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Recruitment Examination- 2017

Post: Executive Officer (Morning)

(Mathematics)

1. Find the greatest number that will divide

43, 91 and 183 so as to leave the same

remainder in each case. (indiabix.com)

[A]. 4

[B]. 7

[C]. 9

[D]. 13

Answer: Option A

Explanation:

Required number = H.C.F. of (91 - 43), (183 -

91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

2. In a business, A and C invested amounts in the

ratio 2:1, whereas the ratio between amounts

invested by A and B was 3:2. If Rs. 1,57,300 was

their profit, how much amount did B receive ?

(sawaal.com)

A) 48400 B) 54200

C) 64000 D) 74000

Answer: A) 48400

Explanation:

A : B = 3 : 2 => B : A = 2 : 3 = 4 : 6 and A : C = 2 : 1

= 6 : 3.

So, B : A : C = 4 : 6 : 3 or A : B : C = 6 : 4 : 3.

B's share = Rs. (157300 x 4/13 ) = Rs. 48400.

3. Which one of the following is not a prime

number? (indiabix)A. 31

B.61

C.71

D. 91

Answer: Option D

Explanation:

91 is divisible by 7. So, it is not a prime number.

4. (0.04)-1.5 = ? (indiabix)A. 25

B.125

C.250

D. 625

Answer: Option B

Explanation:

(0.04)-1.5 = 4

-1.5 100

= 1

-(3/2) 25

= (25)(3/2)

= (52)(3/2)

= (5)2 x (3/2)

= 53

= 125.

5. A sum of money is borrowed and paid back in

two annual instalments of Rs. 882 each allowing

5% compound interest. The sum borrowed was:

A.

182

0

B. 1640

C.

126

0

D. 1440

Here is the answer and explanation

Answer : Option B

Explanation :

Present worth of Rs. x due T years hence is given by

Present Worth (PW) = x(1+R100)T

The sum borrowed

= Present Worth of Rs.882 due 1 year hence +

Present Worth of Rs.882 due 2 year hence

=882(1+5100)1+882(1+5100)2=882(105100)+882(1

05100)2=882(2120)+882(2120)2=8822021+8822

0202121=4220+42202021=840+22020=84

0+800=1640

i.e., The sum borrowed = Rs.1640

6. What is the unit digit in the product (684 x 759

x 413 x 676)?

A. 4

B. 12

C. 8

D. 16

Sol. Unit digit in the given product

= unit digit in the product (4x 9 x3 x6) = 8.

7. A certain number of men can finish a piece of

work in 100 days. If there were 10 men less, it

would take 10 days more for the work to be

finished. How many men were there originally?

(sawaal.com)

A) 75 B) 82

C) 100 D) 110

Answer: D) 110

Explanation:

Originally let there be x men.

Less men, More days (Indirect Proportion)

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(x-10) : x :: 100

:110 10x= 1100 x=

110

8. One year ago, Pinky was four times as old as

her daughter Soma. Six years hence, Pinkys age

will exceed her daughter's age by 9 years. The

ratio of the present ages of Pinky and her

daughter is:

A. 9 : 2 B. 11 : 3 C. 13 : 4 D. 12 : 5

9. The ratio between the perimeter and the

breadth of a rectangle is 5 : 1. If the area of the

rectangle is 216 sq. cm, what is the length of the

rectangle? (indiabix)

A. 16 cm

B. 18 cm

C. 24 cm

D. Data inadequate

E. None of these

Answer: Option B

Explanation:

2(l + b) =

5

b 1

2l + 2b = 5b

3b = 2l

b = 2 l

3

Then, Area = 216 cm2

l x b = 216

l x 2 l = 216

3

l2 = 324

l = 18 cm.

10. (87 X 87 + 61 X 61 -2 X 87 X 61) =?

A. 198 B. 196 C. 296 D. 298

Ans: 676

11. A is faster than B. A and Beach walk 24 km.

The sum of their speeds is 7 km/hr and the sum of

times taken by them is 14 hours. Then, A;s speed

is equal to:

(jake runs faster than paul.jake and paul each

walk 24kms.the sum of the speeds is 7km/hr and

the sum of the time taken by them is 14 hrs.then

jake's speed is?)

ANS:

sol: 24/7-j + 24/j =14

24j + 24(7-j)/ (7-j)j

here j is jack speed n 7-j is paul

on solving we get a eqn

14j^2-98j+168=0

solving we get j=4 n 3

but jack is faster hence ans is 4 km/hr..!!

-------------------------

Say speed of Jake is J and Speed of Paul is P.

Given J + P = 7 . (Eq.1)

Time = Distance/speed.

Time taken by Jake to cover 24 km = 24/J hours

Time taken by Paul to cover 24 km = 24/P hours Given, sum of times = 24 hours.

(24/J) + (24/P) = 14 (1/J) + (1/P) = 7/12 Using Eq.1,

(J + P)/(JP) = 7/12 J P = 12 (J P)2 = (J + P)2 4JP = 72 4 12 = 1 (J P) = 1 . (Eq.2) Eq.1 + Eq.2

2J = 8 J = 4 km/h

12. How many times in a day, the hands of a

clock are straight? (indiabix)

[A]. 22

[B]. 24

[C]. 44

[D]. 48

Answer: Option C

Explanation:

In 12 hours, the hands coincide or are in opposite

direction 22 times.

