Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify...

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Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 4x. Verify by factoring

Transcript of Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify...

Page 1: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Review: 6.5f Mini-Quiz1. Solve: Verify by factoring.

2. Solve by Graphing: y = x2 – 4x. Verify by factoring.

Page 2: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Objective: Students will solve word problems involving quadratic equations.

Page 3: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Solving word problems involving Quadratic Equations

Chapter 6 – Factoring and Solving EquationsSection 5g

Page 4: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Find 2 consecutive positive integers whose product is 240. Let n = the 1st consecutive positive integer.

Write an equation.

n – 15 = 0 or n + 16 = 0

n = {15} MUST BE POSITIVE

CHECK YOUR ANSWER

Then, n + 1 would be the 2nd consecutive positive integer.n(n + 1) = 240

n 2 + n = 240n 2 + n – 240 = 0

Solve the equation.

Factor the equation.

n = {–16, 15}

(n – 15)(n + 16) = 0

Answer: The 2 consecutive positive integers are 15 and 16.

Page 5: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

CHECK n(n + 1) = 240 if n = {15} 15(15 + 1) = 240

15(16) = 240

240 = 240 TRUE

Page 6: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Find 2 consecutive positive odd integers whose product is 323. Let n = the 1st consecutive positive odd integer.

Write an equation.

n – 17 = 0 or n + 19 = 0

n = {–19, 17}

CHECK YOUR ANSWER

Then, n + 2 would be the 2nd consecutive positive odd integer.n(n + 2) = 323n 2 + 2n = 323

n 2 + 2n – 323 = 0

Solve the equation.

Factor the equation.(n – 17)(n + 19) = 0

n = {17} MUST BE POSITIVE Answer: The 2 consecutive positive odd integers are 17 and 19.

Page 7: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

CHECK n(n + 2) = 323 if n = {17}

17(17 + 2) = 323

17(19) = 323

323 = 323 TRUE

Page 8: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Homework

368/53and 55

Page 9: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Lesson Summary: Objective: Students will solve word problems involving quadratic equations.

Page 10: Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify by factoring.

Preview of the next Lesson: Objective: Students will solve real world word problems involving quadratic equations.