/free
ele
ctro
ns/a
ll el
ectro
ns in
co
vale
nt b
onds
[1]
11
Tota
lQ
uest
ion
13 T
otal
55
14(a
)(i)
1.1.
6m
oles
= 0
.287
/ 143
.4 =
0.0
02ra
tio 1
:1
0.00
2 x
107.
9 =
0.21
6ger
ror -
1
22
2
(ii)
1.7.
5A
g+ + e
− → A
g [1
] 1
11
(b)
1.1.
2C
u+ + C
l → C
u2+ +
Cl−
[1]
11
1(c
)(i)
1.7.
4ox
idat
ion
num
ber o
f cop
per c
hang
es fr
om +
2 to
+1
= re
duct
ion
[1]
oxid
atio
n nu
mbe
r of c
oppe
r cha
nges
from
0 to
+1
= ox
idat
ion
[1]
oxid
atio
n an
d re
duct
ion
of th
e sa
me
spec
ies
(cop
per)
in
the
sam
e re
actio
n [1
]
33
(ii)
1.10
it is
inso
lubl
e [1
]1
1(d
)1.
9.6
mol
es o
f cop
per c
hlor
ide
= 2.
0/13
4.5
= 0.
0148
7ra
tio 2
HC
l : 1
CuC
l 20.
0297
47 =
vol
x 1
.0 /1
000
volu
me
= 29
.7cm
3 = 3
0 cm
3 to
2 si
g fig
ures
er
ror -
1
33
3
Tota
lQ
uest
ion
14 T
otal
18
211
7
9
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
15(a
)(i)
1.1.
2C
l 2 + 3
F 2 → 2
ClF
3 [1]
11
1(ii
)1.
3.3
the
elec
trost
atic
attr
actio
n be
twee
n a
shar
ed p
air o
f el
ectro
ns a
nd th
e nu
clei
of t
he b
onde
d at
oms
[2]
22
(iii)
1.3.
6
[2]
22
(b)
(i)1.
6.2
[1]
AsF
F FF
F[1
]
Cl
FF
+
trigo
nal b
ipyr
amid
[1]
bent
/v/n
onlin
ear [
1]fiv
e bo
ndin
g pa
irs o
f ele
ctro
ns re
pel e
ach
othe
r eq
ually
[1]
two
bond
ing
pairs
of e
lect
rons
and
two
lone
pai
rs o
f el
ectro
ns; t
he lo
ne p
airs
of e
lect
rons
repe
l mor
e th
an
bond
ing
pairs
[1]
22
26
2
(ii)
1.6.
210
4.5°
[1]
11
1(c
)(i)
1.3.
9 Idd
Cld–
[1
]ch
lorin
e is
mor
e el
ectro
nega
tive
than
iodi
ne [1
]1
12
F Cl F
Fx
xxxxx
x
10
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(ii)
1.4.
2ch
lorin
e ha
s va
n de
r Waa
ls’ f
orce
s be
twee
n m
olec
ules
[1]
iodi
ne m
onoc
hlor
ide
has
perm
anen
t dip
ole-
dipo
le
attra
ctio
ns b
etw
een
mol
ecul
es [1
]pe
rman
ent d
ipol
e-di
pole
attr
actio
ns a
re s
trong
er/
inte
rmol
ecul
ar fo
rces
stro
nger
in IC
l [1]
mor
e en
ergy
nee
ded
to b
reak
the
stro
nger
in
term
olec
ular
forc
es [1
]
22
4
Tota
lQ
uest
ion
15 T
otal
79
218
416
(a)
1.10.2
-1.10
.4ad
d di
lute
aci
d an
d ef
ferv
esce
nce
for c
arbo
nate
[1]
flam
e te
st y
ello
w/o
rang
e fo
r sod
ium
ions
[1]
add
silv
er n
itrat
e so
lutio
n an
d pp
t for
ms
for h
alid
e [1
]di
ssol
ve in
wat
er [1
]
44
(b)
(i)1.
5.2
Indi
cativ
e C
onte
nt•
in s
odiu
m s
trong
attr
actio
n be
twee
n po
sitiv
e io
nsan
d de
loca
lised
ele
ctro
ns•
in s
odiu
m m
etal
lic b
ondi
ng•
in s
odiu
m c
hlor
ide
stro
ng a
ttrac
tion
betw
een
posi
tive
and
nega
tive
ion
•io
nic
bond
ing
•in
iodi
ne w
eak
van
der W
aals
forc
es b
etw
een
mol
ecul
es•
ioni
c bo
ndin
g is
stro
nger
than
met
allic
bon
ding
whi
ch is
stro
nger
than
van
der
Waa
ls
51
66
11
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(b)
(i)(c
ont.)
Ban
dR
espo
nse
Mar
k
A
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
fully
exp
lain
the
diffe
renc
e in
mel
ting
poin
t usi
ng a
m
inim
um o
f 6 p
oint
s of
indi
cativ
e co
nten
t. Th
ey m
ust u
se g
ood
spel
ling,
pun
ctua
tion
and
gram
mar
an
d th
e fo
rm a
nd s
tyle
are
of a
n ex
celle
nt s
tand
ard.
[5]–
[6]
B
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
the
diffe
renc
e in
mel
ting
poin
t usi
ng a
m
inim
um o
f 4 p
oint
s of
indi
cativ
e co
nten
t. Th
ey m
ust u
se s
atis
fact
ory
spel
ling,
pun
ctua
tion
and
gram
mar
an
d th
e fo
rm a
nd s
tyle
are
of a
goo
d st
anda
rd.
[3]–
[4]
C
Can
dida
tes
expl
ain
parti
ally
the
diffe
renc
e in
mel
ting
poin
t usi
ng a
m
inim
um o
f 2 p
oint
s of
indi
cativ
e co
nten
t. Th
ey u
se li
mite
d co
rrec
t sp
ellin
g, p
unct
uatio
n an
d gr
amm
ar
and
the
form
and
sty
le is
of a
bas
ic
stan
dard
.
[1]–
[2]
DR
espo
nse
not w
orth
y of
cre
dit.
[0]
(ii)
1.8.
6gr
ey –
bla
ck [1
]w
hite
[1]
22
(c)
1.8.
33I
2 + 6
NaO
H →
NaI
O3 +
5NaI
+3
H2O
[2]
22
2
12
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(d)
(i)1.
9.6
46 x
40
= 18
40g
1840
/ 149
.9 =
12.
3 M
[2]
22
2
(ii)
1.8.
5fro
m c
olou
rless
to y
ello
w/b
row
n [1
]1
1To
tal
Que
stio
n 16
Tot
al10
25
174
6
Pape
r Tot
als
4137
1290
226
13
14
CCEA Exemplar Scheme of Work: GCE Chemistry
GCE Chemistry Assessment Grid: Assessment Objectives (AO)
Unit AS 2
15
CCEA Exemplar Scheme of Work: GCE Chemistry
16
CCEA Exemplar Scheme of Work: GCE Chemistry
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) AS
Uni
t 2
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
Sect
ion
A1
2.8.
5C
11
12
2.2.
3A
11
32.
3.9
A1
14
2.6.
1B
11
52.
6.6
B1
16
2.11
.6A
11
72.
1.3
C1
11
82.
4.10
C1
19
2.8.
2D
11
102.
11.2
+
2.11
.3B
11
Sect
ion
A To
tal
Tota
l for
Sec
tion
A –
10 m
arks
55
102
Sect
ion
B11
2.1.
2el
emen
tm
oles
ratio
C22
.2 ÷
12
= 1.
852
H3.
7 ÷
1 =
3.70
4B
r74
.1 ÷
80
= 0.
