NOVILLA, ASHNER P. 4:30 6:00 PMPROBLEM SET NO. 3 PROBABILITY AND STATISTICS26. CLASSINTERVALCLASSBOUNDARIESCLASS MIDPOINT(X)FREQUENCY(F)f(x) f()

1.5 1.91.45 1.951.723.41.71253.425

2.0 2.41.95 2.452.212.21.21251.2125

2.5 2.92.45 2.952.7410.80.71252.85

3.0 3.42.95 3.453.215480.21253.1875

3.5 3.9 3.45 3.953.710370.28752.875

4.0 4.43.95 4.454.25210.78753.9375

4.5 4.9

4.45 4.954.7314.11.28753.8625

n = 40 136.5 21.35 = AD = = AD = = 3.4125 AD = 0.5337527.AL = 1.6; H = 4.7 R = 3.1K = 6.29 6; C = 0.60CLASSESFREQUENCY< cumf

1.6 2.122

2.2 2.746

2.8 3.31319

3.4 3.91332

4.0 4.5638

4.6 5.12

n = 40

40

Q3 1. K = 3 = 30 < cumf 2. Xlb = 3.353. cumfb = 19FQ3 = 13 C = 0.64. Q3 = 3.35 + () (0.6) VALUE IS GIVEN ON P. 63Q3 = 3.86 Q1 = 3.1INTERQUARTILE RANGE = Q3 - Q1INTERQUARTILE RANGE = 3.86 3.1INTERQUARTILE RANGE = 0.76B. L = 7; H =21R = 14K = 5; C = 3CLASSESFREQUENCY< cumf

7 922

10 12810

13 151424

16 181943

19 21750

N = 50

Q11. K = 1 = 12.5 < cumf2. Xlb = 12.53. cumfb = 10FQ1 = 14 C = 3 4. Q1 = 12.5 + () (3) VALUE IS GIVEN ON EXAMPLE 5 P.63 Q1= 13.0 Q3 = 17.6

INTERQUARTILE RANGE = Q3 - Q1INTERQUARTILE RANGE = 17.6 13.0INTERQUARTILE RANGE = 4.6