Nonfinite basicity of one number system with constant
description
Transcript of Nonfinite basicity of one number system with constant
Nonfinite basicity of one number system with
constant
Almaz Kungozhin
Kazakh National University
PhD-student
ACCT 2012, June 15-21
Outline
• History
• Definitions
• Known results
• New definitions
• Main result
History• L. Zadeh, Fuzzy sets, Inform. and Control
8 (1965), 338-353.
• P. Hádjek, L. Godo, F. Esteva, A complete many-valued logic with product-conjunction. Arch. Math. Logic 35 (1996) 191-208.
• A.Kungozhin, Nonfinite basicity for a certain number system, Algebra and Logic, v.51, No 1, 2012, 56-65
t-norms
• Łukasiewicz (Ł) t-norm
x ∗ y = max(0, x + y − 1)
• Gödel (G) t-norm
x ∗ y = min(x, y)
• Product t-norm
x ∗ y = x · y
Negations
• ”Classical” fuzzy negation
¬x = 1 - x
• Godel’s negation
¬0 = 1, ¬x = 0 for x > 0
A = [0;1], ¬, , =A1 = [0;1], ¬, , 1, =
where
[0, 1] is the segment of real numbers
¬(x) = 1 – x (negation)
x · y (ordinary product)
= – symbol of equality
1 – distinguished constant
Terms
0-complexity terms: x, y, .., x1, x2,...(,1)
If t, t1 are terms of complexity n, and complexity of t2 is not bigger than n, then
¬(t), (t1) (∗ t2) and (t2) (∗ t1)
are terms of complexity n + 1
IdentityTerms t1(x1, x2, …, xn) and t2(x1, x2, …, xn)
are identical in algebra
t1(x1, x2, …, xn) = t2(x1, x2, …, xn)
iff equation is satisfied in algebra for every values of variables.
Remark 1. Terms are identical iff so are their corresponding polynomials
Examples of identities
x = (x)
x y = y x
(x y) z = x (y z)
x y = y (x)
(x y) z = (y z) x
Basis of identitiesA basis in a set of identities is its subset such that
every identity turns out to be logical consequence of the basis.
(Birghoff’s completeness theorem 1935)
{bi(x1, x2, …, xni)= i(x1, x2, …, xni): iI}- basis
iff for any t = it is possible to build a chain
t t0 = t1 = ... = tk
each following term is obtained from previous by changing a subterm bi(1, 2, …, ni) to the
subterm i(1, 2, …, ni) (and vice versa)
Nurtazin conjecture (1997)
The basis of identities of the number system A = [0;1], ¬, , = is
x = (x)
x y = y x
(x y) z = x (y z)
Contrary instance
(x (y x y)) = (x y) (x y)
since
1 – x(1 – yx(1 – y)) = 1 – x + yx2 – y 2x2
(1 – xy) (1 – x(1 – y)) = (1 – xy) (1 – x+ xy) = 1 – x+ xy – xy + yx2 – y 2x2 =
= 1 – x + yx2 – y 2x2
Theorem
A system of identities in the number system A does not have a finite basis.
1-trivially identical terms
Two terms are 1-trivially identical (t 1) if they can be derived from each other by substitutions using equations (t) = t, t1 t2 = t2 t1, t1 (t2 t3) = (t1 t2) t3, t1 1 = t1, t1 1 = 1
Examplesx y 1 y (x), (x y) z 1 (y z) x
(x (y x y)) = (x y) (x y), but
(x (y x y)) 1 (x y) (x y)
1-trivial terms
A term t called A1-trivial iff any term identical to it is A1-trivially identical to it.
ExamplesTerms x, (x), (x y) are trivial.
Terms (x (y x y)), (x y) (x y) are not trivial.
Simplifying S(t)
Any A1-term can be simplified by applying the rules (t) = t, t1 1 = t1, 1 t1 = t1, t1 1 = 1, 1 t1 = 1 for any subterm in any order
The minimal term is S(t)
Remark 1. t1 t2 = t2 t1, t1 (t2 t3) = (t1 t2) t3 are not used
Remark 2. S(t) 1, or S(t) ¬1, or doesn’t contain 1’s.
Remark 3. S(t) defined correctly
Properties of S(t)
• t = S(t)
• t 1 if and only if S(t) S() (1 1, ¬1 ¬1)
• t is A1-trivial if and only if S(t) is trivial
• If S(t) is nested (then it is trivial) then t is A1-trivial
Theorem
A system of identities in the algebra
A1 = [0;1], ¬, , 1, =
does not have a finite basis.
Proof (by contradiction)
Let there is a finite basis then we add to it trivial axioms: double negation, commutative, associative lows and (if they are absent):
• x 1 = x• x ¬1 = ¬1Using simplification we can 1-trivially and
equivalently reduce this basis to a basis of identities without 1’s, and the equations x 1 = x, x ¬1 = ¬1, 1 = 1, ¬1 = ¬1. (Let maximal number of variables is lesser than n).
Series of nontrivial equations
For every even positive number n
¬(x1¬(x2… ¬(xn-1¬(xnx1¬(x2…¬(xn-1¬(xn))…) =
¬(x1x2… xn-1xn)¬(x1¬(x2…¬(xn-1¬(xn))…)
is valid in the algebra A1.
Thank You for Your Attention!