Child Nurition Cycle Menu Planning & Production Records 2010.
Production Planning 2010
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Transcript of Production Planning 2010
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PRODUCTION PLANNING
PROF.A.K.CHATTERJEE
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PRODUCTION PLANNING
Planning implies looking ahea in!o !he "#!#$e.%ase on ho& "a$ ahea in!o !he "#!#$e one is
looking a!' &e ha(e !he "ollo&ing )lassi"i)a!ion
CLA**IFICATION OF PLANNING
Long Range Planning: Planning Horizon 5-10years.
+ei#m Range Planning: Planning Horizon 1year.
*ho$! Range Planning: Planning Horizon lessthan 1yr.
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PRODUCTION PLANNINGPRODUCTION PLANNINGby definition would constitute
planning for production /operations for the upcoing year
!ediu and short range". #he ediu range planning ay
be further classified based on the deand.
#he ediu range planning proble is tered as $ggregate
Production Planning in the literature. %n such cases the
deand%s assued to be &ynaic and &eterinistic in nature.
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AGGREGATE PRODUCTION
PLANNING PRO%LE+
E,A+PLE -&eterine the iniu cost
production plan. 'e(d. data is gi)en below:
*an +eb ,ar
&eand 100 5 15
'# ap 100 100 100
# ap 5 5 5
'ele)ant cost: '# cost/unit 's.100
# cost/unit 's.15
%/unit/period 's. 5
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AGGREGATE PRODUCTION
PLANNING PRO%LE+ )on!.
PLAN -
*an +eb ,ar
'# 100 100 100
# 0 0 0PLAN /
*an +eb ,ar
'# 100 5 100
# 0 0 5#radeoff: Produce an unit in '# and carry it o)er as
in)entory for # periods as against producing the
sae unit in #
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AGGREGATE PRODUCTION
PLANNING PRO%LE+ )on!.
FOR+ULATION
&ecision )ariables:
12 no. of units to be produced in *an '#
31 2 no. of units to be produced in *an #2 no. of units to be produced in +eb '#
3 2 no. of units to be produced in +eb #
42 no. of units to be produced in ,ar '#
34 2 no. of units to be produced in ,ar #%1 2 in)entory at the end of *an
% 2 in)entory at the end of +eb
%4 2 in)entory at the end of ,ar
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AGGREGATE PRODUCTION
PLANNING PRO%LE+ )on!.
FOR+ULATION )on!.,iniise 100!16.64"6 15 !3163. 634"
6 5!%16%.6%4"7
8ub9ect to 1631 - %1 2 100%16.63. - %.2 5
%.64 634 -%4 2 15
1 . 4; 10031 3. 34; 5
1 . 4 31 3. 34 %1 %. %4< 0
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PRODUCTION PLANNING
*TRATEGIE*
+a!)hing Deman Plan: Production(uantity in any onth is e(ual to the deand
for the corresponding onth. !as can be seen
in Plan "
Le(el *!$a!eg0: %plying that the production
(uantity reains constant fro onth toonth. !as can be seen in Plan 1"
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DETER+ININGPRODUCTION
PLANNING *TRATEGIE*
#ransportation ,ethod
*an +eb ,ar ap
*an '# 100 # 5
+eb '# 100
# 5
,ar '# 100# 5
&eand 100 5 15
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DETER+ININGPRODUCTION
PLANNING *TRATEGIE*
E1ample /: &eand forecast for the onths *an to
$pr are 5 4= units. #he rele)ant
costs are!a"Production ost 2 c!>" 2 146 > if > ? 0
2 0 otherwise
!b" %n)entory ost 2 's.1/unit le)ied on the end ofonth in)entory.
&eterine the iniu cost production plan.
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CONCEPT OF DO+INANT *E2UENCE
%n any plan the total production is e(ual to the total deand Hence the #otal
)ariable cost for any plan will be sae here 's.@.
#he trade-off is thus between the fi>ed cost of 's.14 and % of 's.1.#o gain
further insight to the proble consider the deand of an ite in the upcoing
two onths as 100 A 50 units. #he proble is to find the iniu cost
production plan. #he rele)ant costs are the fi>ed cost $ !14 here" and in)entorycarrying cost H. !1 here"
#he alternati)e plans can be written as:
1. Produce 100 in first onth and 50 in the second
. Produce 101 in first onth and =B in the second4. Produce 10 in first onth and =@ in the second
n. Produce 150 in first onth and 0 in the second
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CONCEPT OF DO+INANT *E2UENCE )on!.'
