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    Solutions to Practice Problems for Part II1. A fund manager is considering investment in the stock of a health care provider. Themanager's assessment of probabilities for rates of return on this stock over the next yearare summarized in the accompanying table. LetAbe the event "Rate of return will bemore than 10%" and Bthe event "Rate of return will be negative."

    RATE OFRETURN

    Less than - 10% - 10% to 0% 0% to 10% 10% to 20% More than 20%

    PROBABILITY .04 .14 .28 .33 .21

    a. Find the probability of eventA.

    b. Find the probability of event B.

    c. Describe the event that is the complement ofA.

    d. Find the probability of the complement ofA.

    e. Describe the event that is the intersection ofAand B.

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    Managerial Statistics 730 Prof. Juran

    f. Find the probability of the intersection ofAand B.

    g. Describe the event that is the union ofAand B.

    h. Find the probability of the union ofAand B.

    i. AreAand Bmutually exclusive?

    j. AreAand Bcollectively exhaustive?

    2. A manager has available a pool of eight employees who could be assigned to aproject-monitoring task. Four of the employees are women and four are men. Two ofthe men are brothers. The manager is to make the assignment at random, so that each ofthe eight employees is equally likely to be chosen. LetAbe the event "chosen employeeis a man" and Bthe event "chosen employee is one of the brothers."

    a. Find the probability ofA.

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    Managerial Statistics 731 Prof. Juran

    Find the probability of B.b. Find the probability of the intersection ofAand B.c. Find the probability of the union ofAand B.

    3. A department store manager has monitored the numbers of complaints received perweek about poor service. The probabilities for numbers of complaints in a week,established by this review, are shown in the table. Let A be the event "There will be atleast one complaint in a week," and B the event "There will be less than 10 complaints ina week."

    NUMBER OFCOMPLAINTS

    0 1-3 4-6 7-9 10-12 More than12

    PROBABILITY .14 .39 .23 .15 .06 .03

    a. Find the probability ofA.

    b. Find the probability of B.

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    Managerial Statistics 732 Prof. Juran

    c. Find the probability of the complement ofA.

    d. Find the probability of the union ofAand B.

    e. Find the probability of the intersection ofAand B.

    f. AreAand Bmutually exclusive?

    g. AreA and Bcollectively exhaustive?

    4. A local public-action group solicits donations by telephone. For a particular list ofprospects, it was estimated that for any individual, the probability was .05 of animmediate donation by credit card, .25 of no immediate donation but a request forfurther information through the mail, and .7 of no expression of interest. Mailedinformation is sent to all people requesting it, and it is estimated that 20% of thesepeople will eventually donate. An operator makes a sequence of calls, the outcomes ofwhich can be assumed to be independent.

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    Managerial Statistics 733 Prof. Juran

    a. What is the probability that no immediate credit card donation will be receiveduntil at least four unsuccessful calls have been made?

    b. What is the probability that the first call leading to any donation (either

    immediately or eventually after a mailing) is preceded by at least four unsuccessfulcalls?

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    Managerial Statistics 734 Prof. Juran

    5. A mail-order firm considers three possible foul-ups in filling an order:

    A: The wrong item is sent.B: The item is lost in transit.C: The item is damaged in transit.

    Assume that eventAis independent of both Band Cand that events Band Caremutually exclusive. The individual event probabilities are P(A) = .02, P(B) = .01, andP(C) = .04. Find the probability that at least one of these foul-ups occurs for a randomlychosen order.

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    Managerial Statistics 735 Prof. Juran

    6. Market research in a particular city indicated that during a week 18% of all adultswatch a television program oriented to business and financial issues, 12% read apublication oriented to these issues, and 10% do both.

    a. What is the probability that an adult in this city, who watches a television programoriented to business and financial issues, reads a publication oriented to theseissues?

    b. What is the probability that an adult in this city, who reads a publication orientedto business and financial issues, watches a television program oriented to theseissues?

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    Managerial Statistics 736 Prof. Juran

    7. An inspector examines items coming from an assembly line. A review of her recordreveals that she accepts only 8% of all defective items. It was also found that 1% of allitems from the assembly line are both defective and accepted by the inspector. What isthe probability that a randomly chosen item from this assembly line is defective?

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    Managerial Statistics 737 Prof. Juran

    8. A bank classifies borrowers as high-risk or low-risk. Only 15% of its loans are madeto those in the high-risk category. Of all its loans, 5% are in default, and 40% of those indefault are to high-risk borrowers. What is the probability that a high-risk borrower willdefault?

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    Managerial Statistics 738 Prof. Juran

    9. A quality control manager found that 30% of worker-related problems occurred onMondays, and that 20% occurred in the last hour of a day's shift. It was also found that4% of worker-related problems occurred in the last hour of Monday's shift.

    a. What is the probability that a worker-related problem that occurs on a Mondaydoes not occur in the last hour of the day's shift?

    b. Are the events "Problem occurs on Monday" and "Problem occurs in the last hourof the day's shift" statistically independent?

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    Managerial Statistics 740 Prof. Juran

    11. A survey carried out for a supermarket classified customers according to whethertheir visits to the store are frequent or infrequent and to whether they often, sometimes,or never purchase generic products. The accompanying table gives the proportions ofpeople surveyed in each of the six joint classifications.

    Frequency of Visit Purchase of Generic ProductsOFTEN SOMETIMES NEVERFrequent .12 .48 .19Infrequent .07 .06 .08

    a. What is the probability that a customer is both a frequent shopper and oftenpurchases generic products?

    b. What is the probability that a customer who never buys generic products visits thestore frequently?

    c. Are the events "Never buys generic products" and "Visits the store frequently"

    independent?

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    Managerial Statistics 741 Prof. Juran

    d. What is the probability that a customer who infrequently visits the store often buysgeneric products?

    e. Are the events "Often buys generic products" and "Visits the store infrequently"independent?

    f. What is the probability that a customer frequently visits the store?g. What is the probability that a customer never buys generic products?

    h. What is the probability that a customer either frequently visits the store or neverbuys generic products, or both?

