Modern Control System Lab. Changwon National University

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Modern Control System Lab. Changwon National University

Transcript of Modern Control System Lab. Changwon National University

반 복 문반 복 문

Modern Control System Lab. Changwon National University

- while 문문

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

- do - while 문문

Modern Control System Lab. Changwon National University

- for 문문

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

Modern Control System Lab. Changwon National University

#include <iostream>using namespace std;

int main(){// Prompt the user to enter two integerscout << "Enter first integer: ";cout << "Enter first integer: ";int n1;cin >> n1;

cout << "Enter second integer: ";cout << Enter second integer: ;int n2;cin >> n2;

int gcd 1;int gcd = 1;int k = 1;while (k <= n1 && k <= n2){if (n1 % k == 0 && n2 % k == 0)if (n1 % k == 0 && n2 % k == 0)gcd = k;

k++;}

cout << "The greatest common divisor for " << n1 << " and "<< n2 << " is " << gcd <<endl;

system("PAUSE");

Modern Control System Lab. Changwon National University

system( PAUSE );return EXIT_SUCCESS;

}