931
mol
es [1
]em
piric
al F
orm
ula
= C
2H4B
r [1]
216
÷ 10
8 =
2m
olec
ular
For
mul
a =
C4H
8Br 2
[1]
33
3
Tota
lQ
uest
ion
11 T
otal
33
3
17
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
12(a
)2.
2.3
CH
3CH
(CH
3)CH
2CH
3 [1]
2-m
ethy
lbut
ane
[1]
CH
3C(C
H3) 2C
H3 [
1]2,
2 - d
imet
hylp
ropa
ne [1
]
44
(b)
2.2.
1m
olec
ules
whi
ch h
ave
the
sam
e m
olec
ular
form
ula
but a
diff
eren
t st
ruct
ural
form
ula.
22
(c)
2.3.
3ne
open
tane
[1]
incr
ease
d br
anch
ing
[1]
wea
ker v
an d
er W
aals
forc
es [1
]
33
(d)
2.3.
4C
5H12
+ 8
O2 →
5C
O2 +
6H2O
[1]u
nbal
ance
d[1
]bal
ance
d
22
2
(e)
2.3.
10in
itiat
ion
Cl 2 →
2C
l• [1
]pr
opag
atio
n C
l• +
C5H
12 →
C5H
11• +
HC
l [1]
C5H
11• +
Cl 2 →
C5H
11C
l + C
l• [1
]te
rmin
atio
n C
l• +
Cl•
→ C
l 2 [1]
or C
5H11
• + C
5H11
• → C
10H
22or
C5H
11• +
Cl•
→ C
5H11
Cl
44
Tota
lQ
uest
ion
12 T
otal
411
152
13(a
)(i)
2.8.
8en
thal
py c
hang
e(s)
[1]
is/a
re in
depe
nden
t of t
he ro
ute
take
n [1
]2
2
(ii)
2.8.
5en
thal
py c
hang
e w
hich
occ
urs
whe
n 1
mol
e of
a s
ubst
ance
[1]
unde
rgoe
s co
mpl
ete
com
bust
ion
in o
xyge
n [1
] und
er s
tand
ard
cond
ition
s. [1
]
33
(iii)
2.8.
10(–
394)
+ (–
286
× 2)
+ (+
75) [
1]–8
91 k
J m
o1-1 [1
]2
22
(b)
(i)2.
8.13
aver
age
bond
ent
halp
ies
are
used
[1]
11
(ii)
2.8.
11–6
98 =
4(C
–H) –
234
64(
C–H
) = 1
648
412
kJm
ol–1
erro
r -1
33
3
18
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(c)
(i)2.
8.6
Indi
cativ
e C
onte
nt•
mea
sure
mas
s of
spi
rit b
urne
r con
tain
ing
etha
nol b
efor
ean
d af
ter b
urni
ng•
mea
sure
out
kno
wn
volu
me
of w
ater
into
a c
alor
imet
erus
ing
a bu
rette
•bu
rn th
e et
hano
l in
the
spiri
t bur
ner a
nd u
se th
e he
atev
olve
d to
hea
t the
wat
er in
the
calo
rimet
er•
mea
sure
initi
al a
nd fi
nal t
empe
ratu
re o
f wat
er (a
fter
heat
ing)
usi
ng a
ther
mom
eter
•ca
lcul
ate
the
heat
evo
lved
usi
ng th
e eq
uatio
n q
= m
c∆T
•ca
lcul
ate
the
num
ber o
f mol
es o
f eth
anol
use
d fro
m th
em
ass
of e
than
ol b
urne
d•
divi
de th
e he
at e
volv
ed b
y th
e m
oles
of e
than
ol u
sed
toca
lcul
ate
the
enth
alpy
of c
ombu
stio
n
Ban
dR
espo
nse
Mar
k
A
Can
dida
tes
mus
t use
app
ropr
iate
spe
cial
ist
term
s to
exp
lain
fully
the
proc
ess
of d
eter
min
ing
the
enth
alpy
of c
ombu
stio
n (u
sing
a m
inim
um o
f 6
poin
ts o
f ind
icat
ive
cont
ent).
The
y us
e go
od
spel
ling,
pun
ctua
tion
and
gram
mar
and
the
form
an
d st
yle
are
of a
n ex
celle
nt s
tand
ard.
[5]–
[6]
B
Can
dida
tes
mus
t use
app
ropr
iate
spe
cial
ist t
erm
s to
exp
lain
the
proc
ess
of n
mr (
usin
g a
min
imum
of
5 p
oint
s of
indi
cativ
e co
nten
t). T
hey
use
good
sp
ellin
g, p
unct
uatio
n an
d gr
amm
ar a
nd th
e fo
rm
and
styl
e ar
e of
a g
ood
stan
dard
.
[3]–
[4]
66
6
19
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
Ban
dR
espo
nse
Mar
k
C
Can
dida
tes
expl
ain
brie
fly a
nd p
artia
lly
the
proc
ess
of d
eter
min
ing
the
enth
alpy
of
com
bust
ion
(usi
ng a
min
imum
of 4
poi
nts
of
indi
cativ
e co
nten
t). T
hey
use
limite
d sp
ellin
g,
punc
tuat
ion
and
gram
mar
and
the
form
and
st
yle
are
of a
bas
ic s
tand
ard.
[1]–
[2]
DR
espo
nse
not w
orth
y of
cre
dit.
[0]
(c)
(ii)
2.8.
6in
com
plet
e co
mbu
stio
n [1
]he
at lo
ss to
sur
roun
ding
s [1
]2
2
Tota
lQ
uest
ion
13 T
otal
55
919
56
14(a
)2.
9.3
peak
shi
fts to
righ
t and
pea
k is
low
er [2
]ot
her d
raw
ing
erro
rs [–
1]2
2
(b)
2.9.
3nu
mbe
r of m
olec
ules
with
ene
rgy
grea
ter t
han
Ea [
1] in
crea
ses
[1]
22
(c)
2.9.
2ca
taly
st p
rovi
des
an a
ltern
ativ
e ro
ute
[1]
of lo
wer
act
ivat
ion
ener
gy E
a [1]
mor
e m
olec
ules
hav
e en
ergy
gre
ater
than
Ea [1
]nu
mbe
r/fre
quen
cy o
f suc
cess
ful c
ollis
ions
(bet
wee
n S
O2 a
nd O
2 m
olec
ules
) inc
reas
es [1
]
44
Tota
lQ
uest
ion
14 T
otal
62
8
Num
ber o
fm
olec
ules
with
agi
ven
ener
gy
Ene
rgy
Ea
20
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
15(a
)(i)
2.4.
7th
e H
ato
m in
HB
r has
a δ
+ ch
arge
[1]
whi
ch is
attr
acte
d to
are
a of
hig
h el
ectro
n de
nsity
(in
doub
le b
ond)
[1
]
11
2
(ii)
2.4.
8
[3
]cu
rly a
rrow
s dr
awn
corr
ectly
[1]
erro
r –1
13
4
(b)
(i)2.
2.6
CH
3 – C
H2
CH
3
CH
3 H
CC
Z is
omer
[1]
CH
3 – C
H2
H
CH
3C
H3
CC
E is
omer
[1]
22
(ii)
2.4.
9C
H3
Br
CH
3CH
2CC
H2C
H3
maj
or [1
] CH
3 Br
CH
3CH
2CH
CH
CH
3
min
or [1
]
22
CH
2 =
CH
2 C
H2 –
CH
2C
H2 –
CH
2
H+
H..+
H
Br
−B
r −
Br
21
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(iii)
2.4.
9ca
rboc
atio
n in
term
edia
tes
prod
uced
[1]
terti
ary
carb
ocat
ion
mor
e st
able
than
sec
onda
ry c
arbo
catio
n [1
]te
rtiar
y ca
rboc
atio
n le
ads
to fo
rmat
ion
of m
ajor
pro
duct
[1]
33
(c)
(i)2.
