Mechanical Vibration Forced Undamped

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    BFF3103 Mechanical Vibration

    Forced Vibration Undamped

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    Lesson-03 Objectives

    Students will be able to:

    Obtain the harmonic response of systemshaving a SDOF

    Obtain the transfer function from the EOM

    Determine the total response frequency, peakresponse and bandwidth

    Analyze the displacement and transmitted force

    of the systems having base excitation

    Solve the problem related to undamped anddamped harmonic response SDOF vibration

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    Todays Objectives

    Students will be able to: Identify the harmonic response of SDOF

    Obtained the response of an undamped

    system under harmonic force

    Solve the problem related to damped SDOF

    force vibration

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    Forced vibrations occurs when external

    energy is supplied to the system during

    vibration

    The external force can be supplied

    through either an applied force or an

    imposed displacement excitation, which

    may be harmonic, nonharmonic but

    periodic, nonperiodic, or random in

    nature.

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    Harmonic response results when thesystem responses to a harmonicexcitation

    Transient response is defined as theresponse of a dynamic system tosuddenly applied nonperiodic

    excitations

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    There are 4 categories of F(t):

    (1) Harmonic (sin, cos) (3) Transient

    (2) Periodic (4) Random

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    Equation of Motion

    The equation of Motion Using Newtons Second

    Law of Motion:

    )(tFkxxcxm

    The homogeneous

    solution of the equation:

    0 kxxcxm

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    Response of an Undamped System Under

    Harmonic Force

    tFtF cos)( 0

    tFkxxm cos0

    tnDtnCthx sincos)(

    The homogeneous solution is

    where is the natural frequency.2/1)/( mkn

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    where denotes the static deflection

    where X is the maximum amplitude ofxp(t)

    tXtxp cos)(

    220

    1

    n

    st

    mkFX

    kFst

    /0

    Thus, t

    mk

    FtnDtnCtx

    cos

    2

    0sincos)(

    Because the exciting force and particular solution is

    harmonic and has same frequency, we can assume a

    solution in the form:

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    Using initial conditions

    Hence,

    00

    )0(and)0( xtxxtx

    n

    xD

    mk

    FxC

    0,2

    00

    tmk

    F

    tx

    tmk

    Fxtx

    n

    n

    n

    cos

    sincos)(

    2

    0

    0

    2

    0

    0

    The max amplitude: 2

    1

    1

    n

    st

    X

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    where the quantity is

    called the magnificationfactor, amplification factor, or

    amplitude ratio. The

    response of the system can

    be identified to be of three

    types from the figure.

    stX /

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    Case 1. When 0 < < 1, the denominator is positive

    and the response is given without change. The

    harmonic response of the system is in phase with

    external force.

    n/

    2

    1

    1

    n

    st

    X

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    where the amplitude,

    Case 2. When > 1, the denominator is negative

    and the steady-state solution can be expressed asn/

    tXtxp cos)(

    1

    2

    n

    stX

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    Case 3. When = 1, the amplitude X given

    becomes infinite. This condition, for which the forcing

    frequency is equal to the natural frequency of the

    system, is called resonance. Hence, the total responseif the system at resonance becomes

    tt

    tx

    txtx

    n

    nst

    n

    n

    n

    sin2

    sincos)( 00

    n/

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    Total Response

    1for;cos

    1

    )cos()( 2

    n

    n

    stn ttAtx

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    1for;cos

    1

    )cos()(2

    n

    n

    stn ttAtx

    and

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    Beating Phenomenon

    If the forcing frequency is close to, but not exactly equal

    to, the natural frequency of the system, beating may

    occur. The phenomenon of beating can be expressed as:

    ttmF

    tx

    sinsin

    2

    /)( 0

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    The time between the points of zero amplitude or the

    points of maximum amplitude is called theperiod of

    beating and is given by

    n

    b

    2

    2

    2

    The frequency of beating defined as

    nb 2