Pd 5 Chemistry March 18, 2010

Balance the equation

Write the equation

Start the ratio

Go to the Next part of the Question!!!

Hint: What do we need to figure out the moles part of the stoichiometry problem…

Go Back to 1st Q

2Hg + O2 2HgO

Hg + O2 HgOHg Hg + O2

Go to the Next part of the Question!!!

Hint: Is the equation balanced.

Go Back to 2st Q

What’s FIRST?

gHg

molHggHg

59.200

21

gHg

molHggHg

59.200

20.15

gHg

molHggHg

59.200

10.15

Go to the Next part of the Question!!!

Hint: Are all the numbers correct in the ratio equation?

Go Back to 3st Q

gHg

molHggHg

59.200

10.15

molHgO

gHgO

molHg

molHgO

1

59.216

2

2

gHgO

molHgO

molHg

molHgO

59.216

1

2

2

molHgO

gHgO

molHgO

molHg

2

59.216

2

2

HgOHg 22 2

Go to the Next part of the Question!!!

Hint: Look at the element, amount, and where they are placed on the ratio equation.

Go Back to 4st Q

NEXT

molHgO

gHgO

molHg

molHgO

gHg

molHggHg

1

59.216

2

2

59.200

115

And then…And then…And then… And then… And then…

Have to start Stoichiometry

for O2

We are done

Hg is limiting

Go to the Next part of the Question!!!

Hint: What do we need to decide if something is limiting

Go Back to 6st Q

Next?

molHgO

gHgO

molO

molHgO

gO

molOgO

1

59.216

1

2

32

120

22

22

gHgO

molHgO

molHgO

molO

gO

molOgO

95.216

1

2

1

32

11 2

2

22

gHgO

molHgO

molO

molHgO

gO

molOgO

59.216

1

1

2

32

120

22

22

HgOOHg 22 2

Go to the Next part of the Question!!!

Hint: Look at the element, amount, and where they are placed on the ratio equation.

Go Back to 7st Q

270.7 g HgO

NEXT

molHgO

gHgO

molO

molHgO

gO

molOgO

1

59.216

1

2

32

120

22

22

O2 =270.7 g HgO

Hg= 16.2 g HgO

Hint: The smaller number is limiting because there less of that element to use.

Go Back

YAY!!!! We’re done