5.5
C4H
9Br +
NaO
H →
C4H
9OH
+ H
Br [
2]2
22
(ii)
2.6.
2se
cond
ary
[1]
carb
on b
onde
d to
–O
H is
bon
ded
to tw
o ot
her c
arbo
n at
oms
[1]
11
2
(d)
(i)2.
5.8
C4H
9Br +
NaO
H →
C4H
8 + N
aBr +
H2O
[2]
22
2
(ii)
2.5.
8in
eth
anol
[
1]1
1(ii
i)2.
5.8
elim
inat
ion
[1
]1
1
(iv)
2.5.
8bu
t-2-e
ne
[1
]1
1To
tal
Que
stio
n 15
Tot
al12
1022
4
16(a
)2.
10.1
rate
of f
orw
ard
reac
tion
= R
ate
of re
vers
e re
actio
n [1
]th
e am
ount
of a
ny g
iven
reac
tant
or p
rodu
ct re
mai
ns
cons
tant
[1]
22
(b)
2.10
.2in
crea
se [1
]3
mol
es (g
) LH
S 2
mol
es (g
) RH
Seq
uilib
rium
shi
fts to
RH
S to
opp
ose
the
chan
ge [1
]
22
(c)
2.10
.2de
crea
se [1
](fo
rwar
d) re
actio
n is
exo
ther
mic
equi
libriu
m s
hifts
to L
HS
to o
ppos
e th
e ch
ange
/coo
l the
sy
stem
[1]
22
(d)
2.10
.2no
effe
ct o
n yi
eld
[1]
incr
ease
s th
e ra
te o
f the
forw
ard
and
reve
rse
reac
tions
eq
ually
[1]
22
22
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(e)
(i)2.
10.3
Kc=
[NO
2]2 /[N
O]2 [O
2] [1
]m
ol-1dm
3 [1
]2
22
(ii)
2.10
.4K
c >
1 [1
]1
11
(f)2.
1.6
4×46
2×14
8 =
184/
296
= 62
.2%
erro
r –1
22
2
Tota
lQ
uest
ion
16 T
otal
310
135
Pape
r Tot
als
3544
1190
216
23
24
CCEA Exemplar Scheme of Work: GCE Chemistry
GCE Chemistry Assessment Grid: Assessment Objectives (AO)
Unit AS 3
25
CCEA Exemplar Scheme of Work: GCE Chemistry
26
CCEA Exemplar Scheme of Work: GCE Chemistry
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) AS
Uni
t 3Pr
actic
al B
ookl
et A
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
1a
whi
te [1
]1
1b
two
diffe
rent
par
ticle
siz
es a
re s
een
[1]
diffe
rent
sha
des
of w
hite
[1]
22
c(i)
no c
hang
e at
the
star
t, po
ssib
le v
apou
r in
the
mid
dle,
(c
olou
rless
) liq
uid
at th
e en
d (a
ny 2
out
of 3
) [2]
22
(ii)
colo
urle
ss, g
reen
col
our (
pH 7
) [1]
11
d(i)
fizzi
ng/fr
othi
ng/fo
amin
g/ef
ferv
esce
nce
[1]
whi
te s
olid
left/
som
e so
lid d
isap
pear
s [1
]2
2
(ii)
limew
ater
goe
s m
ilky
[1]
11
e(i)
mea
surin
g cy
linde
r [1]
25 c
m3 in
dica
tes
an a
ccur
acy
of 1
cm
3 [1
]1
12
1
(ii)
titre
val
ue/c
m3 [2
]va
lue
of ti
tratio
n 20
cm
3 +
/- 2
cm3 =
[2] +
/- 4
cm3 =
[1]
corr
ect r
ecor
ding
of v
alue
s e.
g. d
ecim
al p
lace
s an
d ca
lcul
atio
n of
titre
[2]
24
61
fbr
ick
red
[1]
11
Tota
lQ
uest
ion
1 To
tal
21
1518
22
aX
: so
dium
floa
ts; n
o ga
s [1
]Y:
sod
ium
floa
ts; l
ots
of g
as p
rodu
ced
[1]
Z: s
odiu
m fl
oats
; not
muc
h ga
s [1
]
33
bY
cont
ains
eth
anol
, fas
test
reac
tion
11
Tota
lQ
uest
ion
2 To
tal
13
4
27
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
3a
subs
tanc
e m
elts
da
rken
s/go
es b
lack
bl
ack
solid
left/
(mos
t) di
sapp
ears
erro
r –1
22
bbl
ack
solid
(car
bon)
form
s1
1To
tal
Que
stio
n 3
Tota
l 1
23
Tota
l for
Boo
klet
A –
25
mar
ks2
320
252
28
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
Prac
tical
The
ory
Boo
klet
B1
ach
ange
s fro
m g
reen
to re
d [2
]2
2b
chan
ges
from
gre
en to
red
and
ther
e is
som
e br
own
(bro
min
e)
pres
ent [
2]2
2
Tota
lQ
uest
ion
1 To
tal
44
2ad
d w
ater
and
stir
to d
isso
lve
[1]
filte
r the
mix
ture
[1]
add
hydr
ochl
oric
aci
d to
the
solid
[1]
it fiz
zes
show
ing
it is
a c
arbo
nate
[1]
filte
r the
sol
utio
n an
d ad
d a
solu
ble
sulfa
te [1
]w
hite
pre
cipi
tate
pro
duce
d [1
]to
a m
axim
um o
f [4]
44
Tota
lQ
uest
ion
2 To
tal
44
3a
sket
ch o
f app
arat
us i.
e. g
as p
assi
ng th
roug
h w
ater
/alk
ali [
2]ex
plan
atio
n of
how
it w
orks
[1]
12
3
bac
ts a
s a
cata
lyst
for t
he re
actio
n [1
]1
1c
the
spee
d of
dro
ps o
f liq
uid
retu
rnin
g to
the
flask
wou
ld in
crea
se
with
vig
orou
s re
fluxi
ng [1
]1
1
da
sim
ilar b
oilin
g po
int t
o th
e 1-
chlo
robu
tane
[1]
11
ew
ater
[1]
11
fpl
ace
in s
epar
atin
g fu
nnel
with
e.g
. wat
er [1
]st
oppe
r the
funn
el [1
]in
vert
the
funn
el [1
]sh
ake
and
allo
w th
e liq
uids
to s
epar
ate
and
rem
ove
the
low
er
one
[1]
44
gus
ed to
dry
the
1-ch
loro
buta
ne [1
]an
hydr
ous
sodi
um s
ulfa
te [1
]2
2
29
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
h(i)
gcm
-3 [1
]0.
81 x
23
= 18
.63
g [1
]2
22
(ii)
18.6
3/74
= 0
.25
mol
; 0.
25 m
ol o
f C4H
9C1
= 0.
25 x
92.
