Maxwell’s Equations in Matter in vacuum in matter .E = / o .D = free Poisson’s Equation .B =...
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Transcript of Maxwell’s Equations in Matter in vacuum in matter .E = / o .D = free Poisson’s Equation .B =...
Maxwell’s Equations in Matter in vacuum in matter
.E = r /eo .D = rfree Poisson’s Equation
.B = 0 .B = 0 No magnetic monopoles
x E = -∂B/∂t x E = -∂B/∂t Faraday’s Law
x B = moj + moeo∂E/∂t x H = jfree + ∂D/∂t Maxwell’s Displacement
D = eo e E = eo(1+ c)E Constitutive relation for D
H = B/(mom) = (1- cB)B/mo Constitutive relation for H
Solve with: model e for insulating, isotropic matter, m = 1,rfree = 0, jfree = 0model e for conducting, isotropic matter, m = 1,rfree = 0, jfree = s(w)E
Bound and Free Charges
Bound chargesAll valence electrons in insulators (materials with a ‘band gap’)Bound valence electrons in metals or semiconductors (band gap absent/small )
Free chargesConduction electrons in metals or semiconductors
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Bound and Free Charges
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Maxwell’s Equations in Matter in vacuum in matter
.E = r /eo .D = rfree Poisson’s Equation
.B = 0 .B = 0 No magnetic monopoles
x E = -∂B/∂t x E = -∂B/∂t Faraday’s Law
x B = moj + moeo∂E/∂t x H = jfree + ∂D/∂t Maxwell’s Displacement
D = eo e E = eo(1+ c)E Constitutive relation for D
H = B/(mom) = (1- cB)B/mo Constitutive relation for H
Solve with: model e for insulating, isotropic matter, m = 1, r = 0, jfree = 0model e for conducting, isotropic matter, m = 1, r = 0, jfree = s(w)E
Maxwell’s Equations in Matter
Solution of Maxwell’s equations in matter for m = 1, rfree = 0, jfree = 0
Maxwell’s equations become
x E = -∂B/∂t
x H = ∂D/∂t H = B /mo D = eo e E
x B = moeo e ∂E/∂t
x ∂B/∂t = moeo e ∂2E/∂t2
x (- x E) = x ∂B/∂t = moeo e ∂2E/∂t2
-(.E) + 2E = moeo e ∂2E/∂t2 . e E = e . E = 0 since rfree = 0
2E - moeo e ∂2E/∂t2 = 0
Maxwell’s Equations in Matter
2E - moeo e ∂2E/∂t2 = 0 E(r, t) = Eo ex Re{ei(k.r - wt)}
2E = -k2E moeo e ∂2E/∂t2 = - moeo e w2E
(-k2 +moeo e w2)E = 0
w2 = k2/(moeoe) moeoe w2 = k2 k = ± w√(moeoe) k = ± √e w/c
Let e = e1 + ie2 be the real and imaginary parts of e and e = (n + ik)2
We need √ e = n + ik
e = (n + ik)2 = n2 - k2 + i 2nk e1 = n2 - k2 e2 = 2nk
E(r, t) = Eo ex Re{ ei(k.r - wt) } = Eo ex Re{ei(kz - wt)} k || ez
= Eo ex Re{ei((n + ik)wz/c - wt)} = Eo ex Re{ei(nwz/c - wt)e- kwz/c)}
Attenuated wave with phase velocity vp = c/n
Maxwell’s Equations in MatterSolution of Maxwell’s equations in matter for m = 1, rfree = 0, jfree = s(w)E
Maxwell’s equations become
x E = -∂B/∂t
x H = jfree + ∂D/∂t H = B /mo D = eo e E
x B = mo jfree + moeo e ∂E/∂t
x ∂B/∂t = mo s ∂E/∂t + moeo e ∂2E/∂t2
x (- x E) = x ∂B/∂t = mo s ∂E/∂t + moeo e ∂2E/∂t2
-(.E) + 2E = mo s ∂E/∂t + moeo e ∂2E/∂t2 . e E = e . E = 0 since rfree = 0
2E - mo s ∂E/∂t - moeo e ∂2E/∂t2 = 0
Maxwell’s Equations in Matter
2E - mo s ∂E/∂t - moeo e ∂2E/∂t2 = 0 E(r, t) = Eo ex Re{ei(k.r - wt)} k || ez
2E = -k2E mo s ∂E/∂t = mo s iw E moeo e ∂2E/∂t2 = - moeo e w2E
(-k2 -mo s iw +moeo e w2 )E = 0 s >> eo e w for a good conductor
E(r, t) = Eo ex Re{ ei(√(wsmo/2)z - wt)e-√(wsmo/2)z}
NB wave travels in +z direction and is attenuated
The skin depth d = √(2/wsmo) is the thickness over which incident radiation is attenuated. For example, Cu metal DC conductivity is 5.7 x 107 (Wm)-1
At 50 Hz d = 9 mm and at 10 kHz d = 0.7 mm
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