MRSM Pengkalan Chepa Quick revision
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Transcript of MRSM Pengkalan Chepa Quick revision
MRSM Pengkalan ChepaQuick revisionGive reasons
on form 4 chemistry topics
Name………………………..Class………………
Chapter periodic table
1) K is situated below Na in group 1 elements. Atom K is more reactive than atom Na. Explain ( 3 marks)
Size of K atom is bigger than Na atom .
nuclei attraction ( force of attractions
between nucleus and electrons) in K atom
is weaker than Na atom.
• Potassium atom easier to donate/ release electron to form positive ion .
Chapter periodic table
2) Cl is situated above Br in group 17 elements. Atom Cl is more reactive than Atom Br . Explain ( 3 marks)
Size of Cl atom is smaller than Br atom .
nuclei attraction ( force of attractions
between nucleus and electrons) in Cl atom
is stronger than Br atom.
• Chlorine atom easier to gain electron to form negative ion .
Chapter periodic table3) Ne does not form compound with other atoms.
Explain ( 2 marks) Atom neon has stable electron
arrangement of octet .
So atom neon does not need to gain,
release or share electron with other atoms
Note: Only helium has duplet electron arrangement.
Other atoms in group 18, has octet electon arrangement.
4) Atom X and atom Y are situated in the same period in the periodic table. Which atom is smaller in size? . Explain( 3 marks)
• size of atom Y is smaller than X• number of proton of atom Y is more than atom X• nuclei attraction in atom Y is stronger
5) Sodium and lithium has similar chemical properties. Why?( 1 marks)
• sodium atom and lithium atom has the same number of valence electrons, that is one
6) Fluorine and chlorine has similar chemical properties. Why?( 1 marks)
• Fluorine atom and chlorine atom has the same number of valence electrons, that is seven
Chapter on chemical bonds
7) Covalent compound has low melting point and boiling point. Why?( 2 marks)
• The molecules are held by weak Van de Waals forces of attractions
• So less heat energy is needed to overcome the attraction8) Ionic compound has high melting point and boiling point. Why?( 2 marks)
• The ions are held by strong electrostatic forces of attractions
• So more heat energy is needed to overcome the attraction
Chapter on chemical bonds
9) Covalent compound does not conduct electricity in all states, but ionic compound conduct electricity in molten and aqueous state . Why?( 2 marks)
• Covalent compound consists of molecules and do not contain mobile ions.
• But ionic compound in molten or aqueous state contain mobile ions to conduct electricity
Chapter electrochemistry
10)Electrolysis of copper(II) sulphate solution using carbon electrodes . After one hour, the intensity of blue solution decrease. Explain( 1 marks)
Because the concentration of copper(II) ion decreases OR Copper(II) ions are discharge to copper atoms( Cu 2+ + 2e Cu)
11)Electrolysis of copper(II) sulphate solution using copper electrodes . After one hour, the intensity of blue solution remain the same. Explain( 3 marks)
• Rate of discharge of copper(II) ions at cathode( Cu2+ + 2e Cu)Is equal to• Rate of ionization of copper atoms to copper(II) ions at anode( Cu Cu2+ + 2e)
• Concentration of copper(II) ions remain constant
12) Explain the observation after 30 minutes experiment is carried out. ( 6 marks)
• Copper(II) ions are discharged to form copper atoms ( Cu2+ + 2e Cu)a) Brown deposit on copper metal
b) Zinc electrode becomes thinner
c) Intensity of blue solution decrease
• Zinc atom ionize to form zinc ions ( Zn Zn2+ + 2e)
• Concentration of copper(II) ions decrease /Copper(II) ions are discharged to form copper atoms ( Cu2+ + 2e Cu)
13) Diagram above shows neutralization reaction between sulphuric acid and NaOH. In this experiment, 20 cm3 of sulphuric acid needed to neutralize exactly the 25 cm3 alkali , NaOH
The experiment is repeated with 1.0 moldm-3
hydrochloric acid to replace the sulphuric acid . Predict the volume of hydrochloric acid needed to neutralise 25.0 cm3 the sodium hydroxide, NaOH solution. Give your reason.( 2 marks)
40 cm3 , conc of hydrogen ions in HCl is half than conc of hydrogen ions in
sulphuric acid
Replace with hydrochloric acid