Organic Chemistry: Benzene and Its Derivates
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Transcript of Organic Chemistry: Benzene and Its Derivates
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Organic Chemistry IVBenzene and Its Derivates
Indra Yudhipratama
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Outline Aromaticity
Huckel’s rule The Reactions (Electrophilic
Substitution) Halogenation Friedel-Craft’s Reaction
Alkylation and acylation Nitration and sulphonation Oxidation and reduction of
benzene derivates
Disubstitution (Ortho, meta, para directing groups)
Phenol and aniline The relative acidity of phenol The relative basicity of aniline Diazoniums compounds
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The Main Features The bond length is between C – C and C=C (1.38 A)
Due to delocalised electron (resonance structure)
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The Main Features The structure is planar Each carbon has p orbital that forms π bonding Maximum bonding benzene should planar
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p Cloud Formation in Benzene
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Aromaticity (Hückel’s Rules) Huckel’s rules define the classification of aromatic and non-aromatic
molecule. The criteria of aromatic molecule:
All the atoms are sp2 hybridised and in planar cyclic arrangement.All atoms are sp2 but not a cyclic. Hence, non-aromatic
There is non-sp2 atom. Hence, non-aromatic
All atoms are sp2 and a cyclic. Hence, could be aromatic
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Huckel’s rules
Huckel’s rule Number of π-electrons is (4n+2), How to calculate π-electrons?
based on the structure, p-orbitals in sp2 arrangement has 1 electron
Has 6 π-electrons (4n+2, n=1)Hence, aromatic
Has 4 π-electrons (4n, n=1)Hence, anti-aromatic
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Huckel’s Rule (summary)
Is the molecule has no non-sp2
atoms?
YES NO
How many π-electrons in the
molecule?
4n+2 Not 4n+2
aromatic Anti-aromatic
non-aromatic
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Huckel’s rules
Porphyrin ring in the haem groupN
NH N
HN
OHO
HOO
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Huckel’s rule
Which molecules are aromatic?
Is this molecule aromatic?
N
HN
6 π-electrons 2 π-electrons
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The reactions
Benzene undergoes electrophilic substitution
Doesn’t undergo electrophilic addition
The consequence of aromatic properties
E+E
+ H+
Cl2
Cl
Cl
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The reactions - Halogenation Halogenation. E.g. chlorination
Via:
The presence of Lewis acid (e.g. AlCl3) helps benzene to react with Cl2
Cl2
AlCl3
Cl
Cl
Al
Cl
Cl
Cl Cl
Cl
Al
Cl
Cl
Cl Cl
H
Cl
H
Cl
H
Cl
H
Cl Cl
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The Reactions – Friedel-Crafts Reaction
Friedel-Crafts Reaction (Alkylation) To substitute with hydrocarbon chain
Via:
Cl
AlCl3
Cl
Al
Cl
Cl
Cl
Cl
Al
Cl
Cl Cl
Electrophilic generation
H
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The reactions Friedel-Crafts Reaction
There is a problem for this reaction when longer alkyl halide is used
Rearrangement of the electrophile (carbocation)
Trying to find the most stable carbocation
Cl
AlCl3
+
+ +
ClAlCl3
H
H
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The Reactions Friedel-Crafts Reaction (Acylation) To substitute with R-CO –
Via:
Electrophilic generation acylium ion stabilised by resonance. Both structures are valid.
Cl
O
AlCl3
O
Cl
O
Cl
Al
Cl
Cl
Cl
O
Cl
Cl ClO
O
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The reactions
Acylation can be used to get around the ‘messy’ long chain alkylation.
O
O
H
O
Cl
O
AlCl3
O
H2NNH2
KOH
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The Reactions The nitration (concentrated sulphuric acid as catalyst)
Via:
HNO3
conc. H2SO4
NO2
O
N
O
OHO
S
OH
O O
H
O
N
O
OH2O
N
O
O
N
O NO2
H
NO2
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The Reactions
Sulphonation
Via:
conc. H2SO4 or
SO3, conc. H2SO4
SO3H
HO
S
O
O O
H
HO
S
OH
O O
H2O
S
OH
O O
S
OO
OH
S
OO
OHO
S
O
O O
H
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The reactions Sulphonation
Producing strong sulphonic acid
S O
O
HO
SO3H
H
SO3H
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The Reactions The Oxidation of toluene
Where R is alkyl group The Reduction of Aniline
ROH
O
1 ) K M n O 4 , O H -, H e a t
2 ) H 3 O +
NO2 NH2F e
H C l
aniline
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The Reactions Formation of Diazonium salts
Diazonium salts is a good precursor compound for: Halogenation formation of phenol deamination coupling reaction of arenediazonium salts
NH2 N+ N
Cl-
N a N O 2 , H C l
H 2 O
0 - 1 5 oC
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The Reactions
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The Reactions Coupling reaction of arenediazonium salts
Where Q is activating group ( –OH, –NR3).
