NMR Lecture 5. Factors affecting 13 C NMR spectra Proton decoupler always on, no pulse delay How do...

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NMR Lecture 5
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Transcript of NMR Lecture 5. Factors affecting 13 C NMR spectra Proton decoupler always on, no pulse delay How do...

NMR Lecture 5

Factors affecting 13C NMR spectra

Proton decoupler always on, no pulse delay

How do you know 3 microsec = 22°

Pulse delay 400 s; gated decoupler-on only when acquiring signal

Effects of the pulse delay between pulses, 400 s

Proton decoupler always on (NOE)

Information obtained by examining nmr spectra

1. Chemical shift (identifies nature of nucleus2. Area (identifies relative number of nuclei)3. Multiplicity ( (NOE)

2D NMR basically provides information about connectivity and proximity

Applications of 1H and 13C NMR

Molecular formula C9H10O

IR: 1720 cm-1

area: 5: 2: 3

CH2 CH3

O

Molecular formula C7H14O2

IR 1720 cm-1

1H NMR

CCH3 CH2

CCH3

O OCH3

CH33:2:3:6

F NMR of F3

CF24

CF25H

=CF3-

F

FF

F

NH2

H

Returning to Dynamic Nuclear Magnetic Resonance

For a simple exchange process coalescence /21/2

Most chemical shift differences are of the order of a few hundred Hz or less. Rate constants are of the order of few hundred sec-1. Large in comparison to k 10-4 – 10-5 sec-1, measured by conventional kinetics but small relative to many dynamic processes occurring in molecular systems such as rotations about bonds.

Assign the spectrum and explain the coupling observed

Let’s do a thought experiment

What would the NMR spectrum of the methyl resonances of 4-dimethyl-3-hydroxycyclobutenone look like if all the methine hydrogens of this molecule had the same spin?

HO

OCH3

H

CH3

HO

OCH3

H

CH3

J13, J15 are the same sign

J13 J15 are of opposite sign

HO

OCH3

H

CH3

J13, J15 are the same sign

J13, J15 are of opposite sign

What are some mechanisms by which the two methyl groups can become identical?

HO

OCH3

H

CH3

O

H

CH3

CH3

H

O

O

CH3

H

CH3

OH

H2O

HO

OCH3

H

CH3

O

CH3

H

CH3

OH

O

O

H

CH3

H

CH3

HO

OCH3

H

CH3

HO CH3

OHCH3

O

CH3

H

CH3

OH

H2O

HO

OCH3

H

CH3

O

CH3

H

CH3

OH

HO CH3

OHCH3

HO

OCH3

H

CH3

OH

O CH3

H

H3C

1,3-hydrogen shift

HO

OCH3

H

CH3

OH

O CH3

H

H3C

1,3-hydrogen shift

HO

OCH3

H

CH3

J is the same sign

J is of opposite sign

OH

O CH3

H

H3C

HO

OCH3

H

CH3

HO CH3

OHCH3

O

CH3

H

CH3

OH

HO

OCH3

H

CH3

O

CH3

H

CH3

OHO

O

H

CH3

H

CH3

1,3-hydrogen shift; JAX

and JAM of the same sign O

CH3

H

CH3

OH

HO

OCH3

H

CH3

HO

OCH3

H

CH3

1,3-hydrogen shift; JAX and JAM of the opposite signs

O

CH3

H

CH3

OH

Problem Set DNMR

By line shape analysis, determine the activation energy for rotation about a carbon nitrogen bond in an amide.

Go to my gateway and down load the Excel file.

A plot of ln k vs 1/T should result in a straight line and the slope of the line should be - Ea/R. Your problem will be to fit the lineshapes as best you can and evaluate k for a series of temperatures. Remember that the most accurate k values will be when the line shapes change the most.

k = rate constant