Newtonian derivation of Plank's quantum error h (constant)

8/8/2019 Newtonian derivation of Plank's quantum error h (constant)

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Newtonian derivation of Plank's quantum error h (constant) and E = h

Greetings: My name is Joe Nahhas founder of real time physics and astronomy

Abstract: Nobel Prize winner sciences are based on the silly ideas of space- time travel,

or, quantum - relativistic - strings mechanics and space- time travel is not any science

Plank's E = h can be derived from Newton's time dependent mechanics as rotational

measurement error made on rotating Earth. Max Plank's E = h ; h = 6.62606957 x 10-34

Joules - second is plank's constant [1]and is particle frequency is Planet Earth rotationalmeasurement error when Earth's (mass x areal velocity) is measured inversely as the photo

electric effect.

Newton's equation solution

Newton's equation is:

F = m; = [r" - r '] r1+ [2 r' ' + r "] 1

With m (r" - r ')= - Gm M/r2 Eq-1

And 2 r' ' + r "= 0 Eq-2

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I - Real numbers or time independent solution

Eq-2: 2 r' ' + r "= 0

Multiply by r> 0

Then 2 r r' ' + r2"= 0

Or, d (r')/d t = 0

And integrating: r' = h = constant

With m (r" - r ')= - Gm M/r2

Then, (r" - r ')= - GM/r2

Let u = 1/r; r = 1/u; r' = h = /u

And r' = d r/d t = (d r/ d u) (d u /d ) (d / d t)

= (- /u ) (d u /d ) '

= (-'/u ) (d u /d )

= - h (d u/ d )

And r' = d r/d t = - h (d u/ d )

And r" = d r/ d t = d (d r'/ d t)/ d t

= d [- h (d u/ d )]/ d t

Multiply (d / d )

Then r" = d r/ d t = {d [- h (d u/ d )]/ d t} (d / d )

= ' {d [- h (d u/ d )]/ d }

= - h (d u/ d )

= (- h/r) (d u/ d )

= - h u (d u/ d )

And r" = d r/ d t = - h u (d u/ d )

With d r/dt - r ' = - G M/r2 E q 1

And - h u (d u/ d ) (1/u) (h u) = - G M u2

Then (d u/ d ) + u = G M/h2

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And u = G M/h2+ A cosine

The r = 1/u = 1/ (G M/h2+ A cosine ); divide by G M/h2

And r = (h2/G M)/ [1 + (A h2/G M) cosine ]

With; h2/G M = a (1 - 2); (A h2/G M) =

This is Newton's equation classical solution

Or, r = a (1 - 2)/ (1 + cosine ); definition of an ellipse ------------- I

Newton's time independent solution

II - Real time or complex numbers solution :

Newton's equation in polar coordinates

F = m; = [r" - r '] r1+ [2 r' ' + r "] 1With m (r" - r ')= - Gm M/r2 Eq-1

And 2 r' ' + r "= 0 Eq-2

Eq-2: 2 r' ' + r "= 0

Separate the variables: 2 r' ' = - r "

Or 2(r'/r) = - ("/') = - 2 ( + )

Then: (r'/r) = +

Or d r/r = ( + ) d t

Then r = r 0(+ )t

And r = r (, 0) r (0, t); r 0= r (, 0)

And r = r (, 0) (+ )t

And r (0, t) = (+ )t

With r (, 0) = a (1 - 2

)/ (1 + cosine )

Then, r (, t) = [a (1-)/ (1+ cosine )] (+ )t ------------- I

If time is frozen that is t = 0

Then r (, 0) = a (1-)/ (1+ cosine ) or classical

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Relativistic is the difference between I and Real II

With - ("/') = - 2 ( + )

Then ' = '0 -2 (+ )t

With '0 = h/[r (, 0)] 2

And '(, t) = [' (, 0)] -2(+ )t

And, '(, t) = ' (, 0) ' (0, t)

And ' (0, t) = -2(+ )t

At Perihelion:

We Have ' (0, 0) = h (0, 0)/r (0, 0) = 2ab/ 0 a (1- ) ;0 = orbital period

= 2a [ (1- )]/0a (1- ) ]

= 2[ (1- )]/0 (1- ) ]

Then '(0, t) = 2 [(1- )/ 0 (1- ) ] -2(+ )t

With = 0; then '(0, t) = 2 [(1-)/ 0 (1-) ] -2(+ )t

= 2 [(1-)/ 0 (1- ) ] (cosine 2 t - sine 2 t)

Real '(0, t) = 2 [(1- )/ 0 (1-) ] cosine 2 t

Real '(0, t) = 2 [(1-)/ 0 (1-) ] (1 - 2sine t)

Naming ' = '(0, t); '0 = 2 [(1-)/ 0 (1-) ]

Then ' = 2 [(1- )/ 0 (1- ) ] (1 - 2 sine t)

And ' = '0 (1 - 2 sine t)

