Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.
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Transcript of Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.
![Page 1: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.](https://reader036.fdocuments.net/reader036/viewer/2022083009/5697bfbb1a28abf838ca0ad8/html5/thumbnails/1.jpg)
Newton’s Law of Gravitation
Chapter 7, Section 3
Pg. 263-265
![Page 2: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.](https://reader036.fdocuments.net/reader036/viewer/2022083009/5697bfbb1a28abf838ca0ad8/html5/thumbnails/2.jpg)
Newton’s Universal Law of GravitationNewton’s Universal Law of Gravitation
EarthMOON
Fg
To keep two moving bodies from shooting off in a straight line, a mutual gravitational force attraction occurs between them.
FEmFmE
![Page 3: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.](https://reader036.fdocuments.net/reader036/viewer/2022083009/5697bfbb1a28abf838ca0ad8/html5/thumbnails/3.jpg)
The amount of gravitational force that occurs between two masses depends on the distance between the two masses.
Newton’s universal law of gravitation
Fg = (G m1m2 )/r²
G = constant of universal gravitation
G = 6.673 x 10-11 Nm²/kg²
![Page 4: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.](https://reader036.fdocuments.net/reader036/viewer/2022083009/5697bfbb1a28abf838ca0ad8/html5/thumbnails/4.jpg)
Sample Problem 2Find the distance between a 0.300 kg billiard ball and a 0.400 kg billiard ball if the magnitude of the gravitational force is 8.92 x 10-11 N.
r = ?m1 = 0.300 kg m2 = 0.400 kg
Fg = (G m1m2) /r²Fg = 8.92 x 10-11 N
r² = (G m1m2) / Fg
r = √(G m1m2) / Fg
r = √[6.673 x 10-11 Nm²/kg² (0.4 kg) (0.3kg)]/8.92x10-11 N
r = 3.00 x 10-1 m
G = 6.673 x 10-11 Nm²/kg²