Me202 engineering mechanics l2

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DEVAPRAKASAM DEIVASAGAYAM Professor of Mechanical Engineering Room:11, LW, 2 nd Floor School of Mechanical and Building Sciences Email: [email protected] , [email protected] ME202: Engineering Mechanics (3:1:0:4) Devaprakasam D, Email: [email protected] , Ph: +91 9786553933

Transcript of Me202 engineering mechanics l2

Page 1: Me202 engineering mechanics l2

DEVAPRAKASAM DEIVASAGAYAMProfessor of Mechanical Engineering

Room:11, LW, 2nd FloorSchool of Mechanical and Building Sciences

Email: [email protected], [email protected]

ME202: Engineering Mechanics (3:1:0:4)

Devaprakasam D, Email: [email protected], Ph: +91 9786553933

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Newtonian Mechanics

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Engineering Mechanics

Devaprakasam D, Email: [email protected], Ph: +91 9786553933

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• Scalar Quantity- Has magnitude and has no associated direction• Examples: Volume, Time, Mass, Speed, Density, Temperature.• Vector Quantity- Has Magnitude and Direction • Examples: Force, Velocity, Moment, Acceleration

Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Scalar and Vector

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Facts

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• Push or Pull on a body• It is a vector

i

Y

X

Z

j

k

F = Fx i + Fy j ……(2D)

F = Fx i + Fy j + Fz k…..(3D)

Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Force

Sign Convention (+ve)

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• Express the 2D and 3D equilibrium equations for particle resulting from the application of Newton’s 1st Law

0

0

0

Y

X

F

F

F

3D

0

0

0

0

Z

Y

X

F

F

F

F2D

0

0

0

||

F

F

F

2 Independent Eqns & 3 Independent Eqns &

Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D and 3D Equilibrium

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Vector Addition

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Vector addition Example

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Vector addition Example

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

Home Work

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• Express a 2D force in terms of rectangular. components.

• Express a 2D force in terms of parallel and perpendicular components.

• Apply vector addition to find resultant of more than one force.

X

F

i

Y

j

θ

F = Fx i + Fy jFx= F cosθ

Fy= F sinθ

Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D Force representation

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D Force representation

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D Force Example

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D Force Example

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D Force Example

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Devaprakasam D, Email: [email protected], Ph: +91 9786553933

2D Force Example