Physics of Sound. Logarithms Do you know how to use your calculator? Find the following functions +,...

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Physics of Sound

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Transcript of Physics of Sound. Logarithms Do you know how to use your calculator? Find the following functions +,...

  • Slide 1
  • Physics of Sound
  • Slide 2
  • Logarithms Do you know how to use your calculator? Find the following functions +, -, x, /, ^, log The log is the exponent to which 10 is raised, representing a number
  • Slide 3
  • Antilogarithm The antilog is 10 raised to the x power, or 10 x
  • Slide 4
  • Logarithms Solve the following together: Log (20) = ___________ Log (400) = ____________ Solve on your own: Log (0.5) = ____________ Log 2 = _____________
  • Slide 5
  • Antilogarithms Solve the following together: X = 2 => _______________ X = 4.3 => _______________ Solve on your own: X = 8.5 => _____________ X = 9.0 => _____________
  • Slide 6
  • What is sound? Any change in air pressure The molecules in the air exerts a pressure of over 1 ton per square foot on our ears Must be a rapid change in sound pressure to be heard, a small rapid change will create noise Travels as sound waves
  • Slide 7
  • Frequency of Sound Rate at which complete high and low pressure regions are produced by the sound source. 1000 cycles per second is 1000 high and low pressure regions passing a point in one second. This is called 1000 Hertz (Hz) or 1 kHz.
  • Slide 8
  • Speech frequencies Speech frequencies: generally regarded to be 500 to 3000 hertz Frequency range of perceivable sound: 20 Hz to 15,000 to 20,000 Hertz. Tuning forks
  • Slide 9
  • Tone and Noise Tuning fork pure tone and related frequencies We cannot see the tines moving back and forth because they are moving back and for the too quickly. Two- hundred cycles a second is too fast to see. Noise random frequencies
  • Slide 10
  • Noise travels through a medium A vibrating object creates a disturbance that travels through a medium A trains noise can travel through the steel tracks by creating sound waves The vibrations of a speaker creates sound waves Frequency is the number of complete back and forth vibrations per second
  • Slide 11
  • Noise travel Vibrational motion of the medium is set up by the object. The vibrations set the molecule of the medium into motion. The motion of the molecule in the medium sets the molecule next to it, in motion. The transfer of energy continues as the vibration of one molecule sets the next molecule into motion.
  • Slide 12
  • Sound wave is a pressure wave Thus an instrument can be used to measure the oscillations of high and low pressure variations in the pressure. These oscillations are shown as the typical sine wave that you may have seen
  • Slide 13
  • Wavelength Distance which a disturbance travels along the medium in one complete wave cycle. Measured from one wave trough or crest to the next wave trough or crest, in a transverse wave. It is from one wave compression to the next wave compression in a longitudinal wave With a pressure wave it is from one high pressure region to the next high pressure region
  • Slide 14
  • Speed of Sound Sound waves are pressure disturbances traveling through a medium by means of particle interaction How fast the disturbance is passed from particle to particle determines the speed of sound. How easily the medium transfers the disturbance determines the speed, which is measured in feet per second (ft/sec)
  • Slide 15
  • Speed of Sound Speed is equal to distance traveled per unit time. Speed = distance/time If a sound waves travels 2,300 feet in 2 seconds the sound is traveling at 1,150 ft/sec Examples of sound travel would be the time it takes for thunder to reach the observer and an echo
  • Slide 16
  • Speed of Sound The speed depends on the properties of the medium, the elastic properties are much greater than are the inertial properties. Thus longitudinal sound waves will travel faster in solids than in liquids, and longitudinal sound waves will travel faster in liquids than in gases
  • Slide 17
  • Speed of Sound in air The speed of sound in air will depend on temperature and pressure of the air. The relationship is: C = 1054 f/s + (1.07 f/s/ o F)xT
  • Slide 18
  • Speed of Sound At 72 o F, the speed of sound is 1,130 f/s The delay between lightning and thunder. Light travels 980,000,000 f/s or reaches the observer in almost no time. The time delay of an echo is the same phenomenon, the distance of a reflecting surface can be determined by the time it takes for the echo to return
  • Slide 19
  • Speed of Sound The speed of sound in different mediums at standard conditions: In air : the velocity is 1,130 f/s In water: the velocity is 4,700 f/s In wood: the velocity is 13,000 f/s In steel: the velocity is 16,500 f/s
  • Slide 20
  • Speed, frequency and wavelength The mathematical relationship between the three is: C = x f The speed is a constant based on the properties of the medium. The length of a wave will vary with the frequency.