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    Managerial Statistics 742 Prof. Juran

    12. An analyst attempting to predict a corporation's earnings next year believes that thecorporation's business is quite sensitive to the level of interest rates. She believes that ifaverage rates in the next year are more than 1% higher than this year, the probability ofsignificant earnings growth is 0.1. If average rates next year are more than 1% lowerthan this year, the probability of significant earnings growth is estimated to be 0.8.

    Finally, if average interest rates next year are within 1% of this year's rates, theprobability for significant earnings growth is put at 0.5. The analyst estimates that theprobability is 0.25 that rates next year will be more than 1% higher than this year, and0.15 that they will be more than 1% lower than this year.

    a. What is the estimated probability that both interest rates will be more than 1%higher and significant earnings growth will result?

    b. What is the probability this corporation will experience significant earningsgrowth?

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    Managerial Statistics 743 Prof. Juran

    c. If the corporation exhibits significant earnings growth, what is the probability thatinterest rates will have been more than 1% lower than in the current year?

    13. A manufacturer produces boxes of candy, each containing ten pieces. Two machines

    are used for this purpose. After a large batch has been produced, it is discovered thatone of the machines, which produces 40% of the total output, has a fault that has led tothe introduction of an impurity into 10% of the pieces of candy it makes. From a singlebox of candy, one piece is selected at random and tested. If that piece contains noimpurity, what is the probability that the box from which it came was produced by thefaulty machine?

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    Managerial Statistics 744 Prof. Juran

    Heres how to do it with a 2x2 box:

    Faulty Machine Not Faulty Machine

    Impurity 0.04 0.00 0.04

    No Impurity 0.36 0.60 0.96

    0.40 0.60

    1. Get the 0.40 and 0.60 at the bottom of the two columns.

    2. Put a zero for FIP because the non-faulty machine produces no impurities.3. That means FIP has to be 0.60 (so the right column will add up).4. 10% of the output from the faulty machine has impurities, so FIP must be

    0.04.

    5. That means FIP has to be 0.36 (so the left column will add up).6. The bottom row adds across to a total of 0.96.

    7. The question is, if we are in the bottom row (no impurity), what is the chance we

    are in the left column (faulty machine)?

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    Managerial Statistics 745 Prof. Juran

    14. A student feels that 70% of his college courses have been enjoyable and theremainder have been boring. He has access to student evaluations of professors andfinds that 60% of his enjoyable courses and 25% of his boring courses have been taughtby professors who had previously received strong positive evaluations from theirstudents. Next semester the student decides to take three courses, all from professors

    who have received strongly positive student evaluations. Assume that his reactions tothe three courses are independent of one another.

    a. What is the probability that he will find all three courses enjoyable?

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    Managerial Statistics 746 Prof. Juran

    Note that the number of courses the student finds enjoyable (call this number X) is abinomially distributed random variable, with n= 3 andp= 0.8485.

    b. What is the probability that he will find at least one of the courses enjoyable?

    15. In a large corporation, 80% of the employees are men and 20% are women. Thehighest levels of education obtained by the employees are graduate training for 10% ofthe men, undergraduate training for 30% of the men, and high school training for 60%of the men. The highest levels of education obtained are also graduate training for 15%of the women, undergraduate training for 40% of the women, and high school trainingfor 45% of the women.

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    Managerial Statistics 747 Prof. Juran

    a. What is the probability that a randomly chosen employee will be a man with only ahigh school education?

    b. What is the probability that a randomly chosen employee will have graduatetraining?

    c. What is the probability that a randomly chosen employee who has graduatetraining is a man?

    d. Are sex and level of education of employees in this corporation statisticallyindependent?

    e. What is the probability that a randomly chosen employee who has not hadgraduate training is a woman?

    16. A large corporation organized a ballot for all its workers on a new bonus plan. It

    was found that 65% of all night-shift workers favored the plan and that 40% of allwomen workers favored the plan. Also, 50% of all employees are night-shift workers,and 30% of all employees are women. Finally, 20% of the night-shift workers arewomen.

    Let us define the following events:Event Definition Probability

    F Employee is Female 0.30

    B Employee Favors Bonus Plan

    N Employee Works the Night Shift 0.50

    NB 0.65

    FB 0.40NF 0.20

    a. What is the probability that a randomly chosen employee is a woman in favor ofthe plan?

    b. What is the probability that a randomly chosen employee is either a woman or anight-shift worker (or both)?

    c. Is employee sex independent of whether the night-shift is worked?

    d. What is the probability that a woman employee is a night-shift worker?

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    Managerial Statistics 748 Prof. Juran

    e. If 50% of all male employees favor the plan, what is the probability that a randomlychosen employee both does not work the night-shift and does not favor the plan?

    17. Subscriptions toAmerican History Illustratedare classified as gift, previous renewal,

    direct mail, or subscription service. In January 1979, 8% of expiring subscriptions weregift; 41%, previous renewal; 6%, direct mail; and 45% subscription service. Thepercentages of renewals in these four categories were 81%, 79%, 60%, and 21%,respectively. In February 1979, 10% of expiring subscriptions were gift; 57%, previousrenewal; 24%, direct mail; and 9% subscription service. The percentages of renewalswere 80%, 76%, 51%, and 14%, respectively.

    a. Find the probability that a randomly chosen subscription expiring in January 1979was renewed.

    b. Find the probability that a randomly chosen subscription expiring in February 1979

    was renewed.

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    Managerial Statistics 749 Prof. Juran

    c. Verify that the probability in part (b) is higher than that in part (a). Do you believethat the editors ofAmerican History Illustratedshould view the change from Januaryto February as a positive or negative development?