5 =
23.1
g
[2]
22
2
ibo
iling
poi
nts
are
usua
lly m
easu
red
in ra
nges
[1]
a ra
nge
of 1
/2 d
egre
es is
the
usua
l ran
ge [1
]th
e ra
nge
is in
crea
sed
to c
olle
ct a
s m
uch
as p
ossi
ble
(if th
ere
are
no in
terfe
ring
com
poun
ds) [
1]
21
3
jco
mpa
re th
e pu
re a
nd “i
mpu
re” s
pect
ra [1
]th
e “im
pure
” spe
ctru
m w
ill h
ave
extra
pea
ks [1
]2
2
Tota
lQ
uest
ion
3 To
tal
39
1022
44
aM
(s) +
H2O
(g) →
MO
(s) +
H2(g
)eq
uatio
n [1
]st
ate
sym
bols
[1]
22
2
bsa
me
mas
s [1
]sa
me
parti
cle
size
[1]
100%
pur
ity [1
]
33
c(i)
stea
m is
dilu
ted
wat
er [1
]1
1(ii
)bu
bble
s/fiz
zing
effe
rves
cenc
e [1
]w
hite
sol
id [1
]ca
lciu
m m
oves
up
and
dow
n [1
]he
at p
rodu
ced
[1]
stea
m p
rodu
ced
[1]
calc
ium
dis
olve
s/di
sapp
ears
[1]
to a
max
imum
of [
3]
33
d(i)
time/
seco
nds
or m
inut
es [1
]vo
lum
e of
hyd
roge
n ga
s/cm
3 [1
]2
2
(ii)
stee
per a
t the
sta
rt [1
]ea
rlier
hor
izon
tal fi
nish
[1]
22
30
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(iii)
allo
w g
as to
go
into
a te
st tu
be [1
]lig
hted
spl
int [
1]po
p no
ise
[1]
21
3
e3.
4 g
of C
a =
3.4/
40 =
0.0
85 m
ol; 0
.085
x 2
4 dm
3 =
2.04
=
2.0
dm3 [4
]er
ror –
1
44
4
fth
e G
roup
two
met
als
are
very
reac
tive
with
oxy
gen
[1]
henc
e th
e ex
perim
ent w
ould
be
over
ver
y qu
ickl
y [1
]ne
ed to
slo
w d
own
the
reac
tion
[1]
only
way
is to
dilu
te th
e ox
ygen
[1]
e.g.
by
mix
ing
it w
ith n
itrog
en/n
oble
gas
[1]
colle
ct th
e ox
ygen
ove
r wat
er/in
a s
yrin
ge [1
]co
mpa
re th
e ra
tes
of o
xyge
n co
llect
ion
and
rela
te to
reac
tivity
[1]
to a
max
imum
of [
5]
55
Tota
lQ
uest
ion
4 To
tal
64
1525
6To
tal f
or B
ookl
et B
– 5
5 m
arks
913
3355
10
Pape
r Tot
als
1116
5380
12
31
32
CCEA Exemplar Scheme of Work: GCE Chemistry
GCE Chemistry Assessment Grid: Assessment Objectives (AO)
Unit A2 1
33
CCEA Exemplar Scheme of Work: GCE Chemistry
34
CCEA Exemplar Scheme of Work: GCE Chemistry
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) A2
Uni
t 1
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
14.
3.7
B1
12
4.2
D1
13
4.4.
1/4.
4.2
C1
11
44.
3.4
A1
11
54.
4.2
B1
11
64.
8.1
C1
17
4.7.
6D
11
84.
9.4
D1
19
2.1.
4B
11
110
4.5.
8D
11
Sect
ion
A To
tal
Tota
l for
Sec
tion
A –
10 m
arks
35
210
4 11
(a)
(i)Sy
nopt
ic4.
2.4
4.2.
54.
2.6
DH⦵
= ∑
D fH⦵
(pro
duct
s) –
∑D fH
⦵ (r
eact
ants
)=
[3 ×
−39
3.5]
– [2
× −
824.
2]=
467.
9 kJ
mol
−1[2
]
DS⦵
= ∑
S⦵
(pro
duct
s) −
∑ S
⦵ (r
eact
ants
)=
[(4 ×
27.
3) +
(3 ×
213
.6)]
− [(2
× 8
7.4)
+ (3
× 5
.7)]
= 55
8.1
J K
−1 m
ol-1
[2]
DG⦵
= DH
⦵ −
TDS
⦵
= 46
7.9
− (2
98 ×
0.5
581)
= 30
1.6
kJ m
ol−1
[1
]
2 2 1
5
2 2 1
(ii)
4.2.
6DG
⦵ is
pos
itive
[1]
11
35
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(b)
4.2.
7T
= (DH
⦵ ÷
DS⦵
)=
(467
.9 ÷
0.5
581)
= 83
8K[2
]
22
2
Tota
lQ
uest
ion
11 T
otal
1
78
712
(a)
4.1.
1th
e en
ergy
requ
ired
to c
onve
rt 1
mol
e of
an
ioni
c so
lid in
to g
aseo
us
ions
[2
]2
2
(b)
(i)4.
1.2
Mg+ (
g) +
e− +
F2(g
)
Mg2+
(g) +
2F− (
g)
Mg(
s) +
F2(g
)
MgF
2(s)
↑ ↑ ↑ ↑↑↑
↓
[1]
[1]
[1]
[1] [4
]
44
(ii)
4.1.
2LE
= (+
1123
) + (1
50) +
(736
) + (1
450)
+ (2
x 7
9) +
(2
x −
348)
= 2
921
kJ m
ol-1
[2
]2
22
36
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(c)
(i)4.
1.3
H
Mg2+
[1]
[1]
F−
OO
O
OH
H
HH
H
HH
[2]
22
(ii)
4.1.
3LE
= (–
155)
– [(
–192
0) +
(2 x
–36
4)] =
249
3 kJ
mol
-1 [2]
22
2
Tota
lQ
uest
ion
12 T
otal
48
124
13(a
)(i)
4.7.
42-
hydr
oxy-
2-m
ethy
lbut
anen
itrile
[2]
22
(ii)
4.6.
2op
tical
[1]
11
(iii)
4.6.
3
CCH
3
CN
HO
H5C
2
CH
3
C
NC
OHC
2H5
corr
ect 3
D re
pres
enta
tion
[1]
mirr
or im
age
[1]
22
2
(iv)
4.7.
5nu
cleo
phili
c ad
ditio
n[1
]1
1
37
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(v)
4.7.
5
erro
r −1
[4]
44
(vi)
4.7.
6th
e ca
rbon
yl g
roup
is p
lana
r [1]
the
nucl
eoph
ile a
ttack
s fro
m b
oth
side
s to
an
equa
l ex
tent
[1]
equa
l am
ount
s of
eac
h op
tical
isom
er fo
rmed
[1]
21
3
(b)
4.7.
9he
at [1
] with
eith
er a
cidi
fied
pota
ssiu
m d
ichr
omat
e,
Tolle
n’s
reag
ent o
r Feh
ling’
s so
lutio
n [1
]co
rrec
t pos
itive
resu
lt w
ith b
utan
al, n
o ch
ange
with
bu
tano
ne [1
][3
]
33
(c)
(i)4.
7.7
[2]
22
O
OH
H+
− OC CC
C2H
5
C2H
5
CH
3C
H3
CH
3C
H3
C2H
5
C2H
5
CN
CN
CN
CN
−
C− O
HH
CC
CH
3C
H3
+H2O
CH
3CH
2C
H3C
H2
NO
2
NO
2N
NN
O2
NO
2
O +
NH
2N
38
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(ii)
4.7.
7/4.
7.8
Indi
cativ
e C
onte
nt
•ye
llow
/ora
nge
•so
lid•
capi
llary
tube
•he
at s
low
ly•
reco
rd th
e te
mpe
ratu
re w
hen
the
solid
mel
ts•
com
pare
to ta
bles
of d
ata
66
6
Tota
lQ
uest
ion
13 T
otal
105
924
26
Ban
dR
espo
nse
Mar
k
A
Can
dida
tes
mus
t use
app
ropr
iate
spe
cial
ist
term
s to
exp
lain
fully
the
proc
ess
of id
entif
ying
th
e ke
tone
(usi
ng a
min
imum
of 6
poi
nts
of
indi
cativ
e co
nten
t). T
hey
use
good
spe
lling
, pu
nctu
atio
n an
d gr
amm
ar a
nd th
e fo
rm a
nd
styl
e ar
e of
an
exce
llent
sta
ndar
d.