#he costs of the alternati)e plans can be seen as $$ 6 H $6HCC$ 6 50H. $s H is positi)e one
needs to consider only the first and the last option
alternati)e. #hus if the re(uireent for the twoonths are &1and &. respecti)ely it is
sufficient to consider the following two plans for
optiality: 1. &16 &. 0 and . &1 &.#hese are called the doinant se(uences.
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CONCEPT OF DO+INANT *E2UENCE )on!.'
#he nuber of doinant se(uences for a # period
proble 2 #-1 thus for a 4 period proble with
re(uireents &1& &4 #he iniu cost plan
will be one aong the following eight plans:
1. &16 & 6 &4 00
. &16 & 0 &4
4. &1 & 6 &4 0
=. &1 & &4
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THE T3RE CO+PAN3 PRO%LE+
$priori $nalysis:
*!ep -%dentify deand and supply gap
+on!h N4F Deman 54R Ho#$s %alan)e O#!p#! Rema$k
*une + 1000 D 10 5@0 1000
E =000 D 5@0 0 4@F D o)er
E ' 1=@ 144
*uly + 5000 D 400 0 500 D o)er
+ ' 450 11@ 500 6 400 '
E @000 ' 1@0 1=@ @000 61=@ '
$ugust + 5000 D F00 =00 5000
E 4000 D =00 0 FF D o)er
E ' 54 = 444 6 = '
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THE T3RE CO+PAN3 PRO%LE+
+ro 8tep 1 its clear that enough supply is there to eet all deands.
*!ep /alculate the contribution per unit for each of the product G
achine cobinations. 1 unit of + produced by D /c will gi)e a
contribution 2 's. !B G 4.B0 G 0.4 G 0.F0" 2 's. =. !neglecting the% which is a relati)ely sall aount". #hus for +D cobination
there is a positi)e contribution. $ (uic chec re)eals that all other
cobinations +' ED E' yield a positi)e contribution iplying it
is worthwhile producing (uantity e(ual to the total deand of both
types of tyres i.e. 15000 of E and 11000 of +
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#HI #3'I ,P$E3 P'JKI,
*!ep 6$s total production 2 total deand the
re)enue is a constant 2 's.!15000 > 6 11000 > B"
2 's. 0=000. 8iilarly the total aterial cost as
well as the shipping cost are also constant.*!ep 7ne ay infer fro the analysis that:
!1"%n this case profit a>iization and cost
iniization are e(ui)alent.
!" #he trade-off is essentially between operating cost
and %
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THE T3RE CO+PAN3 PRO%LE+
Eotethat the proble can be forulated A sol)ed
using KP. 3ou ay reinforce your learning fro '
by defining the decision )ariables ob9ecti)e and the
constraints. +or e.g.De)ision (a$ia8les
Iach of the two tyres can be produced by two
different achines in any of the 4 onths gi)ing rise
to a total of 1 )ariables. +or e.g. ne ay denoteED1 as the no. of units of nylon !E" tyres to be
produced by wheeling !D" achine in *une !say".
$re there any other type of &ecision )ariablesL
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THE T3RE PRO%LE+ )on!.
Cons!$ain!sA(aila8ili!0 o" ma)hine ho#$s in an0 pe$io.
%n *une the wheeling achine is a)ailable for only 00 hrs.
Iach E A + tyre re(uires 0.15 and 0.1 hrs of wheeling
achine respecti)ely. %f ED1 A +D1 denote the productionin *une of E and + using D then 0.15ED1 6 0.1 +D1 ;
00
+a!e$ial %alan)e E9#a!ion.
+or e)ery period and e)ery product one needs to ensure
that beginning in)entory 6 aount produced - aount
deanded 2 ending in)entory. +or *une for Eylon tyre
Jeg. %n)entory 2 0 if *une end %n)entory 2 %E1 then
ED16E'1-%E12=000
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,$88 P'&M#%E PK$EE%EN
$E& P'*I# PK$EE%EN
,ass Production represents high )olue
ProductionO Pro9ect is a one shot affair. #he
data for these are siilar looing but the(ueries and hence the planning techni(ues
are different. +or e>aple gi)en the data on
an assebly the (uery ay be to deterine
how the acti)ities are to be planned to get
a defined continuous output per hour.
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A**E+%L3 DATA
A)!i(i!0 Time;mins.< Imm.P$e.A. / =
%. - A
C. / AD. - %'C
E. 6 D
uestion: How any persons to eploy andacti)ities to be assigned to eachL
&esired output rate 2 0 units/hour.