    This is not a positive development, even though the probability of a renewal increased.The increase is due to a change in the mix of expiring subscriptions. A larger share ofgift and previous renewal subscriptions expired; these types of subscriptions have ahigher probability of being renewed than direct mail or subscription service. Note that,for each category, the probability of a renewal went down from January to February.

    18. The accompanying table shows, for 1,000 forecasts of earnings per share made byfinancial analysts, the numbers of forecasts and outcomes in particular categories(compared with the previous year).

    Outcome ForecastImprovement About the Same Worse

    Improvement 210 82 66About the Same 106 153 75Worse 75 84 149

    a. Find the probability that if the forecast is for a worse performance in earnings, thisoutcome will result.

    b. If the forecast is for an improvement in earnings, find the probability that thisoutcome fails to result.

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    Managerial Statistics 750 Prof. Juran

    19. A corporation produces packages of paper clips. The number of clips per packagevaries, as indicated in the accompanying table.

    NUMBER OF CLIPS 47 48 49 50 51 52 53PROPORTION OF PACKAGES .04 .13 .21 .29 .20 .10 .03

    a. Draw the probability function.

    b. Calculate and draw the cumulative probability function.

    0.000

    0.050

    0.100

    0.150

    0.200

    0.250

    0.300

    0.350

    47 48 49 50 51 52 53

    Proportion

    Number of Clips per Box

    Probability Function

    0.000

    0.100

    0.200

    0.300

    0.400

    0.500

    0.600

    0.700

    0.800

    0.900

    1.000

    47 48 49 50 51 52 53

    Cum.

    Probability

    Number of Clips per Box

    Cumulative Probability Function

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    Managerial Statistics 751 Prof. Juran

    c. What is the probability that a randomly chosen package will contain between 49and 51 clips (inclusive)?

    d. Two packages are chosen at random. What is the probability that at least one ofthem contains at least fifty clips?

    20. Refer to the information in Exercise 19.

    a. Find the mean and standard deviation of the number of paper clips per package.

    Lets use Excel:

    1

    2

    3

    4

    5

    6

    7

    8

    910

    11

    12

    13

    14

    15

    16

    17

    18

    19

    20

    21

    22

    23

    A B C D E F G H I

    Calculations for Expected Value

    NUMBER OF CLIPS PROPORTION OF PACKAGES

    47 0.04 1.88

    48 0.13 6.24

    49 0.21 10.29

    50 0.29 14.5

    51 0.2 10.2

    52 0.1 5.2

    53 0.03 1.5949.9 Expected Value

    Calculations for Variance Error Error^2 Prob. D*E

    47 49.9 -2.9 8.41 0.04 0.3364

    48 49.9 -1.9 3.61 0.13 0.4693

    49 49.9 -0.9 0.81 0.21 0.1701

    50 49.9 0.1 0.01 0.29 0.0029

    51 49.9 1.1 1.21 0.2 0.242

    52 49.9 2.1 4.41 0.1 0.441

    53 49.9 3.1 9.61 0.03 0.2883

    1.95 Variance

    1.396424 Std. Dev.

    =A3*B3

    =C15*C15

    =E17*D17

    =SUM(F14:F20)

    =SQRT(F21)

    =SUM(C3:C9)

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    Managerial Statistics 752 Prof. Juran

    b. The cost (in cents) of producing a package of clips is 16 + 2X, where Xis thenumber of clips in the package. The revenue from selling the package, howevermany clips it contains, is $1.50. If profit is defined as the difference betweenrevenue and cost, find the mean and standard deviation of profit per package.

    Recall the Linear Transformation Rule: If Xis a random variable, and Yis a randomvariable such that in all cases Y= aX+ b(for any numbers aand b). Then,

    Expected Value E(Y) = aE(X) + b,Variance Var(Y) = a2Var(X),

    Standard Deviation (Y) = |a|(X).

    In this case,

    Profit 160501clipsof#020 ..$.$

    ofitPrE 341020 .clipsE.

    341949020 ...

    3420.

    profit 39641020 ..

    02790.

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    Managerial Statistics 753 Prof. Juran

    21. A college basketball player, who sinks 75% of his free throws, comes to the line toshoot a "one and one" (if the first shot is successful, he is allowed a second shot, but nosecond shot is taken if the first is missed; one point is scored for each successful shot).Assume that the outcome of the second shot, if any, is independent of that of the first.Find the expected number of points resulting from the "one and one." Compare this

    with the expected number of points from a "two-shot foul," where a second shot isallowed irrespective of the outcome of the first.

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    Managerial Statistics 754 Prof. Juran

    22. A store owner stocks an out-of-town newspaper, which is sometimes requested by asmall number of customers. Each copy of this newspaper costs him 70 cents, and hesells them for 90 cents each. Any copies left over at the end of the day have no valueand are destroyed. Any requests for copies that cannot be met because stocks have beenexhausted are considered by the store owner as a loss of 5 cents in goodwill. The

    probability distribution of the number of requests for the newspaper in a day is shownin the accompanying table. If the store owner defines total daily profit as total revenuefrom newspaper sales, less total cost of newspapers ordered, less goodwill loss fromunsatisfied demand, how many copies per day should he order to maximize expectedprofit?

    NUMBER OF REQUESTS 0 1 2 3 4 5PROBABILITY .12 .16 .18 .32 .14 .08

    23. An investor is considering three strategies for a $1,000 investment. The probable

    returns are estimated as follows:

    Strategy 1: A profit of $10,000 with probability 0.15 and a loss of $1,000 with probability0.85.

    Strategy 2: A profit of $1,000 with probability 0.50, a profit of $500 with probability 0.30,and a loss of $500 with probability 0.20.

    Strategy 3: A certain profit of $400.

    Which strategy has the highest expected profit? Would you necessarily advise the investorto adopt this strategy?

    24. The accompanying table shows, for credit card holders with one to three cards, thejoint probabilities for number of cards owned (X) and number of credit purchases madein a week (Y).