[5]–
[6]
B
Can
dida
tes
mus
t use
app
ropr
iate
spe
cial
ist
term
s to
exp
lain
the
proc
ess
of id
entif
ying
th
e ke
tone
(usi
ng a
min
imum
of 5
poi
nts
of
indi
cativ
e co
nten
t). T
hey
use
good
spe
lling
, pu
nctu
atio
n an
d gr
amm
ar a
nd th
e fo
rm a
nd
styl
e ar
e of
a g
ood
stan
dard
.
[3]–
[4]
C
Can
dida
tes
expl
ain
brie
fly a
nd p
artia
lly th
e pr
oces
s of
iden
tifyi
ng th
e ke
tone
(usi
ng a
m
inim
um o
f 4 p
oint
s of
indi
cativ
e co
nten
t).
They
use
lim
ited
spel
ling,
pun
ctua
tion
and
gram
mar
and
the
form
and
sty
le a
re o
f a b
asic
st
anda
rd.
[1]–
[2]
DR
espo
nse
not w
orth
y of
cre
dit.
[0]
39
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
14(a
)(i)
4.5.
2K
a = [C
H3C
H2C
OO
− ][H
+ ]
[C
H3C
H2C
OO
H]
[1]
11
1
(ii)
4.5.
3K
a =
[H+ ]2
÷ [C
H3C
H2C
OO
H]
[1]
[H+ ]
= 0.
0018
4 [
1]pH
= 2
.74
[1
]
33
3
(iii)
4.5.
4a
solu
tion
whi
ch m
inim
ises
cha
nges
in p
H o
n ad
ditio
n of
sm
all a
mou
nts
of a
cid
or a
lkal
i
[2
]2
2
(iv)
4.5.
5m
oles
of a
cid
0.25
x 0
.3 =
0.0
75m
oles
of s
alt 0
.15
x 0.
2 =
0.03
(con
cent
ratio
n of
aci
d =
0.15
mol
dm-3)
(con
cent
ratio
n of
sal
t = 0
.06
mol
dm-3)
[H+ ]
= K
a x ([
acid
]/[sa
lt]) =
3.3
8 x
10-5 m
oldm
-3
pH =
4.4
7
[4]
44
4
(b)
(i)4.
8.5
CH
3CH
2CO
OH
+ N
aOH
→ C
H3C
H2C
OO
Na
+ H
2O [
1]1
11
(ii)
4.5.
7ph
enol
phth
alei
n
[1
]co
lour
less
to p
ink
[2]
rang
e m
atch
es th
e ve
rtica
l por
tion
of th
e tit
ratio
n cu
rve
[1]
44
(iii)
1.9.
6m
oles
of N
aOH
= 0
.20
x (1
8.5/
1000
) = 0
.003
7m
oles
of C
H3C
H2C
OO
H =
0.0
037
conc
entra
tion
of C
H3C
H2C
OO
H =
0.1
48 m
oldm
-3
[3]
33
3
(iv)
4.5.
3[H
+ ] =
KW ÷
[OH
– ] =
5 x
10-1
4 mol
dm-3
[1]
pH =
13.
30[1
]2
22
Tota
lQ
uest
ion
14 T
otal
49
720
14
40
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
15(a
)4.
10.1
22
(b)
(i)4.
10.3
HN
O3 +
2H
2SO
4 → N
O2+ +
H3O
+ + 2
HS
O4–
22
2
(ii)
4.10
.4ni
troni
um io
n[1
]1
1(ii
i)4.
10.3
Ele
ctro
phili
c su
bstit
utio
n
erro
r −1
[5]
55
(iv)
4.10
.5m
ethy
l 3-n
itrob
enzo
ate
[1]
11
(v)
4.10
.5cr
eam
sol
id [1
]1
1To
tal
Que
stio
n 15
Tot
al7
512
2
OC
H3
OC
H3
OC
H3
OC
H3
+
CC
C
H
H
C
+H
+N
O2
NO
2NO
2N
O2
OO
OO
befo
reaf
ter
[2]
41
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
16(a
)4.
3.3
first
[1]
valid
exp
lana
tion
[1]
[2]
22
2
(b)
4.3.
3ze
ro [1
]va
lid e
xpla
natio
n [1
][2
]2
22
(c)
4.3.
3ra
te =
k [C
4H0B
r][1
]1
12
(d)
4.3.
120
00 [1
]s-1
[1]
[2]
11
21
(e)
4.3.
5/4.
3.6
[5]
erro
r −1
23
5
Tota
lQ
uest
ion
16 T
otal
39
127
CH
3C
H3
CH
3C
H3
CH
3C
H3
CH
3C
H3
H3C
H3C
H3C
H3C
RD
S
OH
−
OH
Br −
Br
C
CC
+
C+
42
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
17(a
)(i)
4.9.
6
OH
OH
OH
H
HHH
H C C C
[1]
11
(ii)
4.9.
6pr
opan
e-1,
2,3-
triol
[1]
11
(iii)
4.9.
6
(CH
2) 7 ─ C
H =
CH
CH
2CH
= C
H(C
H2) 4C
H3
(CH
2) 7 ─ C
H =
CH
CH
2CH
= C
H(C
H2) 4C
H3
(CH
2) 7 ─ C
H =
CH
CH
2CH
= C
H(C
H2) 4C
H3
O
O O
O O
O
H
H H H
HC C CCCC
[1]
11
(b)
(i)4.
9.4
+ 4.
8.1
3-m
ethy
lbut
anoi
c ac
idm
etha
nol
[1]
11
43
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(ii)
4.9.
4
[2]
22
(iii)
4.9.
5In
dica
tive
Con
tent
•ac
id a
nd a
lcoh
ol in
to ro
und-
botto
med
flas
k an
dad
d co
ncen
trate
d su
lphu
ric a
cid
slow
ly•
add
anti-
bum
ping
gra
nule
s•
heat
und
er re
flux
•di
stil
and
colle
ct a
t boi
ling
poin
t of e
ster
•sh
ake
with
aqu
eous
sod
ium
car
bona
te a
ndre
leas
e pr
essu
re•
sepa
rate
est
er la
yer u
sing
sep
arat
ing
funn
el•
add
a na
med
dry
ing
agen
t•
deca
nt/fi
lter
66
6
CH
3 ─ C
─ C
H2C
OO
H +
CH
3OH
C
H3 ─
C ─
CH
2CO
OC
H3 +
H2O
CH
3 H
CH
3
H
44
Que
stio
nSp
ec R
efM
ark
Sche
me
AO
1A
O2
AO
3To
tal
Mat
hsQ
WC
(iii)
4.9.
5 (c
ont.)
Que
stio
n 17
Tot
al2
46
126
Pape
r Tot
als
3452
2411
040
12
Ban
dR
espo
nse
Mar
k
A
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
fully
the
prep
arat
ion
of th
e es
ter (
usin
g a
min
imum
of 6
poi
nts
of in
dica
tive
cont
ent).
The
y us
e go
od s
pelli
ng,
punc
tuat
ion
and
gram
mar
and
the
form
and
sty
le a
re o
f an
exce
llent
st
anda
rd.
[5]–
[6]
B
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
the
prep
arat
ion
of th
e es
ter (
usin
g a
min
imum
of 5
poi
nts
of in
dica
tive
cont
ent).
The
y us
e go
od s
pelli
ng,
punc
tuat
ion
and
gram
mar
and
th
e fo
rm a
nd s
tyle
are
of a
goo
d st
anda
rd.
[3]–
[4]
C
Can
dida
tes
expl
ain
brie
fly a
nd
parti
ally
the
prep
arat
ion
of th
e es
ter (
usin
g a
min
imum
of 4
po
ints
of i
ndic
ativ
e co
nten
t). T
hey
use
limite
d sp
ellin
g, p
unct
uatio
n an
d gr
amm
ar a
nd th
e fo
rm a
nd
styl
e ar
e of
a b
asic
sta
ndar
d.
