Part Time Sfti

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    PART TIME SFTI

    NAME: AMRIT BOODRAM

    ID#: 54949

    COURSE CODE: CCTD 101B

    COURSE TITLE: ENGINEERING THERMODYNAMICS

    LAB TITLE: TWO SHAFT GAS TURBINE DEMONSTRATION

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    AIM:To obs!" $ o%!&'o( o) & *o s$&) +&s ,!b'( &(- .&/.,/& 's ))'.'(.

    RESULTS:

    CALCULATIONS:

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    A'! M&ss )/o*

    ma =2.729*104PNPaTa

    ma=2.729*1040.0050.001302.15

    ma=3.5gs

    A'!2F,/ R&'o

    airfuel ratio=mamf

    where mf=2.39 gs

    3.2gs2.39 gs=1.33

    S%.')'. F,/ Co(s,3%'o( s).

    sfc=mftu2

    here tu2=2!N2T"#0

    tu2=2!40.3*10000.44#0

    tu2=1$5#.$9 att

    mftu2=1.331$5#.$9*3#00

    mftu2=2.57$ g.%w&

    P!ss,! 6%&(s'o( R&'o 1

    rco=P2P1

    rco=0.4$0.0094

    rco=51.0#

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    Co3%!sso! Po*!

    78co=ma'(aT2)T1

    co=3.51.005357.15)30$.15

    co=172

    I-&/ o,%, &'! 3%!&,! coi=ma'(aT2i)T1

    To )'(- W.o' )'!s T8' (-s o b -!3'(- )!o3 5

    T2iT1=P2P1+)1+=rco+)1+

    T2i30$.15=51.0#0.2$5

    T2i=30$.15*3.0#

    T2i=943

    ,coi=3.51.005943)30$.15

    coi=22330;

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    Co3%!sso! 's(!o%'. ))'.'(. 4-coi=coico=T2i)T1T2)T1

    -coi=2233.0$172

    -coi=13

    Co3%!sso! 's(!o%'. %!o.ss 5T2iT1=P2P1+)1+=rco+)1+

    T$'s $&s b( .&/.,/&- %!"'o,s/

    coi=2233.0$

    Co3%!sso! 's(!o%'. ))'.'(. 's

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    T,!b'( P!ss,! 6%&(s'o( R&'o

    rtu1=P3P4

    rtu1=0.1111$

    rtu1=0.000932

    T,!b'( T$!3&/ E))'.'(.-tui=T3)T4T31)1rtu1+)1+*100

    -tui=1034.15)94#.151034.151)10.0009321.7297*100

    -tui=$

    T,!b'( Po*!

    tu1=ma/mf*'(gT3)T4

    tu1=3.5/2.#3*1.14$1034.15)94#.15

    tu1=#19.3

    Losss b*( .o3%!sso! &(- ,!b'(tu1=co/&osses

    #19.3=172.35/&osses

    &osses=#19.3)172.35

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    &osses=44#.95

    O"!&// ,!b'( %o*!

    tu1o=co/coi2

    tu1o=172.35/#19.32

    tu1o=39#

    O"!&// .o3%!sso! %o*!coo=tu1/co2

    coo=#19.3/172.352

    coo=39#

    T,!b'( 3.$&('.&/ ))'.'(.-tu1m=tu1/co2tu1*100

    -tu1m=#19.3/172.352#19.3*100

    -tu1m=#3.9

    Co3%!sso! 3.$&('.&/ ))'.'(.-com=2cotu1/co*100

    -com=2172.35#19.3/172.35*100

    -com=43.5

    O"!&// Co3%!sso! 's(!o%'. ))'.'(.-coo=-co*-com*100

    -coo=12.9*0.435

    -coo=5.#

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    O"!&// G&s ,!b'( 's(!o%'. ))'.'(.

    -tu1o=-tu1*-tu1m*100

    -tu1o=0.1#*0.#39

    -tu1o=10.2

    G&s T,!b'( P!ss,! R&'ortu2=P4P5

    rtu2=0.11$0.012

    rtu2=9.$3

    G&s T,!b'( Is(!o%'. E))'.'(.-tu2i=1)T5T41)1rtu2+)1+

    ,-tu2i=1)$9#.1594#.151)19.$30.57$

    -tu2i=0.072

    G&s T,!b'( Po*! 8

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    DISCUSSION: T$ ))'.'(. o) $ (+'( *&s .&/.,/&- ,s'(+ $ !s,/s &(- $

    -3o(s!&'o( o) $ *o s$&) ,!b'( (+'( *&s s,..ss),/

    CONCLUSION: I *&s .o(./,-- $& $ *o s$&) ,!b'( (+'( )o//o*s $ )'!s /&* o)

    (!+ '( 's ../s