    Number of Cards (X) Number of Purchases in Week (Y)0 1 2 3 4

    1 0.08 0.13 0.09 0.06 0.032 0.03 0.08 0.08 0.09 0.073 0.01 0.03 0.06 0.08 0.08

    a. For a randomly chosen person from this group, what is the probability function fornumber of purchases made in the week?

    b. For a person in this group who has three cards, what is the probability function fornumber of purchases made in the week?

    c. Are the number of cards owned and number of purchases made statisticallyindependent?

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    Managerial Statistics 755 Prof. Juran

    25. A market researcher wants to determine whether a new model of a personalcomputer, which had been advertised on a late-night talk show, had achieved morebrand name recognition among people who watched the show regularly than amongpeople who did not. After conducting a survey, it was found that 15% of all people bothwatched the show regularly and could correctly identify the product. Also, 16% of all

    people regularly watched the show and 45% of all people could correctly identify theproduct. Define a pair of random variables as follows:

    X

    otherwise

    showthewatchregularlyif

    0

    1

    Y

    otherwise

    identifiedcorrectlyproductif

    0

    1

    a. Find the joint probability function of Xand Y

    b. Find the conditional probability function of Y, given X= 1.

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    Managerial Statistics 756 Prof. Juran

    26. A production manager knows that 5% of components produced by a particularmanufacturing process have some defect. Six of these components, whosecharacteristics can be assumed to be independent of each other, were examined.

    a. What is the probability that none of these components has a defect?

    b. What is the probability that one of these components has a defect?c. What is the probability that at least two of these components have a defect?

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    Managerial Statistics 757 Prof. Juran

    27. Suppose that the probability is .5 that the value of the U.S. dollar will rise against theJapanese yen over any given week, and that the outcome in one week is independent ofthat in any other week. What is the probability that the value of the U.S. dollar will riseagainst the Japanese yen in a majority of weeks over a period of 7 weeks?

    28. A company installs new central heating furnaces, and has found that for 15% of allinstallations a return visit is needed to make some modifications. Six installations weremade in a particular week. Assume independence of outcomes for these installations.

    a. What is the probability that a return visit was needed in all of these cases?

    b. What is the probability that a return visit was needed in none of these cases?

    c. What is the probability that a return visit was needed in more than one of thesecases?

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    Managerial Statistics 758 Prof. Juran

    29. A small commuter airline flies planes that can seat up to eight passengers. Theairline has determined that the probability that a ticketed passenger will not show upfor a flight is 0.2. For each flight, the airline sells tickets to the first ten people placingorders. The probability distribution for the number of tickets sold per flight is shown inthe accompanying table. For what proportion of the airline's flights does the number of

    ticketed passengers showing up exceed the number of available seats? (Assumeindependence between number of tickets sold and the probability that a ticketedpassenger will show up.)

    NUMBER OF TICKETS 6 7 8 9 10PROBABILITY 0.25 0.35 0.25 0.10 .05

    30. An automobile dealer mounts a new promotional campaign, in which it is promisedthat purchasers of new automobiles may, if dissatisfied for any reason, return themwithin two days of purchase and receive a full refund. It is estimated that the cost to the

    dealer of such a refund is $250. The dealer estimates that 15% of all purchasers willindeed return automobiles and obtain refunds. Suppose that fifty automobiles arepurchased during the campaign period.

    a. Find the mean and standard deviation of the number of these automobiles that willbe returned for refunds.

    b. Find the mean and standard deviation of the total refund costs that will accrue as aresult of these fifty purchases.

    31. A company receives a very large shipment of components. A random sample ofsixteen of these components is checked, and the shipment is accepted if fewer than twoof these components are defective. What is the probability of accepting a shipmentcontaining:

    a. 5% defectives?

    Note that we accept a shipment if it has either zero or one defective components. Theprobability of accepting with 5% defective is:

    b. 15% defectives?

    c. 25% defectives?

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    Managerial Statistics 759 Prof. Juran

    32. In the past several years, credit card companies have made an aggressive effort tosolicit new accounts from college students. Suppose that a sample of 200 students atyour college indicated the following information as to whether the student possessed abank credit card and/or a travel and entertainment credit card:

    Travel and EntertainmentCredit Card

    Bank Credit Card Yes NoYes 60 60No 15 65

    (a) Give an example of a simple event.

    (b) Give an example of a joint event.

    (c) What is the complement of having a bank credit card?

    (d) Why is "having a bank credit card and having a travel and entertainment creditcard" a joint event?

    Here is a probability table, for answering the rest of the questions:

    T T

    B 0.300 0.300 0.600

    B 0.075 0.325 0.400

    0.375 0.625

    If a student is selected at random, what is the probability that

    (e) the student has a bank credit card?

    (f) the student has a travel and entertainment credit card?

    (g) the student has a bank credit card and a travel and entertainment card?

    (h) the student has neither a bank credit card nor a travel and entertainment card?

    (i) the student has a bank credit card or has a travel and entertainment card?

    (j) the student does not have a bank credit card or has a travel and entertainmentcard?

    33. A company has made available to its employees (without charge) extensive healthclub facilities that may be used before work, during the lunch hour, after work, and onweekends. Records for the last year indicate that of 250 employees, 110 used thefacilities at some time. Of 170 males employed by the company, 65 used the facilities.

    (a) Set up a 2 x 2 table to evaluate the probabilities of using the facilities.

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    Managerial Statistics 760 Prof. Juran

    (b) Give an example of a simple event.

    (c) Give an example of a joint event.

    (d) What is the complement of "used the health club facilities"?

    Here is a probability table for answering the rest of the questions:

    M M

    U 65/250 = 0.260 45/250 = 0.180 110/250 = 0.440

    U 105/250 = 0.420 35/250 = 0.140 140/250 = 0.560

    170/250 = 0.680 80/250 = 0.320 1.000

    What is the probability that an employee chosen at random

    (e) is a male?