[1]–
[2]
DR
espo
nse
not w
orth
y of
cre
dit.
[0]
45
46
CCEA Exemplar Scheme of Work: GCE Chemistry
GCE Chemistry Assessment Grid: Assessment Objectives (AO)
Unit A2 2
47
CCEA Exemplar Scheme of Work: GCE Chemistry
48
CCEA Exemplar Scheme of Work: GCE Chemistry
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) A2
Uni
t 2
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
15.
2.3
D1
12
5.6.
5A
11
35.
9.6
C1
14
5.5.
5/6
C1
15
5.5.
11D
11
65.
6.2
C1
17
5.10
.1 +
2.4.
10B
11
85.
5.6
C1
19
5.7.
3 +
2.5.
5D
11
105.
9.3
B1
1Se
ctio
n A
Tota
lSe
ctio
n A
Tota
l – 1
0 m
arks
26
210
11a
5.6.
7an
ode
2H
2 +
4O
H-
→ 4
H2O
+ 4
e- [1]
cath
ode
O2
+ 2
H2O
+ 4
e- →
4O
H-
[1]
22
2
b5.
6.7
2H2(g
) +
O2(g
) →
2H
2O(I)
[2
]2
22
c5.
6.8
adva
ntag
es:
rene
wab
le s
ourc
e of
ele
ctric
ity/d
oes
not
prod
uce
pollu
tion/
sile
nt [2
]2
2
Tota
lQ
uest
ion
11 to
tal
42
64
49
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
12a
5.9.
4di
pola
r ion
s [1
]st
rong
attr
actio
n be
twee
n op
posi
te c
harg
es [1
]2
2
b5.
9.5
2H2N
CH
(CH
2SeH
)CO
OH
+ N
a 2CO
3 →
2H2N
CH
(CH
2SeH
)CO
ON
a +
H2O
+ C
O2
[2]
22
2
c(i)
5.10
.1H
2N-C
H(C
H2S
eH)-
CO
-NH
-CH
(CH
2SeH
)-C
OO
H [
3]1
23
(ii)
5.9.
7in
duce
d fit
mec
hani
sm lo
wer
s ac
tivat
ion
ener
gy [1
]1
1(ii
i)5.
9.10
bell
shap
ed c
urve
and
labe
lled
axes
[2]
22
Tota
lQ
uest
ion
12 to
tal
46
102
13a
(i)1.
1.12
Zn +
2Fe
3+
2Fe
2+ +
Zn2+
[1]
11
1(ii
)5.
6.2
E⦵
= +
0.3
2V s
o re
actio
n sh
ould
pro
ceed
[1]
11
b(i)
5.3.
2M
nO4- +
5Fe
2+ +
8H
+ → M
n2+ +
4H
2O +
5Fe
3+ [1
]1
11
(ii)
5.3.
2m
oles
MnO
4- =
26.
0 x
10-3 x
0.0
2 =
0.52
x 1
0-3
mol
es F
e =
5 x
0.52
x 1
0-3 =
2.6
x 1
0-3 in
25c
m3
= 2.
6 x
10-2 in
250
cm3
mas
s Fe
= 2
.6 x
10-2
x 5
6 =
1.45
6 g
% F
e =
1.45
6 x
100
= 9
1%[4
]1.
60
erro
r − [1
]
44
4
(iii)
5.3.
2co
lour
less
to p
ink
[2]
22
Tota
lQ
uest
ion
13 to
tal
25
29
614
ai
5.7.
3nu
cleo
phili
c su
bstit
utio
n [1
]1
1ii
5.7.
3C
4H9B
r + N
H3 →
C4H
9NH
2 +
HB
r [1
]1
1iii
5.7.
3 +
2.5.
6 d+
d−
C –
Br
pol
aris
edd+
lone
pai
r on
N/N
H3 a
ttrac
ted
to C
C-N
bon
d fo
rmed
, C-B
r bon
d br
oken
[3]
33
bi
5.7.
3lit
hal
[1]
11
50
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
ii5.
7.3
C3H
7CN
+ 4
[H] →
C3H
7CH
2NH
2 [2
]2
22
c5.
7.4
C6H
5NO
2 + 6
[H]
→ C
6H5N
H2 +2
H2O
[2]
22
2d
i5.
7.6
less
bas
ic th
an th
e ot
hers
[1]
11
ii5.
7.5
C6H
5NH
2 +
HC
l →
C6H
5NH
3Cl-
[1]
11
iii5.
7.1
phen
ylet
hyl g
roup
atta
ched
to N
ato
m w
hich
has
two
hydr
ogen
s [1
]1
1
ei
5.7.
8C
6H5-N
+ ≡N
[2]
22
ii5.
7.8
sodi
um n
itrite
and
dilu
te h
ydro
chlo
ric a
cid
[1]
11
iii4.
7.8
5.7.
35.
9.5
2.6.
5
A H
Cl/H
2SO
4 or N
aOH
[
1]B
lit
hal
[1]
C
HN
O2/N
aNO
2 + H
Cl
[1
]D
P
Cl 5/H
Cl
[1]
1 1 1 1
4
Tota
lQ
uest
ion
14 to
tal
182
204
15a
5.5.
1tra
nsiti
on m
etal
ions
hav
e an
inco
mpl
ete
d sh
ell [
1]1
1b
i5.
5.11
VO
2+(a
q)
blu
e
[1]
V3+
(aq)
gre
en
[1]
22
ii5.
6.2
3VO
2+ + C
r + 6
H+ →
3V
O2+
+ C
r3+ +
3H
2O [2
]em
f = 1
.74
V [
1]3
33
ci
5.5.
9bl
ue
[1
]ye
llow
[1
] 2
2
ii5.
5.9
octa
hedr
al [
1]1
1iii
2.10
.2hy
droc
hlor
ic a
cid/
sodi
um c
hlor
ide
[1]
11
di
5.5.
7H
2N-C
H2-C
H2-N
H2
[1]
11
ii5.
5.7
two
coor
dina
te b
onds
/poi
nts
of a
ttach
men
t [1]
11
iii5.
5.7
[Ni(e
n)3]2+
[2
]2
2
+
51
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
ei
5.5.
3C
o(C
H3C
OO
) 2.4H
2O [
2]2
2ii
5.5.
6to
oxi
dise
cob
alt(I
I) to
cob
alt(I
II) [
2]2
2iii
5.5.
9oc
tahe
dral
[1]
11
iv5.
5.5
six
[1]
11
v2.
1.3
1 dm
3 of H
2O2 p
rodu
ces
20 d
m3 o
f oxy
gen
20/2
4 m
ole
of o
xyge
n =0
.833
i.e. 0
.833
mol
dm
-3
2:1
ratio
th
eref
ore
1.67
mol
dm
-3 [
3]
33
3
Tota
lQ
uest
ion
15 to
tal
912
223
616
a(i)
4.6.
1sa
me
mol
ecul
ar fo
rmul
a bu
t diff
eren
t stru
ctur
al
form
ula
[2]
22
(ii)
4.8.
6H
CO
OH
+ C
2H5O
H ⇆
HC
OO
C2H
5 + H
2O [2
]2
2(ii
i)2.
10.2
add
conc
. H2S
O4/m
etha
noic
aci
d/et
hano
l [1
]re
mov
e w
ater
[1]
22
b(i)
5.2.
2Te
tram
ethy
lsila
ne,
Si(C
H3) 4
[2]
22
(ii)
5.2.
65.
2.5
5.2.
