Principles of Semiconductor Devices-L33

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    Alam ECE-606 S09 1

    www.nanohub.org

    NCN

    ECE606: Solid State DevicesLecture 33: MOSCAP Electrostatics (II)

    Muhammad Ashraful [email protected]

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    Outline

    Alam ECE-606 S09 2

    1. Review

    2. Induced charges in depletion and inversion

    3. Exact solution of electrostatic problem

    4. Conclusion

    REF: Chapters 15-18 from SDF

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    Topic Map

    Alam ECE-606 S09 3

    Equilibrium DC Small

    signal

    Large

    Signal

    Circuits

    Diode

    Schottky

    BJT/HBT

    MOSCAP

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    Threshold for Inversion

    4

    s(V)

    l o g1 0QS S( )C / c m2

    ~ S

    ~ eqS / 2kBT

    ~ eqS / 2kBT

    0 0

    0

    2 A oxG s s

    ox A

    qN xV qN

    = +

    -Q

    +QExposed

    Acceptors

    VG

    VG >VT

    2F

    0 0

    0

    22 2 A ox

    th

    ox

    F

    A

    F

    qN xV

    qN

    = +

    Electrons

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    What happens when surface potential is 2F ?

    5

    -Q

    +Q

    Electrons

    Exposed

    Acceptors

    Electron concentration equals

    background acceptor concentration

    0 0

    0

    2 2 2 A oxthox

    F

    A

    FqN xVqN

    = +

    ( )F isE E

    in e=

    1sn

    ) ( )(( ) ( )F i bulk i bulk isE E

    i

    E En e e

    =

    ( )( )i bulk isFi

    E En e e

    =

    2F Fi

    n e e =

    1sn

    +qs EC

    EV

    Ei

    Ei,s

    EF

    F

    i An e N

    = =

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    A little bit about scaling .

    Alam ECE-606 S09

    0 0

    0

    22 2 A oxth

    ox

    F

    A

    F

    qN xV

    qN

    = +

    -Q

    +Q

    Electrons

    Exposed

    Acceptors

    Reduce Vth by

    Reducing oxide thickness

    (from 1000 A in 1970s

    to 10 A now)

    Increase dielectric constant

    (SiO2 historically, HfO2 now in

    Intel Penryn)

    +qs EC

    EV

    Ei

    Ei,s

    EF

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    Outline

    Alam ECE-606 S09 7

    1. Review

    2. Induced charges in depletion and inversion

    3. Exact solution of electrostatic problem

    4. Conclusion

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    Induced charges below Threshold

    Alam ECE-606 S09 8

    ( )( )i bulk isF

    s

    E E

    i

    q

    n e e

    Be

    =

    1sn

    0 0

    0

    2 A ox

    G s s

    ox A

    qN xV

    qN

    = +

    -Q

    +Q

    Electrons

    Exposed

    Acceptors

    s(V)

    l o g1 0QS S( )

    C / c m2

    ~ S

    /

    ~ S Bq k T

    e

    ~ eqS / 2kBT

    +qs

    EC

    EV

    Ei

    Ei,sEF

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    Integrated charges below Threshold

    9

    2( )

    0

    2( )

    0

    1

    1

    ( )

    q xi

    B

    q xi

    B

    ne d

    dN

    dxn

    e dN x

    =

    =

    E

    2( )

    0 0

    ( )q xi

    B

    i nn xQ

    dx e dxq N

    = =

    2( )

    0

    1

    ( )

    q xi

    B

    ne d

    x N

    E Winv

    Qs

    QiQB

    +qs

    EC

    EV

    Ei

    Ei,s

    EF

    2

    ( )

    sqis

    B

    B

    inv

    ne

    k T

    qW

    xn

    N

    =

    E

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    Charges above Threshold

    Alam ECE-606 S09 10

    -Q

    +Q

    Electrons

    Exposed

    Acceptors

    VG

    VG >VT

    0

    ( )G s o s o

    ox

    i s Fox

    Q

    x

    Q

    V x

    +

    = + = E

    0

    (2 )2 2

    th F o F o

    ox

    i Fox

    FV x xQQ

    += + =

    E

    ( )0

    2() 2 )(

    G th s F i s F

    o

    x

    i

    o

    V VQQ

    x

    = +

    ( )Gi ox thC VQ V=

    +Q

    VG

    -Q

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    Linear Charge Build-up Above Threshold?

    11

    ~ 2 F

    s(V)

    ( )10log S SQ

    ~ S

    -Q

    +

    Q

    Electrons

    Exposed

    Acceptors

    VG

    VG >VT

    Small changes s in changes Qia lot .. Change in Qichanges Eox, because Eox=Qi/0e0 Vox is large because Vox=Eox x0, i.e. most of the

    drop above 2F goes to Vox.

    Acts like a parallel plate capacitor, hence the inversion equation.