    (f)

    has used the health club facilities?(g) is a female and has used the health club facilities?

    (h) is a female and has not used the health club facilities?

    (i) is a female or has used the health club facilities?

    (j) is a male or has not used the health club facilities?

    (k) has used the health club facilities or has not used the health club facilities?

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    Managerial Statistics 761 Prof. Juran

    34. Each year, ratings are compiled concerning the performance of new cars during thefirst 90 days of use. Suppose that the cars have been categorized according to twoattributes, whether or not the car needs warranty-related repair (yes or no) and thecountry in which the company manufacturing the car is based (United States, notUnited States). Based on the data collected, the probability that the new car needs a

    warranty repair is .04, the probability that the car is manufactured by an American-based company is .60, and the probability that the new car needs a warranty repair andwas manufactured by an American-based company is .025.

    (a) Set up a 2 x 2 table to evaluate the probabilities of a warranty-related repair.

    (b) Give an example of a simple event.

    (c) Give an example of a joint event.

    (d) What is the complement of "manufactured by an American-based company"?

    What is the probability that a new car selected at random

    (e) needs a warranty-related repair?

    (f) is not manufactured by an American-based company?

    (g) needs a warranty repair and is manufactured by a company based in the UnitedStates?

    (h) does not need a warranty repair and is not manufactured by a company based inthe United States?

    (i) needs a warranty repair or was manufactured by an American-based company?

    (j) needs a warranty repair or was not manufactured by an American-based

    company?

    (k) needs a warranty repair or does not need a warranty repair?

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    Managerial Statistics 762 Prof. Juran

    35. Recall the following data from a sample of 200 students in Problem 32 above.

    Travel and EntertainmentCredit Card

    Bank Credit Card Yes No

    Yes 60 60No 15 65

    (a) Assume we know that the student has a bank credit card. What is theprobability, then, that he or she has a travel and entertainment card?

    (b) Assume that we know that the student does not have a travel and entertainmentcard. What, then, is the probability that he or she has a bank credit card?

    (c) Are the two events, having a bank credit card and having a travel andentertainment card, statistically independent? Explain.

    36. Use the data from Problem 33 above (in which a company has made health clubfacilities available to its employees) to answer the following:

    (a) Suppose that we select a female employee of the company. What, then, is theprobability that she has used the health club facilities?

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    (b) Suppose that we select a male employee of the company. What, then, is theprobability that he has not used the health club facilities?

    (c) Are the gender of the individual and the use of the health club facilitiesstatistically independent? Explain.

    37. Use the new car performance ratings data from Problem 34 above to answer thefollowing:

    (a) Suppose we know that the car was manufactured by a company based in theUnited States. What. then, is the probability that the car needs a warranty repair?

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    (b) Suppose we know that the car was not manufactured by a company based in theUnited States. What, then, is the probability that the car needs a warranty repair?

    (c) Are need for a warranty repair and location of the company manufacturing thecar statistically independent?

    38. A standard deck of cards is being used to play a game. There are four suits (hearts,diamonds, clubs, and spades), each having 13 faces (ace. 2, 3, 4, 5, 6, 7, 8, 9, 10, jack,queen, and king), making a total of 52 cards. This complete deck is thoroughly mixed,and you will receive the first two cards from the deck without replacement.

    (a) What is the probability that both cards are queens?

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    (b) What is the probability that the first card is a 10 and the second card is a 5 or 6?

    On the first card, you have four chances to get a 10 out of 52 cards. On the second card(assuming you get a 10 on the first card) there are eight remaining chances to get a 5 or6 out of 51 cards.

    (c) If we were sampling with replacement, what would be the answer in (a)?(d) In the game of Blackjack, the picture cards (jack, queen, king) count as 10 points

    and the ace counts as either 1 or 11 points. All other cards are counted at theirface value. Blackjack is achieved if your two cards total 21 points. What is theprobability of getting blackjack with two cards?

    39. Suppose that the probability that a person has a certain disease is 0.03. Medicaldiagnostic tests are available to determine whether the person actually has the disease.If the disease is actually present, the probability that the medical diagnostic test willgive a positive result (indicating that the disease is present) is 0.90. If the disease is notactually present, the probability of a positive test result (indicating that the disease ispresent) is 0.02. Given this information, we would like to know the following:

    (a) If the medical diagnostic test yields a positive result (indicating that the disease ispresent), what is the probability that the disease is actually present?

    Events Symbol Probability GivenDisease D 0.03No Disease D Test Positive T Test Not Positive T Test Positive, Given Disease DT 0.90

    Test Positive, Given No Disease DT 0.02

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    Probability Table:

    D D

    T 0.0270 0.0194 0.0464

    T 0.0030 0.9506 0.9536

    0.0300 0.9700Note: Here is how these probabilities can be calculated in an Excel spreadsheet:

    The question for Part (a) is "If the medical diagnostic test yields a positive result, what isthe probability that the disease is actually present?" In other words, what is theprobability of D givenT?

    TDP

    TP

    TDP

    04640

    0270

    .

    .

    5820.

    (b) If the medical diagnostic test has given a negative result (indicating the disease isnot present), what is the probability that the disease is not present?

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    A B C D E F G

    Events Probability Given

    Disease 0.030

    Test Positive, Given Disease 0.900

    Test Positive, Given No Disease 0.020

    D Not D

    T 0.0270 0.0194 0.0464

    Not T 0.0030 0.9506 0.9536

    0.0300 0.9700

    =C11*B3

    =C11-C9

    =B2

    =D11*B4

    =D11-D9

    =1-C11

    =SUM(C9:D9)

    =1-E9

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    40. The Olive Construction Company is determining whether it should submit a bid fora new shopping center. In the past, Olive's main competitor, Base ConstructionCompany, has submitted bids 70% of the time. If Base Construction Company does notbid on a job, the probability that the Olive Construction Company will get the job is .50.If Base Construction Company does bid on a job, the probability that the Olive

    Construction Company will get the job is .25.

