5.3 – Solving Quadratic Equations by Factoring. Ex. 1 Solve y = x 2 + 5x + 6 by factoring.
Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify...
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Transcript of Review: 6.5f Mini-Quiz 1. Solve: Verify by factoring. 2. Solve by Graphing: y = x 2 – 4x. Verify...
Review: 6.5f Mini-Quiz1. Solve: Verify by factoring.
2. Solve by Graphing: y = x2 – 4x. Verify by factoring.
Objective: Students will solve word problems involving quadratic equations.
Solving word problems involving Quadratic Equations
Chapter 6 – Factoring and Solving EquationsSection 5g
Find 2 consecutive positive integers whose product is 240. Let n = the 1st consecutive positive integer.
Write an equation.
n – 15 = 0 or n + 16 = 0
n = {15} MUST BE POSITIVE
CHECK YOUR ANSWER
Then, n + 1 would be the 2nd consecutive positive integer.n(n + 1) = 240
n 2 + n = 240n 2 + n – 240 = 0
Solve the equation.
Factor the equation.
n = {–16, 15}
(n – 15)(n + 16) = 0
Answer: The 2 consecutive positive integers are 15 and 16.
CHECK n(n + 1) = 240 if n = {15} 15(15 + 1) = 240
15(16) = 240
240 = 240 TRUE
Find 2 consecutive positive odd integers whose product is 323. Let n = the 1st consecutive positive odd integer.
Write an equation.
n – 17 = 0 or n + 19 = 0
n = {–19, 17}
CHECK YOUR ANSWER
Then, n + 2 would be the 2nd consecutive positive odd integer.n(n + 2) = 323n 2 + 2n = 323
n 2 + 2n – 323 = 0
Solve the equation.
Factor the equation.(n – 17)(n + 19) = 0
n = {17} MUST BE POSITIVE Answer: The 2 consecutive positive odd integers are 17 and 19.
CHECK n(n + 2) = 323 if n = {17}
17(17 + 2) = 323
17(19) = 323
323 = 323 TRUE
Homework
368/53and 55
Lesson Summary: Objective: Students will solve word problems involving quadratic equations.
Preview of the next Lesson: Objective: Students will solve real world word problems involving quadratic equations.