And ' - '0 = - 2 '0 sine t = -2{2 [(1-)/ 0 (1-) ]} sine t

And ' - '0 = -4 [(1-)/0 (1-) ] sine t

With, v = spin velocity; v0 = orbital velocity; 0 = orbital period

And 0= tan-1 [(v + v0)/c]; light aberrations

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' = ' - '0

= - 4 [(1-)]/0 (1-) ] sine tan-1 [(v + v0)/c] radians per0

In degrees per period is multiplication by 180/

' = (-720) [(1-)/0 (1-) ] sine tan-1 [(v + v0)/c]

The angle difference in degrees per period is: = ( ') 0

= (-720) [(1-)/(1-) ] sine tan-1 [(v + v0)/c] calculated in degrees per century ismultiplication = 100 ;= Earth orbital period = 100 x 365.26 =36526 days and dividing byusing 0 in days: (100 /0)= in degrees per century

= (-72000 /0) [(1-)/ (1-) ] sine tan-1 [(v + v0)/c]

In arc second per century is multiplying by 3600

= - 3600 x 720 (100 /0) [(1-)/ (1-) ] x Sine tan-1 [(v + v0)/c]

Approximations I

With v


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And v0 = 48.14 km/sec [Mercury]; c = 300,000

(Calculated in arc second per century)

= (-720x36526x3600/0days) [(1-)/ (1-) ] [(v + v0)/c]

With = 0.206; [(1-)/ (1-) ] = 1.552; v = 3 meters per second

= (-720x36526x3600/88) 1.552 (48.143/300,000)

= 43 arc second per century

Summary

= (-720x36526x3600/0days) [(1-)/ (1-) ] [(v + v0)/c]

= (-720x36526x3600/88) 1.552 (48.143/300,000)

= 43 arc second per century; 8 arc second per century for Venus; v =41.26

Or, r = a (1 - 2)/ (1 + cosine ); definition of an ellipse

Rotating ellipse, r (, t) = [a (1-)/ (1+ cosine )] (+ )t ------------- I

In general:

1 = 1 is self evident; 2 = 2 is self evident

A = A is self evident; B = B is self evident

A = A; add and subtract B

A = B + (A - B); divide by B

(A/B) = 1 + (A - B)/B; multiply by D

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(A/B) D = D + [(A - B)/B] D --------------------------------- Equation - 1

C = C is self evident; D = D is self evident

Or C = C; add and subtract D

C = D + (C - D) ----------------------------------------------- Equation - 2

Comparing equations 1 and 2 yields, (1) AC = BD; (2) D = D; and (3)

C - D = [(A - B)/B] D

Or (C - D)/D = (A - B)/B

Or D/D = B/B; Divide by t

(1/D) ( D/ t) = (1/B) ( B/ t)

Limit [(1/D) ( D/ t)] = Limit [(1/B) ( B/ t)] = ( + )

t --- 0 t --- 0

Or, d B/B = ( + ) d t

Or, B = B0 e ( + ) t = Ae ( + ) t

B = Ae ( + ) t

Distance is A; real time distance is B = Ae ( + ) t

Or in general real time distance is r = r0 e ( + ) t

In general: Euclidean distance r0 measurement on rotating Earthr= r0 e t; = 0

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With r= r0 e t

The velocity equation is: v = [v0 + r0] e t ------------------- Equation - 3

The areal velocity : r v = [r0v0+ r02] e 2 t------------------- Equation - 4

Considering v0 = 0; r v = ( r02) e 2 t

And v2 = - r02 e 2 t = - r02 [cosine 2t + sine 2t]

With h = m r v/2 = - [m r02 /2] [cosine 2t + sine 2t]

Then, h x = - [m r02 /2] cosine 2t

And hy= - [m r02 /2] sine 2t

Also, hy/ h x= tan 2t

Consider the following:


A = A is self evident; B = B is self evident

Or A = A; add and subtract B

A = B + (A - B); divide by B

(A/B) = 1 + (A - B)/B; multiply by D

(A/B) D = D + [(A - B)/B] D --------------------------------- Equation - 1

C = C is self evident; D = D is self evident

Or C = C; add and subtract D

C = D + (C - D) ----------------------------------------------- Equation - 2

Comparing equations 1 and 2 yields, (1) AC = BD; (2) D = D; and (3)

C - D = [(A - B)/B] D

A = Sun - Mercury - distance = 58.2 x 109 meters;

B = Sun - Earth distance = 149.6 x 109 meters

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Sun - Mercury Period in seconds = 88 days x 24 hours x 60 min x 60 sec

Let D be planet Mercury angular velocity around the Sun

D= 2 x /88 x 24 x 60 x 60 radians per period

Planet Mercuryangular velocity around the Sun in arc second per century D

= (2 x /88 x 24 x 60 x 60) (180/ ) (36526/88) (3600)

= 70.75 arc sec per century.

