Normal Stress and Strain
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Transcript of Normal Stress and Strain
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TENSION, COMPRESSION, AND
SHEAR
Sridhar Condoor
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What is Mechanics of Materials?
Deals with the behavior of solid bodies
subjected to different types of loads
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Skyscrapers of Fazlur Khan
Khan used a taper in theJohn Hancock building toreduce the wind loadsand 18-story tall exterior
steel diagonalsthefamous X-bracestocarry this load.
The buildingsconfiguration is a tubestiffened by the floors.
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Skyscrapers of Fazlur Khan
Khan designed theWillis Tower using thebundled tubeapproach.
Nine separate steel-framed square
buildings, each 75 feetsquare, are interlockedto form a massivestructure.
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Skyscrapers of Fazlur Khan
Benefits:
Reduced the material requirements. The net
saving in steel alone is about $10 million.
The tubes terminated at different levels creating
more rentable windowed space (space with
windows as opposed to internal space).
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Design Task
Need Float coins using aluminum foil.
The goal is to float as much weight as possiblewithout wetting the coins.
The size of the foil is 5 X 5.
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Insights
Interrelated subjects
Strength
Stiffness
One or multiple boats
Sheet size translates
into cost
Tipping
Loading
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Prismatic Bar
A straight structural member of constant
cross-section.
Cross-section is taken perpendicular to the
length of the beam.
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Tension - Compression
Tension - The tensile
force or tension
stretches the bar and
increases its length.
Compression - A
compressive force or
compression decreases
the length of the bar.
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Is this a valid tensile loading?
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Examples
Tension
The cable supporting the
elevator
Belt in the belt/pulley
system
Tensile members of a truss
Compression
Legs of a stool
Walking stick
Nail being hammered
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Uniaxial Load
Tension
Not fail-safe
Does not buckle
Compression
Fail-safe
Buckling
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Normal Stress
Intensity of force
where F is the force
andA is the cross-
sectional area.
The stress is independent of structural material and
the length of the prismatic bar.3:24 AM
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Units - Stress
Force/Area
N/m^2 or Pascal
lb/in^2 or psi
7000 Pascal = 1 psi
Sign convention
Tensile stress positive
Compressive stress
negative
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Stress - Strength
The magnitude of the stress alone does not
provide any insight into whether a structure
safe or not.
The stress must be compared to what the
material can safely withstand the strength of
the material.
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Normal Strain
Elongation per unit
length
Dimensionless quantity
Sign convention
Tensile strain positive
Compressive strain
negative
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PROBLEM
A circular aluminum tube
of length L 400 mm is
loaded in compression by
forces P. The outside and
inside diameters are 60
mm and 50 mm,
respectively. A strain gage
is placed on the outside of
the bar to measure normal
strains in the longitudinal
direction.
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PROBLEM
(a) If the measured strain
is 550x10-6, what is the
shortening of the bar?
(b) If the compressive
stress in the bar is
intended to be 40 MPa,
what should be the load
P?
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SOLUTION
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PROBLEM
The cross section of aconcrete pier that isloaded uniformly incompression.
(a) Determine the averagecompressive stress inthe concrete if the loadis equal to 2500 k.
(b) Determine thecoordinates x and y of
the point where theresultant load must actin order to produceuniform normal stress.
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SOLUTION
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SOLUTION
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PROBLEM
A loading crane consistingof a steel girder ABCsupported by a cable BDis subjected to a load P.
The cable has an effectivecross-sectional area A =481 mm2.
The dimensions of thecrane are H = 1.6 m, L1 =3.0 m, and L2 = 1.5 m.
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PROBLEM
(a) If the load P = 32 kN,
what is the average
tensile stress in the
cable?
(b) If the cable stretches
by 5.1 mm, what is the
average strain?
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SOLUTION
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SOLUTION
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SOLUTION
T=102 kN
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STRESS-STRAIN DIAGRAMS
TENSION TEST
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ENGINEERING STRESS-STRAIN DIAGRAM
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ENGINEERING STRESS-STRAIN
DIAGRAM
Nominal stress
Nominal strain
0
PA
0L
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PROPORTIONALITY & ELASTIC LIMIT
Proportional limit: the highest stress at which
stress is directly proportional to strain.
Elastic limit: the greatest stress the material
can withstand without any measurable
permanent strain after unloading.
Elastic limit > Proportional limit
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YIELD STRENGTH
A. Stress at whichconsiderableelongation occurswithout change in
the stress level
B. Offset yield strength -the stress required to
produce a smallspecific amount ofdeformation.
Strain
Stress
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ULTIMATE TENSILE STRENGTH
Ultimate tensile strength or tensile strength Su
is the maximum load Pmax divided by the
original cross-sectional area Ao of the
specimen.
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Engineering Stress-Strain Curve for
Brittle Materials
Perfectly linear
Do not have a yield
point.
Do not strain-harden -
the ultimate strengthand breaking strength
are the same.
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True Stress-Strain or Flow Curve
A true indication of
deformation
characteristics
Based on the true
instantaneous area of
the specimen.
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Specific Stiffness Ratios
E (psi) Density
(lb/in3)
Specific
stiffness
Steel 30 E6 0.283 .106 E 9
Aluminum 10.5 E6 0.1 .105 E 9
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Hookes Law
Strain is directly proportional to stress
E
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Poissons Ratio ()
The negative ratio of
the transverse strain
(perpendicular to the
applied load), to theaxial strain (in the
direction of the applied
load)
Poissons ratio 0 0.5
lateral
longitudinal
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Poissons Ratio ()
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Problem
A steel bar of length 2.5
m with a square cross
section 100 mm on
each side is subjectedto an axial tensile force
of 1300 kN.
Assume that E 200 GPa
and v 0.3.
Determine the increase in volumeof the bar.
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E 200 GPa and v 0.3.
Solution
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Solution
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SHEAR STRESS
Stresses acting parallel
to the surface
PA
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Single vs Double Shear
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BEARING STRESS
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BEARING STRESS
Applied load over
bearing area
Bearing area is theprojected area
In this case, projectedarea is equal to ??????
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PROBLEM
Three steel plates, each 16 mmthick, are joined by two 20-mm diameter rivets.
A. If the load P 50 kN, what isthe largest bearing stressacting on the rivets?
B. If the ultimate shear stressfor the rivets is 180 MPa,what force Pult is required tocause the rivets to fail inshear?
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SOLUTION
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SOLUTION
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Ductility vs Brittleness
DOES A CD FAIL IN A DUCTILE OR BRITTLE
MANNER?
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DUCTILITY VS BRITTLENESS
Ductility - Is a qualitative measure of a
material that indicates the ability of the metal
to flow plastically before failure.