4
Indi
cativ
e co
nten
t•
HC
OO
- s
ingl
et -
nex
t to
O•
CH
2 - q
uarte
t -
next
to 3
H•
CH
3 -
tripl
et -
nex
t to
2H•
ratio
1:2
:3•
area
und
er c
urve
is p
ropo
rtion
al to
the
num
ber o
fH
in e
ach
envi
ronm
ent
•gr
eate
st d
eshi
eldi
ng•
H n
ext t
o O
66
6
52
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
b(ii
)(c
ont.)
c5.
1.2
28
C2H
4+ or
CO
+ [1
]45
H
CO
O+
or C
2H5O
+ [1
]2
2
Ban
dR
espo
nse
Mar
k
A
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
fully
the
proc
ess
of n
mr (
usin
g a
min
imum
of
6 po
ints
of i
ndic
ativ
e co
nten
t). T
hey
use
good
spe
lling
, pun
ctua
tion
and
gram
mar
and
the
form
and
sty
le a
re
of a
n ex
celle
nt s
tand
ard.
[5]–
[6]
B
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
the
proc
ess
of n
mr (
usin
g a
min
imum
of
5 po
ints
of i
ndic
ativ
e co
nten
t). T
hey
use
good
spe
lling
, pun
ctua
tion
and
gram
mar
and
the
form
and
sty
le a
re
of a
goo
d st
anda
rd.
[3]–
[4]
C
Can
dida
tes
expl
ain
brie
fly a
nd
parti
ally
the
proc
ess
of n
mr (
usin
g a
min
imum
of 4
poi
nts
of in
dica
tive
cont
ent).
The
y us
e lim
ited
spel
ling,
pu
nctu
atio
n an
d gr
amm
ar a
nd
the
form
and
sty
le a
re o
f a b
asic
st
anda
rd.
[1]–
[2]
DR
espo
nse
not w
orth
y of
cre
dit.
[0]
53
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
d(i)
2.7.
1bo
nds
in m
olec
ules
vib
rate
abso
rb e
nerg
y of
a c
erta
in fr
eque
ncy
depe
nden
t on
the
atom
s m
ass
in th
e bo
nd-O
H a
bsor
ptio
n pe
ak fo
r pro
pano
ic a
cid
diffe
rent
pos
ition
s fo
r C=O
and
C=O
||
OH
O
[4
]
allo
w a
ny 4
from
the
abov
e 5
stat
emen
ts
22
41
(ii)
4.8.
5so
dium
car
bona
te[1
]ef
ferv
esce
nce
with
the
acid
[1
]2
2
Tota
lQ
uest
ion
16 to
tal
414
422
16
17a
5.11
.7C
7H6O
3 +
C4H
6O3
→
C
9H8O
4 +
C2H
4O2
[2]
22
b5.
11.7
aspi
rin is
not
ver
y so
lubl
e in
wat
er. [
1]1
1c
5.4.
1In
dica
tive
Con
tent
•TL
C p
late
, pen
cil l
ine,
mar
k 3
spot
s•
diss
olve
sm
all a
mou
nts
of ‘c
rude
’ asp
irin,
‘pur
ified
’ asp
irin
and
‘pur
e’(c
omm
erci
al) a
spiri
nin
sep
arat
e te
st tu
bes
in a
sui
tabl
e so
lven
t eg
etha
nol
•sp
ot e
ach
sam
ple
on to
the
TLC
pla
te•
plac
e in
dev
elop
ing
tank
with
a s
uita
ble
solv
ent
eg e
thyl
eth
anoa
te•
rem
ove
plat
e an
d m
ark
the
posi
tion
of s
olve
ntfro
nt•
use
UV
ligh
t or a
loca
ting
reag
ent
6
54
Que
stio
nSp
ecR
ef.
Mar
k Sc
hem
eA
O1
AO
2A
O3
Tota
lM
aths
QW
C
c(c
ont.)
66
d5.
4.3
cost
or v
olat
ility
[1]
11
Tota
lQ
uest
ion
17 to
tal
46
106
Pape
r Tot
al43
4918
110
2312
Ban
dR
espo
nse
Mar
k
A
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
fully
the
proc
ess
of T
LC (u
sing
a m
inim
um o
f 5
poin
ts o
f ind
icat
ive
cont
ent).
The
y us
e go
od s
pelli
ng, p
unct
uatio
n an
d gr
amm
ar a
nd th
e fo
rm a
nd s
tyle
are
of
an e
xcel
lent
sta
ndar
d.
[5]–
[6]
B
Can
dida
tes
mus
t use
app
ropr
iate
sp
ecia
list t
erm
s to
exp
lain
the
proc
ess
of T
LC (u
sing
a m
inim
um o
f 4 p
oint
s of
indi
cativ
e co
nten
t). T
hey
use
good
sp
ellin
g, p
unct
uatio
n an
d gr
amm
ar
and
the
form
and
sty
le a
re o
f a g
ood
stan
dard
.
[3]–
[4]
C
Can
dida
tes
expl
ain
brie
fly a
nd
parti
ally
the
proc
ess
of T
LC (u
sing
a
min
imum
of 3
poi
nts
of in
dica
tive
cont
ent).
The
y us
e lim
ited
spel
ling,
pu
nctu
atio
n an
d gr
amm
ar a
nd th
e fo
rm a
nd s
tyle
are
of a
bas
ic s
tand
ard.
[1]–
[2]
DR
espo
nse
not w
orth
y of
cre
dit.
[0]
55
56
CCEA Exemplar Scheme of Work: GCE Chemistry
GCE Chemistry Assessment Grid: Assessment Objectives (AO)
Unit A2 3
57
CCEA Exemplar Scheme of Work: GCE Chemistry
58
CCEA Exemplar Scheme of Work: GCE Chemistry
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) A2
Uni
t 3
Prac
tical
Boo
klet
A
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3Q
uest
ion
Tota
lM
aths
QW
C
1a
use
of s
tarti
ng v
alue
s to
one
dec
imal
pla
ce [1
]co
rrec
t cal
cula
tion
of a
vera
ge ti
tre [2
]ro
ugh
valu
e be
twee
n 23
.4 a
nd 2
5.2
[1]
accu
racy
of t
itrat
ion
valu
e +/
- 0.2
cm
3 of 2
3.2
cm3
slid
ing
scal
e fo
r [2]
66
2
bre
ad th
e bo
ttom
of t
he m
enis
cus
or a
llow
a m
etho
d ta
king
into
ac
coun
t the
col
our o
f the
pot
assi
um m
anga
nate
(VII)
[2]
22
cco
lour
less
to p
ink
[2]
22
Tota
lQ
uest
ion
1 To
tal
28
102
2a
gree
n [1
]1
1b
gree
n so
lutio
n [1
]1
1c
gree
n pr
ecip
itate
[1]
11
dgr
een
prec
ipita
te [1
]1
1e
whi
te p
reci
pita
te [1
]1
1f
no re
actio
n [1
]1
1g
iron(
II) s
ulfa
te [1
]1
1
Tota
lQ
uest
ion
2 To
tal
16
7
59
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3Q
uest
ion
Tota
lM
aths
QW
C
3a
the
com
paris
on o
f col
ours
wou
ld b
e m
ade
by p
laci
ng te
st tu
bes
of th
e so
lutio
ns s
ide
by s
ide
until
one
col
our e
xact
ly m
atch
ed
the
othe
r col
our i
n in
tens
ity/d
epth
[2]
expl
anat
ion/
desc
riptio
n of
how
the
5M s
olut
ion
wou
ld h
ave
to b
e ap
prop
riate
ly d
ilute
d w
ith th
e co
rrec
t use
of s
uita
ble
appa
ratu
s e.
g. m
easu
ring
cylin
ders
[2]
44
b2M
[1]
11
Tota
lQ
uest
ion
3 To
tal
14
54
aco
rrec
t lab
ellin
g of
sol
vent
fron
t and
sta
rting
poi
nt [1
]tw
o sp
ots
labe
lled
with
app
ropr
iate
siz
es a
t app
roxi
mat
ely
corr
ect p
lace
s [1
]so
lven
t fro
nt n
ear t
he to
p of
the
TLC
slid
e [1
]
12
3
btw
o su
bsta
nces
[1]
11
Tota
lQ
uest
ion
4 To
tal
13
45
ligan
d 1
is a
mm
onia
sol
utio
n lig
and
2 is
eth
ylen
e di
amin
e so
lutio
n lig
and
3 is
edt
a so
lutio
n al
l of t
he li
gand
s w
ill fo
rm a
bl
ue c
ompl
ex; l
igan
d 3
will
dis
plac
e lig
and
2 w
hich
will
dis
plac
e lig
and
1. I
n ea
ch c
ase
for a
pos
itive
resu
lt th
ere
shou
ld b
e an
ap
prop
riate
col
our c
hang
e. F
or a
neg
ativ
e re
sult
ther
e is
no
chan
ge b
ased
on
the
orig
inal
col
our o
f the
sol
utio
ns.
