Project in Math

Submitted by: Nikka Verone C. BacongonSubmitted to: Sir Cadiz

1ST QUARTER

Evaluating FunctionsGiven:f(x)=3x+2f(2)=3(2)+2 =6+2 =8

Substitute 2 in the given equation.

The value of x=2

Another example!The value of x=3

Given: f(x)=2x+6

=2(3)+6=6+6

f(x)=12

The value of x=a+1 f(x)=3x+2

=3(a+1)+2

=3a+3+2

=3a+5

Inverse FunctionConsider the function f(x) = 2x + 1.

We know how to evaluate f at 3, f(3) = 23 + 1 = 7. In this section it helps to think of f as transforming a 3 into a 7

f(x)=x+3 y=x+3 x=y+3

Example: y=2x+5 x=2y+5

x-5=y2

f-1(x)=

f(x)=6-2X=6y-2X+2=6y6 6

f-1 (x)=x+2=y6

f(x)=2x3

(x )=(2y)33

3x=2y

2 2

f-1 (x)=3x=y2

2ND QUARTER

SYNTHETIC DIVISION

2x8-6x2+11x-6

2 -6 11 -64 -4 14

2 -2 7 8 r.

+2

X-2

Add

2x2-2x+7+ 8X-2

2x4+3x2+4x-36

X+2

The exponent should be in order, if one is gone add

0x with the missing exponent

2x4+0x3+3x2+4x-36

X+2Now you can divide it.

2 0 3 4 36 -4 8 -22 36

2 -4 11 -18 0

2x3-4x2+11x-18

Exponetial FunctionGiven:

25 ½ = (52) ½

=51

=5

Another example!

Transpose it.

16 3/2

(2 4) 3/2

2 12/2

2 6 = 64

3RD QUARTER

Logarithm FunctionBefore solving logarithm you need to arrange it first.

Example:

Log 7 x=0

7 0=x log x 8 =3

X 3=8

After arranging you can solve for the log .

Log 7 x=0

7 0=xX=1

log x 8 =3X 3=8X 3 =2 3

X=2

LAW OF LOGARITHM

log 2 32 log2 (8)(4)

logb MN

log2 8+log2 43+2

=5 Transpose 8 & 4 using 2

logb m n log3 9 = log3 27

3 log 3 27 – log 3 3= 3-1

=2

logb MP = p logb M log3 81 4 = 4 log3 81= 4(4)

=16

4TH QUARTER

PARTS OF A CIRCLE

Center Point

Radius

Diameter

Chord

Tangent

Point of tangency

Secant

RADIAN DEGREE

r= πd180o

Degree to Radian

Example

150o π

180o

Cancel the degreesAnd find the GCF of the Given numbers.

150 π

18030

5 π6

Radian to Degrees

Example:

5 π12

The value of Pi is 180o

5(180o) 12900o

12o

=75o

END