Phuong phap giai pt vo ti
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Transcript of Phuong phap giai pt vo ti
- - 2011.
1
( ) ( )n nf x b a af x b ,a b R (1).
( ) ( ( ) ) ( ) ( )nng x af x b g x b af x (2).
( ) ( )n nf x b ag x (3)
( ) ( )
( ) ( )
n
n
g x b af x
f x b ag x
.
.
.
:
:3 31 2 2 1x x .
2, 1, ( )a b f x x .
33y 2x 1 y 1 2x .
V y ta có h :
3
3
x 1 2y
y 1 2x
. Tr ủa h :
3 3 2 2x y 2(y x) (x y)(x xy y 2) 0 x y
(Do 2 2 2 2y 3
x xy y 2 (x ) y 2 02 4
) Thay vào h ta có:
3 3 2x 1 2x x 2x 1 0 (x 1)(x x 1) 0
- - 2011.
2
x 1
1 5x
2
. V m: 1 5
x 1;x2
.
2 3
2 42
xx x
, , ( )a b f x .
( )f x .
. ( )f x .
Ta 2 22 4 2( 2 )x x x x =
2 2 22 4 2( 2 1) 2 2( 1) 2x x x x x .
( )f x = .
( )f x
2 (x 1) 22(x 1) 2
2
2 1 x 1(x 1) 1 1
2 2
.
1
2, .
t
2 ty 1x 1 t
t x 1; y 1 1 22 2
y 0
.
Ta có h :
2
2
1t 1 y
2
1y 1 t
2
t y1
(t y)(t y ) 0 12 y t
2
*
2 2tt 1 2t t 2 0
t y 2t 0t y 0
1 17 3 17
t x4 4
(th a x 3 ).
- - 2011.
3
*
2 21 t(t ) 1 4t 2t 3 0
1 2 2y t 112 tt 22
1 13 5 13t x
4 4
(th x 3 ).
V m: 3 17 5 13
x ;x4 4
.
Gi 2x x 1000 1 8000x 1000 .
1
x8000
2 1000 1000 1 8000x x x .
( )f x .
.
PT24x 4x 4000 4000 4000(2x 1) 3999
2(2x 1) 4001 4000 4000(2x 1) 4001 ( )f x = 2 1, 4000, 4001x a b ).
t u 2x 1; v 1 8000x ; 4001
v 0,u4000
, ta có h
2 2
2 2 2
u 4001 4000v u 4001 4000v
v 4001 4000u u v 4000(v u)
2u 4001 4000v (1)
(u v)(u v 4000) =0 (2)
. Do u v 4000 0 nên T (2) ta có:
u v c:2u 4000u 4001 0
u 0
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4
u 4001 x 2001 . V m: x 2001 .
, , ( )a b f x .
,a b do
.
Gi 24x 7x 1 2 x 2 .
( )f x a =2).
2 24 (2 )x x 2( ) (2 )f x x c c .
( )f x o.
2(2x 1) 3x 2 2(2x 1) 3x . .
t 2t 2x 1; y 2t 3x y 3x 2t và y 0 .
Ta có :
2
2
t 3x 2y y t(t y)(t y 2) 0
y t 2y 3x 2t
.
*
22 4x 3x 1 0
1t 2t 3x 0y t x1 4t 0 x
2
.
*
22 4x 11x 7 0
t 3x 2(t 2) 0y t 2 3
t 2 x2
7x
4 .
V m: 7 1
x ;x4 4
.
Gi 2 24x 11x 10 (x 1) 2x 6x 2 .
2( ) (2 )f x x c .
- - 2011.
5
c :
2 2 2 2
2
4 4 ( 11 4 ) 10 ( 1) ( 1)(2 ) ( 11 4 ) 10
(11 4 ) 10 .
x cx c c x c x x x c c x c
b c x c
3c .
PT 2(2x 3) x 1 (x 1) (x 1)(2x 3) x 1
t u 2x 3; v (x 1)(2x 3) x 1 ,
Ta có h
2
2
u x 1 (x 1)v
v x 1 (x 1)u
2 2u v (x 1)(v u) (u v)(u v x 1) 0
* 2u v u x 1 (x 1)u 2(2x 3) x 1 (x 1)(2x 3)
22x 6x 7 0 m.
* 2u v x 1 0 2x 3 2x 6x 2 x 1 0
22x 6x 2 4 3x 2
4x
3
7x 18x 14 0
h vô nghi m.
V m.
3 2 233 6 3 17 3 9( 3 21 5)x x x x x .
ủ vn.com.
( ) (3 ) ( )f x x c f x x c
( ) (3 )f x x c .
PT 3 2 2327 54 27 153 27 9( 3 21 5)x x x x x . (*)
- - 2011.
6
Tuy nhiên .
.
. ủ
c b =
). b
= 281x . ủ
227x c 3c . .
3 2 2 23 3(3 3) (27 126 108 ) 27 9( 3 21 5) 27 27(3 3) (27 126 108 )x x x x x x x x .
.
233 3; 27(3 3) (27 126 108 )u x v x x x .
3 2
3 2
(27 126 108 ) 27
(27 126 108 ) 27
u x x v
v x x u
.
33 2 210 2 7 23 12x x x x x .
3 2( ) ( 2) ; 7 22 10, 1f x x b x x a .
3 2 232; 7 23 12 ( 2) ( 7 22 10)u x v x x x x x .
