Power Elec Notes 07c Boost Converter Design Example
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Transcript of Power Elec Notes 07c Boost Converter Design Example
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1Boost Converter Design Example M. T. Thompson, 2008
Power Electronics Notes 07CBoost Converter Design Example
© Marc Thompson, 2008
Marc T. Thompson, Ph.D.Thompson Consulting, Inc.
9 Jacob Gates RoadHarvard, MA 01451
Phone: (978) 456-7722 Fax: (888) 538-3824
Email: [email protected]: http://www.thompsonrd.com
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2Boost Converter Design Example M. T. Thompson, 2008
Summary• Design a boost converter with the following specifications:
• Input voltage: 12V• Output: 24V @ 1A, 24 Watts• Continuous conduction mode• Inductor and capacitors: selected from following datasheets• Switching frequency 100 kHz• Output voltage ripple < 50 mV-pp
• Evaluate output ripple and estimate efficiency of converter
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3Boost Converter Design Example M. T. Thompson, 2008
Step-Up (Boost) DC-DC Converter• Output voltage is higher than the input, without a phase inversion
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4Boost Converter Design Example M. T. Thompson, 2008
Boost Converter Waveforms• Continuous current conduction mode
Switch closed:didt
VL
L CC
Switch open:
didt
V vL
L CC o
Inductor Volt-second balance:V DTL
V V D TL
VVD
CC CC o
oCC
( )( )10
1
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5Boost Converter Design Example M. T. Thompson, 2008
Boost: Limits of Cont./Discont. Conduction• The output voltage is held constant• For low load current, current conduction becomes discontinuous
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6Boost Converter Design Example M. T. Thompson, 2008
Boost Converter: Discont. Conduction• Occurs at light loads
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7Boost Converter Design Example M. T. Thompson, 2008
Boost Converter: Effect of Parasitics• The duty-ratio D is generally limited before the parasitic effects become significant
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8Boost Converter Design Example M. T. Thompson, 2008
Boost Converter Output Ripple• ESR is assumed to be zero• Assume that all the ripple component of diode current flows through capacitor; DC component flows through resistor
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9Boost Converter Design Example M. T. Thompson, 2008
Boost Converter 1st-Cut Design --- Inductor• D = 0.5• What is minimum inductor value to keep this converter in continuous conduction mode ? (I.e. this converter operates at the continuous/discontinuous conduction boundary)
• Average diode current: 0.5Ipk(1-D) = Io = 1A• Ipk = 4A• Lmin =(Vo – Vi)(1-D)T/Δi = (24-12)(0.5)(10-5)/4 = 15 µH
• For the diode, ID,rms = = 2.3A31
pkI
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10Boost Converter Design Example M. T. Thompson, 2008
Inductor Datasheet• Use 22 µH (ESR = 0.085 Ohms)• Note that series resonant frequency (SRF) is much higher than operating frequency• Note that IRMS rating of this inductor is 2.7A
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11Boost Converter Design Example M. T. Thompson, 2008
Boost Converter Current Waveforms
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12Boost Converter Design Example M. T. Thompson, 2008
Boost Converter 1st-Cut Design --- Capacitor• What is minimum capacitor value ?
CfD
RVV
sw
oppo
FVRfDVC
pposw
o 100)05.0)(24(10
)5.0)(24(5min
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13Boost Converter Design Example M. T. Thompson, 2008
Capacitor Datasheet• Use 3 47 µF caps in parallel (35V, ESR = 0.9 Ohms)
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14Boost Converter Design Example M. T. Thompson, 2008
MOSFET Datasheet• This device is over-sized, but let’s use it anyway
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15Boost Converter Design Example M. T. Thompson, 2008
1st Cut Design
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16Boost Converter Design Example M. T. Thompson, 2008
Simulation Result --- Inductor Current• Note that inductor ripple is about 3A peak to peak
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17Boost Converter Design Example M. T. Thompson, 2008
Simulation Result --- Output Ripple• Why is output voltage ripple so large ?
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18Boost Converter Design Example M. T. Thompson, 2008
Simulation Result --- Analysis• The culprit is capacitor ESR. Ripple current is 3A pp, divided into 3 capacitors. Ripple voltage = ripple current x ESR• This is a problem with the boost converter --- large output ripple current makes sizing capacitor difficult
Ripple 1 V pp
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19Boost Converter Design Example M. T. Thompson, 2008
Mitigating Strategies• Parallel up more capacitors, or find capacitors with even lower ESR• Alternative strategy: use lower ESR caps with a post-filter
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20Boost Converter Design Example M. T. Thompson, 2008
2nd Cut Design• Lower ESR capacitors and an LC post filter added
Lower ESR caps
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21Boost Converter Design Example M. T. Thompson, 2008
2nd Cut Design --- Simulation Results
Ripple 20 mV pp
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22Boost Converter Design Example M. T. Thompson, 2008
2nd Cut Design --- Efficiency Estimate• Losses due to:
• Inductor loss• Switch conduction loss• Switch switching loss• Diode loss• Capacitor ESR loss• Gate drive loss
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23Boost Converter Design Example M. T. Thompson, 2008
2nd Cut Design --- Efficiency EstimateBoost converter lecture exampleMTT 10-9-03fsw 1.00E+05L 2.20E-05Vi 12Vo 24Rinductor 0.085D 0.5Rsw 0.0825IL,avg 2IL,max 3.36E+00IL,min 6.36E-01tsw 1.50E-07IL,rms 2.15E+00Isw,RMS 1.52E+00Vd 0.8 Diode voltageIo 1 Output currentQg 1.00E-07
LOSSES CALCULATIONPdiode 0.80Pinductor 0.39Pswitch, conduction 0.19Pswitch, switching 0.61Gate drive loss 0.12Capacitor ESR loss 0.12
Total losses 2.23Output power 24Efficiency 91.5%
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24Boost Converter Design Example M. T. Thompson, 2008
2nd Cut Design --- Evaluation • FATAL DESIGN FLAW• Note that ISAT rating of this inductor is 2.6A• Peak current in inductor is 3.4A• Therefore, this design will blow up
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25Boost Converter Design Example M. T. Thompson, 2008
3rd Cut Design --- Replace Inductor• Using next-size up Coilcraft inductor, Isat rating of 22 µH inductor is 7.0A, RMS rating is 3.5A, so this should be OK• Inductor loss will be lower due to lower DC resistance• This comes at the cost of a more expensive inductor, and more PC board space needed