MH-CET 2014 Exam Pattern and Syllabus
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Transcript of MH-CET 2014 Exam Pattern and Syllabus
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JEE / MHCET 2014PHYSICS
An Approach ……………………………by Dr. Arun Shridharan Pillai
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•Board Examination is Repetition
•X or XII (BOARD) is practice
•JEE – No Repetition
•Aptitude is Tested
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Sr. No. CLASS XI CLASS XII
1Physical world and measurement Electrostatics
2 Kinematics Current Electricity
3 Laws of Motion Magnetic Effects of Current and Magnetism
4 Work, Energy and Power Electromagnetic Induction and Alternating Currents
5 Rotational Motion Electromagnetic Waves6 Gravitation Optics
7 Properties of Bulk Matter Dual Nature of Matter and Radiation
8 Thermodynamics Atoms and Nuclei
9Behavior of Perfect Gas and Kinetic Theory Electronic Devices
10 Oscillations and Waves Communication Systems
TOPICS in Physics for JEE
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• No change in Pattern and marking scheme. • The format is the same with 90 questions in total and 30 questions each for Physics, Chemistry and Mathematics. • Each correct answer gets 4 marks• Each wrong answer gets -1 mark.
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Weigtage of Topics for JEE-2014
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Simple Questions
with confusing
replies
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1. (x+5)/(x+5) = 1
(a) Always
(b) Not Always
(c) Only for Positive Numbers
(d) Only for Negative Numbers
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Correct Answer is (b)Not Always?????Why
Suppose x = - 5We know that 0/0=absurd
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2. Sin θ X Cot θ = Cos θ
WE THINK
Sin θ X Cos θ = Cos θ Sin θ
Now is it valid for θ =0
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1 Which of the following quantities have unit, but not the dimensions.
(a) dielectric constant
(b) coefficient of viscosity
(c) plane angle
(d) refractive index
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Questions of Deep Knowledge
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2. A block of mass 10kg is resting on a horizontal surface. A force of 50N is applied on it. If coefficient of friction between the block and the surface is 0.6. what will be the force of friction? (g = 10 m/s2)
(a) Zero
(b) 50 N
(c) 60 N
(d) 40 N
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CORRECT OPTION IS
(b) 50 N
fs = mgμ
fs = 10×10×0.6
fs = 60N
But applied force is 50N.
Hence, the block will not move.
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g
Rcos
R cos
g
R cos2
g
1 g
2 R cos
3. A hemispherical bowl of radius R is revolved around its vertical axis. A Light weight sphere in it also revolves in it, without sliping. The radius of the hemispherical passing through the sphere makes angle θ with the axis of rotation. The angular velocity of the sphere is:
(a) (b)
(c) (d)
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Solution:Motion of the sphere is like motion of conical pendulum.Hence R cos
T 2g
2but T
2 R cos2
g
g
R cos
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Questions on application mind
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1.Charge q moves around charge Q in circular path. The work done by charge Q on q is
(a) (b)
(c) Zero (d)
20
1 Qq
4 k r 0
1 q
4 k r
20
1 Qq2 r
4 k r
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Solution: Charge q is moving over an equipotential surface Hence, work done is zero.
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2. Time taken by radio waves to go come back from communication satellite is nearly
(a) 1s (b)
(c) (d) 4s
1s
4
1s
8
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Height of communication satellite above the surface of the earth is 36000 km.
∴ Distance travelled by radio waves = 72000 km
Velocity of radio waves = 3 × 108 m/s
8
6
6
72000kmtime
3 10 m / s
72 10 1time
300 10 4
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•Identify theoretical chapters •Identify numerical based chapters •Take Practice test
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• An other very important aspect of your JEE/NEET preparation will be the coaching institute– FACULTY – Delivery of Lecture– Concept Understanding and doubt solving
session– Periodic Test– Evaluation of test– Infrastructure
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Full Portion Tests
Time Table
Time Allotment
Mistakes
Confidence
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• Suggested Books For IIT-JEE/ NEET –Physics by H.C. Verma–Problems in Physics by I.E. Irodov –Problems in Physics by Resnick and
Halliday–ELECRICITY AND MAGNETISM by
Resnick and Halliday –Circuits devices and systems by R.J.
Smith
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Thank
you ...!Prof. (Dr) Arun Shridharan Pillai
Ph.D (Physics) , M.Sc (Physics), C-VLSI9819110096 / [email protected]