    (a) If the Olive Construction Company gets the job, what is the probability that theBase Construction Company did not bid?

    Probability Table:

    (b) What is the probability that the Olive Construction Company will get the job?

    41. A municipal bond service has three rating categories (A, B, and C). Suppose that inthe past year, of the municipal bonds issued throughout the United States, 70% wererated A, 20% were rated B, and 10% were rated C. Of the municipal bonds rated A, 50%were issued by cities, 40% by suburbs, and 10% by rural areas. Of the municipal bondsrated B, 60% were issued by cities, 20% by suburbs, and 20% by rural areas. Of themunicipal bonds rated C, 90% were issued by cities, 5% by suburbs, and 5% by ruralareas.

    (a) If a new municipal bond is to be issued by a city, what is the probability it willreceive an A rating?

    (b) What proportion of municipal bonds are issued by cities?

    (c) What proportion of municipal bonds are issued by suburbs?

    42. Using the company records for the past 500 working days, the manager of TorrisiMotors, a suburban automobile dealership, has summarized the number of cars soldper day into the following table:

    Number of Cars FrequencySold per Day of Occurrence

    0 401 1002 1423 664 365 306 267 208 169 1410 811 2

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    Total 500

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    (a) Form the empirical probability distribution (i.e., relative frequency distribution)for the discrete random variable X, the number of cars sold per day.

    Here's how to set this up in Excel:

    (b) Compute the mean or expected number of cars sold per day.

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    Number of Cars FrequencySold per Day of Occurrence

    0 40 0.080

    1 100 0.200

    2 142 0.284

    3 66 0.132

    4 36 0.072

    5 30 0.060

    6 26 0.052

    7 20 0.040

    8 16 0.032

    9 14 0.028

    10 8 0.01611 2 0.004

    Total 500 1.000

    =B3/$B$15

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    Number of Cars Frequency

    Sold per Day of Occurrence

    0 40 0.080 0.000

    1 100 0.200 0.200

    2 142 0.284 0.568

    3 66 0.132 0.396

    4 36 0.072 0.2885 30 0.060 0.300

    6 26 0.052 0.312

    7 20 0.040 0.280

    8 16 0.032 0.256

    9 14 0.028 0.252

    10 8 0.016 0.160

    11 2 0.004 0.044

    Total 500 1.000 3.056

    =A3*C3

    =SUM(D3:D14)

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    (c) Compute the standard deviation.

    (d) What is the probability that on any given day

    (i) fewer than four cars will be sold?

    (ii) at most four cars will be sold?

    (iii) at least four cars will be sold?

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    A B C D E F G H I

    Number of Cars Frequency Weighted Weighted

    Sold per Day of Occurrence Prob. Prob. Error Error 2 by Prob.

    0 40 0.080 0.000 -3.056 9.339 0.747

    1 100 0.200 0.200 -2.056 4.227 0.845

    2 142 0.284 0.568 -1.056 1.115 0.3173 66 0.132 0.396 -0.056 0.003 0.000

    4 36 0.072 0.288 0.944 0.891 0.064

    5 30 0.060 0.300 1.944 3.779 0.227

    6 26 0.052 0.312 2.944 8.667 0.451

    7 20 0.040 0.280 3.944 15.555 0.622

    8 16 0.032 0.256 4.944 24.443 0.782

    9 14 0.028 0.252 5.944 35.331 0.989

    10 8 0.016 0.160 6.944 48.219 0.772

    11 2 0.004 0.044 7.944 63.107 0.252

    Total 500 1.000 3.056 Variance 6.069

    Std. Dev. 2.464

    =A3-$D$15 =E3^2

    =F3*C3

    =SUM(G3:G14)

    =SQRT(G15)

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    Alternatively,

    4XP 41 XP

    69601 . (from Part d(i) above)

    3040.

    (iv) exactly four cars will be sold?

    (v) more than four cars will be sold?

    43. In the carnival game Under-or-over-Seven, a pair of fair dice are rolled once, and theresulting sum determines whether or not the player wins or loses his or her bet. Forexample, the player can bet $1.00 that the sum will be under 7 that is, 2, 3, 4, 5, or 6.For such a bet the player will lose $1.00 if the outcome equals or exceeds 7 or will win

    $1.00 if the result is under 7. Similarly, the player can bet $1.00 that the sum will be over7 that is, 8, 9, 10, II, or 12. Here the player wins $1.00 if the result is over 7 but loses$l.00 if the result is 7 or under. A third method of play is to bet $1.00 on the outcome 7.For this bet the player will win $4.00 if the result of the roll is 7 and lose $1.00 otherwise.

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    (a) Form the probability distribution function representing the different outcomesthat are possible for a $1.00 bet on being under 7.

    Here's a way to set this up in Excel:

    So, for a bet on "Under 7", here are the possibilities:

    Outcome Payoff ProbabilityWin $1 0.417Lose -$1 0.583

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    A B C D E F G H I

    Results

    1st Die 2nd Die Sum Bet Under 7 Bet Over 7 Bet = 7

    1 1 2 Win Lose Lose

    1 2 3 Win Lose Lose

    1 3 4 Win Lose Lose

    1 4 5 Win Lose Lose

    1 5 6 Win Lose Lose

    1 6 7 Lose Lose Win

    2 1 3 Win Lose Lose

    2 2 4 Win Lose Lose

    2 3 5 Win Lose Lose

    2 4 6 Win Lose Lose

    2 5 7 Lose Lose Win

    2 6 8 Lose Win Lose

    3 1 4 Win Lose Lose

    3 2 5 Win Lose Lose

    3 3 6 Win Lose Lose

    3 4 7 Lose Lose Win

    3 5 8 Lose Win Lose

    3 6 9 Lose Win Lose

    4 1 5 Win Lose Lose

    4 2 6 Win Lose Lose

    4 3 7 Lose Lose Win

    4 4 8 Lose Win Lose

    4 5 9 Lose Win Lose

    4 6 10 Lose Win Lose

    5 1 6 Win Lose Lose

    5 2 7 Lose Lose Win5 3 8 Lose Win Lose

    5 4 9 Lose Win Lose

    5 5 10 Lose Win Lose

    5 6 11 Lose Win Lose

    6 1 7 Lose Lose Win

    6 2 8 Lose Win Lose

    6 3 9 Lose Win Lose

    6 4 10 Lose Win Lose

    6 5 11 Lose Win Lose

    6 6 12 Lose Win Lose

    Number of Winning Outcomes 15 15 6

    Probability of Winning 0.417 0.417 0.167

    =IF(C38=7,"Win","Lose")