Hen
ce 3
po
sitiv
e re
sults
and
3 n
egat
ive
resu
lts;
-[1] f
or e
ach
inco
rrec
t res
ult [
4]
44
Tota
lQ
uest
ion
5 To
tal
44
Tota
l for
Boo
klet
A –
30
mar
ks3
225
302
60
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3Q
uest
ion
Tota
lM
aths
QW
C
1a
rete
ntio
n tim
e [1
]e.
g. d
etec
tor r
eadi
ng [1
]2
2
b4
[1]
11
15/2
8 x
100
= 53
.6%
22
2To
tal
Que
stio
n 1
Tota
l2
35
22
agr
een
[1] a
nd b
lue
[1] s
olid
s2
2b
iiro
n(II)
hyd
roxi
de [1
] gr
een
[1]
22
iiC
u(N
H3) 42+
[1]
deep
blu
e [1
]2
2
cad
d a
solu
tion
of b
ariu
m c
hlor
ide
[1]
whi
te p
reci
pita
te p
rodu
ced
[1]
22
Tota
lQ
uest
ion
2 To
tal
26
83
ait
form
s th
e hy
droc
hlor
ide/
salt
[1]
whi
ch is
ioni
c an
d th
us m
ore
solu
ble
[1]
22
bth
e ph
enyl
dia
zoni
um io
n [1
]is
uns
tabl
e at
hig
her t
empe
ratu
res
[1]
22
cio
dine
reac
ts w
ith th
e st
arch
[1]
to p
rodu
ce a
blu
e-bl
ack
colo
ur [1
]2
2
GC
E C
hem
istr
y A
sses
smen
t Grid
Ass
essm
ent O
bjec
tives
(AO
) A2
Uni
t 3
Prac
tical
The
ory
Boo
klet
B
61
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3Q
uest
ion
Tota
lM
aths
QW
C
dit
cont
ains
an
ioni
c gr
oup
[1]
whi
ch is
sol
vate
d by
wat
er [1
]th
e be
nzen
e rin
g is
onl
y a
rela
tivel
y sm
all p
art o
f the
stru
ctur
e [1
] an
y 2
from
3
22
etu
rn d
own
[1]
the
amou
nt o
f wat
er fl
owin
g th
roug
h th
e w
ater
pum
p [1
]2
2
fit
rem
oves
the
etha
noic
aci
d [1
]w
hich
has
a h
igh/
high
er b
oilin
g po
int/m
ore
diffi
cult
to e
vapo
rate
[1
]
22
g(s
eal)
a ca
pilla
ry tu
be a
t one
end
and
put
in s
ome
azo
com
poun
d [1
]pl
ace
in a
n oi
l bat
h/m
eltin
g po
int a
ppar
atus
[1]
heat
slo
wly
[1]
note
whe
n th
e so
lid s
tarts
to m
elt [
1]no
te w
hen
the
solid
sto
ps m
eltin
g [1
]
55
h5
g of
phe
nyla
min
e =
5/93
= 0
.054
mol
7 g
of n
apht
hol =
7/1
44 =
0.0
486
= 0.
049
mol
R
MM
of d
iazo
com
poun
d is
200
.5
0.04
9 m
ol =
0.0
49 x
200
.5 =
9.8
2g%
yie
ld =
3/9
.82
x 10
0 =
30.5
498
= 30
.5 d
epen
ding
on
the
num
bers
pre
sent
ed in
the
calc
ulat
ion
[5]
erro
r −[1
]de
cim
al p
lace
inco
rrec
t –[1
]us
e of
phe
nyla
min
e –[
1]
55
5
Tota
lQ
uest
ion
3 To
tal
67
922
5
62
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3Q
uest
ion
Tota
lM
aths
QW
C
4a
ifla
sk c
onta
inin
g w
ater
+ n
itram
ide
[1]
poss
ible
mec
hani
sm fo
r add
ing
the
wat
er/n
itram
ide
[1]
mea
ns o
f col
lect
ing
the
nitro
us o
xide
[1]
poss
ible
wat
er b
ath
for c
onst
ant t
empe
ratu
re [1
]ex
plan
atio
n ho
w th
e ex
perim
ent i
s ca
rrie
d ou
t i.e
. mea
surin
g vo
lum
e pe
r uni
t tim
e [2
]to
a m
axim
um o
f 5 m
arks
55
iite
mpe
ratu
re [1
]1
1iii
e.g.
ther
e ar
e to
o m
any
bubb
les
to c
ount
/not
all
the
bubb
les
are
the
sam
e si
ze [1
]1
1
ivlo
ne p
air o
n th
e ni
troge
n (o
r oxy
gen)
[1]
form
s hy
drog
en b
onds
[1]
22
bi
the
poin
t at 1
500
seco
nds
[1]
the
volu
me
shou
ld b
e 16
.8 c
m3 [
1]1
12
1
ii11
.2/2
4000
= 0
.000
47 =
0.0
005
mol
of N
2O; h
ence
%
deco
mpo
sed
= 0.
0005
/0.0
5 x
100
= 1%
[3]
33
3
iii5
x 10
-6 m
ol d
m-3 s
-1 =
k x
0.5
mol
dm
-3
k =
10-5 [1
] s-1
[1]
22
2c
ist
ep o
ne in
volv
es th
e se
para
tion
of a
pos
itive
cha
rge
from
a
nega
tive
char
ge w
hich
take
s en
ergy
; a n
egat
ive
ion
prod
uced
fro
m a
neg
ativ
e io
n in
volv
es re
puls
ion.
Hen
ce s
tep
one
is ra
te
dete
rmin
ing
[2]
or n
itram
ide
is th
e on
ly re
acta
nt in
the
rate
equ
atio
n
22
iith
e re
activ
e in
term
edia
te is
NO
2NH
- [1]
11
iiith
e re
activ
e in
term
edia
te n
eeds
to b
e fo
rmed
in s
tep
1 [1
]th
en it
nee
ds to
be
used
up
in s
tep
2 [1
]2
2
di
heat
with
sod
ium
hyd
roxi
de s
olut
ion
[1]
test
gas
giv
en o
ff w
ith c
onc
hydr
ochl
oric
aci
d [1
]w
hite
sm
oke
[1]
33
63
Que
stio
nM
ark
Sche
me
AO
1A
O2
AO
3Q
uest
ion
Tota
lM
aths
QW
C
iihe
at w
ith a
lkal
i am
mon
ium
sal
t pro
duce
s am
mon
ia [1
]1
1To
tal
Que
stio
n 4
Tota
l11
1425
6To
tal f
or B
ookl
et B
– 6
0 m
arks
1021
2960
13
Pape
r Tot
als
1323
5490
15
64