Polinomios Mary
21
POLINOMIOS >> P=[1 4 7 8], Q=[6 7 9 0 2] P = 1 4 7 8 Q = 6 7 9 0 2 >> polyval(P,2) ans = 46 >> X=-10:10 X = Columns 1 through 15 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 Columns 16 through 21 5 6 7 8 9 10 >> Y=polyval(P,X) Y = Columns 1 through 7 -662 -460 -304 -188 -106 -52 -20 Columns 8 through 14 -4 2 4 8 20 46 92 Columns 15 through 21 164 268 410 596 832 1124 1478 >> plot(X,Y)
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Transcript of Polinomios Mary
POLINOMIOS
>> P=[1 4 7 8], Q=[6 7 9 0 2]
P =
1 4 7 8
Q =
6 7 9 0 2
>> polyval(P,2)
ans =
46
>> X=-10:10
X =
Columns 1 through 15
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4
Columns 16 through 21
5 6 7 8 9 10
>> Y=polyval(P,X)
Y =
Columns 1 through 7
-662 -460 -304 -188 -106 -52 -20
Columns 8 through 14
-4 2 4 8 20 46 92
Columns 15 through 21
164 268 410 596 832 1124 1478
>> plot(X,Y)
>> P=[3 6 9 11], Q=[2 4 6 8 10]
P =
3 6 9 11
Q =
2 4 6 8 10
>> polyval(P,4)
ans =
335
>> X=-2:12
X =
-2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12
>> Y=polyval(P,X)
Y =
Columns 1 through 7
-7 5 11 29 77 173 335
Columns 8 through 14
581 929 1397 2003 2765 3701 4829
Column 15
6167
>> plot(X,Y)
>> R=roots(P)
R =
-1.5740 + 0.0000i
-0.2130 + 1.5113i
-0.2130 - 1.5113i
>> P=[1 4 7 8], Q=[6 7 9 0 2]
P =
1 4 7 8
Q =
6 7 9 0 2
>> R=roots(Q)
R =
-0.6784 + 1.0400i
-0.6784 - 1.0400i
0.0951 + 0.4551i
0.0951 - 0.4551i
>> P=[1 4 7 8], Q=[6 7 9 0]
P =
1 4 7 8
Q =
6 7 9 0
>> W=P+Q
W =
7 11 16 8
>> W=4*P-3*Q
W =
-14 -5 1 32
>> C=conv(P,Q)
C =
6 31 79 133 119 72 0
>> P=[1 4 7 8], Q=[6 7 9 0]
P =
1 4 7 8
Q =
6 7 9 0
>> P=[1 4 7 8], Q=[6 7 9 0 1]
P =
1 4 7 8
Q =
6 7 9 0 1
>> [Q,R]=deconv(Q,P)
Q =
6 -17
R =
0 0 35 71 137
>> residue(P,Q)
ans =
13.7816
>> polyder(P,Q)
ans =
24 21 -52 -71
>> residue(P,D)
ans =
0.0718 - 0.0523i
0.0718 + 0.0523i
-0.0361 - 0.1436i
-0.0361 + 0.1436i
>> polyder(P,D)
ans =
98 426 870 1192 954 638 262
>> residue(L,D)
ans =
0
0
0
0
>> polyder(L,D)
ans =
0
line>> line;
x=-2:0.3:7;
y=sin(x.^4);
plot(x,y);
>> line;
>> x=-2:4.3:9;
>> y=sin(x.^10);
>> plot(x,y);
Bar
>> x=-6:0.3:2;
>> y=exp(-x.^2);
>> bar(x,y);
>> x=-8:0.4:2;
>> y=exp(-x.^4);
>> bar(x,y);
barh
x=-3:0.2:3;
y=cos(x.^3)-2.*x+1;
barh(x,y);
x=-6:0.4:9;
>> y=cos(x.^4)-2.*x+1;
>> barh(x,y);
>> x=8:0.5:10;
>> y=sin(x);
>> stairs(x,y);
x=2:0.2:10;
>> y=sin(x);
>> stairs(x,y);
polar
t=0:0.1:2*pi;
y=abs(sin(2*t).*cos(2*t));
polar(t,y);
>> t=0:0.2:4*pi;
>> y=abs(sin(2*t).*cos(2*t));
>> polar(t,y);
pie
>> x=6:1:14;
>> pie(x)
>> x=2:1:6;
>> pie(x)
rose
>> x=[1 9 6 8 7 4 5 28];
>> rose(x);
>> x=[1 2 6 8 7 4 9 21];
>> rose(x);
>> x=0:0.05:5;
y=sin(x);
z=cos(x);
plot(x,y,x,z);
>> x=0:0.03:11;
>> y=sin(x);
>> z=cos(x);
>> plot(x,y,x,z);
GRÁFICAS ESPECIALES EN EL PLANO
>> x=-pi:3.7:pi;
>> y=2-sin(x);
>> compass(x,y);
>> x=-pi:2.12:pi;
>> y=2-sin(x);
>> compass(x,y);
>> x=-pi:1.10:pi;
>> y=3-sin(x);
>> feather(x,y);
>> x=-pi:2.9:pi;
>> y=2-sin(x);
>> feather(x,y);
>> fplot('cos(x)',[-3,6]);
>> fplot('cos(x)',[-1,5]);
>> ezplot('4-abs(x)',[-5,23]);
>> ezplot('4-abs(x)',[-5,28]);
>> x=1:0.2:10;
y=11+exp(-x.^2);
loglog(x,y);
>> x=2:0.4:15;
>> y=9+exp(-x.^1);
>> loglog(x,y);
>> x=1:0.2:10;
y=cos(x);
fill (x,y, 'm');
>> x=3:0.2:25;
>> y=cos(x);
>> fill (x,y, 'm');
1.- Resolver el limite:
>> syms x
>> y=(x^3+1)/(1^2+1)
y =
x^3/2 + 1/2
>> l=limit(x,y,1)
l =
x
2.
>> syms x
y=(x^2-3)/(3*x^5+5*x)
>> l=limit(y,x,3)
l =
1/124
2) Aplicación de Derivadas Comprobar que la función y=Ae−2xcos(3x+b) es la solución de la ecuación diferencial que describe las oscilaciones amortiguadas, donde A y b son constantes que se determinan a partir de las condiciones iniciales (posición inicial y velocidad inicial).
>> syms x A b;
>> y=A*exp(-2*x)*cos(3*x+b);
>> diff(y,2)+4*diff(y)+13*y
ans =
0
2.si deseas derivar f=x3*cos(x)
>> f='x^3*cos(x)'
f =
x^3*cos(x)
>> diff(f,2)
ans =
-17 34 66 -45 -8 -79 155 -159
>> diff(f)
ans =
Columns 1 through 8
-26 -43 -9 57 12 4 -75 80
Column 9
-79
