Mech320 Hw5 Solution Ch5

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5–6. Determine the force in each member of the truss and

state if the members are in tension or compression. Set

and .P2 = 1.5 kNP1 = 2 kN A

E D

30 30

B

C

3 m 3 m

P2P1



288



•5–9. Remove the 500-lb force and then determine the

greatest force P that can be applied to the truss so that none

of the members are subjected to a force exceeding either

800 lb in tension or in compression.600 lb

3 ft

3 ft

3 ft

P

3 ft

500 lb

A

C B

DF E



295



*5–16. Determine the force in each member of the truss,

and state if the members are in tension or compression. Set

.P = 4 kN

P

3 m

A C B

E

D

F

P

3 m 3 m3 m



299



*5–20. Determine the force in each member of the truss in

terms of the load P , and indicate whether the members are

in tension or compression.

A

B

C

DF

E

P

d

d

d d/ 2 d/ 2 d



300



•5–21. If the maximum force that any member can support

is 4 kN in tension and 3 kN in compression, determine the

maximum force P that can be applied at joint B. Take

.d = 1 m

A

B

C

DF

E

P

d

d

d d/ 2 d/ 2 d



302



5–23. The internal drag truss for the wing of a light

airplane is subjected to the forces shown. Determine the

force in members BC , BH , and HC , and state if the

members are in tension or compression.

2 ft

A B C D

J I H G

E

F

2 ft 2 ft 2 ft 1.5 ft

80 lb 80 lb60 lb

40 lb



305



5–26. Determine the force in members JK ,CJ , and CD of

the truss, and state if the members are in tension or

compression.

A

B C D F E

G

H

I J

L

K

6 kN8 kN5 kN4 kN

3 m

2 m 2 m 2 m 2 m 2 m 2 m



315



5–39. Determine the force in membersCD and GF of the

truss and state if the members are in tension or

compression.Also indicate all zero-force members.

1.5 m

2 m2 m

1 m 1 m

0.8 m

2 kN

1.5 kN

A

H

B D

G

C

F E

Mech320 Hw5 Solution Ch5

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