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Eetwor representation of the $ssebly
A
B
D
C
E
2
1
2
1 3
$88I,JK3 PK$EE%EN
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K%EI J$K$E%EN
Ni)en the data on an $ssebly consisting of
!a"the acti)ities coprising the $ssebly
!b" the tie re(uired to perfor each acti)ity and
! c" the precedence relationship go)erning the acti)ities
!suarized in ters of iediate predecessor"
the ob9ecti)e of Kine Jalancing proble is to decide on the
allocation of the acti)ities to )arious Dor stations so as
to achie)e a desired out put rate to a>iize the Kine
efficiency without )iolating the precedence constraints.
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8#IP8 +' K%EI J$K$E%EN
1. +ind the desired cycle tie fro the desired output
rate. 0units/hour would iply a cycle tie 2 4 in.
. +ind the re(uired nuber of wor stations. %f total
assebly tie 2 # then no. of worers to who the
whole assebly can be allocated has to be < #/2B/424 wor stations.
4. Prepare a list of all the acti)ities in specific order for
the purpose of allocation. Jasis of the ordering ay be
any heuristic e.g. 'an Positional Deight !'PD"heuristic would order the acti)ities based on PD !the
tie re(uired to perfor the acti)ity 6 tie re(uired to
perfor all its successors.
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8#IP8 +' K%EI J$K$E%EN
=. reate 8tations and start assigning acti)ities. #he acti)ity with the
highest PD is assigned to 8tation 1. hec the order obtainedfro 8tep 4 is $ J & I. #hus acti)ity $ stands assigned to
8tation 1.
5. +or subse(uent assignents calculate the reaining tie that can
still be assigned without )iolating the ycle #ie constraint. $s $taes in. 24 in its still possible to assign 1 in to 8tation
1. No down the order list to find the acti)ity taing 1 in. Jefore
assigning any acti)ity to a 8tation a)oid !a" ycle #ie and !b"
precedence )iolation.
F. %f none of the reaining acti)ities satisfy the abo)e condition
create a new 8tation and repeat the process till all acti)ities ha)e
been assigned
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PK$EE%EN +' *J 8HP 838#I,8
+or *ob 8hop 8ystes where each product ay be
re(uired to be processed on different achines in
different se(uences the identification of bottlenec
is not straightforward. Here the concept and
approaches of *ob 8hop 8cheduling assue
iportance.
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8HI&MK%EN: 8%ENKI ,$H%EI
P'JKI,P'JKI, 1 onsider 4 *obs each taing 1 4 hours respecti)ely to be
scheduled on a achine to iniize the a)erage waiting tie of the 9obs.
*OLUTION*ob 1 with iniu processing tie to be scheduled first *ob
with ne>t iniu tie second and so on.
P'JKI, onsider the abo)e proble with ore inforation. #he
waiting cost per hour for each *ob are 's. 0 =5 and F4. 3ou ha)e to decide on
the schedule that iniizes the total waiting cost.
*OLUTION#he p/w ratio !p 2 processing tie w2 waiting cost per hour" canbe calculated for each *ob. *ob with the iniu p/w is to be ordered first
followed by the *ob with the ne>t iniu and so on.
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*CHEDULING *INGLE +ACHINE
PRO%LE+
S
S1
i j
j i
T
T
Waiting cost under schedule S or S1 = waiting cost (WC) o !o"s other than #
and j$ % WC o !o" i and j& #t 'a "e noted that the WC o !o"s other than #
and j$ is sa'e in S and S1 and the dierence in WC is "ecause # and j&
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#D ,/ +KD 8HP
P'JKI, 4 #hree boos are to be printed and bound. #here is oneof each ind of /c. Processing tie data are gi)en below:
b9ecti)e is to order the boos so that iniu tie is taen to
coplete all the boos.
%ook N#m8e$ P$in!ing Time ;Ho#$s< %ining Time ;Ho#$s where the
iniu P occurs. %f P occurs on the 1st/c put that 9ob first. %f P
occurs on the nd/c put that 9ob last. hec P2 1 occurs on /c 1.
Hence 9ob will coe first.*!ep / 'eo)e the 9ob fro the list and repeat till all 9obs are
scheduled. #hus 9ob 1 will be ordered last. #hus the schedule 4 1
will iniize the a>iu flow tie which is the tie by which
all 9obs are copleted !tie by which 9ob 1 coes out fro thesecond /c"
No!e +low tie is the tie the 9ob spends in the 8hop.
,a>iu +low tie 2 +,$1 2+low tie of the 9ob which coes last.