REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim...

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REPASO PAU MATEMÁTICAS BLOQUE III MURCIA JUNIO 2014

Transcript of REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim...

Page 1: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

REPASO PAU MATEMÁTICAS

BLOQUE III MURCIA JUNIO 2014

Page 2: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 3: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA SEPTIEMBRE 2014

Page 4: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA JUNIO 2013

Page 5: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 6: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 7: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 8: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA SEPTIEMBRE 2013

Page 9: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA JUNIO 2012

Page 10: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 11: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 12: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA SEPTIEMBRE 2012

Page 13: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 14: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA JUNIO 2011

Page 15: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA SEPTIEMBRE 2011

Page 16: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA JUNIO 2010

Page 17: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 18: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 19: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

MURCIA SEPTIEMBRE 2010

Page 20: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 21: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen
Page 22: REPASO BLOQUE III PAU MATEMÁTICAS CURSO 14-15 · 2015-05-25 · lim 11m lim X 11m 11m 212 +4 lim sen x lim I — cos X x lim x x 2 lim I + X O 0-1 X 2+0 1-0 sen O I — cos O sen

 · xo = ItL(x) lim . limx x : limx x lim = lim -IttX lim limx x : lim neN; Iu(x) . lim lim lim lim xnx In (x) : lim Inx .1 ltL(x) . xo = I . lim

 · xo = ItL(x) lim . limx x : limx x lim = lim -IttX lim limx x : lim neN; Iu(x) . lim lim lim lim xnx In (x) : lim Inx .1 ltL(x) . xo = I . lim

hhsmacintyre.weebly.com · 14. lim 2-1.001 cl..qqq x. + 5x 18. lim x-*Ð2x —X- +4 HA - x 2 +3x—10 HA; 15. lim In co 19. lim 13. lim qgqq (tlgqq 17. lim . AP Calculus-Limits ...

hhsmacintyre.weebly.com · 14. lim 2-1.001 cl..qqq x. + 5x 18. lim x-*Ð2x —X- +4 HA - x 2 +3x—10 HA; 15. lim In co 19. lim 13. lim qgqq (tlgqq 17. lim . AP Calculus-Limits ...

274 Chapter 4 Applications of Derivativesshahrabi/welcome/home/...8x 16x 16 16 cos x 1 sin x cos x 1 # œœ œœ 16. lim lim lim lim x0 x0 x0 x0ÄÄ Ä Ä sin x x cos x sin x cos x

274 Chapter 4 Applications of Derivativesshahrabi/welcome/home/...8x 16x 16 16 cos x 1 sin x cos x 1 # œœ œœ 16. lim lim lim lim x0 x0 x0 x0ÄÄ Ä Ä sin x x cos x sin x cos x

hoc360.net · 2018. 7. 27. · 1- 2x B. lim 1-2x c. lim x 1 0 D. lim 1-2x +00 Câu 451: Trong các menh dê sau, mênh dê nào dúng x A. lim B. x lim 2 c. 2x lim X —00 D. 2x—

hoc360.net · 2018. 7. 27. · 1- 2x B. lim 1-2x c. lim x 1 0 D. lim 1-2x +00 Câu 451: Trong các menh dê sau, mênh dê nào dúng x A. lim B. x lim 2 c. 2x lim X —00 D. 2x—

fileMath I — {x I x 1} = [1, 00) B. No intercepts C. No symmetry D. lim — = lim — = lim = 0, so + + X X isaHA. E. f' (x) = < Ofor all x > 1, since x —1 < x -s

fileMath I — {x I x 1} = [1, 00) B. No intercepts C. No symmetry D. lim — = lim — = lim = 0, so + + X X isaHA. E. f' (x) = < Ofor all x > 1, since x —1 < x -s

Scanned by CamScanner - ایران توشه...@clmcruzlqonlgoor x Ha ry x + rx —a aeØ f(x) a lim = +00 'l x +a f(x) = (r lim tanx lim —sin x mn Jut* lim lim tanx lim (C cosx rx