  • Slide 21
  • Speed, frequency and wavelength At standard conditions, the speed of sound is 1,130 f/s. Say we have a 440 hertz frequency pure tone sound, what is the wavelength of the sound? C = x f = C / f = 1,130 / 440 = 2.57 feet
  • Slide 22
  • Speed, frequency and wavelength How about air at 1,000 o F as part of an exhaust stream? Find the speed of sound traveling through the exhaust? C = 1,054 f/s + (1.07 f/s)x o F C = 1,054 + 1.07*1,000 C = 1,054 + 1070 = 2,124 f/s
  • Slide 23
  • Speed, frequency and wavelength Engine rotating at 3,000 rpm and has 4 cylinders 3,000 * 4 = 12,000 rounds per minute Which equals 200 rounds per second (Hz) What is the frequency of this sound? = C / f = 2,124 / 200 = 10.62 ft
  • Slide 24
  • Speed, frequency and wavelength What is the wavelength of the following frequencies? (at standard conditions) 20 hz = ________ remember: = C/f 1000 hz = ________ 16000 hz = ________
  • Slide 25
  • Period The period is the time for one complete cycle of pressure transition. It is the reciprocal of the frequency. T (sec) = 1/f The period of a 1000 Hz sound wave is: T = 1/f = 1/1000 = 0.001 seconds
  • Slide 26
  • Period What is the period of a 20 Hz and a 16,000 Hz wave? T 20 Hz = 1/f = T 16000 Hz = 1/f =
  • Slide 27
  • Period Below 20 Hz infrasound Above 20,000 Hz ultrasound Dogs 50 Hz to 45,000 Hz Cats 45 Hz to 85,000 Hz Bats to 120,000 Hz Dolphins 200,000 Hz Elephant down to 5 Hz and up to 10,000 Hz
  • Slide 28
  • Sound Waves A pure tone (tuning fork) sound introduced into the room will create a change in the molecules in the room. At 440 Hz the molecules will bunch up every 3 feet Also there will be a net drift of molecules from the bunched up section to the section where the molecules are further apart. The wave is moving toward me at 1,130 f/s
  • Slide 29
  • Sound Waves The sound wave is traveling toward me however, the molecules are not moving toward me. An example would be a garden hose, when I shake it a snaky wave travels away, however, the hose is not moving only the wave energy is moving along it. Other examples would include: sound, water, and football fans
  • Slide 30
  • Sound Waves Mechanical waves they require a medium to transfer energy. So sound will not transfer through a vacuum. Slinky demo Pulse and a wave moves one coil at a time Medium is the slinky. In water it is the water, at a concert it is the air, at a football game its the fans in the stadium
  • Slide 31
  • Intensity The amount of energy which is transported past a given area of the medium per unit time Intensity = energy / (time x area) Since power is energy per unit time, it can also be written as: Intensity = power / area Typical units are Watts/meter 2
  • Slide 32
  • Intensity Inverse square relationship The mathematical relationship of intensity and the distance from the source As you move away from the source (larger distance) the area gets larger and the intensity will decrease. If the distance from a source doubles the intensity will decrease by a factor of 4.
  • Slide 33
  • Threshold of Hearing Humans can detect sound of very low intensity. The faintest sound which the ear can detect has an intensity of 1x10 -12 W/m 2. At this level sound will displace particles of air by a mere one-billionth of a centimeter.