E.g.:
N+ N
Cl- +
Q
N
N Q
N+ N
Cl- +
OH
O+
NN
HH
Cl- OH
NN
N+ N
Cl- +
OH
OH
NN
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Disubstitution of Benzene The benzene ring can be substituted with another FG more than once. The second position is determined by the first FG
Three possible positions:
ortho (1,2) meta (1,3) para (1,4)
CH3 NH2 OH ClCH3O OHONH2O
NH CH3
O
R
R1
R
R1
R
R1
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Disubstitution of Benzene The determining factor
The nature of FG electron withdrawing (EW) or electron donating (ED) group
EW: the FG generally has partial positive charge It deactivate the benzene ring, so it is less reactive
ED: the FG generally has partial negative charge It activate the benzene ring, so it is more reactive
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Disubstitution of Benzene
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Disubstitution of Benzene E.g. Application for synthesis route
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Phenol The structure
The relative acidity Acidity The easiness to release H+ (proton) The stability of the acid conjugate determine the relative acidity. The comparison with water and alcohol (e.g. ethanol)
OH
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Phenol Let’s put water as the standard and the conjugate.
More stable the conjugate, more acid the substance. In ethoxide ions the alkyl group push the electrons increasing the charge In phenoxide ions, it forms a bigger resonance structure due to unbonding
p-orbital
OH
O H
H CH3
OH
O-
O-
HCH3
O-
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Phenol The effect of substituent
The principle: The reduction of the charge The deactivating benzene substituent will make phenol more acidic The activating benzene substituent will make phenol less acidic.
Phenol 3-methylphenol 3-nitrophenol 3-chlorophenol
pKa = 9.89 pKa = 10.01 pKa = 8.28 pKa = 8.80
OH OH
CH3
OH
Cl
OH
NO2
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Phenol
Predict the pKa of 2,4 dinitrophenol.
(a) 10.17
(c) 8.11
(d) 3.96
(b) 9.31
OH
NO2
NO2
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Phenol Esterification of Phenol No reaction with carboxylic acid
Only react with acyl chloride or acetic anhydride
OH+ CH3
OH
O H 3 O +
No reaction
+Cl
OOH
+O
OOH
O
O
O
base
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Phenol Suggest the products from the reactions below
OH
O
OH
EtOH
H3O+
O
OO
conc. H2SO4
O
O
OH
OH
O
O
O
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Phenol How to distinguish with alcohol?
Since the phenol is more acidic than alcohol, so it can reacts with weaker base (e.g. NaHCO3)
Both of them can react with Na
OHNaHCO3
O
Na
+ CO2 + H2O
OHNaHCO3
OH O
NaNa
+ 1/2 H2
OH O
NaNa
+ 1/2 H2
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Aniline The Basicity of amines
Basicity >< Acidity Basicity How easy a compound can accept H+
The case: The relative Basicity of ethylamine, amine, and aniline
The easiness of compound to accept H+
The availability of lone pair electrons on N atom
CH3 NH2 NH3
NH2
aniline
ammoniamethanamine
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Aniline The reactions
Phenylamine cannot react in the similar way like amine. Phenylamine is not a better nucleophile than amine
the availability of the electrons on N atom to do the reaction
H N O 3
c o n c d H 2 S O 4
N+
O-
O
F e /S n
H C l
NH2 N a N O 2 , H C l
0 - 1 5 oC
N+ N
Cl-
NH2n-BuCl
NH2
n-BuCl
HN
This reaction can produce the other amines. Could you draw the other products?
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Aniline Phenylamine could form an amide with acyl chloride.
Important synthetic pathway for aniline-based compound
NH2
Cl
O
HN
O
NH2
H2N
+Cl
O
O
Cl
HN
NH
O
O
n