Scanned by CamScanner - ایران توشه...@clmcruzlqonlgoor x Ha ry x + rx —a aeØ f(x) a lim = +00 'l x +a f(x) = (r lim tanx lim —sin x mn Jut* lim lim tanx lim (C cosx rx

TMA4100Matematikk1 - NTNU · 2017. 9. 24. · 3.2.31–34 Evaluerfølgende grenseverdier: i) lim x!1 log x 2 ii) lim x!0+ log x 1 2 iii) lim x!1+ log x 2 iv) lim x!1 log x 2

TMA4100Matematikk1 - NTNU · 2017. 9. 24. · 3.2.31–34 Evaluerfølgende grenseverdier: i) lim x!1 log x 2 ii) lim x!0+ log x 1 2 iii) lim x!1+ log x 2 iv) lim x!1 log x 2

355mites y Continuidad) - La Reina de las Ciencias...continuidad 5.19 k) lim x l) lim 16 Límite . 3x-1 o Calcula a en cada caso: a) lim ( x 2 + x— x b) lim ax) a ñ) x x 2 six

355mites y Continuidad) - La Reina de las Ciencias...continuidad 5.19 k) lim x l) lim 16 Límite . 3x-1 o Calcula a en cada caso: a) lim ( x 2 + x— x b) lim ax) a ñ) x x 2 six

site-694611.mozfiles.comsite-694611.mozfiles.com/files/694611/Proizvodnye_Praktika_.pdfFIPHMEP 13.1. flaúmu npot1360ðnwo y a: 2'XA'X Ay f'(x) 11m Ax lim x) 6 a: OIIPEAEJIEHHE 13.3.

site-694611.mozfiles.comsite-694611.mozfiles.com/files/694611/Proizvodnye_Praktika_.pdfFIPHMEP 13.1. flaúmu npot1360ðnwo y a: 2'XA'X Ay f'(x) 11m Ax lim x) 6 a: OIIPEAEJIEHHE 13.3.

 · 2015-09-23 · +1, x.0 lim sin3x tan2x-----+2,.1 lim cos8 9 p 2 x x-1!!!!!"3# n.* lim 8 1-9n 4 n! "4# x.0 lim log013+ x1 2x!!!!"5#.* lim2x6log0 x+2log1- x7!"6# x.0 lim esin 32

 · 2015-09-23 · +1, x.0 lim sin3x tan2x-----+2,.1 lim cos8 9 p 2 x x-1!!!!!"3# n.* lim 8 1-9n 4 n! "4# x.0 lim log013+ x1 2x!!!!"5#.* lim2x6log0 x+2log1- x7!"6# x.0 lim esin 32

Document1...lim f(x) —Inx) Jim f lim f lim : lim n f (x) (3 lim lim c lim c I-INX-I (I —In x): F (I —Inx): x: Inx f : eddirasa.com

Document1...lim f(x) —Inx) Jim f lim f lim : lim n f (x) (3 lim lim c lim c I-INX-I (I —In x): F (I —Inx): x: Inx f : eddirasa.com

APLIKASI TURUNAN · lim ( ) xc fx o rf f x b x o rf lim ( ) a x f x x o rf ( ) lim f x ax b x o rf lim ( ) x = a asimtot tegak a f o lim f ( x) x a f o lim f ( x) x a ... Mencari

APLIKASI TURUNAN · lim ( ) xc fx o rf f x b x o rf lim ( ) a x f x x o rf ( ) lim f x ax b x o rf lim ( ) x = a asimtot tegak a f o lim f ( x) x a f o lim f ( x) x a ... Mencari

Teachingbd · 09.09.2016 · lim 312 71 + + 2x2 + lim X 6 X — 3x2 lim @ 2e lim @ : I — f(x) cosx lim I < Sin x2e x S x2e lim sin7x — sinx sin6x tan x — sin x lim sine

