Result mass

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APPENDICES Sample of calculation 1. Determine Kc 2 From the figure 4-1, Kc 2 is equal to slope of the line Kc 2 = 0.0122 Kc = 0.0244 s/L 2. Determine 1 qo From figure 4-1, 1 qo is determined by using y-intercept value. 1 qo = 13.564 3. Determine Rm 1 q o = μR m A ( ΔP ) Rm= 1 q A ( ΔP ) μ 1

description

mass experiment filter process

Transcript of Result mass

APPENDICES

Sample of calculation1. Determine

From the figure 4-1, is equal to slope of the line = 0.0122 = 0.0244 s/L

2. Determine

From figure 4-1, is determined by using y-intercept value.

= 13.564

3. Determine Rm

A = 2.209 m2, = 13.563 , P = 47 psi=324052 pa, = 0.006 Pa.s, Rm = Rm = 1.618 x 109

4.Determine cc is amount of cake over filtrate volumec = c = c = 9.576 x 10-6 kg/m3

5.Determine Specific Cake Resistance ()

A = 2.209 m2, P = 10 psi= 324052 pa, = 0.006 Pa.s, c = 9.576 x 10-6 kg/m3, Kc = 2.44 x 10-5 s/m3 Kc = = 6.715 x 108 m4/kg

RESULTS

Weight fraction of calcium carbonate in slurry : Weight of wet cakeTray 1: 5000 gTray 2: 190 gTray 3: 330 gWeight of dry cakeTray 1: 4000 gTray 2: 152 gTray 3: 264 g

Weight ratio of wet cake to dry cake (): 1.25

Viscosity of filtrate (): 0.006 Pa.s

Density of filtrate (): 0.9976Density of calcium carbonate: 2.93 g/cm3Total active filter area: 47 cm x 470 cmPressure drop (P): 47 psi (324052 pa)Total filtration time: 1060 sTotal volume of filtrate: 85 litre

Filtrate Volume, VTime, t(s)t/V (s/L)

0

58517

1013013

1518412.27

2024512.25

2530112.04

3035911.97

3541711.91

4056014

4561513.67

5066813.36

5572613.2

6078713.12

6584012.92

7089712.81

7595312.71

80100612.58

85106012.47

Volume (Litre)55085Average

Density0.99810.99750.99730.006

Viscosity(pa. s)12x 10-34 x 10-32 x 10-30.9976

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