Neki tamo zadatak...
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Transcript of Neki tamo zadatak...
4.
- 1. EI=const., : =1.3[m], q=13[kN/cm2], F=5[kN], M=6[kNm], E=2.104[kN/cm2], d=10[kM/cm2], treba:1. ,1. , I- (JUS.C.B3.131),1. (), .
1. 1.1. - 1.
Y=0, YA + YB - Fq = 0...(a)MA = 0, F . 2a + Fq . a/2 - YB . a - M = 0....(b)X = 0, F - XB = 0...............................................................................................................(c) (12.23.) : XB = F = 6[kN] (b) je:
YB =
SLIKA
:Fq = qa = 13 . 1.3 = 16.9[kN] - , () :YA = Fq - YB = 16.9 11.88 = 5.02[kN]
1.2. () CD
FTC = YA = 5.02[kN]FTDq = YA - Fq = 5.02 16.9 = -11.88[kN]FTD = YA - Fq + YB = 5.02 16.9 + 11.88 = 0
1.3. () DB
FTD = F = 5[kN]FTB = F - XB = 5 - 3 = 2[kN]
1.4. ()
FaAC = - YA = -5.02 [kN]FaCD = - F = -5[kN] - CD;FaDB = - YB = -11.88[kN] - DB
1.5.
MC = 0;
2.
(6.3.) :
:
Msmax = 6[kNm] = 600 [kNcm] - , , I-, :Wx=89.10 [cm3] . I14, Ix=573 [cm4]
3. -
, () FE = 0. , () : =.................................................................................(d) EI=const., (d), :
- FV = 0, ,
, :
X = 0; F - XB = 0....................................................................................................(f)Y = 0; YA + YB - Fq - FE = 0..................................................................................(g)MA = 0; FE . 2a - YB . a + Fq . a/2 + F . 2a - M = 0..................................................(h)
(h) je:YB = 2FE + Fq/2 + 2F - M/a = 2FE + + 2F - (g), :YA = Fq + FE - YB = aq + FE - 2FE - - 2F - , :YA = - FE - 2F +
- , - 1.Tabela 1.(i)ZiMi = M(Zi)Mi/FE
1.0, aM1 = M - FEz-z
2.0, 2aM2 = M - FEa - Fz-a
3.0, aM3 = (aq/2 - FE - 2F + M/a)z - qz2/2-z
4.0, 2a00
1. (e), FE = 0, :
:
, :