In 24 hours, the hands coincide or are in

opposite direction 44 times a day.

13. Sum of two numbers is 40 and their difference

is 4. The ratio of the numbers is

10:3

5:9

11:9

13:9

Answer: Option C

Explanation:

Let first number is m and second number is n.

Then m + n = 40 ---------[1]

And m n = 4 -------------[2]

Adding eq. 1 and eq. 2

We get, 2m = 44 m = 22 Putting value of m in eq. (1), we get n = 18

m : n = 22 : 18 m : n = 11 : 9

14. Two trains are running in opposite directions

with the same speed. If the length of each train is

120 metres and they cross each other in 12

seconds, then the speed of each train (in km/hr) is:

(indiabix)

A. 10

B. 18

C. 36

D. 72

Answer: Option C

Explanation:

Let the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)

12

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2x = 20

x = 10.

Speed of each train = 10

m/sec =

10

x

18

km/hr = 36

km/hr.

15. The average of first 50 non-zero positive

integers is (algebra.com)

A. 11.5 B. 25.5 C. 22.5 D. 25

Answer :(B)

25.5

Description :

Sum of first n non-zero positive integers n(n + 1)/2

So, average of first n non-zero positive integers n(n +

1)/2n = (n + 1)/2

=> (50 + 1)/2 = 25.5

16. In an election a candidate who gets 84% of the

votes is elected by a majority of 476 votes. What is

the total number of votes polled. (Hotel

Management, 2003)

A) 300

B) 700

C) 749

D) 848

Explanation:

17. The square root of (7 + 35) (7 - 35) is (indiabix)

18. A sum of money lent out at simple interest

amounts to 720 Rs. after 2 years and to 1020

Rs. after a further period of 5 years. The sum

is

: [A]500 Rs. [B]600 Rs. [C]700 Rs. [D]710 Rs.

600 Rs.

Principal + SI for 2 years = 720 Rs. (I)

Principal + SI for 7 years = 1020 Rs. (II)

Subtracting equation (I) from (II),

S.I. for 5 years = (1020 720) = 300 Rs.

S.I. for 2 years = 300\times \frac{2}{5} = 120 Rs.

Principal = (720 120) = 600 Rs. (Description :

S.I. for 5 year = Rs.(1020 - 720)

= Rs. 300.

S.I. for 2 year = Rs.(300/52)

= Rs. 120.

Principal = Rs. (720 - 120)

= Rs. 600.)

20. 138.009 + 341.981 - 146.305 = 123.6 + ? (sawaal.com)

A) 120.o85 B) 199.57

C) 295.05 D) None of these

Answer: D) None of these

Explanation:

Let 138.009 + 341.981 - 146.305 = 123.6 + z

Then, z = (138.09+341.981) - (146.305+123.6)=

479.99 - 269.905 = 210.085

19. In a certain store, the profit is 320% of the

cost. If the cost increases by 25% but the

selling price remains constant, approximately

what percentage of the selling price is the

profit? (indiabix)

[A]. 30%

[B]. 70%

[C]. 100%

[D]. 250%

Answer: Option B

Explanation:

Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. =

Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295.

Required

percentage =

295 x

100 %

=

1475 % = 70%

(approximately). 420 21

Let the total number of votes polled be x. Then, votes polled by other candidate

= (100 - 84) % of x = 16% of x

http://skillgun.com/question/4170/arithmetic/averages/the-average-of-first-50-nonzero-positive-integers-ishttp://skillgun.com/question/4170/arithmetic/averages/the-average-of-first-50-nonzero-positive-integers-is

Today's Janata Bank Executive

Officer Exam(2nd shift)

Math solution

1.

2+3+7+9+11= 28

2.

2x+3y = 39

3x+2y = 36

x = 6

y = 9

ans- 9

3.

100% = 120

125% = 120*125/100

= 150

again

110% = 198

100% = 198*100/110

= 180

pofit = 180-150 = 30

% = 30*100/150

= 20%

4.

x*15*12 = 10*6*18

x = 6

5.

122.5% = 392

100% = 392*100/122.5

= 320

profit = 72

6.

100.....increase 2

600...................12

for 4yr =12*4 = 48

720+48 = 768

7.

(17+3)*5 = 100

17*6 = 102

ans 2yrs

8.

20+10 = 30

20-10 = 10

10*3 = 30

ans : 20

9.

Total = 100

A = 30

remaining = 70

B = 60%

remaining = 40%

now, 40% of 70 = 28

diff= 30-28 = 2

2% = 1200

100% = 1200*100/2

= 60000

10.

3140000

solved by

Md. Ashraful Islam

11.

75/10x - 75/15x = 12.5

1/x(7.5-5) = 12.5

x= 1/5 km/min

so, 10*60*1/5 = 120 km/hr

12.

3(x+3) - 3(x-3)

= 18

13.

