Presentation (distance formula)

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DISTANCE FORMULA

Transcript of Presentation (distance formula)

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DISTANCE FORMULA

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Plot these coordinates on

our Cartesian plane.

(3,2)

(8,7)

(8,2)

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RIGHT TRIANGLE

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AC is

plotted on

the x- axis.

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Find the difference of the two

coordinates in x axis.

x2-x1

x2=8

x1=3

=8 – 3

=5

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AC is

plotted on

the x- axis.

BC is plotted on the y-axis

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Find the difference of the two

coordinates in x axis.

y2-y1

y2=7

y1=2

=7 – 2

=5

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PYTHAGOREAN

THEOREM

c

a

b

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𝑐 = 𝑥2 − 𝑥12 + (𝑦2 − 𝑦1)

2

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DISTANCE FORMULA

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SUBSTITUTION METHOD

By substitution:

𝐷 = 𝑥2 − 𝑥12 + (𝑦2 − 𝑦1)

2

𝐷 = 5 2 + 5 2

𝐷 = 50

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ACTIVITY #1

• Graph and show that the following

coordinates forms an isosceles

triangle by using the distance

formula.

S (-1,4)

C (0,1)

B (2,5)

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𝐶𝐵 = 𝑥2 − 𝑥12 + (𝑦2 − 𝑦1)

2

= 2 − 0 2 + (5 −1)2

= 4 + 16

= 20

=5 2

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𝐵𝑆 = 𝑥2 − 𝑥12 + (𝑦2 − 𝑦1)

2

= 2 + 1 2 + (5 −4)2

= 10

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QUIZ#6

Get ½ crosswise sheet of paper and

answer the following.

Find the distance between the given

points.

1. (0,9) and (0,13)

2. (4,5) and (-3,5)

3. (8,1) and (8,-2)

4. (1,0) and (5,2)

5. (5,-4) and (1,-1)

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ASSIGNMENT

A. Graph and Find the distance using

distance formula.

I (-4,6) and V (2,5)

Y (-1,6) and S (5, 10)

B. Make a research on midpoint and

give at least 2 examples.

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