Physics 42200 Waves & Oscillations · Phys42200_Lecture29 Author: mjones Created Date: 3/25/2013...
Transcript of Physics 42200 Waves & Oscillations · Phys42200_Lecture29 Author: mjones Created Date: 3/25/2013...
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Physics 42200
Waves & Oscillations
Spring 2013 SemesterMatthew Jones
Lecture 29 – Geometric Optics
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Geometric Optics
• When the wavelength of light is much smaller
than the dimensions of objects it interacts
with, we can ignore its wave nature.
• Multiple paths by which light can reach a
given point – phases are random (incoherent).
• We are generally not concerned with
polarization.
• Treat light as rays propagating in straight lines
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Geometric Optics
• Under these conditions, the only physical
principles we need to describe the
propagation of light are:
���
��
��
��
��Reflection:
��� =��Refraction:
�� sin �� = �� sin ��
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Geometric Optics
• Each point on an illuminated
surface is a source of spherical
waves
– Rays diverge from that point
– We perceive an image as the
collection of points from which
the rays emerge
• An optical system can cause the rays to diverge from a different point
– We perceive this point as an image of the original object
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Geometric Optics
• A point from which a portion of the spherical wave diverges is a focus of the bundle of rays
• A point to which the portion of the spherical wave converges is also a focus of the bundle of rays
• The paths are reversible
• P and S are conjugate points
Object spaceImage space
�
�
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Geometric Optics
• A lens is a refractive device that
changes the curvature of the
wavefront
• All points on the wavefront have the same optical
path length (OPL)
= 1������
�
���→ ��� = � � � ��
�
�
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Geometric Optics
• Typical problems in geometric optics:
– Given an optical system, what are the properties of the image that is formed (if any)?
– What configuration of optical elements (if any) will produce an image with certain desired characteristics?
• No new physical principles: the laws of reflection and refraction are all we will use
• We need a method for analyzing these problems in a systematic an organized way
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Types of Images
• Real Image: light emanates from points on the image
• Virtual Image: light appears to emanate from the image
Virtual
Image
Real image
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Spherical Mirrors
Central axis �
����
�
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Spherical Mirrors
Central axis
�
�� ��
�
Image distance, ��
Object distance, �
Focal length, �
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Focal Points of Spherical Mirrors
Sign convention:
• Concave:
– Radius of curvature, > 0– Focal length, � > 0
• Convex:
– Radius of curvature, < 0– Focal length, � < 0
1� + 1
�′ =1�
� = 2
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Properties of Images
Central axis
��
1. Ray parallel to central axis reflected
through focal point
2. Ray through focal point reflected parallel
to central axis.
Reflected rays pass through the image:
it is a real image
The image is inverted.
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Properties of Images
Central axis
��
Object distance, � > 0Focal length, � < 0Image distance, �� < 0
1� + 1
�′ =1�
Reflected rays do not pass
through the image, even
though they might appear to…
the image is virtual.
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Lenses
• Insert a transparent object with � > 1 that is
thicker in the middle and thinner at the edges
Spherical waves can be turned
into plane waves.
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Aspherical Surfaces
• What shape of surface will change spherical
waves to plane waves?
• Time to travel from S to plane DD’ must be
equal for all points A on the surface.
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Aspherical Surfaces
• This is the equation for a hyperbola if �' ��⁄ > 1 and
the equation for an ellipse if �' ��⁄ < 1.
��*+� + *,
+' = ��-��*.� + �'-*,.
�
��* + �'��
*, = constant
nti ≡ nt/ni > 1 - hyperbola nti ≡ nt/ni < 1 - ellipsoid
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Spherical Lens
• Law of cosines: 3� = 4� + �� 5 24� cos*ℓ7 = 8� + �7 + 8 � 5 28-�7 + 8. cos9ℓ� = 8� + �� 5 8 � + 28-�� 5 8. cos9
object distance
image distance
Optical
axis
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Spherical Lens
Fermat’s principle: Light will travel on paths for which
the optical path length is stationary (ie, minimal, but
possibly maximal)
ℓ7 = 8� + �7 + 8 � 5 28-�7 + 8. cos9ℓ� = 8� + �� 5 8 � + 28-�� 5 8. cos9
��� = ��ℓ7� + ��ℓ�
�� ����9 = ��8 �7 + 8 sin9
2ℓ7 5 ��8 �� 5 8 sin92ℓ� = 0
��ℓ7 + ��
ℓ� = 18
����ℓ� 5 ���7
ℓ7 But P will be different for
different values of 9…
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Spherical Lens
��ℓ7 + ��
ℓ� = 18
����ℓ� 5 ���7
ℓ7• Approximations for small 9:
cos 9 = 1sin 9 = 9ℓ7 = �7ℓ� = �����7 + ��
�� = �� 5 ��8
• The position of P is independent of the location of A over a small area close to the optical axis.
• Paraxial rays: rays that form small angles with respect to the optical axis.
• Paraxial approximation: consider paraxial rays only.
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• For parallel transmitted rays, �� → ∞���7 + ��
�� = �� 5 ��8 → ��
�7 = �� 5 ��8
• First focal length (object focal length):
�7 = ;<;=>;<
8• Second focal length
�� = ;=;=>;<
8(Image focal length)
8 > 0, �� > �� → � > 0 (converging lens)
Spherical Lens
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Spherical Lens
• When 8 < 0:
�� = ���� 5 �� 8
A virtual image appears on the object
side.
�7 = ���� 5 �� 8
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Sign Conventions
• Assuming light enters from the left:
�7, �7 > 0 when left of vertex, @�� , �� > 0 when right of vertex, @
8 > 0 if � is on the right of vertex, @
object distance
image distance
Optical
axis
���7 + ��
�� = �� 5 ��8
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Sign Conventions
• Convex surface:
– �7 is positive for objects on the incident-light side
– �� is positive for images on the refracted-light side
– 8 is positive if � is on the refracted-light side
�� A
�� �� > ���7 ��
���7 + ��
�� = �� 5 ��8
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Sign Conventions
• Concave surface:
– �7 is positive for objects on the incident-light side
– �� is negative for images on the incident-light side
– 8 is negative if � is on the incident-light side
��A
�� �� > ���7
�����7 + ��
�� = �� 5 ��8
(same formula)
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Central axis
Spherical Lens8 > 0�7 > 0�� < 0
�7 ��
���7
�7��
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Magnification
• Using these sign conventions, the
magnification is
B = 5 �������7
• Ratio of image height to object height
• Sign indicates whether the image is inverted