    =COUNTIF(F3:F38,"Win")

    =F39/36

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    (b) Form the probability distribution function representing the different outcomesthat are possible for a $1.00 bet on being over 7.

    Same deal:

    Outcome Payoff Probability

    Win $1 0.417Lose -$1 0.583

    (c) Form the probability distribution function representing the different outcomesthat are possible for a $1.00 bet on 7.

    Outcome Payoff ProbabilityWin $4 0.167Lose -$1 0.833

    (d) Show that the expected long-run profit (or loss) to the player is the same nomatter which method of play is used.

    Bet Expected Value Calculation

    Under 7 XE 5830141701 .*.* 1670.$ Over 7 XE 5830141701 .*.* 1670.$ = 7 XE 8330116704 .*.* 1670.$

    44. Suppose that warranty records show the probability that a new car needs a warrantyrepair in the first 90 days is 0.05. If a sample of three new cars is selected,

    (a) what is the probability that

    (i) none needs a warranty repair?

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    (ii) at least one needs a warranty repair?

    (iii) more than one needs a warranty repair?

    Here's how to do the previous questions in Excel:

    (b) What assumptions are necessary in (a)?

    For each of the three cars, there are only two possible outcomes: Either itneeds a warranty repair or it doesn't. (These two outcomes are mutuallyexclusive and collectively exhaustive.)

    The probability of any one car needing warranty repair is the same for allcars, and is independent of what happens with any other car.

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    A B C D E F G

    n 3p 0.05

    (i) probability that none needs a warranty repair? 0.857

    (ii) probability that at least one needs a warranty repair?. 0.143

    (iii) probability that more than one needs a warranty repair? 0.007

    =BINOMDIST(0,$C$1,$C$2,0)

    =1-BINOMDIST(0,$C$1,$C$2,0)

    =1-BINOMDIST(1,$C$1,$C$2,1)

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    (c) What are the mean and the standard deviation of the probability distribution in(a)?

    (d) What would be your answers to (a)-(c) if the probability of needing a warrantyrepair was 0.10?

    45. Suppose that the likelihood that someone who logs onto a particular e-commercesite will purchase an item is 0.20. If the site has 10 people accessing it in the next minute,what is the probability that

    (a) none of the individuals will purchase an item?

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    (b) exactly 2 individuals will purchase an item?

    (c) at least 2 individuals will purchase an item?

    (d) at most 2 individuals will purchase an item?

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    (e) If 20 people accessed the site in the next minute, what would be your answers to(a)-(d)?

    (f) If the probability of purchasing an item was only 0.10, what would be youranswers to (a)-(d)?

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    46. An important part of the customer service responsibilities of a telephone companyrelate to the speed with which troubles in residential service can be repaired. Supposepast data indicate that the likelihood is 0.70 that troubles in residential service can berepaired on the same day.

    (a) For the first five troubles reported on a given day, what is the probability that

    (i) all five will be repaired on the same day?

    (ii) at least three will be repaired on the same day?

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    (iii) fewer than two will be repaired on the same day?

    (b) What assumptions are necessary in (a)?

    (c) What are the mean and the standard deviation of the probability distribution in(a)?

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    Here is how to answer these questions with Excel:

    (d) What would be your answers in (a) and (c) if the probability is 0.80 that troublesin residential service can be repaired on the same day?

    (e) Compare the results of (a) and (d).

    Probability

    Event p= 0.7 p= 0.8All five will be repaired on the same day 0.168 0.328

    At least three will be repaired on the same day 0.837 0.942

    Fewer than two will be repaired on the same day 0.031 0.007

    Expected value 3.5 4.0

    Std Dev 1.025 0.894

    47. Suppose that a student is taking a multiple-choice exam in which each question has

    four choices. Assuming that she has no knowledge of the correct answers to any of thequestions, she has decided on a strategy in which she will place four balls (marked A, B,C, and D) into a box. She randomly selects one ball for each question and replaces theball in the box. The marking on the ball will determine her answer to the question.

    (a) If there are five multiple-choice questions on the exam, what is the probabilitythat she will get

    The number of correct answers out of five is binomially distributed with n= 5 andp=0.25.

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    A B C D E F G H I

    n 5 a(i) 0.168

    p 0.7

    a(ii) 0.837

    a(iii) 0.031

    c 3.500

    1.025

    =BINOMDIST(5,$B$1,$B$2,0)

    =1-BINOMDIST(2,$B$1,$B$2,1)

    =BINOMDIST(1,$B$1,$B$2,1)

    mean =B1*B2

    =SQRT((B1*B2*(1-B2)))

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    (i) five questions correct?

    (ii) at least four questions correct?

    (iii) no questions correct?

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    (iv) no more than two questions correct?

    (b) What assumptions are necessary in (a)?

    (c) What are the average and the standard deviation of the number of questions thatshe will get correct in (a)?

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    (d) Suppose that the exam has 50 multiple-choice questions and 30 or more correctanswers is a passing score. What is the probability that she will pass the exam byfollowing her strategy? (Use Microsoft Excel to compute this probability.)

