Project Management Project planning individual assignment: Project CLOCK [email protected].
Project Management Assignment
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Transcript of Project Management Assignment
CPMQ1. Information related to a project that involves the merger of two marketing firms (in days).ActivityImmediate Predecessor(s)Estimated Duration(days)
A-10
B-15
CA5
DB12
EC,D14
FB8
GD,F15
HE10
IE,G6
JF,I9
a. Draw the project network.b. Develop the project schedule (EST, EFT, LST, LFT).c. What are the critical activities?d. What is the project completion duration?
A1. Network Diagram
Project ScheduleActivityESTEFT
LSTLFT
A0101323
B015015
C10152325
D15271527
E27412842
F15231927
G27422742
H41514757
I42484248
J48574857
Critical ActivitiesA-C-E-HA-C-E-I-JB-D-E-HB-D-E-I-JB-D-G-I-JB-F-G-I-JProject Completion Time57 Days
Q2. A publisher has a contract with an author to publish a textbook. The activities associated with the production of the textbook are given below. The author is required to submit to the publisher a hard copy and a computer file of the manuscript. Develop the associated network for the project and calculate the project duration along with the critical paths.ActivityImmediate Predecessor(s)Estimated Duration(weeks)
A-3
B-2
C-4
D-3
EA,B2
FE4
GF2
HD1
IG,H2
JC,I4
A2. Critical ActivitiesA-E-F-G-I-J = 3+2+4+2+2+4 = 17 weeksB-E-F-G-I-J = 2+2+4+2+2+4 = 16 weeksC-J = 4+4 = 8 weeksD-H-I-J = 3+1+2+4 = 10 weeks
Since the length of the path A-E-F-G-I-J is the longest i.e. 17 weeks, hence it is the critical path.Critical PathA-E-F-G-I-J
Project Completion Time17 weeks
Q3. The following table gives the activities in a construction project and the time duration of each activity:ActivityImmediate Predecessor(s)Estimated Duration(days)
A-16
B-20
CA8
DA10
EB,C6
FD,E12
(i) Draw the activity network of the project. (ii) Find critical path. (iii) Find the total float and free-float for each activityA3. Critical ActivitiesA-C-E-F = 16+8+6+12 = 42 daysA-D-F = 16+10+12 = 38 daysB-E-F = 20+6+12 = 38 daysSince the length of the path A-C-E-F is the longest i.e. 42 days, hence it is the critical path.Critical PathA-C-E-F
Project Completion Time42 days
Total Float is the difference between the maximum time available to perform the activity and the activity durationFree Float is the portion of the total float within which an activity can be manipulated without affecting the floats of subsequent activities.
ActivityImmediate Predecessor(s)Estimated Duration(days)
Total FloatFree Float
A-1600
B-2044
CA800
DA1044
EB,C600
FD,E1200
PERTQ4. Consider the network information shown in question1 in the above section. The duration of some activities is not known with certainty. The estimates of these activities are shown below, assuming that the duration for the other activities remains unchanged.ActivityOptimisticMost Likely
Pessimistic
A81012
C357
D101214
G131517
H81012
a. What is the critical path?b. What is the projects expected completion time and variance?c. What is the probability that the project will be completed in 60 days or more?
A4. Activitytotm
tpte=(to+4tm+tp)/6Variance=((tp-to)/6)^2
A81012104/9
B150
C35754/9
D101214124/9
E140
F80
G131517154/9
H81012104/9
I60
J90
Critical ActivitiesA-C-E-H = 39 DaysA-C-E-I-J = 44 DaysB-D-E-H = 51 DaysB-D-E-I-J = 56 DaysB-D-G-I-J = 57 DaysB-F-G-I-J = 53 DaysSince the length of the path B-D-G-I-J is the longest i.e. 57 days, hence it is the critical path.
Critical Path B-D-G-I-JProject Completion Time57 DaysProbability that the project will be completed in 60 days or moreExpected time = 57 daysScheduled time= atleast60 daysTotal Variance = 4/9*5=2.22Z=(60-57)/2.2=1.363According to the z table, the z value 1.363 corresponds to a probability of 91.35%. So, there is a 91.35% probability that the project will be completed in 60 days or more.
Q5. A mother notes that when her son uses the telephone, he takes no less than 10 minutes for a call and sometimes as much as an hour. Twenty-minute calls are more frequent than calls of any other duration. If sons phone call were an activity in a PERT project:a) What would be the phone calls expected duration?b) What would be its variance?c) In scheduling the project, how much time would be allocated for the phone call?
A5. to = 10 minutes, tp = 60 minutes, tm = 20 minutesSo, te = (to+4tm+tp)/6 = (10+80+60)/6 = 25 minutesVariance = ((tp-to)/6)^2 = ((60-10)/6)^2 = 69.45In scheduling the project, expected duration of the phone call should be allocated i.e. 25 minutes.
Q6. The time estimate(in weeks) for the activities of a PERT network are given below: Activitytotm
tp
1-2117
1-3147
1-4228
2-5111
3-52514
4-6258
5-63615
(a) Draw the project network and identify all the paths through it. (b) Determine the expected project length. (c) Calculate the standard deviation and variance of the project length. (d) What is the probability that the project will be completed:1. At least 4 weeks earlier than expected time? 2. No more that 4 weeks later than expected time? (e) If the project due date is 19 weeks, what is the probability of not meeting the due date? (f) What should be the scheduled completion time for the probability of completion to be 90%?