  • Slide 34
  • Loudness Loudness of a noise is a more subjective response. Factors that affect the perception of loudness includes age and frequency
  • Slide 35
  • Sound Intensity The average rate at which sound energy is flowing through a unit area Intensity can be measured by means of a twin microphone probe, with signal processing by a microprocessor controlled cross correlation spectrum analyzer Measurement of intensity is very useful in industrial noise situations
  • Slide 36
  • Decibels The decibel scale is a logarithmic scale. The logarithmic scale is based on multiples of 10. A sound which is 10 times more intense is assigned a sound level of 10 dB. A sound which is 100 times more intense is assigned a sound level of 20 dB. A sound which is 1000 times more intense is assigned a sound level of 30 dB.
  • Slide 37
  • Decibels Threshold of hearing 0 dB Whisper20 dB Normal conversation60 dB Street traffic70 dB Vacuum cleaner80 dB Walkman at max setting 100 dB Threshold of Pain130 dB Military Jet Takeoff140 dB
  • Slide 38
  • Sound Pressure and Sound Pressure Level Sound pressure is the root mean square (rms) value of the pressure changes above and below atmospheric when used to measure steady state noise. The sound pressure level is the ratio expressed in decibels (dB) of the rms pressure to a reference rms pressure.
  • Slide 39
  • Sound Pressure Level Sound pressure level (Lp) is: L p = 10 log (P / P o ) 2 = 20 log (P / P o ) Where : P o = the reference sound pressure of 2 x 10 -5 N/m 2 L p = sound pressure level in dB P = rms sound pressure in N/m 2
  • Slide 40
  • Sound Pressure Level For a sound source having a sound pressure of 1 N/m 2, what is the sound pressure level in dB? Lp = 20 log (P/Po) = 20 log ((1 N/m 2 )/(2x10 -5 N/m 2 ) = 20 log (0.5 x 10 5 ) = 94 dB
  • Slide 41
  • Sound Pressure Level If the sound source has a sound pressure of 2x10 -3 N/m 2, what is the sound pressure level in dB?
  • Slide 42
  • Sound Pressure Level If the sound source has a sound pressure of 2x10 -3 N/m 2, what is the sound pressure level in dB? Lp = 20 log (P/Po) = 20 log ((2x10 -3 N/m 2 )/(2x10 -5 N/m 2 ) = 20 log (1 x 10 2 ) = 40 dB
  • Slide 43
  • Sound Pressure Level Weighted sound levels Fletcher-Munson curves. Ear is most sensitive around 2 to 5 kHz
  • Slide 44
  • Decibel Addition To add individual sound levels the equation to add these is: L T = 10log(10 L 1 /10 +10 L 2 /10 +10 L 3 /10 ++ 10 L n /10 ) Example: Two machines each operate at 93 dB at a given location. What is the sound pressure level if both machines are on?
  • Slide 45
  • Decibel Addition Add to sound pressure levels of 93 dB together L T = 10log(10 L 1 /10 + 10 L 2 /10 ) L T = 10log(10 93/10 + 10 93/10 ) L T = 10log(2 x 10 9.3 ) = 96 dB
  • Slide 46
  • Decibel Addition Exercise: Three machines have the following sound pressure levels at a given measurement location: 95, 96, 100 dB What is the resulting sound pressure level if all three machines are on?
  • Slide 47
  • Decibel Addition Rule of thumb (can only be used when a limited number of sources are added together) 0 dB differenceadd 3 dB to the higher value 1-1.5 dB differenceadd 2.5 dB 2-3 dB differenceadd 2 dB 3.5 to 4.5 dBadd 1.5 dB 5 to 7 dBadd 1 dB 7.5 to 13 dBadd 0.5 dB
  • Slide 48
  • Decibel Addition Using the rule of thumb in the previous exercise, find the total sound pressure level:
  • Slide 49
  • Sound Pressure Level in decibels of common sources of noise See page 38 and 39 in your manual Examples: refrigerator 50 dB rainfall 50 dB doorbell 80 dB