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    Since only mass has an INERTIA, The term MOMENT OFINERTIA OF AREA applied to an area is misnomer(inappropriate).

    Last chapter (Chapter X- Centroid):The first moment of area, sometimes misnamed as thefirst moment of inertia:

    First moment of area is commonly used in engineeringapplications to determine the centroid of an object orthe statical moment of area.

    Chapter XI

    Page: 206

    http://en.wikipedia.org/wiki/Centroidhttp://en.wikipedia.org/wiki/Centroid
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    From Centroid:

    The moment of any area or First Moment of Inertia or First

    Moment of Area is defined as the product of the area and

    the perpendicular distance from the centroid of the area to

    the moment axis. ; dAxAx dAxAy

    Second moment of Inertia is defined as the product of thearea and square of the perpendicular distance from thecentroid of the area to the moment axis.

    If Axis is in the plane of an area is called RectangularMoment of Inertia:

    dAxIx2

    dAyIy2

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    Polar Moment of Inertia

    If Axis is perpendicular to the area called

    Polar Moment of Inertia:

    dAydAxdArJ2

    22

    SHOW THE ANIMATED CLIP TO DEFINE

    MOMENT OF INERTIA OF AREA

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    Radius of Gyration

    The Radius of Gyration k of an area is also amathematical conception defined by:

    A rectangular and polar Radius of Gyration

    Are respectably: I= k2A. andJ= k2A

    kx =

    Ix

    A ky =

    Iy

    A kO =

    JO

    A

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    yThe radius of gyration ofan areaAwith respect to

    thex axis is defined asthe distance kx, where

    Ix

    = kx

    A. With similar

    definitions for the radii ofgyration ofA with respect

    to they axis and withrespect to O, we have

    x

    kx

    2

    O

    kx =IxA

    ky =IyA

    kO =JOA

    A

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    Why Second Moment of Inertia

    also known as the Second Moment of the Areais a termused to describe the capacity of a cross-section to resistbending.

    It is a mathematical property of a section concerned with a

    surface area and how that area is distributed about thereference axis. The reference axis is usually a centroidal

    axis.

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    EXAMPLES

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    Example 135 (Page: 208)

    simple rectangular shape

    I y dAz 2

    bdydA

    b

    h/2

    h/2

    z

    y

    dy

    12

    883

    3

    3

    33

    2

    2

    3

    2

    2

    2

    bh

    hhb

    yb

    bdyyI

    h

    h

    h

    hz

    Centroidor Neutral axis

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    APPLICATION

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    I Is an Important value!

    It is used to determine the state of stress in a section. It is used to calculate the resistance to bending.

    It can be used to determine the amount of deflection in abeam.

    b

    h/2

    h/2

    z

    y

    y

    b/2

    b/2z

    h

    12

    3bhI

    z

    12

    3hbI

    z>

    Stronger section

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    Some Practical Concept

    Different types of Rectangular Section.Which one is more efficient to resistbending or deflection.

    [Square/rectangular/hollow or box etc] Why we use corrugated tin instead of

    plane sheet?

    If a beam is rectangular not squared howto place it.

    Why we use Truss in Mills or Factory?

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    Example 136(Page: 208): Triangle

    Determine the moment ofinertia of a triangle withrespect to its base.

    A differential strip parallel to the xaxis is chosenfor dA.

    dyldAdAydIx 2

    For similar triangles,

    dyh

    yhbdA

    h

    yhbl

    h

    yh

    b

    l

    Integrating dIx from y= 0 to y = h,

    h

    hh

    x

    yyh

    h

    b

    dyyhyhbdy

    hyhbydAyI

    0

    43

    0

    32

    0

    22

    43

    12

    3bhIx

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    Example 138: Circle

    a) Determine the centroidal polarmoment of inertia of a circular

    area by direct integration.

    b) Using the result of part a,determine the moment ofinertia of a circular area withrespect to a diameter.

    An annular differential area element is chosen,

    rr

    OO

    O

    duuduuudJJ

    duudAdAudJ

    0

    3

    0

    2

    2

    22

    2

    4

    2rJO

    From symmetry, Ix= Iy,

    xxyxO IrIIIJ 22

    2 4

    4

    4rII xdiameter

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    Next Class

    Transfer Formula