Teachingbd · 09.09.2016 · lim 312 71 + + 2x2 + lim X 6 X — 3x2 lim @ 2e lim @ : I — f(x) cosx lim I < Sin x2e x S x2e lim sin7x — sinx sin6x tan x — sin x lim sine

GIỚI HẠN CỦA HÀM SỐ Giáo viên: Nguyễn Tiến Đạt file2) Giới hạn của hàm số tại vô cực: Các giới hạn x lim f x , x lim f x , x lim f x L, x lim f

GIỚI HẠN CỦA HÀM SỐ Giáo viên: Nguyễn Tiến Đạt file2) Giới hạn của hàm số tại vô cực: Các giới hạn x lim f x , x lim f x , x lim f x L, x lim f

lim x 1 1. x -1 x 1 lim 2x x 3 2. x -1 x 1 lim 2 x 8 3. x 0

lim x 1 1. x -1 x 1 lim 2x x 3 2. x -1 x 1 lim 2 x 8 3. x 0

moutamadris.ma...limf (x ) — ex 12/27 — lim 2x + D -1#0} -4-00 limf (x ) — — lim 2x + lim 2x — — —00 lim ex = lim2x + lim 2x — lim e lime X = lim2x + lim 2x — lim

moutamadris.ma...limf (x ) — ex 12/27 — lim 2x + D -1#0} -4-00 limf (x ) — — lim 2x + lim 2x — — —00 lim ex = lim2x + lim 2x — lim e lime X = lim2x + lim 2x — lim

³ - GOOL Math A for Economics.pdf · 6 1.5 4 x x lim of §· ¨¸ ©¹ 1.1 4 x x lim o f §· ¨¸ ©¹ 1. 5x x lim of 1. 5x x lim o f. 3 2 x lim of x.12 x lnx x lim e of 2.11 2

³ - GOOL Math A for Economics.pdf · 6 1.5 4 x x lim of §· ¨¸ ©¹ 1.1 4 x x lim o f §· ¨¸ ©¹ 1. 5x x lim of 1. 5x x lim o f. 3 2 x lim of x.12 x lnx x lim e of 2.11 2

Damit sind die Grenzwerte lim f x lim f x lim f x lim f xfma2.math.uni-magdeburg.de/~mathww/wise2012/folien_07... · 2012. 12. 7. · l’Hospital lim x →∞ ln(x) x2 −1 ... einmal

Damit sind die Grenzwerte lim f x lim f x lim f x lim f xfma2.math.uni-magdeburg.de/~mathww/wise2012/folien_07... · 2012. 12. 7. · l’Hospital lim x →∞ ln(x) x2 −1 ... einmal

Web viewf x = lim n→∞ f n x = lim n→∞ nx 1+ n 2 x 2 = lim n→∞ x 1 n 2 + x 2 = x x 2 = x x =sgn x

Web viewf x = lim n→∞ f n x = lim n→∞ nx 1+ n 2 x 2 = lim n→∞ x 1 n 2 + x 2 = x x 2 = x x =sgn x

9alami.info · 1 ﻦﻳرﺎﻤﺗ ﺔﻟﻮﻠﺤﻣ ﻦﻳرﺎﻤﺗ 1ﻦﻳﺮﻤﺗ دﺪﺣ 2 0 0 3 lim ; lim ln ; lim x x x x xx x ee xx → + →+∞ xx→ − − ﻞﺤﻟا

9alami.info · 1 ﻦﻳرﺎﻤﺗ ﺔﻟﻮﻠﺤﻣ ﻦﻳرﺎﻤﺗ 1ﻦﻳﺮﻤﺗ دﺪﺣ 2 0 0 3 lim ; lim ln ; lim x x x x xx x ee xx → + →+∞ xx→ − − ﻞﺤﻟا