Parallel Lines Cut by a Transversal - 7TH & 8TH...

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Geometry P a r a l l e l L i n e s C u t b y a T r a n s v e r s a l A Mathemagical Puzzle FREEBIE A l i g n e d t o t h e C o m m o n C o r e S t a t e S t a n d a r d s 8 . G . A . 5 Grades 7-10

Transcript of Parallel Lines Cut by a Transversal - 7TH & 8TH...

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Geometry

Parallel Lines Cut by a

Transversal A Mathemagical Puzzle

FREEBIE

Aligned to the Common Core State Standards

8.G.A.5 Grades

7-10

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Teacher’sGuide

CCSS8.G.A.5

Useinformalargumentstoestablishfactsabouttheanglesumandexterior

angleoftriangles,abouttheanglescreatedwhenparallellinesarecutbya

transversal,andtheangle-anglecriterionforsimilarityoftriangles.For

example,arrangethreecopiesofthesametrianglesothatthesumofthethree

anglesappearstoformaline,andgiveanargumentintermsoftransversals

whythisisso.

Objective

•  Studentswillbeabletodetermineanglerelationshipsandmeasureswhen

parallellinesarecutbyatransversal.

Materials

•  “ParallelLinesCutbyaTransversal”Worksheet

•  Projectorand/orDocumentCamera(optional)

Procedure

•  Givestudentsabout5minutestoworkthroughthepuzzleontheirown.

•  Havestudentsworkinpairsorsmallgroupsforabout10moreminutes.

•  Discussasalargegroup.Here’smypersonalprocedure:

–  Iprojectthepuzzleonthefrontboard.

–  ThenIcallonestudentuptotheboardtoXillin3anglesmeasures

thattheyknowbasedontheinformationalreadyXilledin.

–  Iaskacoupleofdifferentstudentstoprovidevocabularywordsto

describepairsofanglemeasuresthatwerejustaddedtothefront

board.

–  Repeatuntilallanglesmeasureshavebeendiscussed.

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Name:______________________________________________________________Class:__________Date:____________________

ParallelLinesCutbyaTransversalAMathemagicalPuzzle

Directions:Determinethemeasureofeachofthelabeledanglesgiventhatlinesmandnareparallel.

© Free to Discover (Amanda Nix) – 2016

52o 44o m

n

t u

1 = ___ 2 = ___

3 = ___ 4 = ___ 5 = ___ 6 = ___

7 = ___

8 = ___ 9 = ___

10 = ___

11 = ___ 12 = ___ 13 = ___ 14 = ___

15 = ___ 16 = ___ 17 = ___ 18 = ___

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Name:______________________________________________________________Class:__________Date:____________________

ParallelLinesCutbyaTransversalAMathemagicalPuzzle–AnswerKey

Directions:Determinethemeasureofeachofthelabeledanglesgiventhatlinesmandnareparallel.

© Free to Discover (Amanda Nix) – 2016

52o 44o m

n

t u

1 = 128o 2 = 136o

3 = 128o 4 = 52o 5 = 44o 6 = 136o

7 = 84o

8 = 96o 9 = 96o

10 = 84o

11 = 136o 12 = 44o 13 = 52o 14 = 128o

15 = 44o 16 = 136o 17 = 128o 18 = 52o

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