Power Persentaion pipin
5
LUAS PERMUKAAN BALOK OLEH : PIPIN RIDMANINGSIH NIM : 2012 121 226
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Transcript of Power Persentaion pipin
![Page 1: Power Persentaion pipin](https://reader036.fdocuments.net/reader036/viewer/2022082813/55c7da99bb61ebd5288b471a/html5/thumbnails/1.jpg)
LUAS PERMUKAAN BALOK
OLEH : PIPIN RIDMANINGSIHNIM : 2012 121 226
![Page 2: Power Persentaion pipin](https://reader036.fdocuments.net/reader036/viewer/2022082813/55c7da99bb61ebd5288b471a/html5/thumbnails/2.jpg)
MATERILUAS
PERMUKAAN BALOK
CONTOH SOAL
LATIHAN SOAL
![Page 3: Power Persentaion pipin](https://reader036.fdocuments.net/reader036/viewer/2022082813/55c7da99bb61ebd5288b471a/html5/thumbnails/3.jpg)
LUAS PERMUKAAN BALOK
BACKBy : Pipin Ridmaningsih
![Page 4: Power Persentaion pipin](https://reader036.fdocuments.net/reader036/viewer/2022082813/55c7da99bb61ebd5288b471a/html5/thumbnails/4.jpg)
Contoh SoalPerhatikan gambar dibawah ini, hitunglah luas permukaan bangun ruang tersebut!
4 cm
6 cm
12 cm
![Page 5: Power Persentaion pipin](https://reader036.fdocuments.net/reader036/viewer/2022082813/55c7da99bb61ebd5288b471a/html5/thumbnails/5.jpg)
Penyelesaian :Diketahui p = 4 cm l = 6 cm t = 12 cmDitanya luas bangun ruang tersebut?Jawab :
Luas = 2(pl + pt + lt) =
2((4.6)+(4.12)+(6.12)) = 2(24 + 48 + 72) = 2(144) = 288
Jadi luas bangun ruang tersebut adalah 288
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