    The Excel function =1-BINOMDIST(29,50,0.25,1) returns the probability: 0.00000016 (notbloody likely).

    48. Suppose that a survey has been undertaken to determine if there is a relationshipbetween place of residence and ownership of a foreign-made automobile. A randomsample of 200 car owners from large cities, 150 from suburbs, and 150 from rural areaswas selected with the following results.

    Type of AreaCar Ownership Large City Suburb Rural Total

    Own foreign car 90 60 25 175Do not own foreign car 110 90 125 325Total 200 150 150 500

    (a) If a car owner is selected at random, what is the probability that he or she

    (i) owns a foreign car?

    (ii) lives in a suburb?

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    (iii) owns a foreign car or lives in a large city?

    (iv) lives in a large city or a suburb?

    (v) lives in a large city and owns a foreign car?

    (vi) lives in a rural area or does not own a foreign car?

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    (b) Assume we know that the person selected lives in a suburb. What is theprobability that he or she owns a foreign car?

    (c) Is area of residence statistically independent of whether the person owns aforeign car? Explain.

    49. The finance society at a college of business at a large state university would like todetermine whether there is a relationship between a student's interest in finance and hisor her ability in mathematics. A random sample of 200 students is selected and they areasked whether their interest in finance and ability in mathematics are low, average, orhigh. The results are as follows:

    Ability in MathematicsInterest in Finance Low Average High Total

    Low 60 15 15 90

    Average 15 45 10 70High 5 10 25 40Total 80 70 50 200

    (a) Give an example of a simple event.

    (b) Give an example of a joint event.

    (c) Why are high interest in finance andhigh ability in mathematics a joint event?

    This is a joint event because two separate conditions must both be true.

    Event SymbolLow interest in finance LF

    Average interest in finance AFHigh interest in finance HFLow ability in mathematics LMAverage ability in mathematics AMHigh ability in mathematics HM

    (d) If a student is chosen at random, what is the probability that he or she

    (1) has a high ability in mathematics?

    (2) has an average interest in finance?

    (3) has a low ability in mathematics?(4) has a high interest in finance?

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    (5) has a low interest in finance and a low ability in mathematics?

    (6) has a high interest in finance and a high ability in mathematics?

    (7) has a low interest in finance or a low ability in mathematics?

    (8) has a high interest in finance or a high ability in mathematics?

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    (9) has a low ability in mathematics or an average ability in mathematics or ahigh ability in mathematics? Are these events mutually exclusive? Arethey collectively exhaustive? Explain.

    Event Symbol Probability

    Low ability in mathematicsLM

    0.4Average ability in mathematics AM 0.35High ability in mathematics HM 0.25

    These three probabilities add up to 1.0. They are mutually exclusive because only one ofthem can occur at a time (a student can't have average ability and have low ability at thesame time). They are collectively exhaustive because one of them must occur (everystudent must fall into one of the three categories).

    (e) Assume we know that the person selected has a high ability in mathematics.What is the probability that the person has a high interest in finance?

    (f)

    Assume we know that the person selected has a high interest in finance. What isthe probability that the person has a high ability in mathematics?

    (g) Explain the difference in your answers to (e) and (f).

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    In (e) we are interested in the subset of students who have a high ability inmathematics, and would like to know how likely they are to have a high interest infinance. In (f) we are interested in the subset of students who have a high interest infinance, and would like to know how likely they are to have a high ability inmathematics.

    (h) Are interest in finance and ability in mathematics statistically independent?Explain.

    50. On the basis of past experience, 15% of the bills of a large mail-order book companyare incorrect. A random sample of three current bills is selected.

    We assume the number of incorrect bills is binomially distributed with n= 3 andp=0.15.

    (a) What is the probability that

    (1) exactly two bills are incorrect?

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    (2) no more than two bills are incorrect?

    (3) at least two bills are incorrect?

    (b) What assumptions about the probability distribution are necessary to solve thisproblem?

    (c) What would be your answers to (a) if the percentage of incorrect bills was 10%?

    (1) 0.0270

    (2) 0.9990

    (3) 0.0280

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    51. Suppose that on a very long mathematics test, the probability is that Lauren wouldget 70% of the items right.

    The number of correct items is binomially distributed with n= 10 andp= 0.7. We'llsolve this one using Excel.

    (a) For a 10-item quiz, calculate the probability that Lauren will get(1) at least 7 items right.

    (2) fewer than 6 items right (and therefore fail the quiz).

    (3) 9 or 10 items right (and get an A on the quiz).

    (b) What is the expected number of items that Lauren will get right? Whatproportion of the time will she get that number right?

    (c) What is the standard deviation of the number of items that Lauren will get right?

    (d) What would be your answers to (a)-(c) if she typically got 80% correct?

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    A B C D E F

    n p10 0.7

    a

    (1) at least 7 items right. 0.650

    (2) fewer than 6 items right (and therefore fail the quiz). 0.150(3) 9 or 10 items right (and get an A on the quiz). 0.149

    (b) What is the expected number of items that Lauren will get right? 7What proportion of the time will she get that number right? 0.2668

    (c) What is the standard deviation of the number of items that Lauren will get right? 1.4491

    d

    (1) at least 7 items right. 0.879

    (2) fewer than 6 items right (and therefore fail the quiz). 0.033

    (3) 9 or 10 items right (and get an A on the quiz). 0.376

    0.8

    =1-BINOMDIST(6,$B$2,$C$2,1)=BINOMDIST(5,$B$2,$C$2,1)

    =1-BINOMDIST(8,$B$2,$C$2,1)

    =B2*C2

    =BINOMDIST(B9,B2,C2,0)

    =SQRT(B2*C2*(1-C2))

    =1-BINOMDIST(6,$B$2,$C$19,1)=BINOMDIST(5,$B$2,$C$19,1)=1-BINOMDIST(8,$B$2,$C$19,1)