A = 58.2 x 109; B = 149.6 x 109; D = 70.75

Andthe answer is[(A - B)/B] D = [(58.2 x 109 - 149.6 x 109)/ 149.6 x 109] x 70.75 = 43arc sec per/100 years

This equation said: (A/B) D = D + [(A - B)/B] D

Or, visual = actual + (visual - actual)

Or, visual = actual + visual effects

Measured = actual + (measured - actual)

Measured = actual + visual effects

Measured = actual + relativistic

(A/B) D = D + [(A - B)/B] D said

If measuring D, then multiplying by (A/B)

Same argument:


With hy= hyis self evident; h x = h x is self evident

Or hy= h y; then add and subtract h x

Then, h y= h x + (hy- h x); divide by h x

Then, (h y/ h x) = 1 + (hy- h x)/ h x; multiply by h0

And (hy/ h x) h0 = h0 + [(h y- h x)/ h x] h0 --------------------------------- Equation - 1

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With h = h is self evident; h0 = h0 is self evident

Or h = h; add and subtract h0

Then, h = h0 + (h - h0) ----------------------------------------------- Equation - 2

Comparing equations 1 and 2 yields, (1) h = (hy/ h x) h0; (2) h0 = h0

And (3) h - h0 = [(h y- h x)/ h x] h0

From (1) h = (hy/ h x) h0

With hy/ h x= tan 2t

Then h = h0 tan 2t

Measurement error I

A disc on a rotating spherical Earth has a circumference of 2 re and 2 re / re = 2 .Modern Nobel physicists and astronomers measurements were/are made in an inverse

square distance Newton's law and that would make the error 1/ (2). Modern Nobel

physicists and astronomers measure space distance vertically and that would make the

vertical error Sine-1[1/ (2)]. Modern Nobel physicists and astronomers use standard

time period Ts = 24 hours = 86400 seconds and not Earth's spin period Te = 86164

seconds and that bring the measurement error to (Te/ Ts) Sine-1[1/ (2)]. Modern

Nobel physicists and astronomers measure in air and not vacuum with air index of

refraction n a = 1.000293 brings the total measurement error to a value equals to:

Error 1is the celestial sphere:(1/ n a) (Te/ Ts) Sine-1[1/ (2)] = 23.44

This celestial sphere is a visual illusion or measurement error of spherical Earth

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In atomic physics the factor (Te/ Ts) is never considered and the quantity (Te/ Ts) is

taken out of (1/ n a) (Te/ Ts) Sine-1[1/ (2)] and the new value is and they use kinetic theoriesor volumes and hydrogen with hydrogen index of refraction 1.000132

Measurement error I is

(1/ n a) 3 Sine-1[1/ (2)] = 23.50276363 0

And h = h0 tan 2t;2 t = 2 x 23. 50 0= 47.0 5527270

Measurement error II

NASA's Earth data sheet: Earth's radius is re = 6, 371, 000 meters; Earth's densitye =5515 kg/m3; Earth's spin Te = 86164, but Te = 86164.08 by proceedings of the American

philosophical society held in 1884 page 132 and Te = 86164.09 by Practical handbook of

marine science. An average of 86164.085 is reasonable

Earth's mass: me= (4/3)e re3= (4/3) (5515) (6371, 000) 3= 5.973886146 x 1024 kg

Earth's he = h0 = me re2/2 = (5.973886146 x 1024) (6371, 000) 2/ (86164.085)

= 1.407070556 x1033 kg m2 sec-1

And he = 1.407070556 x1033 kg m2 sec-1 tan47.0 5527270

Then he tan 2 t= 1.509190303 x 1033

What Plank's mania did is an error measurement regarding gases mass x

areal velocity using emission spectrum or light or photo electric effect. They

used translational quantities and measured rotational quantities and the

emission did not rotate but Earth is rotating and what is measured is 1/he

The quantity h =1/ he tan 2 t = 6.62606957 x 10-34Joules - second plank's error

In theory: They made theoretical mistakes

With r= r0 e t

The velocity equation is: v = [v0+ r0] e t ------------------- Equation - 3

The velocity squared: v2 = [v0+ r0]2e 2 t------------------- Equation - 4

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At t = 0, time of measurement

And v2 = [v0+ r0]2

= v02 - 2 r02 + 2 r0 v0

And Kinetic energy E = m v2/2 = (m/2) [v02 - 2 r02 + 2 r0 v0]

E = (m v2/2) - (m v02/2)

E = - m 2 r02/2 + m r0 v0 Newtonian time dependent energy

E = Ex+ E y= - m 2 r02/2 + m r0 v0

I - Classical or time independent Newtonian time independent energy

Ex = - m 2 r02/2

= - m c2/2; r0 = c

= - h /2; m r02 = h; =

II - Modern or Nobel or Quantum - Relativistic or Newtonian time dependent energy

E y= m r0 v0

= mc2; r0 = c

= h ; m r02 = h; =

Conclusion is: The atomic - electronic shell structure measurements are an

inverse Earth nucleus and the electron is an inverse Sun electron

References: [1] NIST 2010 data

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Newtonian derivation of Plank's quantum error h (constant)

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