Readings for those who have problems with calculus.

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Readings for those who have problems with calculus. Mathematics for economists: Sydsæter, K., P. Hammond, 2008, "Essential Mathematics for Economic Analysis", 3rd ed., Prentice Hall. Fundamental Methods of Mathematical Economics, Kevin Wainwright, Alpha Chiang. Mathematics for Economists, Carl P. Simon, Lawrence E. Blume

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Readings for those who have problems with calculus. Mathematics for economists: Sydsæter , K., P. Hammond, 2008, "Essential Mathematics for Economic Analysis", 3rd ed., Prentice Hall. Fundamental Methods of Mathematical Economics, Kevin Wainwright, Alpha Chiang. - PowerPoint PPT Presentation

Transcript of Readings for those who have problems with calculus.

Page 1: Readings for those who have problems with calculus.

Readings for those who have problems with calculus.

Mathematics for economists: Sydsæter, K., P. Hammond, 2008, "Essential Mathematics for Economic Analysis", 3rd ed., Prentice Hall.

Fundamental Methods of Mathematical Economics, Kevin Wainwright, Alpha Chiang.

Mathematics for Economists, Carl P. Simon, Lawrence E. Blume

Page 2: Readings for those who have problems with calculus.

Derivatives - introduction

• Suppose a car is accelerating from 30mph to 50mph.

• At some point it hits the speed of 40mph, but when?

• Speed = (distance travelled)/(time passed)• How is it possible to define the speed at a

single point of time?

Page 3: Readings for those who have problems with calculus.

Approximations

• Idea: find distance/time for smaller and smaller time intervals.

Here f shows how the distance is changing with the time, x.

The time difference is h while the distance travelled is

f(x+h) – f(x).

Page 4: Readings for those who have problems with calculus.

The derivative

• Our approximation of the speed is

• As h gets smaller, the approximation of the speed gets better.

• When h is infinitesimally small, the calculation of the speed is exact.

• Leibniz used the notation dy/dx for the exact speed.

Page 5: Readings for those who have problems with calculus.

Example

• f(x) = x2

• f(x+h) – f(x) = (x + h)2 – x2

= (x2 + 2xh + h2) - x2 = 2xh + h2

• Speed = (2xh + h2)/h = 2x + h• When h is infinitesimally small, this is just 2x.

Page 6: Readings for those who have problems with calculus.

If the derivative of a function is its slope, then for a constant function, the derivative must be zero.

0dc

dx

example: 3y

0y

The derivative of a constant is zero.

Rules for Differentiation

Page 7: Readings for those who have problems with calculus.

We saw that if , .2y x 2y x

This is part of a pattern.

1n ndx nx

dx

examples:

4f x x

34f x x

8y x

78y x

power rule

Rules for Differentiation

Page 8: Readings for those who have problems with calculus.

1n ndx nx

dx

Rules for Differentiation

Proof:

h

xhxx

dx

d nn

h

n

)(lim

0

h

xhhnxxx

dx

d nnnn

h

n

...lim

1

0

h

hhnxx

dx

d nn

h

n

...lim

1

0

1

0lim

n

h

n nxxdx

d

Page 9: Readings for those who have problems with calculus.

d ducu c

dx dx

examples:

1n ndcx cnx

dx

constant multiple rule:

5 4 47 7 5 35dx x x

dx

Rules for Differentiation

Page 10: Readings for those who have problems with calculus.

(Each term is treated separately)

d ducu c

dx dxconstant multiple rule:

sum and difference rules:

d du dvu v

dx dx dx d du dv

u vdx dx dx

4 12y x x 34 12y x

4 22 2y x x

34 4dy

x xdx

Rules for Differentiation

Page 11: Readings for those who have problems with calculus.

product rule:

d dv duuv u v

dx dx dx Notice that this is not just the

product of two derivatives.

This is sometimes memorized as: d uv u dv v du

2 33 2 5d

x x xdx

2 3x 26 5x 32 5x x 2x

Rules for Differentiation

Page 12: Readings for those who have problems with calculus.

quotient rule:

2

du dvv ud u dx dx

dx v v

or 2

u v du u dvdv v

3

2

2 5

3

d x x

dx x

2 2 3

22

3 6 5 2 5 2

3

x x x x x

x

Rules for Differentiation

Page 13: Readings for those who have problems with calculus.

Formulas you should learn

(Cxa)’=Cax(a-1); C, a – a real number(ex)’=ex

(ax)’=axlna; a>0

0,1

)'(ln xx

x

0,1,0,ln

1)'(log xaa

axxa

Page 14: Readings for those who have problems with calculus.

Derivatives rules - summary

, xgxxgx ff

2

fff

xg

xgxxgx

xg

x

0xg

xcxc ff

,

,,

for

c is a constant

xgxxgxxgx fff

0C ,

Page 15: Readings for those who have problems with calculus.

Consider a simple composite function:6 10y x

2 3 5y x

If 3 5u x

then 2y u

6 10y x 2y u 3 5u x

6dy

dx 2

dy

du 3

du

dx

dy dy du

dx du dx

6 2 3

Chain Rule

Page 16: Readings for those who have problems with calculus.

dy dy du

dx du dx Chain Rule:

example: sinf x x 2 4g x x Find: at 2f g x

cosf x x 2g x x 2 4 4 0g

0 2f g cos 0 2 2 1 4 4

Chain Rule

If is the composite of and , then:f g y f u u g x

at at xu g xf g f g )('))((' xgxgf

Page 17: Readings for those who have problems with calculus.

Differentiation of Multivariate Functions

• The partial derivative of a multivariate function f(x,y) with respect to x is defined as

h

yxfyhxfxyxf

h

,,lim

,0

Page 18: Readings for those who have problems with calculus.

Differentiation of Multivariate Functions

f(x1,x2)= Cx1ax2

b

)(*),( )1(

12

1

21

ab axCxx

xxf

)(*),( )1(

21

2

21

ba bxCxx

xxf