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    Tunneling Current

    Alam ECE-606 S09 12

    ( ) ( )GqV

    T i G m th J Q V qn e T E

    =

    EC

    EV

    EF

    EG

    T( )

    ( ) ox C

    C oxC

    T s g g s

    m th

    qV E

    i G m t

    i G

    h

    qVE E

    J J J

    e qn e e

    Q V q

    Q

    e T

    V

    n T e

    = =

    =

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    Outline

    Alam ECE-606 S09 13

    1. Review

    2. Induced charges in depletion and inversion

    3. Exact solution of electrostatic problem

    4. Conclusion

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    A step back: Exact Solution ofQS(

    S)

    Alam ECE-606 S09 14

    EC

    EV

    EFEG

    qS

    S> 0

    D=

    Jn q( )= GR( )

    Jp q

    ( )= GR( )

    0 0

    0

    2 A ox

    s sG

    ox A

    qN xV

    qN

    = +Approximate

    2

    0 02

    0

    ( ) ( )D A

    si

    d qp x n x N N

    dx

    + = +

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    Normalized Variable (to save some writing)

    Alam ECE-606 S09 15

    q x( )qS x( )= 0

    EC(x) = constant q(x)

    qVG > 0

    x

    , ( )( )

    C bulk C E E x

    xq

    =

    ( ) ( )( )/

    i bulk i x

    B B

    E Exu

    k T q k T

    = =

    ( ) ( )

    /

    i bulk i surfaceS

    B B

    SuE E

    k T q k T

    = =

    ( )

    /

    i bu

    F

    lk FF

    B B

    E E

    k T q k T u

    = =

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    Normalized Variable (to save some writing!)

    Alam ECE-606 S09 16

    q x( )qS x( )= 0

    qVG > 0

    x

    [ ( ) ] ( )( ) F Fi

    E x E U

    i

    U

    i p x n e n e + = =

    [ ( ) ] ( )( ) Fi F

    E x E U

    i

    U

    in x n e n e = =

    ,[ ] ( )F i bulk FE E

    D i

    U

    i N n e n e + = =

    ,[ ] ( )F i bulk FE EA i

    Ui N n e n e

    = =

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    Poisson-Boltzmann Equation

    Alam ECE-606 S09 17

    2

    20

    ( ) ( )D A

    s

    d q

    p x n x N N dx

    + = +

    ( ) ( )2

    2

    0

    ( , )F F F FU U U U U U

    F

    i

    i i

    B s

    qnq d Ue e n e n e

    k dg U

    xU

    T

    + = +

    2

    2

    0

    (2 , ) 2i B

    s

    F

    n k Td U

    d

    dU dU

    dx dxxg U U

    =

    2

    2 2( , )12 D

    Fd d g U UU dUdx dxdx dx L dx =

    2( ) ( )

    2

    0 0

    ( , )1

    q x kT U

    F

    x

    D

    dUd dU

    LxUg

    dU

    =

    E

    Can be evaluated

    at any U

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    Exact Solution (continued)

    Alam ECE-606 S09 18

    2 ( ) 2

    2 2

    0

    1 ( , )( ,

    ( ))

    U x

    D

    F

    D

    FF U Ug U Uq x

    dU

    L LkT

    =

    E

    2( ) ( )

    2

    0 0

    ( , )1

    q x kT U

    D

    F

    x

    d dUL

    dUdx

    g U U

    =

    E

    ( , )B

    D

    Ss FF U

    k T

    qLU=E

    0 0( , )s s B

    G s s s

    ox ox

    s

    D

    F

    k TV

    LU x

    qUx F

    = + = +

    E

    0 0

    0

    2 A ox

    s sG

    ox A

    qN xV

    qN

    = +

    Compare

    Vox

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    How does the calculation go

    19

    2 ( ) 2

    2 2

    0

    1 ( , )

    ( ,

    ( )

    )

    U x

    D

    F

    D

    FF U U

    g U U

    xq

    dUkT L L

    =

    E

    0 0( , )s s B

    G s s s

    ox ox D

    s F

    k TV x x

    qLF U U

    = + = +E

    Begin with a surface potential

    Calculate Us and then divide Us by N points.

    Calculate g(U, UF) at those points

    and integrate to find F(Us,UF)

    Find VG.

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    Exact Solution

    Alam ECE-606 S09 20

    Accumulation Depletion Inversion (weak)

    Inversion (strong)

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    Exact solution is not really exact

    Alam ECE-606 S09 21

    EC

    EV

    EF

    EG

    qS

    S> 0

    2

    2

    2( ) ( ) ( )

    D A

    xd q

    p x n x N N dx

    + = +

    Wave function should be accounted for

    Bandgap widening near the interface

    must also should be accounted for.

    Assumption of nondegeneracy may not

    always be valid

    wavefunction, not potential !

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    Conclusion

    Alam ECE-606 S09 22

    Our discussion today was focused on calculating the

    induced charge in the depletion and inversion region as a

    function of gate bias.

    We found that we could calculate the tunneling currentfrom the inversion changes by using the thermionic

    emission theory.

    We also discussed the exact solution of the MOS-capacitor electrostatics. The exact solution is

    mathematically exact, but not necessarily physically exact

    solution of the electrostatic problem.