May 13, 2015
Transcript of May 13, 2015
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Today
Make-Up Tests?
Review For Final Exam
Review Pythagorean Theorem
New Material: Distance Formula
Class Work 4.10
May 13
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2
x2 – x + 2 = 0
(x – 2)(x + 1) Solutions are: x = 2, x = -1
Extraneous Solution is x = -1
Final Exam Review:
Add, Subtract, Multiply, & Divide 𝟑𝟖
and 𝟕𝟗. Reduce to its simplest terms.
a. 𝟑
𝟖+ 𝟕𝟗
= 𝟑
𝟖+ 𝟕𝟗
= 𝟖𝟑𝟕𝟐
= b. 𝟑
𝟖- 𝟕
𝟗= 𝟐𝟕−𝟓𝟔
𝟕𝟐= - 𝟐𝟗
𝟕𝟐
c. 𝟑
𝟖•𝟕
𝟗= 𝟐𝟏
𝟕𝟐= 𝟕
𝟐𝟒d.
𝟑
𝟖÷ 𝟕
𝟗= 𝟑
𝟖•𝟗
𝟕= 𝟐𝟕
𝟓𝟔=
1𝟏𝟏𝟕𝟐
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Pythagorean Theorem
81 – 26 = 𝟓𝟔 = A building is on fire and you need to set the ladder back 10 ft. to prevent burning. What is the shortest ladder (in feet) that will reach the third story window ?
What is the perimeter of
the sail?
9' + 12' + 15' = 36'
2 𝟏𝟒
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The distance between A and B is
| | | | | | | | | | | | | |
-5 4
A B
| -5 – 4 | = | -9 | = 9
Remember: Distance is always positive
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A
B
The Distance Formula Is Derived From The Pythagorean Formula
6
15
6² + 15² = C²
𝟐𝟔𝟏 = C
As you can see, the shortest distance between two points is...
A straight line; 16.16 < 21
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Distance Formula
Dist. = ( x2 - x1 )² + ( y2 - y1 )²
Remember the order ( x , y )
All answers are positive
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Find the distance between the two points on the graph.
The Distance Formula:
What is the distance along the x axis?
What is the distance along the y axis?
Let's first use the P.T. to find the distance: a2 + b2 = c2
Now, let's use the distance formula....
52 + 42 = 412
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Find the distance between:
( 3 – 8 )² + ( 6 - 10 )²
( -5 )² + ( -4 )²
25 + 16
41 = 6.40
( 8 – 3 )² + ( 10 – 6 )²
( 5 )² + ( 4 )²
25 + 16
41 =6.40
( 3, 6 ) and ( 8, 10 )Find the distance between:
( 8, 10 ) and ( 3, 6 )
When Using the distance formula, it does not matter what
point is used for x1 and x2. Be sure your y1 is from the same
coordinate pair as the x1
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Find the distance between the two points
(x1,y1) (x2, y2)
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Find the distance of the line.
(x1, y1) (x2, y2)
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Find the distance between:
12 − 6 + (3 5 2 5)2 2 = 45 – 30 – 30 + 20
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The Distance Formula
There are two different types of problems to solve withe the distance formula.
A. All four of the coordinates are known. Solve for the distance.B. Three of four coordinates and the distance is known. Solve for the fourth coordinate.
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Example 1. Find the distance between the two points.
(-2,5) and (3,-1)
• Let (x1,y1) = (-2,5) and (x2,y2) = (3,-1)
A. All four of the coordinates are known. Solve for the distance.
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Example 2.
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B. Three of four coordinates and the distance is known. Solve for the fourth coordinate.
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B. Three of four coordinates and the distance is known. Solve for the fourth coordinate.
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Class Work: 4.10
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Review Graphingy
x
( 0,0 )
Origin
Positive
Negative
Order ( X,Y )Quadrant
I
Quadrant
II
Quadrant
III
Quadrant
IV
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Khan Academy: Radical Equations