2q+1 = 1-q

q= 0

14.

24+8*2 = 40

15.

A+B = 5*20/5+20

= 4 hrs

1/4 - 1/C = 1/4.5

C = 36 hrs

16.

-20% - 10% + (-20)*(-10)/100 %

= -28%

17.

10*root(125-25)*5 = 500

18.

(root2)^n = root(2)^ 12

n = 12

19.

let,

6-x/7-x = 16/21

x= 2.8

as least

so ans : 3

6-3/7-3 = 3/4 = 3*5/4*5 = 15/20 <

16/21

20.

50ab = 75bc

c = 2a/3 = 0.67a

Solved by

Md. Ashraful Islam

=============

Solution of English Part (

Afternoon) ( Janata Bank..EO 2017 )

1. Laudable

2. Generosity

3. Criticise

4. Failure

5. Correct Manners

6. C

7. D

8. C

9. C

10. A

11. Revolutionary

12. Bookworm

13. Regicide

14. Heresy

15.Geologist

16. Deceives

17. To spend lavishly

18. Final outcome

19. A sudden idea

20. Do a mild business to keep busy

21. Dolorous

22. Sedate

23. Suggest

24. Canine

25. Jovial

()

=================================

. --

. --

. --

. --

.

--

. Dhaka

. --

. --

--

. --

.

. --

. --

.

. --

.

. --

.

. --

. --

=

)

-

) ,

-

) -

) -

) -

) -

) - ,

) - -

) -

) -

) -

)

)Notification

-

)

-

) -

) -

===============

Part-1

Fill in the black

1. Increase, populist

2. Several, behaves

3. Offender, details

4. Carelessness, nullify

5. Difficult, perseverance

.

Part-2

Best replaces:

1. sets the fire on the bus--set the bus on fire

2. being cordially-- being cordial to

3. for keep up the city clean -- to keep the city

clean

4. take place around-- taking place around

5. so much similar in-- so different in

.

Part-3

SYNONYMS:

1. MOROSEdepressed

2. SUNDRYVarious

3. AGILITYquickness

4. OSTENTATIONShowy

5. LATENT--- Concealed

.

Part-4

Similar or Opposite:

1. Transit-Permanent-B(1-3)

2. Ambience-Atmosphere-A(1-3)

3. Vivacious-Fanatical-D(3-4)

4. Poor-Sterling-B(3-4)

5. Benevolent-Charitable-D(1-3)

.

Part-5

Spelling:

1. Acquaintance

2. Accommodate

3. Occurred

4. Erroneously

5. Demurrage

============

Computer Part:

================

1. FTP = file transfer Protocol

2. insted of binary machine code = Symbolic code

3. Excel file into a word document = Placed in a

word table

4. Processor use RISC technology = power pc

5. Keyboard = Input

6. Plotter accuracy = Resolution

7. First electronic computer = ENIAC

8. FORTRAN = Formula Translation

9. Spelling Check = F7

10. Cybernetics = Control and communication

=====================

Math solution

1.( 87-61)^2 = 26^2 = 676

2. 4*9= 6

6*3 = 8

8*6= 8

3. 91

4. 43 4 , 40+3 remainder=3

914, 88+3 r= 3

1834 = 180+3 r =3

ans-4

5. 210.085

6. root[( 7)^2 -(3root5)^2]

=root 4 = 2

7. 50*51/2*50 = 25.5

8. x+y = 40

x-y = 4

x= 22

y = 18

ratio = 11:9

10. 13-4 = 9

(13-1)3 = 4

13:4

Solved by

Md. Ashraful Islam

11. 1/(0.04^1)* (0.04^0.5)

= 1/0.04*root0.04

= 1/0.04*0.2 = 100*10/8

= 125

12. ( 84-16)% = 476

100% = 476*100/68 =700

13. initial cost price = 100

sell price = 420

at 25% increase CP = 125

Profit = 295

% = 295*100/420 = 70%

14.

A:C = ( 2:1)*3= 6:3

A:B = (3:2)*2 =6:4

B gets = 157300*4/13 = 48400

15.

x*100 = 110(x-10)

x= 110

16.

x+y = 7

24/x + 24/y = 14

24(x+y/xy) = 14

xy = 12

so, x=4

y = 3

Ans = 4

17.

(120+120)/12 = 20 m/s

20/2 = 10m/s = 36 km/h

18.

7yr sum+profit = 1020

2 yr sum+profit = 720

5 yr = 300

2 yr profit = 300*2/5 = 120

sum = 720-120 = 600

19.

5:1 = 10:2

Br = 2x

Ln = 10x/2 -2x = 3x

now, 3x*2x = 216

x= 6

3x = 18 cm

20.

Ans: 44

Solved by

Computer Part:

1. FTP = file transfer Protocol 2. insted of binary machine code = Symbolic code 3. Excel file into a word document

= Placed in a word table 4. Processor use RISC technology = power pc 5. Keyboard = Input 6. Plotter accuracy =

Resolution 7. First electronic computer = ENIAC 8. FORTRAN = Formula Translation 9. Spelling Check = F7 10.

Cybernetics = Control and communication

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