Pre-Calculus. Objectives : 1. Identify the relationship of trig functions and positive and negative...
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Transcript of Pre-Calculus. Objectives : 1. Identify the relationship of trig functions and positive and negative...
8.4 TRIG IDENTITIES & EQUATIONS
Objectives:1. Identify the relationship of trig functions
and positive and negative angles2. Identify the Pythagorean trig relationships3. Identify the cofunction trig relationships4. Apply various trig relationships to simplify
expressions.
Vocabulary:sine, cosine, tangent, cosecant, secant, cotangent, cofunction
PART 1:PYTHAGOREAN TRIG RELATIONSHIPS
Let’s take a look at the unit circle. Using the Pythagorean Theorem, how
can you relate all three sides of the triangle?sin2θ + cos2θ = 1
This is one of the PythagoreanTrig Relationships
PART 1:PYTHAGOREAN TRIG RELATIONSHIPS
Starting with sin2θ + cos2θ = 1, how can you manipulate it to get other following Pythagorean Trig Relationships?
1 + tan2θ = sec2θ Divide both sides by cos2θ
1 + cot2θ = csc2θ Divide both sides by sin2θ
These are the final 2 of the 3 Pythagorean Trig Relationships
PART 2:COFUNCTION TRIG RELATIONSHIPS Sine & Cosine, Tangent & Cotangent,
Secant & Cosecant are all Cofunctions. Trig Cofunctions have the following
relationship
WHY?
PART 3:TRIG RELATIONSHIPS WITH NEGATIVE & POSITIVE ANGLES
Let’s take a look at a positive and negative angle on the unit circle
PART 3:TRIG RELATIONSHIPS WITH NEGATIVE & POSITIVE ANGLES
Let’s take a look at sin θ. What does this equal according to our picture?
What about sin –θ. What does this equal according to our picture?
What can we say about the relationship between sin θ & sin –θ?
PART 3:TRIG RELATIONSHIPS WITH NEGATIVE AND POSITIVE ANGLES
We just proved that sin (-θ) = - sin θ What do you think the relationship
between cos (- θ) and cos θ is?cos (- θ) = cos θ
What about the relationship between tan (- θ) and tan θ? tan (- θ) = - tan θ
Let’s look at csc (- θ) and csc θ. What is the relationship? csc (- θ) = - csc θ
What about the relationship betweensec (- θ) and sec θ? sec (- θ) = sec θ
What about the relationship between cot (- θ) and cot θ? cot (- θ) = - cot θ
Part 3:Trig Relationships With Negative and Positive Angles
EXAMPLES: PRACTICE SIMPLIFYING Write the equivalent trig function with a
positive angle Sin (-π/2)
Cos (-π/3)
Cot (-3π/4)
SUGGESTIONS Start with the more complicated side Try substituting basic identities (changing all
functions to be in terms of sine and cosine may make things easier)
Try algebra: factor, multiply, add, simplify, split up fractions
If you’re really stuck make sure to:
Change everything on both sides to sine and cosine.
Work with only one side at a time!
DON’T GET DISCOURAGED! Every identity is different Keep trying different approaches The more you practice, the easier it will be
to figure out efficient techniques If a solution eludes you at first, sleep on it!
Try again the next day. Don’t give up! You will succeed!
TIPS TO HELP SIMPLIFY EXPRESSIONS There are 4 different categories of trig
relationships which each have different key components to look forReciprocal Relationships
Most commonly used in some type of format similar to cot y · sin ymanipulating a fraction with trig functions
Usually the functions aren’t squared when they are in this format
Negative/Positive Angle Relationships Similar to the example problems previously in
this powerpoint tan (-45°)
TIPS TO HELP SIMPLIFY EXPRESSIONS There are 4 different categories of trig
relationships which each have different key components to look for Cofunction Relationships
Similar to the example problems previously in this powerpoint
cos (90° – A) Pythagorean Relationships (MOST
COMMON/CHALLENGING!) Includes exponents to the second degree Includes expanding two binomials Addition and subtraction of fractions May need to factor out a trig function before
simplifying Or some type of variation of the previous
TIPS TO HELP SIMPLIFY EXPRESSIONS Though most of the problems are
separated into their respective categories, you may find yourself having to combine multiple relationships to fully simplify an expression.Maybe you’ll start with Pythagorean
relationships, then to fully simplify you may use Reciprocal relationships.
In most cases, fully simplifying an expression will leave the expression with only one term