3 2
3 3
3 2
2 2
3 2
2 2 2 2
7 22 10
7 22 10
( )( 1) 0
( 2) 7 23 12(*)
31 0 ( ) 1 0(**)
2 4
u x x vu v v u
v x x u
u v u v uv
x x xu v
vu v uv u v
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7
3 2 2(*) 5 11 4 0 ( 4)( 3 1) 0
4
3 5
2
3 5
2
x x x x x x
x
x
x
3 5 3 5
4; ;2 2
x x x
.
ủ .
.
3 27 23 12x x .
4t x . Thay 3 27 23 12 6x x = t , do 4t
2 . 3 22 7 23 12t x x .
3 2 2
3 2
3 3 2 2 2 2
6 12 7 23 4
10 4
6 6 13 13 0 ( )( 6 6 13) 0
t t t x x
x x x t
t x t x x t t x t x tx t x
.
2 2 6 6 13 0
t x
t x tx t x
3 23 2
22 2
( 2) 7 23 12(*)2 7 23 12
3[( 3) ] 3 4 0(**)( 3) ( 3) 3 4 0
2 4
x x xx x x
xt x xt x t x x
- - 2011.
8
3 2 2(*) 5 11 4 0 ( 4)( 3 1) 0
4
3 5
2
3 5
2
x x x x x x
x
x
x
3 5 3 5
4; ;2 2
x x x
.
a
" "
a " "
B 8: Gi 32 21
8x 13x 7 (1 ) 3x 2x
.
ủ .
33 2 28x 13x 7x (x 1) 3x 2 . (*)
v . v
.
( ) (2 1)f x x
(*) 3 2 23(2x 1) (x x 1) (x 1) (x 1)(2x 1) x x 1
3 2u 2x 1; v 3x 2
Ta
3 22 2
3 2
u (x x 1) (x 1)v(u v)(u uv v x 1) 0
v (x x 1) (x 1)u
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9
* 3 2 3 2u v 2x 1 3x 2 8x 15x 6x 1 0
2x 1
(x 1)(8x 7x 1) 0 1x
8
.
* 2 2 2 2u 3
u uv v x 1 0 (v ) (2x 1) x 1 02 4
2 2u4(v ) 12x 8x 7 0
2
2 2 2u4(v ) 4x 2(2x 1) 5 0
2 m.
V ghi m: 1
x 1; x8
.
( )f x " "
.
9: Gi 2 2 237x 13x 8 2x . x(1 3x 3x ) .
. Tuy nhiên . 2x .
32 3 2
7 13 8 1 32 3
x xx x x . (*)
1
tx .
33 2 28t 13t 7t 2 t 3t 3 .
3 2 23(2t 1) (t t 1) 2 2(2t 1) t t 1 .
t 23u 2t 1, v 2(2t 1) t t 1 , ta có h
3 23 3
3 2
u t t 1 2vu v 2v 2u
v t t 1 2u
2 2(u v)(u uv v 2) 0
- - 2011.
10
3 2u v 2t 1 t 3t 3 3 28t 13t 3t 2 0
2(t 1)(8t 5t 2) 0 2
t 1t 1
5 89t8t 5t 2 0
16
.
Th l i ta th y ba nghi m này th
V m: 16
x 1; x5 89
.
Tuy n
c
( )f x t t .
t
t x
. .
10: 2 22 2 1 (4 1) 1x x x x .
. 2 2 21 1 1(*)x t x t .
2 22( 1) 2 1 (4 1) 2 (4 1) 2 1 0t x x t t x t x . (**)
Xem (**
2 2
1
2
(4 1) 8(2 1) (4 3)
4 1 4 3 11
4 2(*)
4 1 4 32 1
4
x x x
x xt
x xt x
1t do (*). 2t t
v
2
2 2
2
2 1 12 1, 1 2 1
1 (2 1)
1 4.
33 4 0
xt x x x
x x
xx
x x
- - 2011.
11
t .
x
x - 1). .
1: 2 23 5 6 2 3x x x x x .
.
2: 2 22 6 7 5 3 5x x x x .
2 3 5t x x ; 0t .
PT 22 5 3 0t t . 3t . 2 3 5 3 1 4x x x x .
t
t .
ủ
3: 2 26 14 98 35 6x x x x
2 2 26 35 98 6 14 6 14 .t x x x t t t x
K
2
2
6 14
6 14
x x t
t t x
.
.
t ,x t .
trên.
. .
: Gi 3 38x 4x 1 6x 1 .
.
2 298 35 6 6 14t x x x x
- - 2011.
12
5 7x cos ;x cos ;x cos
9 9 9
.
: 3 31 3 3 1x x .
2 4 8
2cos ;2cos ;2cos .3 3 3
: 2 3
2 4 , 12
xx x x
.
3 17
4x
7: 2 4 2 2 2x x x .
5 17
2x
.
: 24 3 1 5 13x x x .
15 97 11 73
;8 8
x
.
: 33 2 2 32 10 17 8 2 5x x x x x x
33 2 2 21 4 2 7.
4
xx x x x x
232 32 2 15 20x x x . ( .
1 9 221
;2 16
x
.
2 210 6 2(2 1) 2 4x x x x x
: 17 97 17 97
;12 12
x x
.
2 22 12 6 2 2 4x x x x
- - 2011.
13
-8;-2; 0; 6}
G
22 4 3 5
2 2 52
x xx x
.
S= { 5 1 3 5
;2 4
}.
32 22 6 5 3 3 2x x x x .
3 5 3 5
;2 2
}.
.
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